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Fórmulas de Cálculo Diferencial e Integral (Página 1 de 3)                                                                                                                                                                                                               http://www.geocities.com/calculusjrm/                                       Jesús Rubí M.
Fórmulas de                                                             ( a + b ) ⋅ ( a − ab + b ) = a + b
                                                                                           2                       2           3      3                                                                                                         Gráfica 4. Las funciones trigonométricas inversas
                                                                                                                                                                                                                                                arcctg x , arcsec x , arccsc x :                      sin α + sin β = 2sin
                                                                                                                                                                                                                                                                                                                           1               1
                                                                                                                                                                                                                                                                                                                             (α + β ) ⋅ cos (α − β )
                                                                        ( a + b ) ⋅ ( a3 − a 2 b + ab 2 − b3 ) = a 4 − b 4
                                                                                                                                                                                                                                                                                                                           2               2
Cálculo Diferencial                                                                                                                                                                                   HIP
                                                                                                                                                                                                                                       CO               4                                                                  1               1
                                                                                                                                                                                                                                                                                                      sin α − sin β = 2 sin (α − β ) ⋅ cos (α + β )
                                                                        ( a + b ) ⋅ ( a 4 − a 3b + a 2 b 2 − ab3 + b 4 ) = a 5 + b5
e Integral ACTUALIZADO AGO-2007                                                                                                                                                                 θ                                                       3
                                                                                                                                                                                                                                                                                                                           2               2
                                                                        ( a + b ) ⋅ ( a5 − a 4 b + a 3b 2 − a 2 b3 + ab 4 − b5 ) = a 6 − b 6
                                                                                                                                                                                                                                                                                                                            1               1
                                                                                                                                                                                                          CA                                                                                          cos α + cos β = 2 cos (α + β ) ⋅ cos (α − β )
Jesús Rubí Miranda (jesusrubim@yahoo.com)                                                                                                                                                                                                               2                                                                   2               2
Móvil. Méx. DF. 044 55 13 78 51 94                                                                                                                                                                                                                                                                                           1               1
                                                                                       ⎛                                          ⎞                                                                                                                                                                   cos α − cos β = −2 sin (α + β ) ⋅ sin (α − β )
                                                                                           n
                                                                        ( a + b ) ⋅ ⎜ ∑ ( −1)
                                                                                                          k +1
                                                                                                                   a n − k b k −1 ⎟ = a n + b n ∀ n ∈        impar         θ      sin  cos   tg   ctg  sec csc
                                                                                                                                                                                                                                                        1

                                                                                                                                                                                                                                                                                                                             2               2
                                                                                       ⎝ k =1                                     ⎠
1. VALOR ABSOLUTO                                                                                                                                                         0        0    1    0     ∞    1   ∞
                                                                                                                                                                                                                                                                                                                               sin (α ± β )
                                                                                                                                                                                                                                                        0

                                                                                       ⎛   n
                                                                                                     ⎞                                                                                                                                                                                                tg α ± tg β =
                                                                        ( a + b ) ⋅ ⎜ ∑ ( −1)
                                                                                                          k +1                                                                    12
    ⎧a si a ≥ 0                                                                       a n − k b k −1 ⎟ = a n − b n ∀ n ∈                                     par          30            3 2 1 3     3 2 3 2
 a =⎨                                                                         ⎝ k =1                 ⎠
                                                                                                                                                                                                                                                        -1
                                                                                                                                                                                                                                                                                      arc ctg x                            cos α ⋅ cos β
                                                                                                                                                                          45     1 2 1 2                 2   2
    ⎩− a si a < 0
                                                                                                                                                                                              1    1                                                                                  arc sec x
                                                                                                                                                                                                                                                                                      arc csc x
                                                                                                                                                                                                                                                                                                                     1
                                                                                                                                                                                                                                                                                                                       ⎡sin (α − β ) + sin (α + β ) ⎤
                                                                        5. SUMAS Y PRODUCTOS                                                                              60       3 2 12      3 1 3    2 2 3                                           -2
                                                                                                                                                                                                                                                                                                      sin α ⋅ cos β =
 a = −a                                                                                                                                                                                                                                                                                                              2⎣                             ⎦
                                                                                                                                                                                                                                                          -5                      0               5


