There is a well-defined classification s developed originally by Caro.pdf
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There is a well-defined classification s developed originally by Carolus Linneaus in the 1800\'s. you remember what it is? choose an organism that you\'re curious about. Next, fill in the blanks below, and also come mnemonic (no overly explicit ones and give the correct up with your own terms for your example organism choose something different from that in Campbell (see Fig. 1.14) Solution Kingdom Kid insect(animalia) Phylum Plays fish(chordata) Class Card pig(mammalia) Order On dog(carnivora) Family Flat panda(ursidae) Genera Grey black bear(ursus) Species Steps grizzly bear(horribillis.
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Part C AssessmentsAs you examined each specific connective tissue,.pdf
Part C Assessments
As you examined each specific connective tissue, you should have noted some general
characteristics that they possess as described in the laboratory exercise. List any of these you
were able to observe.
describe them from the photos in your manual and textbook. How does the Matrix of these
tissues differ?
Solution
Different kinds of connective tissues:
Connective tissue represents the binding tissue which helps in holding and keeping the
tissues/cells at their right places. The connective tissue can be of atleast three types:
1. Blood/fluid connective tissue
2. Bones/cartilage or the solid connective tissue
3. Organ specific soft connective tissue such as in myocardium, epididymis etc.
The basic features of the connective tissues shared by all types are discussed below:
1. MATRIX: A matrix or medium is always present in the connective tissue. This matrix
represents the ground matter in which all the cell types/tissue types are actually embedded. The
matrix can be solid or liquid in nature depending upon the nature of host tissue.
2. GROUND MATTER: The ground matter is a characteristic of each type of tissue. It is mainly
composed or organic and inorganic matter and helps in providing shape and support to the
organ/tissue. This matrix is resistant to many infections and also provides immune support to the
host tissue/organ.
3. CELLS: Most of the times, the matrix is also accompanied by particular types of immune-
responsive cells which help in preventing infections in the host tissue/organ. Depending upon the
nature of host tissue/organ, the types and number of these cells can vary.
How does the Matrix of these tissues differ?
The matrix is a highly flexible part of the connective tissue. Depending upon the nature of host
tissue, the matrix can be solid or liquid in nature. For example, the matrix of blood is plasma
which is a liquid in nature. However, it also contains all the characteristics of a basic matrix i.e.
possession of different types of cells and helps in preventing infections. Similarly, the matrix of
bones is solid in nature which comprises of not only ground matter (both organic and inorganic),
but also contains different types of cells which help in maintaining structure and function of
bones.
Thus, different types of tissues/organs carry different types of matrices which help in
maintenance of their functionality..
please answer in details12 A communication system consists of 13 a.pdf
please answer in details
12 A communication system consists of 13 antennas arranged in a line. The system functions as
long as no two functioning antennas are next to each other. Suppose five antennas stop
functioning. How many different arrangements of the five nonfunctioning antennas result in the
system being functional?
Solution.
Name the plant phylum that exhibit the follow characteristics Co.pdf
Name the plant phylum that exhibit the follow characteristics Complete the following table
highlighting the major differences between monocots and dicots
Solution
1)1.dominant phase of life cycle: phylum Bryophyta
2.vascular tissue:Phyllum Pteridophytae
3.Reproduction:Phyllum Angiosperms
4.Seeds:Phyllum Gymnosperms here
2) monocots dicots
type of root system fibrous roots taproot system
Distribution of Bundles of vascular tissue Bundles of vascular tissue
arranged in a ring
vascular bundles scattered throughout the stem
with no particular arrangement
vein pattern Leaf veins are parallel Leaf veins are reticulated
number of one two
cotyledons
examples: daffodils mint.
Individuals that express the disease sickle cell anemia are homozygo.pdf
Individuals that express the disease sickle cell anemia are homozygous for a recessive allele for a
hemoglobin gene. The frequency of individuals expressing the disease in a particular population
is 0.0025.
If we assume that the population is at HWE, what is the frequency of the recessive sickle cell
allele?
If the population is at HWE, what is the expected frequency of carriers of the disease
(heterozygotes)?
If mating is random, what is the probability that two carriers will mate?
*University of Washington
Solution
q2 = .0025
q=.0025=0.05
(p+q=1)
(q=1-0.05=0.95)
If we assume that the population is at HWE, what is the frequency of the recessive sickle cell
allele?
The frequency of the recessive sickle cell allele, q=0.05
If the population is at HWE, what is the expected frequency of carriers of the disease
(heterozygotes)?
Expected frequency of carriers of the disease=2pq= 2*0.05*0.95=0.095
If mating is random, what is the probability that two carriers will mate?
The probability that two carriers will mate =0.095*0.095=9.025x10-3 or 9.025x10-3
x100=0.9025%.
I will provide my LinkedList from my last lab.LinkedList.cpp~~~~.pdf
I will provide my LinkedList from my last lab.
LinkedList.cpp
~~~~~~~~~~~~~~
#include \"LinkedList.h\"
LinkedList::LinkedList()
{
first = last = NULL;
}
LinkedList::~LinkedList()
{
while (first != NULL)
{
Node *temp;
temp = first;
first = first->next;
free(temp);
}
last = NULL;
}
void LinkedList::insertAtBack(int valueToInsert)
{
Node *temp = (Node *)malloc(sizeof(Node));
temp->val = valueToInsert;
temp->next = NULL;
if (last == NULL)
first = last = temp;
else
{
last->next = temp;
last = temp;
}
}
bool LinkedList::removeFromBack()
{
if (first == NULL)
return false;
else if (first == last)
{
free(first);
first = last = NULL;
}
else
{
Node *temp;
temp = first;
while (temp->next != last)
temp = temp->next;
last = temp;
temp = temp->next;
free(temp);
last->next = NULL;
}
return true;
}
void LinkedList::print()
{
Node *temp = first;
while (temp != last)
{
cout << temp->val << \" \";
temp = temp->next;
}
if (temp != NULL)
cout << temp->val;
}
bool LinkedList::isEmpty()
{
if (first == last)
return true;
return false;
}
int LinkedList::size()
{
int count = 0;
Node *temp = first;
if (temp == NULL)
return count;
while (temp != last)
{
count++;
temp = temp->next;
}
return count + 1;
}
void LinkedList::clear()
{
while (first != NULL)
{
Node *temp;
temp = first;
first = first->next;
free(temp);
}
last = NULL;
}
/*Exercise2 */
void LinkedList::insertAtFront(int valueToInsert)
{
Node *temp = (Node *)malloc(sizeof(Node));
temp->val = valueToInsert;
if (last == NULL)
first = last = temp;
else
{
temp->next = first;
first = temp;
}
}
bool LinkedList::removeFromFront()
{
if (first == NULL)
return false;
Node *temp = first;
first = first->next;
free(temp);
if (first == NULL)
last = NULL;
return true;
}
LinkedList.h
~~~~~~~~~~~
#include \"LinkedList.h\"
LinkedList::LinkedList()
{
first = last = NULL;
}
LinkedList::~LinkedList()
{
while (first != NULL)
{
Node *temp;
temp = first;
first = first->next;
free(temp);
}
last = NULL;
}
void LinkedList::insertAtBack(int valueToInsert)
{
Node *temp = (Node *)malloc(sizeof(Node));
temp->val = valueToInsert;
temp->next = NULL;
if (last == NULL)
first = last = temp;
else
{
last->next = temp;
last = temp;
}
}
bool LinkedList::removeFromBack()
{
if (first == NULL)
return false;
else if (first == last)
{
free(first);
first = last = NULL;
}
else
{
Node *temp;
temp = first;
while (temp->next != last)
temp = temp->next;
last = temp;
temp = temp->next;
free(temp);
last->next = NULL;
}
return true;
}
void LinkedList::print()
{
Node *temp = first;
while (temp != last)
{
cout << temp->val << \" \";
temp = temp->next;
}
if (temp != NULL)
cout << temp->val;
}
bool LinkedList::isEmpty()
{
if (first == last)
return true;
return false;
}
int LinkedList::size()
{
int count = 0;
Node *temp = first;
if (temp == NULL)
return count;
while (temp != last)
{
count++;
temp = temp->next;
}
return count + 1;
}
void LinkedList::clear()
{
while (first != NULL)
{
Node *temp;
temp = first;
first = first->next;
free(temp);
}
last = NULL;
}
/*Exercise2 */
vo.
