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Second Order Terms in Purity
      Calculations of 

 Pharmaceutical Reference
        Standards!



            jbladon!           1!
CASE I!
 Protocol requires using HPLC purity and!
the water content to determine analyte purity!

 %Purity = 100% − %Water − % HPLC Impurities


                    ?!
                    jbladon!                   2!
CASE I!
  Protocol requires using HPLC purity and!
the water content to determine analyte purity!

        %Purity = F1 F2 100%
F1 is the fraction of entire sample that is not water.
F2 is the fraction of sample excluding water that is analyte.



                            jbladon!                        3!
Let,
A = Analyte*
Im = Impurities*
 W = Water
 Then,
      ⎛ A + Im ⎞           ⎛ A ⎞
 F1 = ⎜           ⎟ , F2 = ⎜
      ⎝ A + Im+ W ⎠        ⎝ A + Im ⎟
                                    ⎠
        ⎛ A + Im ⎞ ⎛ A ⎞ ⎛              A    ⎞
 F1F2 = ⎜                      ⎟ =⎜
        ⎝ A + Im+ W ⎠ ⎝ A + Im ⎠ ⎝ A + Im+ W ⎟
                    ⎟⎜                       ⎠
____________________
• Where each response factor is known or it is assumed
they are identical          jbladon!                     4!
%HPLC Impurities ⎛ Im ⎞
                =⎜        ⎟
      100%       ⎝ A + Im ⎠
Rearrange F2
     ⎛ A ⎞ ⎛ A + Im− Im ⎞ ⎛       Im ⎞
F2 = ⎜        ⎟ =⎜       ⎟ = ⎜1 −    ⎟
     ⎝ A + Im ⎠ ⎝ A + Im ⎠ ⎝ A + Im ⎠
     ⎛ %HPLC Impurities ⎞
F2 = ⎜ 1 −              ⎟
     ⎝     100%         ⎠

                 jbladon!            5!
%Water        W
        =
 100%     A + Im+ W
Rearrange F1
     ⎛ A + Im ⎞ ⎛ A + Im+ W − W ⎞
F1 = ⎜           ⎟ =⎜           ⎟
     ⎝ A + Im+ W ⎠ ⎝ A + Im+ W ⎠
 ⎛ A + Im+ W     W     ⎞
=⎜           −         ⎟
 ⎝ A + Im+ W A + Im+ W ⎠
     ⎛ %Water ⎞
F1 = ⎜ 1 −      ⎟
     ⎝     100% ⎠
                jbladon!            6!
jbladon!   7!
The Second Order Term

             ⎛     %Water ⎞ ⎛    %HPLC Impurities ⎞
   %Purity = ⎜ 1 −        ⎟ ⎜1 −                  ⎟ 100%
             ⎝      100% ⎠ ⎝         100%         ⎠


          ⎧ %Water %HPLC Impurities ⎛ %Water ⎞ ⎛ %HPLC Impurities ⎞ ⎫
          ⎪                                                         ⎪
%Purity = ⎨1−     −                +⎜        ⎟⎜                   ⎟ ⎬100%
          ⎪ 100%
          ⎩            100%         ⎝ 100% ⎠ ⎝       100%         ⎠⎪⎭




                                 jbladon!                                   8!
Example

                   Let
              %Water = 2.5%
           %HPLC Impurities = 5.0%

                       Then
%Purity = {1- 0.025 - 0.050 + (0.025)(0.050)}100%
                 %Purity = 92.6%

       If the second order term is omitted,
                 %Purity = 92.5%


                       jbladon!                     9!
CASE II

Protocol requires using the HPLC purity,!
  the water and solvent content, and!
       the inorganic ion content !
      to determine analyte purity!




                  jbladon!                  10!
1.  Water Content by TGA!
2.  Solvent Content by Gas
    Chromatography!
3.  Inorganic Ions by Ion Chromatography!
4.  Fraction of what is left by HPLC Purity!




                     jbladon!                  11!
%Purity = 100% − %Water − % Solvent
          − % Inorganic − % HPLC Impurities


                   ?!
                   jbladon!               12!
%Purity = F1 F2 100%

F1 is the fraction of sample that is
   not water/solvent/inorganic

F2 is the fraction of sample
   excluding water/solvent/inorganic
   that is analyte.

