Pleas help explain how to solve I don\'t know even how to start the problem Suppose E and F are two events. It is given that P(E)=.22, P(not F)=.65, and P(E and F)=.13. Determine the probability that either E or F occur. Solution 1) P(E) = 0.22 P(F\') = 0.65, => P(F) = 1 - P(F \' ) = 0.35 P(E and F) = 0.13 P(E or F) = P(E) + P(F) - P( E and F) = 0.22 + 0.35 - 0.13 = 0.44 2) P(E \' ) = 0.33 => P(E) = 1 - P(E \' ) = 0.67 P(F \' ) = 0.54 => P(F) = 1 - P(F \' ) = 0.46 P(E or F) = 0.68 P(E and F) = P(E) + P(F) - P( E or F) = 0.67 + 0.46 - 0.68 = 0.45.