Implementing a basic directory-tree structure that is derived from a.pdf
Implementing a basic directory-tree structure that is derived from a base tree structure.
#ifndef SRC_TREENODE_HPP_
#define SRC_TREENODE_HPP_
#include
#include
//#define USE_OSS
#ifndef USE_OSS
#define OUT std::cout
#else
#include
extern std::ostringstream oss;
#define OUT oss
#endif
namespace ensc251 {
static unsigned count = 0;
class TreeNode;
typedef TreeNode* (TreeNode::*action_func)(void);
typedef void (TreeNode::*traverse_func)(const TreeNode*);
class TreeNode
{
typedef std::vector TreeNodePVect;
protected:
TreeNodePVect childPVector;
public:
TreeNode() {};
TreeNode(const TreeNode& nodeToCopy) {
// ***** this needs work *****
if (nodeToCopy.childPVector.size())
add_childP(nodeToCopy.childPVector[0]->clone());
}
virtual TreeNode* clone() const { return new TreeNode(*this); };
virtual ~TreeNode() {
// do not modify this insertion on OUT
OUT << \"Destroying TreeNode with \" << childPVector.size() << \" children.\"<< std::endl;
// ***** Complete this member function *****
}
void swap(TreeNode & other) // the swap member function (should never fail!)
{
// ***** fill this in if desired *****
}
TreeNode & operator = (TreeNode other) // note: argument passed by value, copy made!
{
// ***** Complete this code *****
return *this; // by convention, always return *this
}
void add_childP(TreeNode* child) { /* ***** Complete this member function ***** */ }
void add_children(const TreeNodePVect& childPV) { childPVector.insert(childPVector.end(),
childPV.begin(), childPV.end()); }
const TreeNodePVect& get_children() const { return childPVector; }
TreeNode* traverse_children_post_order(traverse_func tf, action_func af)
{
for(auto childP : childPVector) {
(childP->*tf)(this); // traverse child\'s children using tf
}
return (this->*af)();
}
TreeNode* traverse_children_pre_order(traverse_func tf, action_func af)
{
// ***** Complete this member function *****
}
TreeNode* traverse_children_in_order(traverse_func tf, action_func af)
{
// ***** Complete this member function *****
}
TreeNode* count_action()
{
count++;
return nullptr;
}
void count_traverse(const TreeNode*)
{
traverse_children_post_order(count_traverse, count_action);
}
void reset_count() { count = 0; }
unsigned get_count() const { return count; }
};
}
#endif /* SRC_TREENODE_HPP_ */
#include \"makeDirectoryTree.hpp\"
using namespace std;
int doStuff()
{
// call function to build directory tree in memory
auto root_dir1P = make_directory_tree(\".\", \"test_dir\");
if (root_dir1P) {
root_dir1P->print_traverse(nullptr);
OUT << endl;
root_dir1P->reset_count();
root_dir1P->count_traverse(nullptr);
OUT << \"Count is \" << root_dir1P->get_count() << \"\ \" << endl;
auto root_dir2 = Directory(*root_dir1P); // copy construction
root_dir2.print_traverse(nullptr);
OUT << endl;
auto root_dir3P = make_directory_tree(\"test_dir\", \"Lectures\");
if (root_dir3P) {
root_dir2 = *root_dir3P; // overloaded copy assignment operation
OUT << endl;
delete root_dir3P;
OUT << endl;
}
root_dir2.print_traverse(nullptr);
OUT.
I need help summarizing a research article!! I need to summarize an .pdf
I need help summarizing a research article!! I need to summarize an academic article in 500
words or less and the paper is confusing me. The paper is on Ctneophora and how they are
related to other animals. Can anyone help me Interrupt this article? I linked the article.
file:///C:/Users/malge/Downloads/PNAS-2015-Whelan-5773-8-1%20(1).pdf
Solution
Definition of Ctenophora:
Soft, transparent, dioplblastic, marine metazoans with out nematocysts, but with adhersive
colloblasts and eight meridional ciliated combplates called Ctenophora.
Features of Ctenophora:
Ctenephores from an animal phylum that is more complex than sponges, about as complex as
cnidarians (jellyfish, sea anemones etc.,) and less complex than bilaterians ( which includes
almost all other animals). Unlike sponges, both ctenophores and cnidarians have : cells bound by
inter- cell connection and carpet- like basement membranes; muscles; nervous systems; and
some have sensory organs. Ctenophores are distinguished from all other animals by having
colloblasts, which are sticky and adhere to prey, although a few ctenophore species lack
them.Like sponges and cnidarians, ctenophores have two main layers of cell that sandwich a
middle layer of jelly- like material, which is called the mesoglea in cnidarians are ctenophoress;
more complex animals have three main cell layers and no intermediate jelly- like layer. Hence
ctenophores have traditionally been labelled diaploblastic, along with sponges. Ctenophores have
a type of muscles that , in more complex animals, have three main cell arises from the middle
cell layer, and as a result text books classify ctenophores as triploblastic, while other still regard
them as diploblastic. Ranging from about 1 millimeter (0.039in) to 1.5 meters (4.9) in size,
ctenophores are the largest non- colonial animals that use cilia as their main method of
locomotion. Most species have eight strips, called comb rows, that run the length of their bodies
and bear comb- like bands of cilia, called ctenes, stacked aiong the comb rows so that when the
cilia beat, thosee of each comb touch below. The name ctenophores means comb- bearing from
the Greek meaning comb and the suffix meaning carrying.
Types of Ctenophores
Oceanic ctenophores:
In addition to the relative well- known coastal ctenophores, there are many species found only
far offshore near the surface, or in the mid- water or in the deep sea. Although the ocean seems
rather uniform, each species is representative of only a small portion of the water column,
defined by a combination of water temperature, light availability, depth and other factores- many
oceanic cternophores species are found under similar conditions world wide. Oceanic
ctenophores tend to be much more fragile that coastal species, because they do not need to
tolerate wave action or the turbulence and sediment load of coastal water. Some of them have
fastastic, unlikely shapes. Recognizable species include the lobe- flapping Ocyropsis, which.
For the pedigree on the right, individuals affected with the genetic.pdf
For the pedigree on the right, individuals affected with the genetic condition are indicated by the
shaded symbols. A) Based on this pedigree, what type of inheritance does this genetic condition
have (dominant, recessive, sex-linked)? Explain. B) What is the genotype of the parents? C)
What makes an allele dominant or recessive? O-TI ] 60-Do
Solution
It represents recessive genetic inheritence in which both the parents are carriers and belong to
autosomal recessive groups. If an allele, which is made of gene needs only one gene to show up
is termed as dormant and if it requires two genes to show up is termed as recessive..
Recommended
Part C AssessmentsAs you examined each specific connective tissue,.pdf
Part C Assessments
As you examined each specific connective tissue, you should have noted some general
characteristics that they possess as described in the laboratory exercise. List any of these you
were able to observe.
describe them from the photos in your manual and textbook. How does the Matrix of these
tissues differ?
Solution
Different kinds of connective tissues:
Connective tissue represents the binding tissue which helps in holding and keeping the
tissues/cells at their right places. The connective tissue can be of atleast three types:
1. Blood/fluid connective tissue
2. Bones/cartilage or the solid connective tissue
3. Organ specific soft connective tissue such as in myocardium, epididymis etc.
The basic features of the connective tissues shared by all types are discussed below:
1. MATRIX: A matrix or medium is always present in the connective tissue. This matrix
represents the ground matter in which all the cell types/tissue types are actually embedded. The
matrix can be solid or liquid in nature depending upon the nature of host tissue.
2. GROUND MATTER: The ground matter is a characteristic of each type of tissue. It is mainly
composed or organic and inorganic matter and helps in providing shape and support to the
organ/tissue. This matrix is resistant to many infections and also provides immune support to the
host tissue/organ.
3. CELLS: Most of the times, the matrix is also accompanied by particular types of immune-
responsive cells which help in preventing infections in the host tissue/organ. Depending upon the
nature of host tissue/organ, the types and number of these cells can vary.
