This document provides mock test questions and download links for various tests like MAT, RMAT, CET to help PGPSE participants prepare. It includes over 20 quantitative aptitude questions covering topics like time and work problems, percentages, ratios, mixtures, boats on streams, time and distance etc. along with explanations. Contact details and download links for practice material on basic math, probability, permutations, combinations and English are also provided. Difficult words and their meanings are listed at the end.
This material is for PGPSE / CSE students of AFTERSCHOOOL. PGPSE / CSE are free online programme - open for all - free for all - to promote entrepreneurship and social entrepreneurship PGPSE is for those who want to transform the world. It is different from MBA, BBA, CFA, CA,CS,ICWA and other traditional programmes. It is based on self certification and based on self learning and guidance by mentors. It is for those who want to be entrepreneurs and social changers. Let us work together. Our basic idea is that KNOWLEDGE IS FREE & AND SHARE IT WITH THE WORLD
The document provides instruction on converting between different units of measurement in both the US customary and metric systems. It gives examples of conversion factors like milli-, centi-, and kilo- and shows how to use dimensional analysis to perform unit conversions between units like kilometers and miles, grams and kilograms, or feet and yards. Students are asked to practice these conversions by working through examples as pairs checks and on a worksheet.
This material is for PGPSE / CSE students of AFTERSCHOOOL. PGPSE / CSE are free online programme - open for all - free for all - to promote entrepreneurship and social entrepreneurship PGPSE is for those who want to transform the world. It is different from MBA, BBA, CFA, CA,CS,ICWA and other traditional programmes. It is based on self certification and based on self learning and guidance by mentors. It is for those who want to be entrepreneurs and social changers. Let us work together. Our basic idea is that KNOWLEDGE IS FREE & AND SHARE IT WITH THE WORLD
Chemical Reaction Stoichiometry. Practical matters in chemical reaction stoichiometry.
Haber process to produce ammonia. production of ammonia from Calcium cyanamide. Manganese dioxide to produce chlorine.
Averages, Mixtures and Alligations Concept SessionGeorge Prep
1. The document discusses various properties and concepts related to averages, mixtures, and alligations such as how the average is affected when values are increased/decreased, surplus and deficit below the average being equal, and weighted averages.
2. Several examples of word problems involving averages, mixtures, and alligations are provided along with step-by-step solutions.
3. Key concepts like inclusion/exclusion, replacement/substitution, and applications to percentages, time-speed-distance problems are explained through examples.
This document provides links to download resources on various topics like statistics, reasoning, mathematics, English, general knowledge etc. It is authored by Dr. T.K. Jain from Afterschoool centre for social entrepreneurship. The document encourages spreading social entrepreneurship and provides additional download links for study materials.
The document provides examples of mathematical shortcuts for percentage, ratio, partnership, time and distance, decimal equivalents of fractions, rule of alligation, and least common multiple word problems. It includes 7 examples of percentage calculations involving increases, decreases, and combined changes. It also discusses finding ratios when mixing quantities at different rates, calculating partner profits when investing different amounts for different time periods, and determining average speeds from distances and times. The document aims to provide concise steps and formulas for solving various aptitude problems involving common mathematical concepts.
The document provides information about the Management Aptitude Test (MAT) Afterschool Centre for Social Entrepreneurship and its PGPSE (Post Graduate Programme in Social Entrepreneurship) program. The 3-year integrated PGPSE program can be done along with civil service exams and provides an option to do a part-time job while studying. The 18-month PGPSE is available in both regular and distance learning modes and focuses on developing social entrepreneurs. Workshops on social entrepreneurship are also conducted across India.
This material is for PGPSE / CSE students of AFTERSCHOOOL. PGPSE / CSE are free online programme - open for all - free for all - to promote entrepreneurship and social entrepreneurship PGPSE is for those who want to transform the world. It is different from MBA, BBA, CFA, CA,CS,ICWA and other traditional programmes. It is based on self certification and based on self learning and guidance by mentors. It is for those who want to be entrepreneurs and social changers. Let us work together. Our basic idea is that KNOWLEDGE IS FREE & AND SHARE IT WITH THE WORLD
The document provides instruction on converting between different units of measurement in both the US customary and metric systems. It gives examples of conversion factors like milli-, centi-, and kilo- and shows how to use dimensional analysis to perform unit conversions between units like kilometers and miles, grams and kilograms, or feet and yards. Students are asked to practice these conversions by working through examples as pairs checks and on a worksheet.
