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JumlahdanHasil Kali Akar-AkarPersamaanKuadrat
1. Jika x1dan x2akar-akarpersamaankuadrat 4x2 – 2x – 1 = 0
a. x1 + x2 =
=
=
=
b. x1. x2 =
=
c. (x1 + x2)2 = x12 + 2x1x2 + x22
(x1+ x2)2 = x12 + x22 + 2x1x2
(x1 + x2)2 – 2x1x2 = x12 + x22
Jadi :
x12 + x22 = (x1 + x2)2 – 2x1x2
=

2

–2(

= +
=
d.

+

+
=
=
= .
=
= 2

2. 3x2 + (p − 2)x – 1 = 0
x1 + x2 = 2
− =2
−

=2

−p + 2 = 6

SMK NEGERI 1 TABANAN

1

MATEMATIKA KLS X
−p = 6 – 2
p = −4
jadi : 3x2 + (p – 2)x – 1 = 0
3x2 + (−4 −2)x – 1= 0
3x2 – 6x – 1= 0
x2 – 2x − = 0
x2 – 2x =
x2 – 2x (−1)2 = + (−1)2
(x – 1)2 =
(x – 1)2 = +
(x – 1)2 =
(x – 1) = ±√
x–1=√
x1 = 1 + √
3. x2 – px + 6 = 0

atau

x – 1 = −√

x2 = 1 − √

x1 = 2

x1. x2 =
2 .x2 =
x2= 6
x2 = 3
x1 + x2 =
2+3=
5=
5=p

SMK NEGERI 1 TABANAN

2

MATEMATIKA KLS X
4. p + q =
p.q=
(p – q)2 = p2 – 2pq + q2
= p2 + q2 – 2pq
= (p + q)2 – 2pq – 2pq
= (p + q)2 – 4pq
2

=(
=

−

=

−4

−

=

SMK NEGERI 1 TABANAN

3

MATEMATIKA KLS X

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Menemukan

  • 1. JumlahdanHasil Kali Akar-AkarPersamaanKuadrat 1. Jika x1dan x2akar-akarpersamaankuadrat 4x2 – 2x – 1 = 0 a. x1 + x2 = = = = b. x1. x2 = = c. (x1 + x2)2 = x12 + 2x1x2 + x22 (x1+ x2)2 = x12 + x22 + 2x1x2 (x1 + x2)2 – 2x1x2 = x12 + x22 Jadi : x12 + x22 = (x1 + x2)2 – 2x1x2 = 2 –2( = + = d. + + = = = . = = 2 2. 3x2 + (p − 2)x – 1 = 0 x1 + x2 = 2 − =2 − =2 −p + 2 = 6 SMK NEGERI 1 TABANAN 1 MATEMATIKA KLS X
  • 2. −p = 6 – 2 p = −4 jadi : 3x2 + (p – 2)x – 1 = 0 3x2 + (−4 −2)x – 1= 0 3x2 – 6x – 1= 0 x2 – 2x − = 0 x2 – 2x = x2 – 2x (−1)2 = + (−1)2 (x – 1)2 = (x – 1)2 = + (x – 1)2 = (x – 1) = ±√ x–1=√ x1 = 1 + √ 3. x2 – px + 6 = 0 atau x – 1 = −√ x2 = 1 − √ x1 = 2 x1. x2 = 2 .x2 = x2= 6 x2 = 3 x1 + x2 = 2+3= 5= 5=p SMK NEGERI 1 TABANAN 2 MATEMATIKA KLS X
  • 3. 4. p + q = p.q= (p – q)2 = p2 – 2pq + q2 = p2 + q2 – 2pq = (p + q)2 – 2pq – 2pq = (p + q)2 – 4pq 2 =( = − = −4 − = SMK NEGERI 1 TABANAN 3 MATEMATIKA KLS X