How does the Matrix of these tissues differ?
The matrix is a highly flexible part of the connective tissue. Depending upon the nature of host
tissue, the matrix can be solid or liquid in nature. For example, the matrix of blood is plasma
which is a liquid in nature. However, it also contains all the characteristics of a basic matrix i.e.
possession of different types of cells and helps in preventing infections. Similarly, the matrix of
bones is solid in nature which comprises of not only ground matter (both organic and inorganic),
but also contains different types of cells which help in maintaining structure and function of
bones.
Thus, different types of tissues/organs carry different types of matrices which help in
maintenance of their functionality..
please answer in details12 A communication system consists of 13 a.pdf
please answer in details
12 A communication system consists of 13 antennas arranged in a line. The system functions as
long as no two functioning antennas are next to each other. Suppose five antennas stop
functioning. How many different arrangements of the five nonfunctioning antennas result in the
system being functional?
Solution.
Name the plant phylum that exhibit the follow characteristics Co.pdf
Name the plant phylum that exhibit the follow characteristics Complete the following table
highlighting the major differences between monocots and dicots
Solution
1)1.dominant phase of life cycle: phylum Bryophyta
2.vascular tissue:Phyllum Pteridophytae
3.Reproduction:Phyllum Angiosperms
4.Seeds:Phyllum Gymnosperms here
2) monocots dicots
type of root system fibrous roots taproot system
Distribution of Bundles of vascular tissue Bundles of vascular tissue
arranged in a ring
vascular bundles scattered throughout the stem
with no particular arrangement
vein pattern Leaf veins are parallel Leaf veins are reticulated
number of one two
cotyledons
examples: daffodils mint.
Individuals that express the disease sickle cell anemia are homozygo.pdf
Individuals that express the disease sickle cell anemia are homozygous for a recessive allele for a
hemoglobin gene. The frequency of individuals expressing the disease in a particular population
is 0.0025.
If we assume that the population is at HWE, what is the frequency of the recessive sickle cell
allele?
If the population is at HWE, what is the expected frequency of carriers of the disease
(heterozygotes)?
If mating is random, what is the probability that two carriers will mate?
*University of Washington
Solution
q2 = .0025
q=.0025=0.05
(p+q=1)
(q=1-0.05=0.95)
If we assume that the population is at HWE, what is the frequency of the recessive sickle cell
allele?
The frequency of the recessive sickle cell allele, q=0.05
If the population is at HWE, what is the expected frequency of carriers of the disease
(heterozygotes)?
Expected frequency of carriers of the disease=2pq= 2*0.05*0.95=0.095
If mating is random, what is the probability that two carriers will mate?
The probability that two carriers will mate =0.095*0.095=9.025x10-3 or 9.025x10-3
x100=0.9025%.
I will provide my LinkedList from my last lab.LinkedList.cpp~~~~.pdf
I will provide my LinkedList from my last lab.
LinkedList.cpp
~~~~~~~~~~~~~~
#include \"LinkedList.h\"
LinkedList::LinkedList()
{
first = last = NULL;
}
LinkedList::~LinkedList()
{
while (first != NULL)
{
Node *temp;
temp = first;
first = first->next;
free(temp);
}
last = NULL;
}
void LinkedList::insertAtBack(int valueToInsert)
{
Node *temp = (Node *)malloc(sizeof(Node));
temp->val = valueToInsert;
temp->next = NULL;
if (last == NULL)
first = last = temp;
else
{
last->next = temp;
last = temp;
}
}
bool LinkedList::removeFromBack()
{
if (first == NULL)
return false;
else if (first == last)
{
free(first);
first = last = NULL;
}
else
{
Node *temp;
temp = first;
while (temp->next != last)
temp = temp->next;
last = temp;
temp = temp->next;
free(temp);
last->next = NULL;
}
return true;
}
void LinkedList::print()
{
Node *temp = first;
while (temp != last)
{
cout << temp->val << \" \";
temp = temp->next;
}
if (temp != NULL)
cout << temp->val;
}
bool LinkedList::isEmpty()
{
if (first == last)
return true;
return false;
}
int LinkedList::size()
{
int count = 0;
Node *temp = first;
if (temp == NULL)
return count;
while (temp != last)
{
count++;
temp = temp->next;
}
return count + 1;
}
void LinkedList::clear()
{
while (first != NULL)
{
Node *temp;
temp = first;
first = first->next;
free(temp);
}
last = NULL;
}
/*Exercise2 */
void LinkedList::insertAtFront(int valueToInsert)
{
Node *temp = (Node *)malloc(sizeof(Node));
temp->val = valueToInsert;
if (last == NULL)
first = last = temp;
else
{
temp->next = first;
first = temp;
}
}
bool LinkedList::removeFromFront()
{
if (first == NULL)
return false;
Node *temp = first;
first = first->next;
free(temp);
if (first == NULL)
last = NULL;
return true;
}
LinkedList.h
~~~~~~~~~~~
#include \"LinkedList.h\"
LinkedList::LinkedList()
{
first = last = NULL;
}
LinkedList::~LinkedList()
{
while (first != NULL)
{
Node *temp;
temp = first;
first = first->next;
free(temp);
}
last = NULL;
}
void LinkedList::insertAtBack(int valueToInsert)
{
Node *temp = (Node *)malloc(sizeof(Node));
temp->val = valueToInsert;
temp->next = NULL;
if (last == NULL)
first = last = temp;
else
{
last->next = temp;
last = temp;
}
}
bool LinkedList::removeFromBack()
{
if (first == NULL)
return false;
else if (first == last)
{
free(first);
first = last = NULL;
}
else
{
Node *temp;
temp = first;
while (temp->next != last)
temp = temp->next;
last = temp;
temp = temp->next;
free(temp);
last->next = NULL;
}
return true;
}
void LinkedList::print()
{
Node *temp = first;
while (temp != last)
{
cout << temp->val << \" \";
temp = temp->next;
}
if (temp != NULL)
cout << temp->val;
}
bool LinkedList::isEmpty()
{
if (first == last)
return true;
return false;
}
int LinkedList::size()
{
int count = 0;
Node *temp = first;
if (temp == NULL)
return count;
while (temp != last)
{
count++;
temp = temp->next;
}
return count + 1;
}
void LinkedList::clear()
{
while (first != NULL)
{
Node *temp;
temp = first;
first = first->next;
free(temp);
}
last = NULL;
}
/*Exercise2 */
vo.
Implementing a basic directory-tree structure that is derived from a.pdf
Implementing a basic directory-tree structure that is derived from a base tree structure.
#ifndef SRC_TREENODE_HPP_
#define SRC_TREENODE_HPP_
#include
#include
//#define USE_OSS
#ifndef USE_OSS
#define OUT std::cout
#else
#include
extern std::ostringstream oss;
#define OUT oss
#endif
namespace ensc251 {
static unsigned count = 0;
class TreeNode;
typedef TreeNode* (TreeNode::*action_func)(void);
typedef void (TreeNode::*traverse_func)(const TreeNode*);
class TreeNode
{
typedef std::vector TreeNodePVect;
protected:
TreeNodePVect childPVector;
public:
TreeNode() {};
TreeNode(const TreeNode& nodeToCopy) {
// ***** this needs work *****
if (nodeToCopy.childPVector.size())
add_childP(nodeToCopy.childPVector[0]->clone());
}
virtual TreeNode* clone() const { return new TreeNode(*this); };
virtual ~TreeNode() {
// do not modify this insertion on OUT
OUT << \"Destroying TreeNode with \" << childPVector.size() << \" children.\"<< std::endl;
// ***** Complete this member function *****
}
void swap(TreeNode & other) // the swap member function (should never fail!)
{
// ***** fill this in if desired *****
}
TreeNode & operator = (TreeNode other) // note: argument passed by value, copy made!