This material is for PGPSE / CSE students of AFTERSCHOOOL. PGPSE / CSE are free online programme - open for all - free for all - to promote entrepreneurship and social entrepreneurship PGPSE is for those who want to transform the world. It is different from MBA, BBA, CFA, CA,CS,ICWA and other traditional programmes. It is based on self certification and based on self learning and guidance by mentors. It is for those who want to be entrepreneurs and social changers. Let us work together. Our basic idea is that KNOWLEDGE IS FREE & AND SHARE IT WITH THE WORLD
Chemical Reaction Stoichiometry. Practical matters in chemical reaction stoichiometry.
Haber process to produce ammonia. production of ammonia from Calcium cyanamide. Manganese dioxide to produce chlorine.
Averages, Mixtures and Alligations Concept SessionGeorge Prep
1. The document discusses various properties and concepts related to averages, mixtures, and alligations such as how the average is affected when values are increased/decreased, surplus and deficit below the average being equal, and weighted averages.
2. Several examples of word problems involving averages, mixtures, and alligations are provided along with step-by-step solutions.
3. Key concepts like inclusion/exclusion, replacement/substitution, and applications to percentages, time-speed-distance problems are explained through examples.
This document provides links to download resources on various topics like statistics, reasoning, mathematics, English, general knowledge etc. It is authored by Dr. T.K. Jain from Afterschoool centre for social entrepreneurship. The document encourages spreading social entrepreneurship and provides additional download links for study materials.
The document provides examples of mathematical shortcuts for percentage, ratio, partnership, time and distance, decimal equivalents of fractions, rule of alligation, and least common multiple word problems. It includes 7 examples of percentage calculations involving increases, decreases, and combined changes. It also discusses finding ratios when mixing quantities at different rates, calculating partner profits when investing different amounts for different time periods, and determining average speeds from distances and times. The document aims to provide concise steps and formulas for solving various aptitude problems involving common mathematical concepts.
The document provides information about the Management Aptitude Test (MAT) Afterschool Centre for Social Entrepreneurship and its PGPSE (Post Graduate Programme in Social Entrepreneurship) program. The 3-year integrated PGPSE program can be done along with civil service exams and provides an option to do a part-time job while studying. The 18-month PGPSE is available in both regular and distance learning modes and focuses on developing social entrepreneurs. Workshops on social entrepreneurship are also conducted across India.
The document provides examples for calculating percentages in various scenarios involving increases, decreases, and combined changes. It also discusses shortcuts for calculating percentages, ratios, proportions, time and distance problems, simple and compound interest, partnerships, and alligation. Examples are provided for calculating percentages when lengths, areas, prices, or quantities are increased or decreased. Ratios and proportions are explained for scenarios involving investments and profits for partners. Shortcuts are given for finding averages and calculating changes when distances are travelled at different speeds. Methods for solving problems involving simple interest, compound interest, and finding the difference between the two are described.
The document provides frequently asked questions related to aptitude tests. It contains 15 questions covering topics like percentages, ratios, time/work/speed problems involving trains, and geometry questions related to circles, spheres, and tethered animals grazing fields. The questions are meant to help students prepare for competitive exams.
The document provides a collection of aptitude test questions and their solutions. Some key questions covered include: calculating percentages in mixtures, work problems, interest rate problems, sets and Venn diagrams, time and work problems related to trains, and geometry problems involving circles, spheres, cylinders. The questions are meant to help students prepare for competitive exams.
Statistics, Index Numbers, And Analysis For Business 18 OctoberDr. Trilok Kumar Jain
The document provides information about the Mock Test Afterschool Centre for Social Entrepreneurship and its PGPSE program. The 3 year integrated PGPSE program can be taken along with civil service exams and provides comprehensive training in social and spiritual entrepreneurship. The program has case study focused curriculum and flexible specializations. It aims to promote entrepreneurship and social development.
The document provides examples of speed and boat-related questions that are often asked in aptitude tests. It includes 6 questions with solutions related to the speed of boats traveling upstream or downstream in rivers at various speeds, or the speed of the river current. It also includes additional practice questions related to the speed of trains, walking rates, and geometric concepts like area and perimeter calculations.
This document contains a 10 question mathematics sample test for selective schools. It includes questions on topics like geometry, time, speed, percentages, and patterns. After each question is a multiple choice answer set. The document concludes by providing information on NotesEdu, a resource for selective school test preparation, and encourages the user to view their online content and subscription options.
The document discusses how to write and solve proportions using equivalent ratios and cross products. It provides examples of setting up proportions for word problems involving rates and distances, and using cross products to solve for the unknown quantity. Cross products allow for setting up an equation where the products of the cross ratios are set equal, in order to then solve for the missing term.
This document provides materials for the PGPSE program including practice questions for management aptitude tests. It includes over 30 questions across various topics like ratios, percentages, time/work problems, probability, and geometry. The questions are multiple choice or require short calculations to arrive at the answer. Accompanying some questions are step-by-step solutions modeled by the author. The materials are intended to help participants prepare for the quantitative and logical reasoning aspects of the PGPSE program.