                                                                                                                                                                                             ∞          ∞
                                                                                                               n
                                                                                               + a n = ∑ ak
                                                                                                                                                                          90       1    0          0        1
a ≤ a y −a ≤ a                                                          a1 + a2 +                                                                                                                                                               8. IDENTIDADES TRIGONOMÉTRICAS                                       1
                                                                                                            k =1                                                                      ⎡ π π⎤                                                                                                          sin α ⋅ sin β = ⎡cos (α − β ) − cos (α + β ) ⎤
                                                                                                                                                                                                                                                sin θ + cos 2 θ = 1                                                  2⎣                             ⎦
                                                                                                                                                                                                                                                    2

 a ≥0 y a =0 ⇔ a=0                                                        n                                                                                           y = ∠ sin x y ∈ ⎢− , ⎥
                                                                        ∑ c = nc                                                                                                      ⎣ 2 2⎦
                                                                                                                                                                                                                                                1 + ctg 2 θ = csc 2 θ
                                                                                                                                                                                                                                                                                                      cos α ⋅ cos β =
                                                                                                                                                                                                                                                                                                                                1
                                                                                                                                                                                                                                                                                                                                  ⎡cos (α − β ) + cos (α + β ) ⎤
                                                                                                                                                                      y = ∠ cos x y ∈ [ 0, π ]
                                 n                    n

                                ∏a          = ∏ ak                                                                                                                                                                                                                                                                              2⎣                             ⎦
                                                                         k =1
 ab = a b ó                            k                                  n                 n                                                                                                                                                   tg 2 θ + 1 = sec 2 θ
                                k =1              k =1
                                                                        ∑ ca         = c ∑ ak
                                                                                                                                                                      y = ∠ tg x           y∈ −
                                                                                                                                                                                                          π π                                                                                                   tg α + tg β
                                                                                                                                                                                                                                                sin ( −θ ) = − sin θ
                                                                                k
                                        n                  n             k =1              k =1
                                                                                                                                                                                                           ,                                                                                          tg α ⋅ tg β =
 a+b ≤ a + b ó                         ∑a             ≤ ∑ ak              n                         n                   n
                                                                                                                                                                                                          2 2                                                                                                  ctg α + ctg β
                                                                                                                                                                                                                                                cos ( −θ ) = cos θ
                                                  k
                                       k =1               k =1
                                                                        ∑(a     k    + bk ) = ∑ ak + ∑ bk
                                                                                                                                                                      y = ∠ ctg x = ∠ tg
                                                                                                                                                                                                     1
                                                                                                                                                                                                           y ∈ 0, π                                                                                   9. FUNCIONES HIPERBÓLICAS
                                                                                                                                                                                                                                                tg ( −θ ) = − tg θ
                                                                         k =1                      k =1                k =1
2. EXPONENTES                                                                                                                                                                                        x                                                                                                         ex − e− x
                                                                                                                                                                                                                                                                                                      sinh x =
                                                                          n
 a p ⋅ a q = a p+q                                                      ∑(a
                                                                         k =1
                                                                                k    − ak −1 ) = an − a0                                                              y = ∠ sec x = ∠ cos
                                                                                                                                                                                          1
                                                                                                                                                                                            y ∈ [ 0, π ]                                        sin (θ + 2π ) = sin θ                                               2
 ap                                                                                                                                                                                       x
    = a p−q                                                                                                                                                                                                                                                                                                    e x + e− x
                                                                          n
                                                                                                                   n                                                                      1       ⎡ π π⎤                                        cos (θ + 2π ) = cos θ                                 cosh x =
 aq
                                                                        ∑ ⎡ a + ( k − 1) d ⎤ = 2 ⎡ 2a + ( n − 1) d ⎤
                                                                          ⎣                ⎦     ⎣                 ⎦                                                  y = ∠ csc x = ∠ sen    y ∈ ⎢− , ⎥
                                                                                                                                                                                                  ⎣ 2 2⎦                                        tg (θ + 2π ) = tg θ
                                                                                                                                                                                                                                                                                                                    2
(a )
   p q
            =a          pq                                               k =1                                                                                                             x
                                                                                                                                                                                                                                                                                                      tgh x =
                                                                                                                                                                                                                                                                                                              sinh x e x − e − x
                                                                                                                                                                                                                                                                                                                      =
                                                                                             n
                                                                                               (a + l )                                                              Gráfica 1. Las funciones trigonométricas: sin x ,                          sin (θ + π ) = − sin θ                                        cosh x e x + e− x
(a ⋅b)          = a ⋅b                                                                                    =
            p               p    p
                                                                                             2                                                                       cos x , tg x :                                                             cos (θ + π ) = − cos θ                                            1       e x + e− x
        p                                                                n
                                                                                     1 − r n a − rl                                                                                                                                                                                                   ctgh x =        =
⎛a⎞  ap
⎜ ⎟ = p                                                                 ∑ ar k −1 = a 1 − r = 1 − r                                                                        2                                                                    tg (θ + π ) = tg θ                                             tgh x e x − e − x
⎝b⎠  b                                                                  k =1
                                                                                                                                                                                                                                                                                                                   1            2
                                                                                                                                                                                                                                                sin (θ + nπ ) = ( −1) sin θ                           sech x =          =
                                                                                                                                                                         1.5                                                                                              n

