2. Troponin T detection strip by Muller-Bardoff (American Heart Association)
● Paper test strip
○ Troponin T sensor band and control band
● 160 ul of blood flows in from the top
○ At least 0.18 ug/L of troponin T needed in sample for positive reading
[1]Heart Disease Statistics. American College of Cardiology
[2]Heart and Stroke Statistics. American Heart Association
[3]Muller-Bardoff et al
● Heart disease costs $108.9 billion for health care
services, medications, and lost productivity
● Every year, 735,000 people have a heart attack and
610,000 of those people die
3. Comsol Model of the Paper Strip Test
● Diffusion and convection (1e-9[m^2/s])
○ Material used is Serum
■ Density = 0.994 g/ml
■ Viscosity = 1.39mPa.s
● Input concentration is 1mol/m^3
● Inlet of -0.0001 mol/s for test and control
bands
● Stationary
● Mesh: normal
Test
band
Control
band
50 um
100 um
Fig. 1: Simulated comsol model at pressure of 10 Pa
4. Fig. 3: Simulate comsol model at pressure of 0.1 PaFig. 2: Simulate comsol model at pressure of 1 Pa
5. Perfect binding + purely diffusive:
t >> H^2/D = 10s
Flux D: 4.57*10^-25 mol/s
Perfect binding only:
Q about 4.5*10^-14 m^3/s (approximation of Poiseuille’s Law)
or
P about 0.129 Pa
Fig. 4: Linear Depletion Zone (Dr. Grover)
6. Volume Capacity of my 3D model
Total volume Capacity of my model is 3.5x10^6 um^3
160 ul of blood = 1.57 * 10^11 um^3 or 44857 times larger than my total volume
Fig. 5: Dimension of 3D model
50 um
0 um 100 um
50 um
7. Appendix A (Perfect binding + purely diffusive)
Formula weight of Troponin T: 35kDa
Concentration detection wanted: 2-50ng/ml
Amount of Troponin T in 160uL of blood: 0.32 - 8 ng
Concentration of Troponin T input: 9.14*10^-12 to 2.28 *10^-10 mol/m^3
8. Appendix B (Perfect binding only)
Poiseuille’s Law:
Q = pi * Dimension ^4 * delta P / (8 * viscosity * length)
Peclet = Q / (D*Wc):
Q = Peclet * D * Wc, where Wc = 100 um
9. Appendix C (Volume capacity)
160 ul = 160 * 10^-3 ml = 0.16 cm^3 (*)
Assuming this is volume of a cube, cube root of 0.16 is 0.54 cm
(*) = (5400 um)^3 = 1.57 * 10^11 um^3
Total volume of my model = 200*50*50 + 6*100*100*50 = 3.5 x 10^6 um^3
(*) / total volume = 44857.14