The document provides frequently asked questions about aptitude tests, including data sufficiency and reasoning questions. It discusses topics like geometry, ratios, percentages, time/speed/distance problems, and series questions. The questions are meant to help students prepare for competitive exams.
Applications of rational equations powerpointDawn Adams2
1) Hannah and Kendrick need to clean two stretches of beach. Working together, it will take them 3.75 hours to clean one stretch and 7.5 hours to clean both stretches.
2) Tony sails 90 miles round trip in 10 hours. With a 20 mph current, his speed in still water is 25 mph.
3) Down East Kayaks' tour covers 10 miles in 3 hours. With a 6 mph kayaking speed, the current is 4 mph.
4) Joyce needs to mix 12 ml of a 15% citric acid solution with 54 ml of a 70% solution to make 60 ml of a 60% citric acid solution.
A proportion is an equation that equates two ratios. The cross product property of proportions states that the product of the means equals the product of the extremes, or ad = bc. This property can be used to solve word problems involving ratios and determine unknown values. For example, if a car gets 40 miles per gallon, and someone drives 5 miles to school and 5 miles back each day, it would take 1/4 gallon per day. For a full week it would take 5/3 gallons, or about 1.67 gallons, costing around $6.16 at $3.69 per gallon.
The document provides examples of quantitative reasoning questions and their step-by-step solutions. It includes questions related to percentages, ratios, averages, time/work problems, profit/loss calculations, and other math concepts. The solutions clearly explain the logical steps taken to arrive at the answers.
Ratios and proportions are explored. Key points:
- A ratio compares two numbers and can be written in different formats like a:b. Ratios can be simplified by dividing both terms by their greatest common factor.
- A proportion equates two ratios through an equal sign, such as a/b = c/d. The cross product property (ad = bc) and reciprocal property allow solving proportions.
- Examples demonstrate setting up and solving word problems involving ratios, proportions, and unit conversions to calculate costs. Understanding proportions allows scaling solutions proportionally.
This is a collection of fifty questions from important topics in Aptitude where students should pay more attention and practice. Questions taken from various net sources. Some of the answers were edited. This presentation could be run only in office 2010 or latest.
1. The company sold shoes to retailers in 2005 and the previous year.
2. In 2005, the number of pairs sold decreased by 20% while the price per pair increased by 20%.
3. The company's revenue from shoe sales in 2005 was Tk. 300,000. The question asks to find the revenue from the previous year.
The document provides tricks and solutions for quantitative aptitude questions related to simplification, number series, percentage, profit and loss, simple and compound interest, ratio and proportion, time and work, and time, speed and distance. It includes 5 sample questions for each topic, along with step-by-step explanations. The topics covered are relevant for exams like IBPS PO, SSC, and other banking and competitive exams.
this book is useful for those people who preparing competitive examinations. in this book we included all mathematical topics like HCF, LCM, Number system, profit and loss, simple interest, compound interest, percentage, data interpretation and all mathematical topics.
Actuarial Science (ACET) Mock Test Paper II By Sourav Sir's ClassesSOURAV DAS
Actuarial Science (ACET) Mock Test Paper II With Solution By Sourav Sir's Classes, Kolkata, New Delhi.
Contact Us For Any Query About Mock Tests & Solutions.
Call : 9836793076
1) The document discusses fractions, alligation, and mixtures. It provides examples of using chain rules or fractions to solve multi-step word problems involving changes in quantities over time or mixing of substances.
2) Alligation problems deal with mixing different quantities or compounds in specific ratios to form a mixture. The rule for alligation uses a formula to determine the ratio of quantities that need to be mixed.
3) Examples demonstrate using alligation to find numbers of items or volumes when quantities change over multiple steps due to reductions in amounts, replacements, or repeated operations.
Examination reforms are essential to transform the education system according to the document. The current examination system focuses only on rote memorization but needs to evaluate creativity and problem-solving. The document outlines steps to reform examinations including setting goals based on program and course objectives, evaluating whether objectives are achieved through direct and indirect methods, using continuous evaluations, and adopting open book exams and multiple evaluation methods.
The document provides examples for calculating percentages in various scenarios involving increases, decreases, and combined changes. It also discusses shortcuts for calculating percentages, ratios, proportions, time and distance problems, simple and compound interest, partnerships, and alligation. Examples are provided for calculating percentages when lengths, areas, prices, or quantities are increased or decreased. Ratios and proportions are explained for scenarios involving investments and profits for partners. Shortcuts are given for finding averages and calculating changes when distances are travelled at different speeds. Methods for solving problems involving simple interest, compound interest, and finding the difference between the two are described.