                      jbladon!         13!
Let,
A = Analyte*
IMP = Impurities*
W = Water
S = Solvent
IN = Inorganic
Then,
     ⎛       A + IMP        ⎞        ⎛    A ⎞
F1 = ⎜                      ⎟ , F2 = ⎜
     ⎝ A + IMP + IN + W + S ⎠        ⎝ A + IMP ⎟
                                               ⎠
  ____________________
• Where each response factor is known or
it is assumed they are identical
                           jbladon!                14!
⎛       A + IMP        ⎞⎛     A ⎞
F1F2 = ⎜
       ⎝ A + IMP + W + S + IN ⎟ ⎜ A + IMP ⎟
                              ⎠⎝          ⎠
       ⎛          A           ⎞
F1F2 = ⎜
       ⎝ A + IMP + W + S + IN ⎟
                              ⎠




                    jbladon!                  15!
%HPLC Impurities     IMP
                 =
      100%         A + IMP
Rearrange F2
     ⎛    A ⎞ ⎛ A + IMP − IMP ⎞
F2 = ⎜         ⎟ =⎜           ⎟
     ⎝ A + IMP ⎠ ⎝  A + IMP   ⎠
     ⎛ A + IMP     IMP ⎞
F2 = ⎜         −
     ⎝ A + IMP A + IMP ⎟⎠
         %HPLC Impurities
F2 = 1 −
               100%
                jbladon!          16!
%Water / Solvent          W +S
                 =
     100%          A + IMP + W + S + IN
%IN              IN
      =
100% A + IMP + W + S + IN
Rearrange F1
     ⎛       A + IMP        ⎞
F1 = ⎜                      ⎟=
     ⎝ A + IMP + W + S + IN ⎠
     ⎛ A + IMP + W + S + IN − W − S − IN ⎞
F1 = ⎜                                   ⎟
     ⎝       A + IMP + W + S + IN        ⎠
     ⎛ A + IMP + W + S + IN        W +S          ⎞
                            −
     ⎜ A + IMP + W + S + IN A + IMP + W + S + IN ⎟
F1 = ⎜                                           ⎟
     ⎜−           IN                             ⎟
     ⎝ A + IMP + W + S + IN                      ⎠
         %Water / Solvent %IN
F1 = 1 −                 −
             100%          100%
                             jbladon!                17!
⎛     %Water / Solvent % IN ⎞
%Purity = ⎜ 1 −                 −
          ⎝         100%          100% ⎟
                                       ⎠
            ⎛    %HPLC Impurities ⎞
          x ⎜1 −                  ⎟ 100%
            ⎝        100%         ⎠




                   jbladon!                18!
The Second Order Terms
          ⎧ %Water/Solvents %IN %HPLC Impurities ⎫
          ⎪1−                  −      −              ⎪
          ⎪        100%          100%        100%    ⎪
          ⎪ ⎛ %Water/Solvents ⎞ ⎛ %HPLC Impurities ⎞
          ⎪                                          ⎪
                                                     ⎪
%Purity = ⎨+ ⎜                ⎟⎜                   ⎟ ⎬100%
          ⎪ ⎝     100%        ⎠⎝      100%         ⎠ ⎪
          ⎪ ⎛ %IN ⎞ ⎛ %HPLC Impurities ⎞             ⎪
          ⎪+ ⎜     ⎟⎜                   ⎟            ⎪
          ⎪ ⎝ 100% ⎠ ⎝
          ⎩                100%         ⎠            ⎪
                                                     ⎭



                           jbladon!                          19!
Example
                     Let
             %Water/Solvent = 2.5%
              %Inorganic = 5.0%
            %HPLC Impurities = 5.0%

                        Then
%Purity = {1- 0.025 - 0.050 - 0.050 + (0.025)(0.050)
               + (0.050)(0.050)}100%
                  %Purity = 87.9%

      If both second order terms are omitted,
                  %Purity = 87.5%

                        jbladon!                       20!
Meet the Boys of the FDA




            Dr. Wiley and the Division of Chemistry Staff in 1883.
                       Wiley, third from right, was 37.
Courtesy Wallace F. Janssen
FDA Historian                     jbladon!                           21!
If you have a question about an
equation to calculate the purity of a
reference standard in a protocol or
 method, see your supervisor and
      bring my handouts for this
             presentation




                 jbladon!               22!