{
// ***** Complete this code *****
return *this; // by convention, always return *this
}
void add_childP(TreeNode* child) { /* ***** Complete this member function ***** */ }
void add_children(const TreeNodePVect& childPV) { childPVector.insert(childPVector.end(),
childPV.begin(), childPV.end()); }
const TreeNodePVect& get_children() const { return childPVector; }
TreeNode* traverse_children_post_order(traverse_func tf, action_func af)
{
for(auto childP : childPVector) {
(childP->*tf)(this); // traverse child\'s children using tf
}
return (this->*af)();
}
TreeNode* traverse_children_pre_order(traverse_func tf, action_func af)
{
// ***** Complete this member function *****
}
TreeNode* traverse_children_in_order(traverse_func tf, action_func af)
{
// ***** Complete this member function *****
}
TreeNode* count_action()
{
count++;
return nullptr;
}
void count_traverse(const TreeNode*)
{
traverse_children_post_order(count_traverse, count_action);
}
void reset_count() { count = 0; }
unsigned get_count() const { return count; }
};
}
#endif /* SRC_TREENODE_HPP_ */
#include \"makeDirectoryTree.hpp\"
using namespace std;
int doStuff()
{
// call function to build directory tree in memory
auto root_dir1P = make_directory_tree(\".\", \"test_dir\");
if (root_dir1P) {
root_dir1P->print_traverse(nullptr);
OUT << endl;
root_dir1P->reset_count();
root_dir1P->count_traverse(nullptr);
OUT << \"Count is \" << root_dir1P->get_count() << \"\ \" << endl;
auto root_dir2 = Directory(*root_dir1P); // copy construction
root_dir2.print_traverse(nullptr);
OUT << endl;
auto root_dir3P = make_directory_tree(\"test_dir\", \"Lectures\");
if (root_dir3P) {
root_dir2 = *root_dir3P; // overloaded copy assignment operation
OUT << endl;
delete root_dir3P;
OUT << endl;
}
root_dir2.print_traverse(nullptr);
OUT.
I need help summarizing a research article!! I need to summarize an .pdf
I need help summarizing a research article!! I need to summarize an academic article in 500
words or less and the paper is confusing me. The paper is on Ctneophora and how they are
related to other animals. Can anyone help me Interrupt this article? I linked the article.
file:///C:/Users/malge/Downloads/PNAS-2015-Whelan-5773-8-1%20(1).pdf
Solution
Definition of Ctenophora:
Soft, transparent, dioplblastic, marine metazoans with out nematocysts, but with adhersive
colloblasts and eight meridional ciliated combplates called Ctenophora.
Features of Ctenophora:
Ctenephores from an animal phylum that is more complex than sponges, about as complex as
cnidarians (jellyfish, sea anemones etc.,) and less complex than bilaterians ( which includes
almost all other animals). Unlike sponges, both ctenophores and cnidarians have : cells bound by
inter- cell connection and carpet- like basement membranes; muscles; nervous systems; and
some have sensory organs. Ctenophores are distinguished from all other animals by having
colloblasts, which are sticky and adhere to prey, although a few ctenophore species lack
them.Like sponges and cnidarians, ctenophores have two main layers of cell that sandwich a
middle layer of jelly- like material, which is called the mesoglea in cnidarians are ctenophoress;
more complex animals have three main cell layers and no intermediate jelly- like layer. Hence
ctenophores have traditionally been labelled diaploblastic, along with sponges. Ctenophores have
a type of muscles that , in more complex animals, have three main cell arises from the middle
cell layer, and as a result text books classify ctenophores as triploblastic, while other still regard
them as diploblastic. Ranging from about 1 millimeter (0.039in) to 1.5 meters (4.9) in size,
ctenophores are the largest non- colonial animals that use cilia as their main method of
locomotion. Most species have eight strips, called comb rows, that run the length of their bodies
and bear comb- like bands of cilia, called ctenes, stacked aiong the comb rows so that when the
cilia beat, thosee of each comb touch below. The name ctenophores means comb- bearing from
the Greek meaning comb and the suffix meaning carrying.
Types of Ctenophores
Oceanic ctenophores:
In addition to the relative well- known coastal ctenophores, there are many species found only
far offshore near the surface, or in the mid- water or in the deep sea. Although the ocean seems
rather uniform, each species is representative of only a small portion of the water column,
defined by a combination of water temperature, light availability, depth and other factores- many
oceanic cternophores species are found under similar conditions world wide. Oceanic
ctenophores tend to be much more fragile that coastal species, because they do not need to
tolerate wave action or the turbulence and sediment load of coastal water. Some of them have
fastastic, unlikely shapes. Recognizable species include the lobe- flapping Ocyropsis, which.
For the pedigree on the right, individuals affected with the genetic.pdf
For the pedigree on the right, individuals affected with the genetic condition are indicated by the
shaded symbols. A) Based on this pedigree, what type of inheritance does this genetic condition
have (dominant, recessive, sex-linked)? Explain. B) What is the genotype of the parents? C)
What makes an allele dominant or recessive? O-TI ] 60-Do
Solution
It represents recessive genetic inheritence in which both the parents are carriers and belong to
autosomal recessive groups. If an allele, which is made of gene needs only one gene to show up
is termed as dormant and if it requires two genes to show up is termed as recessive..
How are the xylem and phloem arranged in a eudicot rootA. the xyl.pdf
How are the xylem and phloem arranged in a eudicot root?
A. the xylem is at the center of the root, surrounded by several phloems
B. eudicots do not have xylem and phloem in the roots
C. the xylem is at the periphery of the root, whereas the phloem is in the center of the root
D. xylem and phloem are arranged in rings in the periphery of the root
Solution
Answer:
A. the xylem is at the center of the root, surrounded by several phloems
Explanation:
Monocot roots, interestingly, have their vascular bundles arranged in a ring. Dicot roots have
their xylem in the center of the root and phloem outside the xylem. A carrot is an example of a
dicot root..
Graph 1 Annual growth () of national output 25 20 15 15 10 0 So.pdf
Graph 1: Annual growth (%) of national output 25 20 15 15 10 0
Solution
Growth can be observed with the increased per-capita income. That can be improved by
encouraging investments, and production. This improves the production capacity, earnining
capability and finally improves the economy as a whole..
Explain why Drosophila are often used as model organisms in the study.pdf
Explain why Drosophila are often used as model organisms in the study of genetics:
Solution
Drosophila melanogaster or fruit flies have about 75 of the genes that causes disease in humans
so scientists are able to know about the human genetics clearly by studying the fruit fly genetics.
Fruit flies are less expensive when compared with rat and other organisms, they are small and it
is very easy to take care of it and easy to carry out the research.
Fruit fly has many characteristics to study about animal behaviour and
development,neurobiology, human genetic diseases and their conditions.
Drosophila has become an predominant model and it gives information about how the genes
direct the development of embryo from a single cell to mature multicellular cells.
Drosophila has many set of molecular tools and mutants that dissect the genetic pathway that are
important for the normal and abnormal conditions of cardiac functions. It became popular to
investigate the genes that causes cardiovascular disease.
It is easy to evolve many generations of fruit fly because of its short lifespan due to this many
experiments can be easily carried out.
By the above conditions,we can consider that the Drosophila melanogaster is often used as a
model organism in the study of genetics..
Examine the two animals in the photographs figure. Use all of the c.pdf
Examine the two animals in the photographs figure. Use all of the clues in this figure. These
two organisms belong to _____. The same genus the same species different orders different
phyla different families
Solution
These two organisms belong to same genus which is Ammospermophilus, but are different
species of the same genus..
Assess the types of stakeholders involved in the development process.pdf
Assess the types of stakeholders involved in the development process for the product/service
Evaluate the impact of key inputs from stakeholder groups on new product/service development
efforts.
Analyze the role these key stakeholder groups can play in contributing to the success of a new
product/service
Justify at least two persuasive strategies that can be used to engage stakeholders in new
product/service development projects.
Assess the key competitive advantages that utilizing the current trends in information technology
(IT) will deliver to the area of new product/service development.
Solution
Stakeholders include Shareholders ,Banks,financial institutions and Private Equity in the
Development Process for a tire company like Michelin tires
Each of Michelin businesses is encouraged to identify and engage with key stakeholders at a
national and operational level. Michelin Stakeholder Relations Guidance provides information to
help these businesses identify and engage with their stakeholders.
A stakeholder is an individual who is affected by or who can affect a project\'s outcome.