The document provides frequently asked questions related to aptitude tests. It contains 15 questions covering topics like percentages, ratios, time/work/speed problems involving trains, and geometry questions related to circles, spheres, and tethered animals grazing fields. The questions are meant to help students prepare for competitive exams.
The document provides a collection of aptitude test questions and their solutions. Some key questions covered include: calculating percentages in mixtures, work problems, interest rate problems, sets and Venn diagrams, time and work problems related to trains, and geometry problems involving circles, spheres, cylinders. The questions are meant to help students prepare for competitive exams.
Statistics, Index Numbers, And Analysis For Business 18 OctoberDr. Trilok Kumar Jain
The document provides information about the Mock Test Afterschool Centre for Social Entrepreneurship and its PGPSE program. The 3 year integrated PGPSE program can be taken along with civil service exams and provides comprehensive training in social and spiritual entrepreneurship. The program has case study focused curriculum and flexible specializations. It aims to promote entrepreneurship and social development.
The document provides examples of speed and boat-related questions that are often asked in aptitude tests. It includes 6 questions with solutions related to the speed of boats traveling upstream or downstream in rivers at various speeds, or the speed of the river current. It also includes additional practice questions related to the speed of trains, walking rates, and geometric concepts like area and perimeter calculations.
This document contains a 10 question mathematics sample test for selective schools. It includes questions on topics like geometry, time, speed, percentages, and patterns. After each question is a multiple choice answer set. The document concludes by providing information on NotesEdu, a resource for selective school test preparation, and encourages the user to view their online content and subscription options.
The document discusses how to write and solve proportions using equivalent ratios and cross products. It provides examples of setting up proportions for word problems involving rates and distances, and using cross products to solve for the unknown quantity. Cross products allow for setting up an equation where the products of the cross ratios are set equal, in order to then solve for the missing term.
This document provides materials for the PGPSE program including practice questions for management aptitude tests. It includes over 30 questions across various topics like ratios, percentages, time/work problems, probability, and geometry. The questions are multiple choice or require short calculations to arrive at the answer. Accompanying some questions are step-by-step solutions modeled by the author. The materials are intended to help participants prepare for the quantitative and logical reasoning aspects of the PGPSE program.
The document provides frequently asked questions about aptitude tests, including data sufficiency and reasoning questions. It discusses topics like geometry, ratios, percentages, time/speed/distance problems, and series questions. The questions are meant to help students prepare for competitive exams.
Applications of rational equations powerpointDawn Adams2
1) Hannah and Kendrick need to clean two stretches of beach. Working together, it will take them 3.75 hours to clean one stretch and 7.5 hours to clean both stretches.
2) Tony sails 90 miles round trip in 10 hours. With a 20 mph current, his speed in still water is 25 mph.
3) Down East Kayaks' tour covers 10 miles in 3 hours. With a 6 mph kayaking speed, the current is 4 mph.
4) Joyce needs to mix 12 ml of a 15% citric acid solution with 54 ml of a 70% solution to make 60 ml of a 60% citric acid solution.
A proportion is an equation that equates two ratios. The cross product property of proportions states that the product of the means equals the product of the extremes, or ad = bc. This property can be used to solve word problems involving ratios and determine unknown values. For example, if a car gets 40 miles per gallon, and someone drives 5 miles to school and 5 miles back each day, it would take 1/4 gallon per day. For a full week it would take 5/3 gallons, or about 1.67 gallons, costing around $6.16 at $3.69 per gallon.
The document provides examples of quantitative reasoning questions and their step-by-step solutions. It includes questions related to percentages, ratios, averages, time/work problems, profit/loss calculations, and other math concepts. The solutions clearly explain the logical steps taken to arrive at the answers.
Ratios and proportions are explored. Key points:
- A ratio compares two numbers and can be written in different formats like a:b. Ratios can be simplified by dividing both terms by their greatest common factor.
- A proportion equates two ratios through an equal sign, such as a/b = c/d. The cross product property (ad = bc) and reciprocal property allow solving proportions.
- Examples demonstrate setting up and solving word problems involving ratios, proportions, and unit conversions to calculate costs. Understanding proportions allows scaling solutions proportionally.
This is a collection of fifty questions from important topics in Aptitude where students should pay more attention and practice. Questions taken from various net sources. Some of the answers were edited. This presentation could be run only in office 2010 or latest.
1. The company sold shoes to retailers in 2005 and the previous year.
2. In 2005, the number of pairs sold decreased by 20% while the price per pair increased by 20%.
3. The company's revenue from shoe sales in 2005 was Tk. 300,000. The question asks to find the revenue from the previous year.
