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Pleas help explain how to solve I don't know even how to start the problem
Suppose E and F are two events. It is given that P(E)=.22, P(not F)=.65, and P(E and F)=.13.
Determine the probability that either E or F occur.
Solution
1)
P(E) = 0.22
P(F') = 0.65, => P(F) = 1 - P(F ' ) = 0.35
P(E and F) = 0.13
P(E or F) = P(E) + P(F) - P( E and F)
= 0.22 + 0.35 - 0.13
= 0.44
2) P(E ' ) = 0.33 => P(E) = 1 - P(E ' ) = 0.67
P(F ' ) = 0.54 => P(F) = 1 - P(F ' ) = 0.46
P(E or F) = 0.68
P(E and F) = P(E) + P(F) - P( E or F)
= 0.67 + 0.46 - 0.68
= 0.45

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Pleas help explain how to solve I dont know even how to start the .pdf

  • 1. Pleas help explain how to solve I don't know even how to start the problem Suppose E and F are two events. It is given that P(E)=.22, P(not F)=.65, and P(E and F)=.13. Determine the probability that either E or F occur. Solution 1) P(E) = 0.22 P(F') = 0.65, => P(F) = 1 - P(F ' ) = 0.35 P(E and F) = 0.13 P(E or F) = P(E) + P(F) - P( E and F) = 0.22 + 0.35 - 0.13 = 0.44 2) P(E ' ) = 0.33 => P(E) = 1 - P(E ' ) = 0.67 P(F ' ) = 0.54 => P(F) = 1 - P(F ' ) = 0.46 P(E or F) = 0.68 P(E and F) = P(E) + P(F) - P( E or F) = 0.67 + 0.46 - 0.68