                                                                        ∑ k = 2 ( n2 + n )
                                                                         n
 a = a                                                                          1
                                                                                                                                                                                                                                                                                                               cosh x e x + e − x
  p/q           q       p
                                                                                                                                                                           1

                                                                                                                                                                                                                                                cos (θ + nπ ) = ( −1) cos θ
                                                                                                                                                                                                                                                                          n
3. LOGARITMOS                                                           k =1                                                                                                                                                                                                                                      1            2
                                                                                                      n ( n + 1)( 2n + 1)
                                                                                                                                                                         0.5
                                                                                                                                                                                                                                                                                                      csch x =         =
                                                                        ∑ k 2 = 6 ( 2n3 + 3n2 + n ) =                                                                                                                                           tg (θ + nπ ) = tg θ                                            sinh x e x − e − x
                                                                          n
 log a N = x ⇒ a x = N                                                          1
                                                                                                                                                                           0


log a MN = log a M + log a N                                            k =1                                   6                                                                                                                                                                                      sinh :     →
                                                                                                                                                                        -0.5
                                                                                                                                                                                                                                                sin ( nπ ) = 0
                                                                        ∑ k = 4 ( n + 2n + n )                                                                                                                                                                                                                   → [1, ∞
                                                                         n
      M                                                                      3  1 4        3    2                                                                                                                                                                                                     cosh :
         = log a M − log a N                                                                                                                                                                                                                    cos ( nπ ) = ( −1)
                                                                                                                                                                          -1
                                                                                                                                                                                                                                                                     n
log a                                                                   k =1
      N                                                                                                                                                                 -1.5                                                        sen x
                                                                                                                                                                                                                                                                                                      tgh :    → −1,1
                                                                                                                                                                                                                                                tg ( nπ ) = 0
                                                                                                                                                                                                                                    cos x