The document provides tricks and solutions for quantitative aptitude questions related to simplification, number series, percentage, profit and loss, simple and compound interest, ratio and proportion, time and work, and time, speed and distance. It includes 5 sample questions for each topic, along with step-by-step explanations. The topics covered are relevant for exams like IBPS PO, SSC, and other banking and competitive exams.
this book is useful for those people who preparing competitive examinations. in this book we included all mathematical topics like HCF, LCM, Number system, profit and loss, simple interest, compound interest, percentage, data interpretation and all mathematical topics.
Actuarial Science (ACET) Mock Test Paper II By Sourav Sir's ClassesSOURAV DAS
Actuarial Science (ACET) Mock Test Paper II With Solution By Sourav Sir's Classes, Kolkata, New Delhi.
Contact Us For Any Query About Mock Tests & Solutions.
Call : 9836793076
1) The document discusses fractions, alligation, and mixtures. It provides examples of using chain rules or fractions to solve multi-step word problems involving changes in quantities over time or mixing of substances.
2) Alligation problems deal with mixing different quantities or compounds in specific ratios to form a mixture. The rule for alligation uses a formula to determine the ratio of quantities that need to be mixed.
3) Examples demonstrate using alligation to find numbers of items or volumes when quantities change over multiple steps due to reductions in amounts, replacements, or repeated operations.
Similar to M O C K P A P E R C A T, R M A T, M A T, S B I, B A N K P O, A P T I T U D E T E S T S (20)
Examination reforms are essential to transform the education system according to the document. The current examination system focuses only on rote memorization but needs to evaluate creativity and problem-solving. The document outlines steps to reform examinations including setting goals based on program and course objectives, evaluating whether objectives are achieved through direct and indirect methods, using continuous evaluations, and adopting open book exams and multiple evaluation methods.
Fueling AI with Great Data with Airbyte WebinarZilliz
This talk will focus on how to collect data from a variety of sources, leveraging this data for RAG and other GenAI use cases, and finally charting your course to productionalization.
Freshworks Rethinks NoSQL for Rapid Scaling & Cost-EfficiencyScyllaDB
Freshworks creates AI-boosted business software that helps employees work more efficiently and effectively. Managing data across multiple RDBMS and NoSQL databases was already a challenge at their current scale. To prepare for 10X growth, they knew it was time to rethink their database strategy. Learn how they architected a solution that would simplify scaling while keeping costs under control.
This talk will cover ScyllaDB Architecture from the cluster-level view and zoom in on data distribution and internal node architecture. In the process, we will learn the secret sauce used to get ScyllaDB's high availability and superior performance. We will also touch on the upcoming changes to ScyllaDB architecture, moving to strongly consistent metadata and tablets.
How information systems are built or acquired puts information, which is what they should be about, in a secondary place. Our language adapted accordingly, and we no longer talk about information systems but applications. Applications evolved in a way to break data into diverse fragments, tightly coupled with applications and expensive to integrate. The result is technical debt, which is re-paid by taking even bigger "loans", resulting in an ever-increasing technical debt. Software engineering and procurement practices work in sync with market forces to maintain this trend. This talk demonstrates how natural this situation is. The question is: can something be done to reverse the trend?
"$10 thousand per minute of downtime: architecture, queues, streaming and fin...Fwdays
Direct losses from downtime in 1 minute = $5-$10 thousand dollars. Reputation is priceless.
As part of the talk, we will consider the architectural strategies necessary for the development of highly loaded fintech solutions. We will focus on using queues and streaming to efficiently work and manage large amounts of data in real-time and to minimize latency.
We will focus special attention on the architectural patterns used in the design of the fintech system, microservices and event-driven architecture, which ensure scalability, fault tolerance, and consistency of the entire system.
Your One-Stop Shop for Python Success: Top 10 US Python Development Providersakankshawande
Simplify your search for a reliable Python development partner! This list presents the top 10 trusted US providers offering comprehensive Python development services, ensuring your project's success from conception to completion.
Conversational agents, or chatbots, are increasingly used to access all sorts of services using natural language. While open-domain chatbots - like ChatGPT - can converse on any topic, task-oriented chatbots - the focus of this paper - are designed for specific tasks, like booking a flight, obtaining customer support, or setting an appointment. Like any other software, task-oriented chatbots need to be properly tested, usually by defining and executing test scenarios (i.e., sequences of user-chatbot interactions). However, there is currently a lack of methods to quantify the completeness and strength of such test scenarios, which can lead to low-quality tests, and hence to buggy chatbots.