Stakeholders shape projects in the early stages, ensuring resources are available to contribute to
project success, and provide insight regarding the probable reaction to a project\'s outcome,
which facilitates project adjustments when necessary to win organizational support. The roles of
stakeholders change throughout a project life cycle. However, the willingness of stakeholders to
perform the activities assigned to them during the project planning process greatly contributes to
the success or failure of the project.
Group stakeholder engagement on sustainability is managed by the Performance and
Responsibility team at Michelin Group. Site-level stakeholder engagement is the responsibility
of site managers. Together, these provide critical input to help guide Michelin strategy and PRM
activities..
Write the level of protein structure below each picture. A word bank .pdf
Write the level of protein structure below each picture. A word bank is not provided here as you
should know these vocabulary words.
Solution
21.Quaternary structure
22.Secondary structure has 2 types- alpha helix and beta sheet
23.Tertiary structure (3-Dimensional arrangement of protein)
24.Amino acids joined by peptide bond forming the primary structure of protein.
Why should assembly language be avoided for general application deve.pdf
Why should assembly language be avoided for general application development? Under what
circumstances is assembly language preferred or required?
Solution
Reasons for avoiding Assembly Language for General Application Development:
(i) It is difficult to understand the code (as Assembly Language is a low-level language).
Debugging and modification of code requires extensive work.
(ii) Application Development time will be higher than higher level languages because even the
basic operations like additions, subtractions etc needs to be implemented as part of the code.
(iii) In case of higher level languages, we can use the existing libraries to complete the
development work faster. This is not possible with the Assembly Language.
(iv) Assembly Languages are hardware specific and not portable to all machines. This is not the
case with the higher level languages.
Circumstances under which Assembly Language is preferred:
(i) Assembly Language is preferred when we have a limited availability of memory and
computational space. To maximum utilize the available memory and computational space,
Assembly Language is preferred over Higher Level languages in such cases.
Ex: chipsets
(ii) Assembly Language is also used when we need to do some hardware manipulation. This is
not possible with higher level languages.
(iii) When we need to design something specific to a computer architecture where support for
higher languages is not available yet..
Who was Jesus of Nazareth What was his message How did he convey t.pdf
Who was Jesus of Nazareth? What was his message? How did he convey that message? What
role did parables and miracles play in his ministry? What event convinced his followers that he
was more than an ordinary man?
Solution
Jesus Christ, best known as Jesus of Nazareth or simply Jesus, is Christianity\'s central figure,
both as Messiah and, on most Christians, as God incarnate. Muslims regard him as a general
major prophet several regard him because Messiah. Many Hindus also recognize him as a
general manifestation belonging to the divine, and some Buddhists identify him as a Bodhisattva.
Jesus was born sometime right before 4 B.C. He was raised in Nazareth, a tiny village in Galilee,
within the peasant class. Jesus\'father has been a carpenter and the man became one, too,
meaning that they had likely lost their agricultural land at some point. Jesus was raised Jewish
and the man remained deeply Jewish nearly every one of his life. His intention wasn\'t to create a
new religion. Rather, he saw himself as doing something within Judaism.
His followers experienced him after his death. It is see-through that they had visions of Jesus as
that you had known him during his historical life. Only after his death did they declare Jesus to
be \"Lord\" or \"the Son of God.\" Right away of Jesus\'life through His death and beyond, the
Herodian dynasty ruled Palestine and nearby area, the lands belonging to the eastern
Mediterranean coast. These rulers were clients of Imperial Rome, who served with all the
appointment and permission of Rome. The firstly this family turn out to be appointed as ruler in
Israel was Herod the Great. Upon his death, his kingdom was divided between three of his sons:
Herod Archelaus, Herod Antipas, and Philip the Tetrarch. The Parables of Jesus can be found in
all the canonical gospels, whereas in the a few of the non-canonical gospels, but are found
mainly while in the three synoptic gospels.They represent a vital element of the teachings of
Jesus, forming approximately 33 % of his recorded teachings. Christians place high focus on
these parables; because they are the purported words of Jesus, they can indeed be believed to be
what the Father has taught, indicated by John 8:28 and 14:10. Jesus parables are seemingly
simple and easy and memorable stories, often with imagery, and all sorts of convey messages.
Scholars have commented that although these parables seem simple, the messages they convey
are deep, and central in the teachings of Jesus. Christian authors view them not as mere
similitudes which serve the purpose of illustration, but as internal analogies in which nature
becomes a witness for the spiritual world.
why has America never been a homogenous societywhy has Amer.pdf
why has America never been a homogenous society?
why has America never been a homogenous society?
why has America never been a homogenous society?
Solution
A homogeneous society refers to that society where people share same type of values, culture,
languages and religious system.
America is a developed nations and the standard living is rich. There are different standard living
style, different culture and opinions. The citizens in US are from different nations and have
different opinions. Therefore America could not be consider a homogenous society..
Which of these statements about Java are trueA.( T F ) Using va.pdf
Which of these statements about Java are true?
A.( T / F ) Using variables for real contents is an implementation of Inheritance.
B.( T / F ) An object usually interacts with other objects through method(s).
C.( T / F ) One class can create only one object.
D.( T / F ) According to the naming convention, the names of classes and objects begin with a
upper case.
E.( T / F ) Every header (signature) for paragraphs (classes, constructors, and methods) must
have a pair of parenthesis for parameters.
F.( T / F ) Knowing and using a method by just the signature of the method, without
understanding how the method does, is an implementation of Encapsulation.
G. ( T / F ) One superclass(parent class) can have more than one of its subclasses(children
classes).
H.( T / F ) Objects have their own information and features, called parameters and methods.
I.( T / F ) Every paragraph must have both { } and its signature.
J. ( T / F ) Every declaration statement must provide at least the type and name information about
the variable.
Solution
A.
False
Inheritance is the inheriting something from parent class
B.
True
C.
False
You can create any number of objects of a class
D.
False
Class Name: begin with upper case
Object name: camel case
E.
True
F.
True
G,
False
It is not allowed in java to inherit more than one class
In java we can implement multiple interfaces
H.
True
Object have their states(instance variables) and methods(behaviours)
I.
True
J.
true.
When someone suffers from arteriosclerosis, there is a widening of th.pdf
When someone suffers from arteriosclerosis, there is a widening of the vessel\'s lumen that
ensues. True False The tunica that usually distinguishes the oxygenated vessels from one
another is: media externa depends on the location of the vessel interna Choose among the
following choices the relationship that is erroneous: continuous capillary-skin-tight junction
fenestrated capillary muscle -incomplete basement membrane sinusoidal capillary liver
discontinued basal lamina fenestrated capillary-kidney-pore with diaphragm
Solution.
What is the relationship of Computer System Validation to the Softwa.pdf
What is the relationship of Computer System Validation to the Software Development Life
Cycle.
Solution
The computer system validtation process steps are:
(i) Standard operating procedures
(ii) Training procedures and training records.
Software developement cycle ralationship involves:
Planning, Requirement Analysis, design, developement, integration test and validation,
installatoin, qualification and implementation, then next operations and maintainance..
What is the developmental mechanism that Piaget proposed to account .pdf
What is the developmental mechanism that Piaget proposed to account for movement to higher
stages of cognitive development? In other words, why do children begin to construct a different
type of cognitive structure at different stages?
Solution
The following are the assumptions of piaget’s about the children.
The first important assumption is that the children usually construct their own knowledge
.This knowledge is usually In response to their experiences in life.Another important fact
is that the children have the power to learn various things on their own without the
intervention of older children or adults..It has the following stages
Piaget’s Stages:
1)The first one is Sensorimotor stage (birth to 2 years) in which the child grows.
2)The second one the Preoperational stage(2 to 7 years).In this stage the knowledge
which is gained by the child is represented by language, mental imagery,and symbolic
thought.
3)The third one is the Concrete operational stage(7 to 12 years).In this stage the
Children are able to reason logically about concrete objects and events.
4)Finally we have the Formal operational stage(12 years and up)-In this stage the
Children have the ability to think deeply about concrete events .They can also reason
abstractly and hypothetically at the same time..
What is meant by a privileged instruction How does it apply to .pdf
What is meant by a \" privileged\" instruction? How does it apply to operating systems?
