1. OOPS stands for
“Object Oriented Programming System”
That is, OOPS itself is not a technology, some technology or language needs to follow
the standards of in order to become Object-Oriented

4. Behaviour
Parent Class
Variable
s
Method

5. To inherit the Generic Properties

8. In java , Inheritance can be implemented using two keywords
Extends keyword supports only one class to inherit at a time

9. Class Example{
}
Class Sample extends Example{
}

10. class Parent{
}
int a=10;
int b=20;
void m1(){
System.out.println("m1");
}
class Child extends Parent{
}
public static void main(String args[]){
}
Child c=new Child();
System.out.println(c.a);
System.out.println(c.b);
c.m1();
Output
10
20
m1

11. They can ’ t be inherited
As they are allowed to access only in the in class in which they are defined

12. class Parent{
}
int a=10;
int b=20;
void m1(){
System.out.println("m1");
}
class Private_Var extends Parent{
}
public static void main(String args[]){
}
Child c=new Child();
System.out.println(c.a);
System.out.println(c.b);
c.m1();
privat
e
private

13. Nothing to worry , they can be inherited

14. class Parent{
}
int a=10;
int b=20;
void m1(){
System.out.println("m1");
}
class Final_Var extends Parent{
}
public static void main(String args[]){
}
Child c=new Child();
System.out.println(c.a);
System.out.println(c.b);
c.m1();
final
final
Output
10
20
m1

15. By Declaring it as

16. final class Parent{
}
int a=10;
int b=20;
void m1(){
System.out.println("m1");
}
class Final extends Parent{
}
public static void main(String args[]){
}
Child c=new Child();
System.out.println(c.a);
System.out.println(c.b);
c.m1();

17. Private accessibility modifier is not
allowed for a class
The only allowed accessibility
modifiers for class are
 public
 <default>

18. private class Parent{
}
int a=10;
int b=20;
void m1(){
System.out.println("m1");
}
class PrivateDemo extends Parent{
}
public static void main(String args[]){
}
Child c=new Child();
System.out.println(c.a);
System.out.println(c.b);
c.m1();

19. Types of Inheritance

20. A B
C D
A A
A A A
B B
B
B
B C
C
C
C
D D
D
Singl
e
Multiple Hierarchical
Multilevel
Hybrid Multi-path

21. In any type of inheritance, if all the classes has at most one super class then that type is
in java
A
B
A
B C DC
A
B
Single
Multilevel
Hierarchical

22. A
D
B A
B C
D
A
B C
D
C
Multiple Hybrid Multi-path
In any type of inheritance, if any class has more than one super class then that type is
in java

23. Extends keyword supports only one class to inherit at a time

24. When a member is accessed using subclass object , the compiler first searches In subclass , if
it is available then it should be accessed
If it is not available , then it will search in super class
If it is not available in subclass also ,then compiler gives the error
This process is known as

25. static variables and static blocks are identified
and then executed from super class to sub
class
Non-static variables, Non-static blocks and
constructors are identified and then executed
from super class to subclass
For executing method definition , searching starts from subclass to super class
Class loading order is from super class to subclass
Object creation order is also from super class to subclass

26. }
Static{
Sopln(“Super class
SB”);
}
Static{
Sopln(“Subclass SB”);
}
class Sub_Control extends
Super_Control{
Super_Control(){
Sopln(“Super
Cons”);
}
Sub_Control(){
Sopln(“Sub Cons”);
}
class Super_Control
{
{
Sopln(“Subclass
NSB”);
}
{
Sopln(“Super class
NSB”);
}
}
Public static void main(S
args[]){
sopln(“main”);
Sub_Control sb=new
Sub_Control

27. Super class SB
Subclass SB
main
Super class NSB
Super Cons
Subclass NSB
Sub Cons

28. How memory is created for super class when object is created for sub-class??
With the help of
Super()

29. This process continues until java.lang.Object is reached
Constructor places super(); statement in each constructor of all the sub-classes
Automatically in compilation phase

30. class Sup1{
Sup1(){
}
}
class Sub1 extends
Sup1{
Sub1(){
}
}
class Sup1{
Sup1(){
}
}
class Sub1 extends
Sup1{
Sub1(){
}
}
compile
r
Compiles
to
super();
super();
public class Object{
public Object(){
}
}

32. class First{
}
class Second extends
First{
}
compile
r
Compiles
to
class First{
}
class Second
extends First{
}
super();
First(){
}
Second(){
super();
}

33. Compiler places the default constructor , only when there is no explicit constructor in the class
But compiler places the super(); in all the constructors in a class
And super(); should be the first statement in the constructor

34. class Sup2{
Sup2(int a){
}
}
Super();
In this case the compiler can’t be place the default constructor

35. Let us see , some cases

36. class Sup3{
class Sub3 extends Sup3{
Sup3(){
super();
}
Sub3(){
super();
}
}
}
public static void main(String args[]){
Sub3 sb=new Sub3();
}

37. class Sup4{
Sup4(int a){
System.out.println(“int-arg”);
}
}
Class Sub4 extends Sup4{
}
Sub4(){
}
Super();
In this case the developer has two alternatives.
public static void main(String args[]){
Sub4 sb=new Sub4();
}

38. Developer should explicitly call the super class parameterized
constructor
class Sup5{
}
Class Sub5 extends Sup5{
}
Sub5(){
}
Super(20);
Sup5(int a){
System.out.println(“int-arg”);
}
public static void main(String args[]){
Sub5 sb=new Sub5();
}

39. class Sup6{
Sup6(int a){
super();
System.out.println(“int-arg”);
}
}
Class Sub6 extends Sup6{
}
Sub6(){
}
Super();
Developer must place the no-arg Constructor in super class
public static void main(String args[]){
Sub6 sb=new Sub6();
}
Sup6(){
super();
}