To fill this gap, we propose adapting mutation testing (MuT) for task-oriented chatbots. To this end, we introduce a set of mutation operators that emulate faults in chatbot designs, an architecture that enables MuT on chatbots built using heterogeneous technologies, and a practical realisation as an Eclipse plugin. Moreover, we evaluate the applicability, effectiveness and efficiency of our approach on open-source chatbots, with promising results.
What is an RPA CoE? Session 1 – CoE VisionDianaGray10
In the first session, we will review the organization's vision and how this has an impact on the COE Structure.
Topics covered:
• The role of a steering committee
• How do the organization’s priorities determine CoE Structure?
Speaker:
Chris Bolin, Senior Intelligent Automation Architect Anika Systems
High performance Serverless Java on AWS- GoTo Amsterdam 2024Vadym Kazulkin
Java is for many years one of the most popular programming languages, but it used to have hard times in the Serverless community. Java is known for its high cold start times and high memory footprint, comparing to other programming languages like Node.js and Python. In this talk I'll look at the general best practices and techniques we can use to decrease memory consumption, cold start times for Java Serverless development on AWS including GraalVM (Native Image) and AWS own offering SnapStart based on Firecracker microVM snapshot and restore and CRaC (Coordinated Restore at Checkpoint) runtime hooks. I'll also provide a lot of benchmarking on Lambda functions trying out various deployment package sizes, Lambda memory settings, Java compilation options and HTTP (a)synchronous clients and measure their impact on cold and warm start times.
Connector Corner: Seamlessly power UiPath Apps, GenAI with prebuilt connectorsDianaGray10
Join us to learn how UiPath Apps can directly and easily interact with prebuilt connectors via Integration Service--including Salesforce, ServiceNow, Open GenAI, and more.
The best part is you can achieve this without building a custom workflow! Say goodbye to the hassle of using separate automations to call APIs. By seamlessly integrating within App Studio, you can now easily streamline your workflow, while gaining direct access to our Connector Catalog of popular applications.
We’ll discuss and demo the benefits of UiPath Apps and connectors including:
Creating a compelling user experience for any software, without the limitations of APIs.
Accelerating the app creation process, saving time and effort
Enjoying high-performance CRUD (create, read, update, delete) operations, for
seamless data management.
Speakers:
Russell Alfeche, Technology Leader, RPA at qBotic and UiPath MVP
Charlie Greenberg, host
Dandelion Hashtable: beyond billion requests per second on a commodity serverAntonios Katsarakis
This slide deck presents DLHT, a concurrent in-memory hashtable. Despite efforts to optimize hashtables, that go as far as sacrificing core functionality, state-of-the-art designs still incur multiple memory accesses per request and block request processing in three cases. First, most hashtables block while waiting for data to be retrieved from memory. Second, open-addressing designs, which represent the current state-of-the-art, either cannot free index slots on deletes or must block all requests to do so. Third, index resizes block every request until all objects are copied to the new index. Defying folklore wisdom, DLHT forgoes open-addressing and adopts a fully-featured and memory-aware closed-addressing design based on bounded cache-line-chaining. This design offers lock-free index operations and deletes that free slots instantly, (2) completes most requests with a single memory access, (3) utilizes software prefetching to hide memory latencies, and (4) employs a novel non-blocking and parallel resizing. In a commodity server and a memory-resident workload, DLHT surpasses 1.6B requests per second and provides 3.5x (12x) the throughput of the state-of-the-art closed-addressing (open-addressing) resizable hashtable on Gets (Deletes).
Session 1 - Intro to Robotic Process Automation.pdfUiPathCommunity
👉 Check out our full 'Africa Series - Automation Student Developers (EN)' page to register for the full program:
https://bit.ly/Automation_Student_Kickstart
In this session, we shall introduce you to the world of automation, the UiPath Platform, and guide you on how to install and setup UiPath Studio on your Windows PC.
📕 Detailed agenda:
What is RPA? Benefits of RPA?
RPA Applications
The UiPath End-to-End Automation Platform
UiPath Studio CE Installation and Setup
💻 Extra training through UiPath Academy:
Introduction to Automation
UiPath Business Automation Platform
Explore automation development with UiPath Studio
👉 Register here for our upcoming Session 2 on June 20: Introduction to UiPath Studio Fundamentals: https://community.uipath.com/events/details/uipath-lagos-presents-session-2-introduction-to-uipath-studio-fundamentals/
Monitoring and Managing Anomaly Detection on OpenShift.pdfTosin Akinosho
Monitoring and Managing Anomaly Detection on OpenShift
Overview
Dive into the world of anomaly detection on edge devices with our comprehensive hands-on tutorial. This SlideShare presentation will guide you through the entire process, from data collection and model training to edge deployment and real-time monitoring. Perfect for those looking to implement robust anomaly detection systems on resource-constrained IoT/edge devices.