                                                                        ∑ k 4 = 30 ( 6n5 + 15n4 + 10n3 − n )
                                                                         n
log a N = r log a N
       r                                                                         1
                                                                                                                                                                                                                                                                                                                 − {0} → −∞ , −1 ∪ 1, ∞
                                                                                                                                                                                                                                    tg x
                                                                                                                                                                          -2
                                                                                                                                                                            -8   -6        -4        -2     0   2       4       6           8                                                         ctgh :
                                                                        k =1
                                                                                                                                                                                                                                                    ⎛ 2n + 1 ⎞
                                                                                                                                                                                                                                                            π ⎟ = ( −1)
          log b N ln N
                                                                                                                                                                                                                                                                                                                 → 0 ,1]
                                                                                                                                                                                                                                                                        n
log a N =         =                                                     1+ 3 + 5 +                + ( 2n − 1) = n 2                                                  Gráfica 2. Las funciones trigonométricas csc x ,                           sin ⎜                                                 sech :
           log b a ln a                                                                                                                                                                                                                             ⎝ 2       ⎠
                                                                                                                                                                     sec x , ctg x :                                                                                                                  csch :     − {0} →             − {0}
                                                                                                                                                                                                                                                    ⎛ 2n + 1 ⎞
                                                                                 n
log10 N = log N y log e N = ln N                                        n! = ∏ k                                                                                                                                                                cos ⎜       π⎟=0
4. ALGUNOS PRODUCTOS                                                            k =1                                                                                     2.5                                                                        ⎝ 2       ⎠                                       Gráfica 5. Las funciones hiperbólicas sinh x ,
 a ⋅ ( c + d ) = ac + ad                                                ⎛n⎞         n!                                                                                     2
                                                                                                                                                                                                                                                   ⎛ 2n + 1 ⎞                                         cosh x , tgh x :
                                                                        ⎜ ⎟=                 , k≤n                                                                                                                                              tg ⎜       π⎟=∞
                                                                        ⎝ k ⎠ ( n − k ) !k !
                                                                                                                                                                         1.5

( a + b ) ⋅ ( a − b ) = a 2 − b2                                                                                                                                           1
                                                                                                                                                                                                                                                   ⎝ 2      ⎠                                                      5


                                                                                                                                                                                                                                                                                                                   4
                                                                                      n
                                                                                         ⎛n⎞                                                                                                                                                                ⎛    π⎞
( a + b ) ⋅ ( a + b ) = ( a + b ) = a 2 + 2ab + b 2                     ( x + y ) = ∑ ⎜ ⎟ x n −k y k
                                 2                                               n                                                                                       0.5
                                                                                                                                                                                                                                                sin θ = cos ⎜ θ − ⎟                                                3

                                                                                    k =0 ⎝ k ⎠                                                                                                                                                              ⎝    2⎠
                                                                                                                                                                           0


( a − b ) ⋅ ( a − b ) = ( a − b ) = a 2 − 2ab + b 2
                                                                                                                                                                                                                                                                                                                   2
                                 2
                                                                                                                                                                        -0.5

                                                                                                                                                                                                                                                            ⎛    π⎞                                                1


                                                                        ( x1 + x2 +               + xk ) = ∑
                                                                                                                                     n!                                                                                                         cos θ = sin ⎜ θ + ⎟
( x + b ) ⋅ ( x + d ) = x 2 + ( b + d ) x + bd                                                                                               x1n1 ⋅ x2 2
                                                                                                           n                                                              -1
                                                                                                                                                     n
                                                                                                                                                           xknk
                                                                                                                                                                                                                                                            ⎝    2⎠                                                0
                                                                                                                              n1 ! n2 ! nk !                            -1.5


( ax + b ) ⋅ ( cx + d ) = acx 2 + ( ad + bc ) x + bd
                                                                                                                                                                                                                                    csc x                                                                          -1

                                                                                                                                                                                                                                                sin (α ± β ) = sin α cos β ± cos α sin β
                                                                                                                                                                          -2                                                        sec x
                                                                        6. CONSTANTES                                                                                                                                               ctg x                                                                          -2


( a + b ) ⋅ ( c + d ) = ac + ad + bc + bd
                                                                                                                                                                        -2.5

                                                                         π = 3.14159265359…                                                                                                                                                     cos (α ± β ) = cos α cos β ∓ sin α sin β
                                                                                                                                                                            -8   -6        -4        -2     0   2       4       6           8                                                                                                                senh x
                                                                                                                                                                                                                                                                                                                   -3                                        cosh x
                                                                                                                                                                                                                                                                                                                                                             tgh x