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2nd Order Terms in Purity Calculations of Reference Standards

  • 1. Second Order Terms in Purity Calculations of 
 Pharmaceutical Reference Standards! jbladon! 1!
  • 2. CASE I! Protocol requires using HPLC purity and! the water content to determine analyte purity! %Purity = 100% − %Water − % HPLC Impurities ?! jbladon! 2!
  • 3. CASE I! Protocol requires using HPLC purity and! the water content to determine analyte purity! %Purity = F1 F2 100% F1 is the fraction of entire sample that is not water. F2 is the fraction of sample excluding water that is analyte. jbladon! 3!
  • 4. Let, A = Analyte* Im = Impurities* W = Water Then, ⎛ A + Im ⎞ ⎛ A ⎞ F1 = ⎜ ⎟ , F2 = ⎜ ⎝ A + Im+ W ⎠ ⎝ A + Im ⎟ ⎠ ⎛ A + Im ⎞ ⎛ A ⎞ ⎛ A ⎞ F1F2 = ⎜ ⎟ =⎜ ⎝ A + Im+ W ⎠ ⎝ A + Im ⎠ ⎝ A + Im+ W ⎟ ⎟⎜ ⎠ ____________________ • Where each response factor is known or it is assumed they are identical jbladon! 4!
  • 5. %HPLC Impurities ⎛ Im ⎞ =⎜ ⎟ 100% ⎝ A + Im ⎠ Rearrange F2 ⎛ A ⎞ ⎛ A + Im− Im ⎞ ⎛ Im ⎞ F2 = ⎜ ⎟ =⎜ ⎟ = ⎜1 − ⎟ ⎝ A + Im ⎠ ⎝ A + Im ⎠ ⎝ A + Im ⎠ ⎛ %HPLC Impurities ⎞ F2 = ⎜ 1 − ⎟ ⎝ 100% ⎠ jbladon! 5!
  • 6. %Water W = 100% A + Im+ W Rearrange F1 ⎛ A + Im ⎞ ⎛ A + Im+ W − W ⎞ F1 = ⎜ ⎟ =⎜ ⎟ ⎝ A + Im+ W ⎠ ⎝ A + Im+ W ⎠ ⎛ A + Im+ W W ⎞ =⎜ − ⎟ ⎝ A + Im+ W A + Im+ W ⎠ ⎛ %Water ⎞ F1 = ⎜ 1 − ⎟ ⎝ 100% ⎠ jbladon! 6!
  • 7. jbladon! 7!
  • 8. The Second Order Term ⎛ %Water ⎞ ⎛ %HPLC Impurities ⎞ %Purity = ⎜ 1 − ⎟ ⎜1 − ⎟ 100% ⎝ 100% ⎠ ⎝ 100% ⎠ ⎧ %Water %HPLC Impurities ⎛ %Water ⎞ ⎛ %HPLC Impurities ⎞ ⎫ ⎪ ⎪ %Purity = ⎨1− − +⎜ ⎟⎜ ⎟ ⎬100% ⎪ 100% ⎩ 100% ⎝ 100% ⎠ ⎝ 100% ⎠⎪⎭ jbladon! 8!
  • 9. Example Let %Water = 2.5% %HPLC Impurities = 5.0% Then %Purity = {1- 0.025 - 0.050 + (0.025)(0.050)}100% %Purity = 92.6% If the second order term is omitted, %Purity = 92.5% jbladon! 9!
  • 10. CASE II Protocol requires using the HPLC purity,! the water and solvent content, and! the inorganic ion content ! to determine analyte purity! jbladon! 10!
  • 11. 1.  Water Content by TGA! 2.  Solvent Content by Gas Chromatography! 3.  Inorganic Ions by Ion Chromatography! 4.  Fraction of what is left by HPLC Purity! jbladon! 11!
  • 12. %Purity = 100% − %Water − % Solvent − % Inorganic − % HPLC Impurities ?! jbladon! 12!