Key Topics Covered
1. Introduction to Anomaly Detection
- Understand the fundamentals of anomaly detection and its importance in identifying unusual behavior or failures in systems.
2. Understanding Edge (IoT)
- Learn about edge computing and IoT, and how they enable real-time data processing and decision-making at the source.
3. What is ArgoCD?
- Discover ArgoCD, a declarative, GitOps continuous delivery tool for Kubernetes, and its role in deploying applications on edge devices.
4. Deployment Using ArgoCD for Edge Devices
- Step-by-step guide on deploying anomaly detection models on edge devices using ArgoCD.
5. Introduction to Apache Kafka and S3
- Explore Apache Kafka for real-time data streaming and Amazon S3 for scalable storage solutions.
6. Viewing Kafka Messages in the Data Lake
- Learn how to view and analyze Kafka messages stored in a data lake for better insights.
7. What is Prometheus?
- Get to know Prometheus, an open-source monitoring and alerting toolkit, and its application in monitoring edge devices.
8. Monitoring Application Metrics with Prometheus
- Detailed instructions on setting up Prometheus to monitor the performance and health of your anomaly detection system.
9. What is Camel K?
- Introduction to Camel K, a lightweight integration framework built on Apache Camel, designed for Kubernetes.
10. Configuring Camel K Integrations for Data Pipelines
- Learn how to configure Camel K for seamless data pipeline integrations in your anomaly detection workflow.
11. What is a Jupyter Notebook?
- Overview of Jupyter Notebooks, an open-source web application for creating and sharing documents with live code, equations, visualizations, and narrative text.
12. Jupyter Notebooks with Code Examples
- Hands-on examples and code snippets in Jupyter Notebooks to help you implement and test anomaly detection models.
Must Know Postgres Extension for DBA and Developer during MigrationMydbops
Mydbops Opensource Database Meetup 16
Topic: Must-Know PostgreSQL Extensions for Developers and DBAs During Migration
Speaker: Deepak Mahto, Founder of DataCloudGaze Consulting
Date & Time: 8th June | 10 AM - 1 PM IST
Venue: Bangalore International Centre, Bangalore
Abstract: Discover how PostgreSQL extensions can be your secret weapon! This talk explores how key extensions enhance database capabilities and streamline the migration process for users moving from other relational databases like Oracle.
Key Takeaways:
* Learn about crucial extensions like oracle_fdw, pgtt, and pg_audit that ease migration complexities.
* Gain valuable strategies for implementing these extensions in PostgreSQL to achieve license freedom.
* Discover how these key extensions can empower both developers and DBAs during the migration process.
* Don't miss this chance to gain practical knowledge from an industry expert and stay updated on the latest open-source database trends.
Mydbops Managed Services specializes in taking the pain out of database management while optimizing performance. Since 2015, we have been providing top-notch support and assistance for the top three open-source databases: MySQL, MongoDB, and PostgreSQL.
Our team offers a wide range of services, including assistance, support, consulting, 24/7 operations, and expertise in all relevant technologies. We help organizations improve their database's performance, scalability, efficiency, and availability.
Contact us: info@mydbops.com
Visit: https://www.mydbops.com/
Follow us on LinkedIn: https://in.linkedin.com/company/mydbops
For more details and updates, please follow up the below links.
Meetup Page : https://www.meetup.com/mydbops-databa...
Twitter: https://twitter.com/mydbopsofficial
Blogs: https://www.mydbops.com/blog/
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Must Know Postgres Extension for DBA and Developer during Migration
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5. Tea worth Rs 120 & 130 per Kg are mixed with a third variety in the ratio 1:1:2. If the mixture is worth Rs 150 per Kg , the price of the third variety per Kg will be?
6. SOLUTION Let us assume that we use 1kg of first two varieties and 2 kg of 3 rd variety. Total is 4 kg. So the total price is : 150*4 = 600 price paide for 1 st two varieties : (120+130) = 250 price paid for 3 rd variety : 600-250 = 350 Price per kg for 3 rd variety : 175 per kg.
7. A bill for Rs.6000 is drawn on July 14 at 5 months . It is discounted on 5th October at 10%.Find the bankers discount true discount, bankers gain and the money that the holder of the bill receives. Due date of bill : 17 december interest for period (17 dec – 5 oct) = 73 days interst : 6000*73/365 * 10/100 = 120 this is banker's discount, the bank will give 5880 (money the holder will get ) formula for present value : 6000 * 100/ (100+rt) = 6000 *100/102 =5882.35 true discount is 117.65 answer
8. In one hour a boat goes 11 km with the stream and 5 km against the stream. The speed of the boat in still water is? The speed in still water is simple average of the two speeds. So it is ½ ( 11+5) = 8 Km. So the speed of boat in still water is 8 km per hour.