Solution
1)it is type of instruction which contains protection settings,interrupt handlers,i/o, process status
instruction
and this instruction is executed only when system is in supervised mode or priviliged mode
which is in operating
system
2)in os there are two modes user mode and previliged mode all preveliged instruction run in this
mode
1)these instruction are used in memory address mapping and flush the cache data
2)it also read and load system registers
3)changing the modes in operating system
4)it also perform some i/o operations.
What are the major capabilities of database management systems (DBMS.pdf
What are the major capabilities of database management systems (DBMS) and why is a
relational DBMS so powerful? Explanin in 100-150 words.
Solution
A database management system (DBMS) refers to a system software for creating and organizing
databases.
Capabilities of database management system (DBMS) is explained as below-
Data Structuring
All information in a digital store is organized into a clear hierarchical structure with records,
tables or objects. Every piece of information by help of database can be organized in a kind of
catalogue, so that it could be easier to search and update records later on.
Query Languages
A typical DBMS makes it possible to utilize query languages for collecting, searching, sorting,
and modifying.
Multi-user Access
DBMS provides many users access to all types of information stored in one and the same data
store.
The relational database is the key method for organizing and maintaining data in information
systems as it is so flexible and easy to get to. It organizes data in two-dimensional tables called.
Each row expresses a record, and each column represents an attribute or field. Each table also
contains a key field to identify each record for manipulation. Relational database tables can be
add easily to send data required by users.
Hence, relational database is powerful..
what ia managerial accountingSolutionAnswer - The branch o.pdf
what ia managerial accounting?
Solution
Answer :- The branch of accounting which helps the management to perform its functions like
\"Planning, Organization, Coordination, Control, Communication and decision-making\", is
called managerial accounting. Mangerial accounting provides required information to the
management to take effective decisions and control over the business. Managerial accounting is
the presentation of accounting information in such a way as to assist the management in the
creation of policy and in the day to day operation of an undertaking..
What is Impersonation, why do you use it and how does SQL perform im.pdf
What is Impersonation, why do you use it and how does SQL perform implicit Impersonation?
Solution
Impersonation is an arrangement in which an SQL Server is configured to allow an instance of
one SQL server to connect to another instance of SQL server under the context of an autenticated
Windows User.
Impersonation can be done explicitly or implicitly on a SQL server.
The EXECUTE AS statement is used to do explicity Impersonation, It can be used to
impersonate server-level,database-level principals on logins, users.
implicit Impersonation is on modules(server-level,database-level)
database-level -> stored procedure , function
server-level -> server-level trigger.
The EXECUTE AS CALLER will change the context to the caller\'s context, this change does
not revert to the implicitly impersonated context,
REVERT should be called to get back to previous context.
EXECUTE AS CALLER does not require any permission check.
Based on the triggers the implicit impersonation is called directly..
The answers to these questions are covered both in the lecture materi.pdf
The answers to these questions are covered both in the lecture material and the text book What
reaction, oxidation or reduction, is key to uranium bioremediation? How does the role of energy
production lead to the action of bioremediation by microorganisms? What are xenobiotics and
what are some examples? What is the role of microbes in the bioremediation of xenobiotics?
Explain how the bioremediation of the herbicide 2, 4, 5-1 shown below, produces energy lord
microbes.
Solution
1. Bioremediation is a process which involves the use of microorganisms to remove or
neutralize from contaminants, such as polluted soil or water. In the absence of oxygen, bacteria
are able to respire various electron acceptors for the energy required for its metabolism. At the
environmentally neutral pH, the aquaous U has a similar redox couple to Fe(III), therefore
Fe(III)-reducing bacteria are able to respire aquaous U as an alternative electron acceptor,
reducig it to insoluble U. Reduction of Uranium is the key reaction for the bioremediation of
uranium, For the bioremediation of Uranium the process is stimulated by adding electron donor
such as acetate, lactate or ethanol from which electrons can be taken up by bacteria to gain the
energy to promote the enzymatic (microbial) reduction of aquaous U to insoluble U in anaerobic
condition. The end product of this process would be uraninite. 3. Xenobiotics are the synthetic
compounds found in living organisms, which are not produced by and foreign to that organisms.
They are also synthetic substances (doesn\'t produced naturally) which are found in higher
concentration than its normal level in the entire biological system. Examples of xenobiotics are:
Halocarbons: consist of halogen group in their structure and used in solvents, pesticides,
propellents etc. Due to their volatile nature, they often escape and destruct the ozone layer.
Synthetic polymers: mainly used to form polyester, polyvinyl chloride etc Carcinogen, food
additives, drugs are also examples of the xenobiotics. Normally the degradation of xenobiotics
by microorganisms is very rare, as the availability of the xenobiotics to the microorganisms is
very low as compared to its concentration in environment. However, when certain microbes are
exposed to these xenobiotics continuously, they develop the ability to degrade the compounds.
Mutations in microbes occur in such a way so that its active site can shows increased affinity
towards the xenobiotics and some mutates to form new enzymatic pathway for degradation of
xenobiotics. Use of mixed population is very effective for bioremediation of xenobiotics. It
creates the cometabolism process n their combined effect is higher than the individual alone.
Genetic engineering can also be used to modify microbes for degrading xenobiotics. 4. The
microbes while degrading herbicide 2,4,5-T, it produces an end product named succinate +
acetate. Succinate is the intermediate of the TCA (TriCarboxylicAcid) cycle, so it.
Are these correct I am confused with the book pictures and the actu.pdf
Are these correct? I am confused with the book pictures and the actual pictures Post-Lab
Questions eScience Labs, LLC 2013
Solution
A . INTERPHASE.
B.PROPHASE.
C.PROPHASE.
D.INTERPHASE.
E. EARLY ANAPHASE (you can see the pulling of chromosomes towards oppsite side).
F.METAPHASE (Chromosomes are aligned on the equatorial plate).
Students arrive at a library reference desk at an average rate of 15.pdf
Students arrive at a library reference desk at an average rate of 15 per hour. Assume Poisson
arrivals. What is the probability that NO MORE THAN 2 students arrive in 30 minutes?
Solution
mean for one hour = 15/hour
mean for 30 min = 15/2 = 7.5 student/30 min
lamda = 7.5
P(x=r) = e^(-lamda) * lamda^r / r!
P(x<2) = P(x=0) + P(x=1)
P(x<2) = e^(-7.5) * 7.5^0 / 0! + e^(-7.5) * 7.5^1 / 1!
P(x<2) = 0.004701.
Normal Labour/ Stages of Labour/ Mechanism of Labour
Normal labor is also termed spontaneous labor, defined as the natural physiological process through which the fetus, placenta, and membranes are expelled from the uterus through the birth canal at term (37 to 42 weeks
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How are the xylem and phloem arranged in a eudicot rootA. the xyl.pdf
How are the xylem and phloem arranged in a eudicot root?
A. the xylem is at the center of the root, surrounded by several phloems
B. eudicots do not have xylem and phloem in the roots
C. the xylem is at the periphery of the root, whereas the phloem is in the center of the root
D. xylem and phloem are arranged in rings in the periphery of the root
Solution
Answer:
A. the xylem is at the center of the root, surrounded by several phloems
Explanation:
Monocot roots, interestingly, have their vascular bundles arranged in a ring. Dicot roots have
their xylem in the center of the root and phloem outside the xylem. A carrot is an example of a
dicot root..
Graph 1 Annual growth () of national output 25 20 15 15 10 0 So.pdf
Graph 1: Annual growth (%) of national output 25 20 15 15 10 0
Solution
Growth can be observed with the increased per-capita income. That can be improved by
encouraging investments, and production. This improves the production capacity, earnining
capability and finally improves the economy as a whole..
Explain why Drosophila are often used as model organisms in the study.pdf
Explain why Drosophila are often used as model organisms in the study of genetics:
Solution
Drosophila melanogaster or fruit flies have about 75 of the genes that causes disease in humans
so scientists are able to know about the human genetics clearly by studying the fruit fly genetics.
Fruit flies are less expensive when compared with rat and other organisms, they are small and it
is very easy to take care of it and easy to carry out the research.
Fruit fly has many characteristics to study about animal behaviour and
development,neurobiology, human genetic diseases and their conditions.
