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LP Formulation
Two products, namely P1 and P2 are being manufactured.
Each product has to be processed through two machines
M1 and M2. One unit of product P1 consumes 4 hours of
time on M1 and 2 hours of time on M2. Similarly, one unit
of P2 consumes 2 hours of time on M1 and 4 hours of
time on M2. 60 hours of time is available on M1 and 48
hours on M2. The per unit contribution margin of P1 is 8
and of P2 is 6. Determine the number of units of P1 and
P2 to be manufactured so as to maximise total
contribution.
Products M1 M2 Contribution
Margin
P1 4hrs 2hrs Rs.8
P2 2hrs 4hrs Rs.6
Total Machine
hours
60hrs 48hrs
๐‘ถ๐’ƒ๐’‹๐’†๐’„๐’•๐’Š๐’—๐’†: ๐‘ป๐’ ๐’Ž๐’‚๐’™๐’Š๐’Ž๐’Š๐’”๐’† ๐’•๐’‰๐’† ๐’•๐’๐’•๐’‚๐’ ๐’„๐’๐’๐’•๐’“๐’Š๐’ƒ๐’–๐’•๐’Š๐’๐’ ๐’Ž๐’‚๐’“๐’ˆ๐’Š๐’
๐‘ช๐’๐’๐’”๐’•๐’“๐’‚๐’Š๐’๐’•๐’”: ๐‘จ๐’—๐’‚๐’Š๐’๐’‚๐’ƒ๐’Š๐’๐’Š๐’•๐’š ๐’๐’‡ ๐’Ž๐’‚๐’„๐’‰๐’Š๐’๐’† ๐’‰๐’๐’–๐’“๐’”
๐‘ณ๐’†๐’• ๐’–๐’” ๐’‚๐’”๐’”๐’–๐’Ž๐’† ๐’•๐’‰๐’‚๐’• ๐’™ ๐Ÿ ๐’–๐’๐’Š๐’•๐’” ๐’๐’‡ ๐‘ท๐Ÿ ๐’‚๐’๐’… ๐’™ ๐Ÿ ๐’–๐’๐’Š๐’•๐’” ๐’๐’‡ ๐‘ท๐Ÿ ๐’‚๐’“๐’†
๐’‘๐’“๐’๐’…๐’–๐’„๐’†๐’…
๐‘ถ๐’ƒ๐’†๐’‹๐’„๐’•๐’Š๐’—๐’† ๐’‡๐’–๐’๐’„๐’•๐’Š๐’๐’:
๐‘ด๐’‚๐’™๐’Š๐’Ž๐’Š๐’”๐’† ๐’› = ๐Ÿ–๐’™ ๐Ÿ + ๐Ÿ”๐’™ ๐Ÿ
๐‘ด๐’‚๐’„๐’‰๐’Š๐’๐’† ๐‘ด๐Ÿ ๐’„๐’๐’๐’”๐’•๐’“๐’‚๐’Š๐’๐’•:
๐Ÿ’๐’™ ๐Ÿ + ๐Ÿ๐’™ ๐Ÿ โ‰ค ๐Ÿ”๐ŸŽ
๐‘ด๐’‚๐’„๐’‰๐’Š๐’๐’† ๐‘ด๐Ÿ ๐’„๐’๐’๐’”๐’•๐’“๐’‚๐’Š๐’๐’•:
๐Ÿ๐’™ ๐Ÿ + ๐Ÿ’๐’™ ๐Ÿ โ‰ค ๐Ÿ’๐Ÿ–
๐‘ต๐’๐’ โˆ’ ๐’๐’†๐’ˆ๐’‚๐’•๐’Š๐’—๐’Š๐’•๐’š ๐’„๐’๐’๐’”๐’•๐’“๐’‚๐’Š๐’๐’•๐’”:
๐’™ ๐Ÿ โ‰ฅ ๐ŸŽ
๐’™ ๐Ÿ โ‰ฅ ๐ŸŽ
โˆด ๐‘ป๐’‰๐’† ๐’‡๐’๐’“๐’Ž๐’–๐’๐’‚๐’•๐’†๐’… ๐’‘๐’“๐’๐’ƒ๐’๐’†๐’Ž ๐’„๐’‚๐’ ๐’ƒ๐’† ๐’”๐’•๐’‚๐’•๐’†๐’… ๐’‚๐’”:
๐‘ด๐’‚๐’™๐’Š๐’Ž๐’Š๐’”๐’† ๐’› = ๐Ÿ–๐’™ ๐Ÿ + ๐Ÿ”๐’™ ๐Ÿ
๐’”๐’–๐’ƒ๐’‹๐’†๐’„๐’• ๐’•๐’ ๐’•๐’‰๐’† ๐’„๐’๐’๐’”๐’•๐’“๐’‚๐’Š๐’๐’•๐’”:
๐Ÿ’๐’™ ๐Ÿ + ๐Ÿ๐’™ ๐Ÿ โ‰ค ๐Ÿ”๐ŸŽ
๐Ÿ๐’™ ๐Ÿ + ๐Ÿ’๐’™ ๐Ÿ โ‰ค ๐Ÿ’๐Ÿ–
๐’™ ๐Ÿ โ‰ฅ ๐ŸŽ
๐’™ ๐Ÿ โ‰ฅ ๐ŸŽ

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Lp formulation

  • 2. Two products, namely P1 and P2 are being manufactured. Each product has to be processed through two machines M1 and M2. One unit of product P1 consumes 4 hours of time on M1 and 2 hours of time on M2. Similarly, one unit of P2 consumes 2 hours of time on M1 and 4 hours of time on M2. 60 hours of time is available on M1 and 48 hours on M2. The per unit contribution margin of P1 is 8 and of P2 is 6. Determine the number of units of P1 and P2 to be manufactured so as to maximise total contribution.
