This document provides specifications for an AC 3 Phase 8040 TEFC motor with a voltage of 230V, 50Hz, and speed of 2500rpm without a gearbox. Key specifications include an output speed of 2522rpm, torque of 5.9lb-in, current of 0.96amps, power of 177watts, and horsepower of 0.2367HP. The motor has a breakdown speed of 1582.94rpm, pullup torque of 10.35lb-in, continuous duty cycle, and efficiency of 61.7%. Start/stall conditions are 2.65amps current and 10.35lb-in torque. A graph shows efficiency and torque curves versus speed in both cold and hot conditions

1. Prepared by: Groschopp.com 02/24/14
Motor:
Voltage:
Speed:
Gearbox:
AC 3 Ph 8040 TEFC
230 v 50 Hz
2500 rpm 2 Poles
None
Product ID: 5293
SPECIFICATIONS
Rating:
Speed:
Torque:
Current:
Output:
Output:
2522.0 rpm
5.9lb-in
0.96 amps
177 watts
0.2367 HP
Breakdown (Cold):
Speed:
Torque:
1582.94 rpm
11.22 lb-in
Pullup (Cold):
Speed:
Torque:
0.0 rpm
10.35lb-in
Duty Cycle:
On:
Off:
Continuous
Efficiency:
Gearbox:
Motor:
System:
61.7 %
61.7 %
Start/Stall Conditions:
Current:
Torque:
2.65 amps
10.35 lb-in
Torque (lb-in)
Speed
RPM
Efficiency
300
0
0.0
1.2
600
2.4
900
3.6
1200
4.8
1500
6.0
1800
7.2
2100
8.4
2400
9.6
2700
10.8
90.0
80.0
70.0
60.0
50.0
40.0
30.0
20.0
10.0
Speed, Efficiency Vs. Torque
Cold
Hot
Notes:
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