Drosophila has become an predominant model and it gives information about how the genes
direct the development of embryo from a single cell to mature multicellular cells.
Drosophila has many set of molecular tools and mutants that dissect the genetic pathway that are
important for the normal and abnormal conditions of cardiac functions. It became popular to
investigate the genes that causes cardiovascular disease.
It is easy to evolve many generations of fruit fly because of its short lifespan due to this many
experiments can be easily carried out.
By the above conditions,we can consider that the Drosophila melanogaster is often used as a
model organism in the study of genetics..
Examine the two animals in the photographs figure. Use all of the c.pdf
Examine the two animals in the photographs figure. Use all of the clues in this figure. These
two organisms belong to _____. The same genus the same species different orders different
phyla different families
Solution
These two organisms belong to same genus which is Ammospermophilus, but are different
species of the same genus..
Assess the types of stakeholders involved in the development process.pdf
Assess the types of stakeholders involved in the development process for the product/service
Evaluate the impact of key inputs from stakeholder groups on new product/service development
efforts.
Analyze the role these key stakeholder groups can play in contributing to the success of a new
product/service
Justify at least two persuasive strategies that can be used to engage stakeholders in new
product/service development projects.
Assess the key competitive advantages that utilizing the current trends in information technology
(IT) will deliver to the area of new product/service development.
Solution
Stakeholders include Shareholders ,Banks,financial institutions and Private Equity in the
Development Process for a tire company like Michelin tires
Each of Michelin businesses is encouraged to identify and engage with key stakeholders at a
national and operational level. Michelin Stakeholder Relations Guidance provides information to
help these businesses identify and engage with their stakeholders.
A stakeholder is an individual who is affected by or who can affect a project\'s outcome.
Stakeholders shape projects in the early stages, ensuring resources are available to contribute to
project success, and provide insight regarding the probable reaction to a project\'s outcome,
which facilitates project adjustments when necessary to win organizational support. The roles of
stakeholders change throughout a project life cycle. However, the willingness of stakeholders to
perform the activities assigned to them during the project planning process greatly contributes to
the success or failure of the project.
Group stakeholder engagement on sustainability is managed by the Performance and
Responsibility team at Michelin Group. Site-level stakeholder engagement is the responsibility
of site managers. Together, these provide critical input to help guide Michelin strategy and PRM
activities..
Write the level of protein structure below each picture. A word bank .pdf
Write the level of protein structure below each picture. A word bank is not provided here as you
should know these vocabulary words.
Solution
21.Quaternary structure
22.Secondary structure has 2 types- alpha helix and beta sheet
23.Tertiary structure (3-Dimensional arrangement of protein)
24.Amino acids joined by peptide bond forming the primary structure of protein.
Why should assembly language be avoided for general application deve.pdf
Why should assembly language be avoided for general application development? Under what
circumstances is assembly language preferred or required?
Solution
Reasons for avoiding Assembly Language for General Application Development:
(i) It is difficult to understand the code (as Assembly Language is a low-level language).
Debugging and modification of code requires extensive work.
(ii) Application Development time will be higher than higher level languages because even the
basic operations like additions, subtractions etc needs to be implemented as part of the code.
(iii) In case of higher level languages, we can use the existing libraries to complete the
development work faster. This is not possible with the Assembly Language.
(iv) Assembly Languages are hardware specific and not portable to all machines. This is not the
case with the higher level languages.
Circumstances under which Assembly Language is preferred:
(i) Assembly Language is preferred when we have a limited availability of memory and
computational space. To maximum utilize the available memory and computational space,
Assembly Language is preferred over Higher Level languages in such cases.
Ex: chipsets
(ii) Assembly Language is also used when we need to do some hardware manipulation. This is
not possible with higher level languages.
(iii) When we need to design something specific to a computer architecture where support for
higher languages is not available yet..
Who was Jesus of Nazareth What was his message How did he convey t.pdf
Who was Jesus of Nazareth? What was his message? How did he convey that message? What
role did parables and miracles play in his ministry? What event convinced his followers that he
was more than an ordinary man?
Solution
Jesus Christ, best known as Jesus of Nazareth or simply Jesus, is Christianity\'s central figure,
both as Messiah and, on most Christians, as God incarnate. Muslims regard him as a general
major prophet several regard him because Messiah. Many Hindus also recognize him as a
general manifestation belonging to the divine, and some Buddhists identify him as a Bodhisattva.
Jesus was born sometime right before 4 B.C. He was raised in Nazareth, a tiny village in Galilee,
within the peasant class. Jesus\'father has been a carpenter and the man became one, too,
meaning that they had likely lost their agricultural land at some point. Jesus was raised Jewish
and the man remained deeply Jewish nearly every one of his life. His intention wasn\'t to create a
new religion. Rather, he saw himself as doing something within Judaism.
His followers experienced him after his death. It is see-through that they had visions of Jesus as
that you had known him during his historical life. Only after his death did they declare Jesus to
be \"Lord\" or \"the Son of God.\" Right away of Jesus\'life through His death and beyond, the
Herodian dynasty ruled Palestine and nearby area, the lands belonging to the eastern
Mediterranean coast. These rulers were clients of Imperial Rome, who served with all the
appointment and permission of Rome. The firstly this family turn out to be appointed as ruler in
Israel was Herod the Great. Upon his death, his kingdom was divided between three of his sons:
Herod Archelaus, Herod Antipas, and Philip the Tetrarch. The Parables of Jesus can be found in
all the canonical gospels, whereas in the a few of the non-canonical gospels, but are found
mainly while in the three synoptic gospels.They represent a vital element of the teachings of
Jesus, forming approximately 33 % of his recorded teachings. Christians place high focus on
these parables; because they are the purported words of Jesus, they can indeed be believed to be
what the Father has taught, indicated by John 8:28 and 14:10. Jesus parables are seemingly
simple and easy and memorable stories, often with imagery, and all sorts of convey messages.
Scholars have commented that although these parables seem simple, the messages they convey
are deep, and central in the teachings of Jesus. Christian authors view them not as mere
similitudes which serve the purpose of illustration, but as internal analogies in which nature
becomes a witness for the spiritual world.
why has America never been a homogenous societywhy has Amer.pdf
why has America never been a homogenous society?
why has America never been a homogenous society?
why has America never been a homogenous society?
Solution
A homogeneous society refers to that society where people share same type of values, culture,
languages and religious system.
America is a developed nations and the standard living is rich. There are different standard living
style, different culture and opinions. The citizens in US are from different nations and have
different opinions. Therefore America could not be consider a homogenous society..
Which of these statements about Java are trueA.( T F ) Using va.pdf
Which of these statements about Java are true?
A.( T / F ) Using variables for real contents is an implementation of Inheritance.
B.( T / F ) An object usually interacts with other objects through method(s).
C.( T / F ) One class can create only one object.
D.( T / F ) According to the naming convention, the names of classes and objects begin with a
upper case.
E.( T / F ) Every header (signature) for paragraphs (classes, constructors, and methods) must
have a pair of parenthesis for parameters.
F.( T / F ) Knowing and using a method by just the signature of the method, without
understanding how the method does, is an implementation of Encapsulation.
G. ( T / F ) One superclass(parent class) can have more than one of its subclasses(children
classes).
H.( T / F ) Objects have their own information and features, called parameters and methods.
I.( T / F ) Every paragraph must have both { } and its signature.
J. ( T / F ) Every declaration statement must provide at least the type and name information about
the variable.
Solution
A.
False
Inheritance is the inheriting something from parent class
B.
True
C.
False
You can create any number of objects of a class
D.
False
Class Name: begin with upper case
Object name: camel case
E.
True
F.
True
G,
False
It is not allowed in java to inherit more than one class
In java we can implement multiple interfaces
H.
True
Object have their states(instance variables) and methods(behaviours)
I.
True
J.
true.
When someone suffers from arteriosclerosis, there is a widening of th.pdf
When someone suffers from arteriosclerosis, there is a widening of the vessel\'s lumen that
ensues. True False The tunica that usually distinguishes the oxygenated vessels from one
another is: media externa depends on the location of the vessel interna Choose among the
following choices the relationship that is erroneous: continuous capillary-skin-tight junction
fenestrated capillary muscle -incomplete basement membrane sinusoidal capillary liver
discontinued basal lamina fenestrated capillary-kidney-pore with diaphragm
Solution.