( a + b ) = a3 + 3a 2b + 3ab 2 + b3                                      e = 2.71828182846…
         3                                                                                                                                                                                                                                                                                                         -4
                                                                                                                                                                     Gráfica 3. Las funciones trigonométricas inversas                                        tg α ± tg β                                            -5                          0                    5

                                                                                                                                                                                                                                                tg (α ± β ) =                                         10. FUNCIONES HIPERBÓLICAS INV
( a − b ) = a 3 − 3a 2b + 3ab 2 − b3
         3                                                              7. TRIGONOMETRÍA                                                                             arcsin x , arccos x , arctg x :                                                         1 ∓ tg α tg β

( a + b + c ) = a 2 + b 2 + c 2 + 2ab + 2ac + 2bc
               2                                                         sen θ =
                                                                                  CO
                                                                                            cscθ =
                                                                                                     1                                                                     4                                                                    sin 2θ = 2sin θ cos θ                                                     (
                                                                                                                                                                                                                                                                                                      sinh −1 x = ln x + x 2 + 1 , ∀x ∈      )
                                                                                                   sen θ
                                                                                                                                                                                                                                                                                                                           (                 )
                                                                                 HIP
                                                                                                                                                                                                                                                cos 2θ = cos θ − sin θ
                                                                                                                                                                                                                                                                 2            2
                                                                                                                                                                                                                                                                                                      cosh −1 x = ln x ± x 2 − 1 , x ≥ 1
( a − b ) ⋅ ( a 2 + ab + b 2 ) = a 3 − b3
                                                                                                                                                                           3
                                                                                  CA                 1
                                                                         cosθ =             secθ =                                                                                                                                                         2 tg θ
                                                                                 HIP               cosθ                                                                                                                                         tg 2θ =                                                             1 ⎛1+ x ⎞
( a − b ) ⋅ ( a 3 + a 2 b + ab 2 + b3 ) = a 4 − b 4                                                                                                                                                                                                      1 − tg 2 θ
                                                                                                                                                                           2

                                                                                sen θ CO            1                                                                                                                                                                                                 tgh −1 x =     ln ⎜   ⎟,            x <1
                                                                         tgθ =       =      ctgθ =                                                                                                                                                                                                                  2 ⎝1− x ⎠
( a − b ) ⋅ ( a 4 + a 3b + a 2 b 2 + ab3 + b 4 ) = a 5 − b5                     cosθ CA            tgθ                                                                                                                                                    1
                                                                                                                                                                                                                                                sin 2 θ = (1 − cos 2θ )
                                                                                                                                                                           1


                                                                                                                                                                                                                                                                                                                        1 ⎛ x +1⎞
                                                                                                                                                                           0
                                                                                                                                                                                                                                                          2                                           ctgh −1 x =        ln ⎜   ⎟,            x >1
                    ⎛   n
                                              ⎞                                                                                                                                                                                                                                                                         2 ⎝ x −1⎠
( a − b ) ⋅ ⎜ ∑ a n − k b k −1 ⎟ = a n − b n                     ∀n ∈   π radianes=180                                                                                                                                                                     1
                                                                                                                                                                                                                                                cos 2 θ = (1 + cos 2θ )
                    ⎝ k =1                    ⎠                                                                                                                           -1
                                                                                                                                                                                                                            arc sen x
                                                                                                                                                                                                                                                           2                                                         ⎛ 1 ± 1 − x2             ⎞
                                                                                                                                                                                                                                                                                                      sech −1 x = ln ⎜                        ⎟, 0 < x ≤ 1
                                                                                                                                                                                                                            arc cos x
                                                                                                                                                                                                                            arc tg x
                                                                                                                                                                                                                                                         1 − cos 2θ                                                  ⎜                        ⎟
                                                                                                                                                                          -2
                                                                                                                                                                            -3        -2        -1          0       1       2               3   tg 2 θ =                                                             ⎝     x                  ⎠
                                                                                                                                                                                                                                                         1 + cos 2θ
                                                                                                                                                                                                                                                                                                                     ⎛1              x2 + 1 ⎞
                                                                                                                                                                                                                                                                                                      csch −1 x = ln ⎜ +                    ⎟, x ≠ 0
                                                                                                                                                                                                                                                                                                                     ⎜x               x ⎟
                                                                                                                                                                                                                                                                                                                     ⎝                      ⎠
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Formulario Cálculo