  • 3. Products M1 M2 Contribution Margin P1 4hrs 2hrs Rs.8 P2 2hrs 4hrs Rs.6 Total Machine hours 60hrs 48hrs
  • 4. ๐‘ถ๐’ƒ๐’‹๐’†๐’„๐’•๐’Š๐’—๐’†: ๐‘ป๐’ ๐’Ž๐’‚๐’™๐’Š๐’Ž๐’Š๐’”๐’† ๐’•๐’‰๐’† ๐’•๐’๐’•๐’‚๐’ ๐’„๐’๐’๐’•๐’“๐’Š๐’ƒ๐’–๐’•๐’Š๐’๐’ ๐’Ž๐’‚๐’“๐’ˆ๐’Š๐’ ๐‘ช๐’๐’๐’”๐’•๐’“๐’‚๐’Š๐’๐’•๐’”: ๐‘จ๐’—๐’‚๐’Š๐’๐’‚๐’ƒ๐’Š๐’๐’Š๐’•๐’š ๐’๐’‡ ๐’Ž๐’‚๐’„๐’‰๐’Š๐’๐’† ๐’‰๐’๐’–๐’“๐’” ๐‘ณ๐’†๐’• ๐’–๐’” ๐’‚๐’”๐’”๐’–๐’Ž๐’† ๐’•๐’‰๐’‚๐’• ๐’™ ๐Ÿ ๐’–๐’๐’Š๐’•๐’” ๐’๐’‡ ๐‘ท๐Ÿ ๐’‚๐’๐’… ๐’™ ๐Ÿ ๐’–๐’๐’Š๐’•๐’” ๐’๐’‡ ๐‘ท๐Ÿ ๐’‚๐’“๐’† ๐’‘๐’“๐’๐’…๐’–๐’„๐’†๐’… ๐‘ถ๐’ƒ๐’†๐’‹๐’„๐’•๐’Š๐’—๐’† ๐’‡๐’–๐’๐’„๐’•๐’Š๐’๐’: ๐‘ด๐’‚๐’™๐’Š๐’Ž๐’Š๐’”๐’† ๐’› = ๐Ÿ–๐’™ ๐Ÿ + ๐Ÿ”๐’™ ๐Ÿ ๐‘ด๐’‚๐’„๐’‰๐’Š๐’๐’† ๐‘ด๐Ÿ ๐’„๐’๐’๐’”๐’•๐’“๐’‚๐’Š๐’๐’•: ๐Ÿ’๐’™ ๐Ÿ + ๐Ÿ๐’™ ๐Ÿ โ‰ค ๐Ÿ”๐ŸŽ ๐‘ด๐’‚๐’„๐’‰๐’Š๐’๐’† ๐‘ด๐Ÿ ๐’„๐’๐’๐’”๐’•๐’“๐’‚๐’Š๐’๐’•: ๐Ÿ๐’™ ๐Ÿ + ๐Ÿ’๐’™ ๐Ÿ โ‰ค ๐Ÿ’๐Ÿ– ๐‘ต๐’๐’ โˆ’ ๐’๐’†๐’ˆ๐’‚๐’•๐’Š๐’—๐’Š๐’•๐’š ๐’„๐’๐’๐’”๐’•๐’“๐’‚๐’Š๐’๐’•๐’”: ๐’™ ๐Ÿ โ‰ฅ ๐ŸŽ ๐’™ ๐Ÿ โ‰ฅ ๐ŸŽ
  • 5. โˆด ๐‘ป๐’‰๐’† ๐’‡๐’๐’“๐’Ž๐’–๐’๐’‚๐’•๐’†๐’… ๐’‘๐’“๐’๐’ƒ๐’๐’†๐’Ž ๐’„๐’‚๐’ ๐’ƒ๐’† ๐’”๐’•๐’‚๐’•๐’†๐’… ๐’‚๐’”: ๐‘ด๐’‚๐’™๐’Š๐’Ž๐’Š๐’”๐’† ๐’› = ๐Ÿ–๐’™ ๐Ÿ + ๐Ÿ”๐’™ ๐Ÿ ๐’”๐’–๐’ƒ๐’‹๐’†๐’„๐’• ๐’•๐’ ๐’•๐’‰๐’† ๐’„๐’๐’๐’”๐’•๐’“๐’‚๐’Š๐’๐’•๐’”: ๐Ÿ’๐’™ ๐Ÿ + ๐Ÿ๐’™ ๐Ÿ โ‰ค ๐Ÿ”๐ŸŽ ๐Ÿ๐’™ ๐Ÿ + ๐Ÿ’๐’™ ๐Ÿ โ‰ค ๐Ÿ’๐Ÿ– ๐’™ ๐Ÿ โ‰ฅ ๐ŸŽ ๐’™ ๐Ÿ โ‰ฅ ๐ŸŽ