What is the relationship of Computer System Validation to the Softwa.pdf
What is the relationship of Computer System Validation to the Software Development Life
Cycle.
Solution
The computer system validtation process steps are:
(i) Standard operating procedures
(ii) Training procedures and training records.
Software developement cycle ralationship involves:
Planning, Requirement Analysis, design, developement, integration test and validation,
installatoin, qualification and implementation, then next operations and maintainance..
What is the developmental mechanism that Piaget proposed to account .pdf
What is the developmental mechanism that Piaget proposed to account for movement to higher
stages of cognitive development? In other words, why do children begin to construct a different
type of cognitive structure at different stages?
Solution
The following are the assumptions of piaget’s about the children.
The first important assumption is that the children usually construct their own knowledge
.This knowledge is usually In response to their experiences in life.Another important fact
is that the children have the power to learn various things on their own without the
intervention of older children or adults..It has the following stages
Piaget’s Stages:
1)The first one is Sensorimotor stage (birth to 2 years) in which the child grows.
2)The second one the Preoperational stage(2 to 7 years).In this stage the knowledge
which is gained by the child is represented by language, mental imagery,and symbolic
thought.
3)The third one is the Concrete operational stage(7 to 12 years).In this stage the
Children are able to reason logically about concrete objects and events.
4)Finally we have the Formal operational stage(12 years and up)-In this stage the
Children have the ability to think deeply about concrete events .They can also reason
abstractly and hypothetically at the same time..
What is meant by a privileged instruction How does it apply to .pdf
What is meant by a \" privileged\" instruction? How does it apply to operating systems?
Solution
1)it is type of instruction which contains protection settings,interrupt handlers,i/o, process status
instruction
and this instruction is executed only when system is in supervised mode or priviliged mode
which is in operating
system
2)in os there are two modes user mode and previliged mode all preveliged instruction run in this
mode
1)these instruction are used in memory address mapping and flush the cache data
2)it also read and load system registers
3)changing the modes in operating system
4)it also perform some i/o operations.
What are the major capabilities of database management systems (DBMS.pdf
What are the major capabilities of database management systems (DBMS) and why is a
relational DBMS so powerful? Explanin in 100-150 words.
Solution
A database management system (DBMS) refers to a system software for creating and organizing
databases.
Capabilities of database management system (DBMS) is explained as below-
Data Structuring
All information in a digital store is organized into a clear hierarchical structure with records,
tables or objects. Every piece of information by help of database can be organized in a kind of
catalogue, so that it could be easier to search and update records later on.
Query Languages
A typical DBMS makes it possible to utilize query languages for collecting, searching, sorting,
and modifying.
Multi-user Access
DBMS provides many users access to all types of information stored in one and the same data
store.
The relational database is the key method for organizing and maintaining data in information
systems as it is so flexible and easy to get to. It organizes data in two-dimensional tables called.
Each row expresses a record, and each column represents an attribute or field. Each table also
contains a key field to identify each record for manipulation. Relational database tables can be
add easily to send data required by users.
Hence, relational database is powerful..
what ia managerial accountingSolutionAnswer - The branch o.pdf
what ia managerial accounting?
Solution
Answer :- The branch of accounting which helps the management to perform its functions like
\"Planning, Organization, Coordination, Control, Communication and decision-making\", is
called managerial accounting. Mangerial accounting provides required information to the
management to take effective decisions and control over the business. Managerial accounting is
the presentation of accounting information in such a way as to assist the management in the
creation of policy and in the day to day operation of an undertaking..
What is Impersonation, why do you use it and how does SQL perform im.pdf
What is Impersonation, why do you use it and how does SQL perform implicit Impersonation?
Solution
Impersonation is an arrangement in which an SQL Server is configured to allow an instance of
one SQL server to connect to another instance of SQL server under the context of an autenticated
Windows User.
Impersonation can be done explicitly or implicitly on a SQL server.
The EXECUTE AS statement is used to do explicity Impersonation, It can be used to
impersonate server-level,database-level principals on logins, users.
implicit Impersonation is on modules(server-level,database-level)
database-level -> stored procedure , function
server-level -> server-level trigger.
The EXECUTE AS CALLER will change the context to the caller\'s context, this change does
not revert to the implicitly impersonated context,
REVERT should be called to get back to previous context.
EXECUTE AS CALLER does not require any permission check.
Based on the triggers the implicit impersonation is called directly..
The answers to these questions are covered both in the lecture materi.pdf
The answers to these questions are covered both in the lecture material and the text book What
reaction, oxidation or reduction, is key to uranium bioremediation? How does the role of energy
production lead to the action of bioremediation by microorganisms? What are xenobiotics and
what are some examples? What is the role of microbes in the bioremediation of xenobiotics?
Explain how the bioremediation of the herbicide 2, 4, 5-1 shown below, produces energy lord
microbes.
Solution
1. Bioremediation is a process which involves the use of microorganisms to remove or
neutralize from contaminants, such as polluted soil or water. In the absence of oxygen, bacteria
are able to respire various electron acceptors for the energy required for its metabolism. At the
environmentally neutral pH, the aquaous U has a similar redox couple to Fe(III), therefore
Fe(III)-reducing bacteria are able to respire aquaous U as an alternative electron acceptor,
reducig it to insoluble U. Reduction of Uranium is the key reaction for the bioremediation of
uranium, For the bioremediation of Uranium the process is stimulated by adding electron donor
such as acetate, lactate or ethanol from which electrons can be taken up by bacteria to gain the
energy to promote the enzymatic (microbial) reduction of aquaous U to insoluble U in anaerobic
condition. The end product of this process would be uraninite. 3. Xenobiotics are the synthetic
compounds found in living organisms, which are not produced by and foreign to that organisms.
They are also synthetic substances (doesn\'t produced naturally) which are found in higher
concentration than its normal level in the entire biological system. Examples of xenobiotics are:
Halocarbons: consist of halogen group in their structure and used in solvents, pesticides,
propellents etc. Due to their volatile nature, they often escape and destruct the ozone layer.
Synthetic polymers: mainly used to form polyester, polyvinyl chloride etc Carcinogen, food
additives, drugs are also examples of the xenobiotics. Normally the degradation of xenobiotics
by microorganisms is very rare, as the availability of the xenobiotics to the microorganisms is
very low as compared to its concentration in environment. However, when certain microbes are
exposed to these xenobiotics continuously, they develop the ability to degrade the compounds.
Mutations in microbes occur in such a way so that its active site can shows increased affinity
towards the xenobiotics and some mutates to form new enzymatic pathway for degradation of
xenobiotics. Use of mixed population is very effective for bioremediation of xenobiotics. It
creates the cometabolism process n their combined effect is higher than the individual alone.
Genetic engineering can also be used to modify microbes for degrading xenobiotics. 4. The
microbes while degrading herbicide 2,4,5-T, it produces an end product named succinate +
acetate. Succinate is the intermediate of the TCA (TriCarboxylicAcid) cycle, so it.
Are these correct I am confused with the book pictures and the actu.pdf
Are these correct? I am confused with the book pictures and the actual pictures Post-Lab
Questions eScience Labs, LLC 2013
Solution
A . INTERPHASE.
B.PROPHASE.
C.PROPHASE.
D.INTERPHASE.
E. EARLY ANAPHASE (you can see the pulling of chromosomes towards oppsite side).
F.METAPHASE (Chromosomes are aligned on the equatorial plate).
Students arrive at a library reference desk at an average rate of 15.pdf
Students arrive at a library reference desk at an average rate of 15 per hour. Assume Poisson
arrivals. What is the probability that NO MORE THAN 2 students arrive in 30 minutes?
Solution
mean for one hour = 15/hour
mean for 30 min = 15/2 = 7.5 student/30 min
lamda = 7.5
P(x=r) = e^(-lamda) * lamda^r / r!
P(x<2) = P(x=0) + P(x=1)
P(x<2) = e^(-7.5) * 7.5^0 / 0! + e^(-7.5) * 7.5^1 / 1!
P(x<2) = 0.004701.
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