  • 1. Fórmulas de Cálculo Diferencial e Integral (Página 1 de 3) http://www.geocities.com/calculusjrm/ Jesús Rubí M. Fórmulas de ( a + b ) ⋅ ( a − ab + b ) = a + b 2 2 3 3 Gráfica 4. Las funciones trigonométricas inversas arcctg x , arcsec x , arccsc x : sin α + sin β = 2sin 1 1 (α + β ) ⋅ cos (α − β ) ( a + b ) ⋅ ( a3 − a 2 b + ab 2 − b3 ) = a 4 − b 4 2 2 Cálculo Diferencial HIP CO 4 1 1 sin α − sin β = 2 sin (α − β ) ⋅ cos (α + β ) ( a + b ) ⋅ ( a 4 − a 3b + a 2 b 2 − ab3 + b 4 ) = a 5 + b5 e Integral ACTUALIZADO AGO-2007 θ 3 2 2 ( a + b ) ⋅ ( a5 − a 4 b + a 3b 2 − a 2 b3 + ab 4 − b5 ) = a 6 − b 6 1 1 CA cos α + cos β = 2 cos (α + β ) ⋅ cos (α − β ) Jesús Rubí Miranda (jesusrubim@yahoo.com) 2 2 2 Móvil. Méx. DF. 044 55 13 78 51 94 1 1 ⎛ ⎞ cos α − cos β = −2 sin (α + β ) ⋅ sin (α − β ) n ( a + b ) ⋅ ⎜ ∑ ( −1) k +1 a n − k b k −1 ⎟ = a n + b n ∀ n ∈ impar θ sin cos tg ctg sec csc 1 2 2 ⎝ k =1 ⎠ 1. VALOR ABSOLUTO 0 0 1 0 ∞ 1 ∞ sin (α ± β ) 0 ⎛ n ⎞ tg α ± tg β = ( a + b ) ⋅ ⎜ ∑ ( −1) k +1 12 ⎧a si a ≥ 0 a n − k b k −1 ⎟ = a n − b n ∀ n ∈ par 30 3 2 1 3 3 2 3 2 a =⎨ ⎝ k =1 ⎠ -1 arc ctg x cos α ⋅ cos β 45 1 2 1 2 2 2 ⎩− a si a < 0 1 1 arc sec x arc csc x 1 ⎡sin (α − β ) + sin (α + β ) ⎤ 5. SUMAS Y PRODUCTOS 60 3 2 12 3 1 3 2 2 3 -2 sin α ⋅ cos β = a = −a 2⎣ ⎦ -5 0 5 ∞ ∞ n + a n = ∑ ak 90 1 0 0 1 a ≤ a y −a ≤ a a1 + a2 + 8. IDENTIDADES TRIGONOMÉTRICAS 1 k =1 ⎡ π π⎤ sin α ⋅ sin β = ⎡cos (α − β ) − cos (α + β ) ⎤ sin θ + cos 2 θ = 1 2⎣ ⎦ 2 a ≥0 y a =0 ⇔ a=0 n y = ∠ sin x y ∈ ⎢− , ⎥ ∑ c = nc ⎣ 2 2⎦ 1 + ctg 2 θ = csc 2 θ cos α ⋅ cos β = 1 ⎡cos (α − β ) + cos (α + β ) ⎤ y = ∠ cos x y ∈ [ 0, π ] n n ∏a = ∏ ak 2⎣ ⎦ k =1 ab = a b ó k n n tg 2 θ + 1 = sec 2 θ k =1 k =1 ∑ ca = c ∑ ak y = ∠ tg x y∈ − π π tg α + tg β sin ( −θ ) = − sin θ k n n k =1 k =1 , tg α ⋅ tg β = a+b ≤ a + b ó ∑a ≤ ∑ ak n n n 2 2 ctg α + ctg β cos ( −θ ) = cos θ k k =1 k =1 ∑(a