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5.1 Estimating with Finite Sums




                                                 Greenfield Village, Michigan
   Photo by Vickie Kelly, 2002    Greg Kelly, Hanford High School, Richland, Washington
3

If the velocity is not constant,
we might guess that the
                                            2
distance traveled is still equal
to the area under the curve.
                                            1




                   1       2
 Example:     V        t       1            0           1                  2               3                4
                   8                                                1                                   1
                                                                                   1
                                                    1                          1
                                                                1                                  2
                                                                    8                                   8
                                                                                   2
                                                                                       t        v
We could estimate the area under the curve by                                          0        1
drawing rectangles touching at the left corners.                                                 1
                                                                                       1       1
                                                                                                 8
 This is called the Left-hand Rectangular                                                        1
                                                                                       2
 Approximation Method (LRAM).                                                                  1
                                                                                                 2
                                    1       1       1       3                                       1
  Approximate area:                                                                    3
                               11       1       2       5           5.75                       2
                                    8       2       8       4                                       8
1                   3
                             2
                 V       t       1
                     8

                                         2




                                         1




                                         0               1           2            3       4
                                                     1                        1
                                                                 1
                                                             1
                                                 1                       2            3
                                                     8                        8
                                                                 2


We could also use a Right-hand Rectangular Approximation
Method (RRAM).

                                     1       1       1           3
    Approximate area:            1       1       2       3   7       7 .7 5
                                     8       2       8           4
1               3
                                     2
                         V       t       1
    t                        8
           v
   0 .5   1 .0 3 1 2 5                       2



          1 .2 8 1 2 5
  1 .5
                                             1
          1 .7 8 1 2 5
   2 .5

          2 .5 3 1 2 5
  3 .5
                                             0               1            2           3            4

                                                 1 .0 3 1 2 5 1 .2 8 1 2 5 1 .7 8 1 2 5 2 .5 3 1 2 5


Another approach would be to use rectangles that touch at
the midpoint. This is the Midpoint Rectangular
Approximation Method (MRAM).
                           In this example there are four
                           subintervals.
   Approximate area:
                           As the number of subintervals
        6 .6 2 5
                           increases, so does the accuracy.
1               3
                                              2
                                 V        t       1
With 8 subintervals:                  8

                                                      2
         t        v
      0 .2 5 1 .0 0 7 8 1
                                                      1
      0 .7 5 1 .0 7 0 3 1

      1 .2 5 1 .1 9 5 3 1
                                                      0   1         2            3   4
                 1.38281
      1 .7 5

      2 .2 5 1.63281
                                                              Approximate area:
      2 .7 5 1.94531
                                                                  6 .6 5 6 2 4
      3 .2 5 2 .3 2 0 3 1

      3 .7 5 2 .7 5 7 8 1

               1 3 .3 1 2 4 8   0.5   6 .6 5 6 2 4

                   width of subinterval
Rectangular Approximation
 Methods

 ◦ LRAM: smaller than true area
 ◦ RRAM: larger than true area
 ◦ MRAM: closest to true area

    More Accurate = More intervals
With the trapezoidal rule you take the

    LRAM and add the RRAM and then divide
    by two.
    So we take LRAM (5.75) from the first

    problem and the RRAM (7.75) and we add
    them to together.
    The answer is 13.5 and then we divide

    that by two to get our answer:
    The answer is 6.75.

Finite Sums

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Finite Sums

  • 1. 5.1 Estimating with Finite Sums Greenfield Village, Michigan Photo by Vickie Kelly, 2002 Greg Kelly, Hanford High School, Richland, Washington
  • 2. 3 If the velocity is not constant, we might guess that the 2 distance traveled is still equal to the area under the curve. 1 1 2 Example: V t 1 0 1 2 3 4 8 1 1 1 1 1 1 2 8 8 2 t v We could estimate the area under the curve by 0 1 drawing rectangles touching at the left corners. 1 1 1 8 This is called the Left-hand Rectangular 1 2 Approximation Method (LRAM). 1 2 1 1 1 3 1 Approximate area: 3 11 1 2 5 5.75 2 8 2 8 4 8
  • 3. 1 3 2 V t 1 8 2 1 0 1 2 3 4 1 1 1 1 1 2 3 8 8 2 We could also use a Right-hand Rectangular Approximation Method (RRAM). 1 1 1 3 Approximate area: 1 1 2 3 7 7 .7 5 8 2 8 4
  • 4. 1 3 2 V t 1 t 8 v 0 .5 1 .0 3 1 2 5 2 1 .2 8 1 2 5 1 .5 1 1 .7 8 1 2 5 2 .5 2 .5 3 1 2 5 3 .5 0 1 2 3 4 1 .0 3 1 2 5 1 .2 8 1 2 5 1 .7 8 1 2 5 2 .5 3 1 2 5 Another approach would be to use rectangles that touch at the midpoint. This is the Midpoint Rectangular Approximation Method (MRAM). In this example there are four subintervals. Approximate area: As the number of subintervals 6 .6 2 5 increases, so does the accuracy.
  • 5. 1 3 2 V t 1 With 8 subintervals: 8 2 t v 0 .2 5 1 .0 0 7 8 1 1 0 .7 5 1 .0 7 0 3 1 1 .2 5 1 .1 9 5 3 1 0 1 2 3 4 1.38281 1 .7 5 2 .2 5 1.63281 Approximate area: 2 .7 5 1.94531 6 .6 5 6 2 4 3 .2 5 2 .3 2 0 3 1 3 .7 5 2 .7 5 7 8 1 1 3 .3 1 2 4 8 0.5 6 .6 5 6 2 4 width of subinterval
  • 6. Rectangular Approximation Methods ◦ LRAM: smaller than true area ◦ RRAM: larger than true area ◦ MRAM: closest to true area More Accurate = More intervals
  • 7. With the trapezoidal rule you take the  LRAM and add the RRAM and then divide by two. So we take LRAM (5.75) from the first  problem and the RRAM (7.75) and we add them to together. The answer is 13.5 and then we divide  that by two to get our answer: The answer is 6.75. 