  • 13. %Purity = F1 F2 100% F1 is the fraction of sample that is not water/solvent/inorganic F2 is the fraction of sample excluding water/solvent/inorganic that is analyte. jbladon! 13!
  • 14. Let, A = Analyte* IMP = Impurities* W = Water S = Solvent IN = Inorganic Then, ⎛ A + IMP ⎞ ⎛ A ⎞ F1 = ⎜ ⎟ , F2 = ⎜ ⎝ A + IMP + IN + W + S ⎠ ⎝ A + IMP ⎟ ⎠ ____________________ • Where each response factor is known or it is assumed they are identical jbladon! 14!
  • 15. A + IMP ⎞⎛ A ⎞ F1F2 = ⎜ ⎝ A + IMP + W + S + IN ⎟ ⎜ A + IMP ⎟ ⎠⎝ ⎠ ⎛ A ⎞ F1F2 = ⎜ ⎝ A + IMP + W + S + IN ⎟ ⎠ jbladon! 15!
  • 16. %HPLC Impurities IMP = 100% A + IMP Rearrange F2 ⎛ A ⎞ ⎛ A + IMP − IMP ⎞ F2 = ⎜ ⎟ =⎜ ⎟ ⎝ A + IMP ⎠ ⎝ A + IMP ⎠ ⎛ A + IMP IMP ⎞ F2 = ⎜ − ⎝ A + IMP A + IMP ⎟⎠ %HPLC Impurities F2 = 1 − 100% jbladon! 16!
  • 17. %Water / Solvent W +S = 100% A + IMP + W + S + IN %IN IN = 100% A + IMP + W + S + IN Rearrange F1 ⎛ A + IMP ⎞ F1 = ⎜ ⎟= ⎝ A + IMP + W + S + IN ⎠ ⎛ A + IMP + W + S + IN − W − S − IN ⎞ F1 = ⎜ ⎟ ⎝ A + IMP + W + S + IN ⎠ ⎛ A + IMP + W + S + IN W +S ⎞ − ⎜ A + IMP + W + S + IN A + IMP + W + S + IN ⎟ F1 = ⎜ ⎟ ⎜− IN ⎟ ⎝ A + IMP + W + S + IN ⎠ %Water / Solvent %IN F1 = 1 − − 100% 100% jbladon! 17!
  • 18. %Water / Solvent % IN ⎞ %Purity = ⎜ 1 − − ⎝ 100% 100% ⎟ ⎠ ⎛ %HPLC Impurities ⎞ x ⎜1 − ⎟ 100% ⎝ 100% ⎠ jbladon! 18!
  • 19. The Second Order Terms ⎧ %Water/Solvents %IN %HPLC Impurities ⎫ ⎪1− − − ⎪ ⎪ 100% 100% 100% ⎪ ⎪ ⎛ %Water/Solvents ⎞ ⎛ %HPLC Impurities ⎞ ⎪ ⎪ ⎪ %Purity = ⎨+ ⎜ ⎟⎜ ⎟ ⎬100% ⎪ ⎝ 100% ⎠⎝ 100% ⎠ ⎪ ⎪ ⎛ %IN ⎞ ⎛ %HPLC Impurities ⎞ ⎪ ⎪+ ⎜ ⎟⎜ ⎟ ⎪ ⎪ ⎝ 100% ⎠ ⎝ ⎩ 100% ⎠ ⎪ ⎭ jbladon! 19!
  • 20. Example Let %Water/Solvent = 2.5% %Inorganic = 5.0% %HPLC Impurities = 5.0% Then %Purity = {1- 0.025 - 0.050 - 0.050 + (0.025)(0.050) + (0.050)(0.050)}100% %Purity = 87.9% If both second order terms are omitted, %Purity = 87.5% jbladon! 20!
  • 21. Meet the Boys of the FDA Dr. Wiley and the Division of Chemistry Staff in 1883. Wiley, third from right, was 37. Courtesy Wallace F. Janssen FDA Historian jbladon! 21!
  • 22. If you have a question about an equation to calculate the purity of a reference standard in a protocol or method, see your supervisor and bring my handouts for this presentation jbladon! 22!