k + bk ) = ∑ ak + ∑ bk y = ∠ ctg x = ∠ tg 1 y ∈ 0, π 9. FUNCIONES HIPERBÓLICAS tg ( −θ ) = − tg θ k =1 k =1 k =1 2. EXPONENTES x ex − e− x sinh x = n a p ⋅ a q = a p+q ∑(a k =1 k − ak −1 ) = an − a0 y = ∠ sec x = ∠ cos 1 y ∈ [ 0, π ] sin (θ + 2π ) = sin θ 2 ap x = a p−q e x + e− x n n 1 ⎡ π π⎤ cos (θ + 2π ) = cos θ cosh x = aq ∑ ⎡ a + ( k − 1) d ⎤ = 2 ⎡ 2a + ( n − 1) d ⎤ ⎣ ⎦ ⎣ ⎦ y = ∠ csc x = ∠ sen y ∈ ⎢− , ⎥ ⎣ 2 2⎦ tg (θ + 2π ) = tg θ 2 (a ) p q =a pq k =1 x tgh x = sinh x e x − e − x = n (a + l ) Gráfica 1. Las funciones trigonométricas: sin x , sin (θ + π ) = − sin θ cosh x e x + e− x (a ⋅b) = a ⋅b = p p p 2 cos x , tg x : cos (θ + π ) = − cos θ 1 e x + e− x p n 1 − r n a − rl ctgh x = = ⎛a⎞ ap ⎜ ⎟ = p ∑ ar k −1 = a 1 − r = 1 − r 2 tg (θ + π ) = tg θ tgh x e x − e − x ⎝b⎠ b k =1 1 2 sin (θ + nπ ) = ( −1) sin θ sech x = = 1.5 n ∑ k = 2 ( n2 + n ) n a = a 1 cosh x e x + e − x p/q q p 1 cos (θ + nπ ) = ( −1) cos θ n 3. LOGARITMOS k =1 1 2 n ( n + 1)( 2n + 1) 0.5 csch x = = ∑ k 2 = 6 ( 2n3 + 3n2 + n ) = tg (θ + nπ ) = tg θ sinh x e x − e − x n log a N = x ⇒ a x = N 1 0 log a MN = log a M + log a N k =1 6 sinh : → -0.5 sin ( nπ ) = 0 ∑ k = 4 ( n + 2n + n ) → [1, ∞ n M 3 1 4 3 2 cosh : = log a M − log a N cos ( nπ ) = ( −1) -1 n log a k =1 N -1.5 sen x tgh : → −1,1 tg ( nπ ) = 0 cos x ∑ k 4 = 30 ( 6n5 + 15n4 + 10n3 − n ) n log a N = r log a N r 1 − {0} → −∞ , −1 ∪ 1, ∞ tg x -2 -8 -6 -4 -2 0 2 4 6 8 ctgh : k =1 ⎛ 2n + 1 ⎞ π ⎟ = ( −1) log b N ln N → 0 ,1] n log a N = = 1+ 3 + 5 + + ( 2n − 1) = n 2 Gráfica 2. Las funciones trigonométricas csc x , sin ⎜ sech : log b a ln a ⎝ 2 ⎠ sec x , ctg x : csch : − {0} → − {0} ⎛ 2n + 1 ⎞ n log10 N = log N y log e N = ln N n! = ∏ k cos ⎜ π⎟=0 4. ALGUNOS PRODUCTOS k =1 2.5 ⎝ 2 ⎠ Gráfica 5. Las funciones hiperbólicas sinh x , a ⋅ ( c + d ) = ac + ad ⎛n⎞ n! 2 ⎛ 2n + 1 ⎞ cosh x , tgh x : ⎜ ⎟= , k≤n tg ⎜ π⎟=∞ ⎝ k ⎠ ( n − k ) !k ! 1.5 ( a + b ) ⋅ ( a − b ) = a 2 − b2 1 ⎝ 2 ⎠ 5 4 n ⎛n⎞ ⎛ π⎞ ( a + b ) ⋅ ( a + b ) = ( a + b ) = a 2 + 2ab + b 2 ( x + y ) = ∑ ⎜ ⎟ x n −k y k 2 n 0.5 sin θ = cos ⎜ θ − ⎟ 3 k =0 ⎝ k ⎠ ⎝ 2⎠ 0 ( a − b ) ⋅ ( a − b ) = ( a − b ) = a 2 − 2ab + b 2 2 2 -0.5 ⎛ π⎞ 1 ( x1 + x2 + + xk ) = ∑ n! cos θ = sin ⎜ θ + ⎟ ( x + b ) ⋅ ( x + d ) = x 2 + ( b + d ) x + bd x1n1 ⋅ x2 2 n -1 n xknk ⎝ 2⎠ 0 n1 ! n2 ! nk ! -1.5 ( ax + b ) ⋅ ( cx + d ) = acx 2 + ( ad + bc ) x + bd csc x -1 sin (α ± β ) = sin α cos β ± cos α sin β -2 sec x 6. CONSTANTES ctg x -2 ( a + b ) ⋅ ( c + d ) = ac + ad + bc + bd -2.5 π = 3.14159265359… cos (α ± β ) = cos α cos β ∓ sin α sin β -8 -6 -4 -2 0 2 4 6 8 senh x -3 cosh x tgh x ( a + b ) = a3 + 3a 2b + 3ab 2 + b3 e = 2.71828182846… 3 -4 Gráfica 3. Las funciones trigonométricas inversas tg α ± tg β -5 0 5 tg (α ± β ) = 10. FUNCIONES HIPERBÓLICAS INV ( a − b ) = a 3 − 3a 2b + 3ab 2 − b3 3 7. TRIGONOMETRÍA arcsin x , arccos x , arctg x : 1 ∓ tg α tg β ( a + b + c ) = a 2 + b 2 + c 2 + 2ab + 2ac + 2bc 2 sen θ = CO cscθ = 1 4 sin 2θ = 2sin θ cos θ ( sinh −1 x = ln x + x 2 + 1 , ∀x ∈ ) sen θ ( ) HIP cos 2θ = cos θ − sin θ 2 2 cosh −1 x = ln x ± x 2 − 1 , x ≥ 1 ( a − b ) ⋅ ( a 2 + ab + b 2 ) = a 3 − b3 3 CA 1 cosθ = secθ = 2 tg θ HIP cosθ tg 2θ = 1 ⎛1+ x ⎞ ( a − b ) ⋅ ( a 3 + a 2 b + ab 2 + b3 ) = a 4 − b 4 1 − tg 2 θ 2 sen θ CO 1 tgh −1 x = ln ⎜ ⎟, x <1 tgθ = = ctgθ = 2 ⎝1− x ⎠ ( a − b ) ⋅ ( a 4 + a 3b + a 2 b 2 + ab3 + b 4 ) = a 5 − b5 cosθ CA tgθ 1 sin 2 θ = (1 − cos 2θ ) 1 1 ⎛ x +1⎞ 0 2 ctgh −1 x = ln ⎜ ⎟, x >1 ⎛ n ⎞ 2 ⎝ x −1⎠ ( a − b ) ⋅ ⎜ ∑ a n − k b k −1 ⎟ = a n − b n ∀n ∈ π radianes=180 1 cos 2 θ = (1 + cos 2θ ) ⎝ k =1 ⎠ -1 arc sen x 2 ⎛ 1 ± 1 − x2 ⎞ sech −1 x = ln ⎜ ⎟, 0 < x ≤ 1 arc cos x arc tg x 1 − cos 2θ ⎜ ⎟ -2 -3 -2 -1 0 1 2 3 tg 2 θ = ⎝ x ⎠ 1 + cos 2θ ⎛1 x2 + 1 ⎞ csch −1 x = ln ⎜ + ⎟, x ≠ 0 ⎜x x ⎟ ⎝ ⎠