9. A boat can travel with a speed of 13 kmph in still water. if the speed of stream is 4 kmph,find the time taken by the boat to go 68 km downstream? In downstream the speed of boat and stream will add up. 13+4 = 17 km per hour. Thus 68/17 = 4 hours. The boat will take 4 ours to cover a distance of 68 km downstream. Answer
10. A boat takes 19 hrs for travelling downstream from point A to point B. And coming back to a point C midway between A and B. if the velocity of the sream is 4 kmph . and the speed of the boat in still water is 14 kmph. what is the distence between A and B? The boat initially travelled at (14+4) = 18 km per hour. Then it travelled at (14-4) = 10 km per hour. Let us assume distance from A to B to be 2X. So it has travelled : 2x/18 + x/10 = 19 38X = 3420 x= 3420/38 = 90 so distance = 180 ans.
11. A boat takes 90 min less to travel 36 miles downstream then to travel the same distence upstream. if the speed of the boat in still water is 10 mph . the speed of the stream is : 90 minute = 1.5 hours Let us assume the speed of stream = x 36/ (10-x) – 36/ (10+x) = 1.5 so X = 2.
12. A can contains a mixture of two liquids A and B in the ratio 7:5 when 9 liters of mixture are drawn off and the can is filled with B,the ratio of A and B becomes 7:9. How many liters of liquid A was contained by the can initially? Total quantity is same before and after = X. The only change is in the ratio. 9 liters are taken out in ratio : 7:5, thus 9*7/12 = 5.25 is A and 3.75 is B. We can write it as : 5/12 X + (9-3.75) = 9/16 X 5/12X -9/16X = -5.25 -7/48X = -5.25 or X = 360 the original quantity of A = 360 * 7/12 = 210 answer
13. .One quantity of wheat at Rs 9.30 per Kg are mixed with another quality at a certain rate in the ratio 8:7. If the mixture so formed be worth Rs 10 per Kg ,what is the rate per Kg of the second quality of wheat? Let us assume that the two types of wheat is mixed 8Kg and 7Kg respectively – total is 15 kg. Total cost : 15*10 = 150. Price paid for 1 st type : 9.3*8 = 74.4 price paid for 2 nd : 150 – 74.4 = 75.6 divide it by 7 to get price of 2 nd : 75.6 / 7 = 10.8 answer
14. Tea worth Rs 120 and 130 per Kg are mixed with a third variety in the ratio 1:1:2. If the mixture is worth Rs 150 per Kg ,the price of the third variety per Kg will be? We have taken 1 kg of 1st, 1kg of 2 nd and 2kg of 3rd. Total = 4 kg. Thus total price = 150*4 = 600. price paid on 1 st and 2 nd = 250. price paid on 3 rd : 600-250 = 350 price per kg = 350/2 = 175 per kg. Answer
15. A vessel is filled with liquid,3 parts of which are water and 5 parts syrup. How much of the mixture must be drawn off and replaced with water so that the mixture may be half water and half syrup? The ratio of water and syrup is 3:5. total is 8. we want them to be equal : 4:4. thus we want syrup to be 4. now syrup is 5. thus we have to take 1 out of 5. Thus the ratio in which mixture has to be drawn out is 1/5. thus 8 * 1/5 = 1.6 must be drawn out, which in 3:5 is : .6 and 1 thus after drawing, the water and syrup is 2.4 and 4. add 1.6 water again, and it is 4:4. so 1/5 th of the mixture should be drawn off. Answer.
16. The price of an article including the sales tax is Rs 616.The rate of sales tax is 10%,if the shopkeeper has made a profit of 12%,then the cost price of the article is? Let us assume cost = 100 add profit(+12) = 112 add sales tax (11.2) = 123.2 thus 100/123.2 * 616 = cost = 500 answer
17. By selling 33m of cloth ,one gains the selling price of 11m.Find the gain percent? Suppose sale price is 1 per meter. Total sale price = 33 profit = 11 cost = 33-11 = 22 thus profit is : 11/22 * 100 = 50% of cost. Answer
18. Find 3 numbers in the ratio : 2:3:5, the sum of whose squares is 608? 2x^2 +3x^2 +5x^2 = 608 38x^2 = 608 X^2 = 608/38 = 16 x= 4 numbers are 8, 12, 20 ans.
19. Download links ...for time and work problems http://www.scribd.com/doc/24305787/Time-amp-Work-amp-Time-amp-Distance-in-Quantitative-Aptitude
25. Find the meaning of the following words ? 1.Sage : highly learned person 2.Salubrious : healthful 3.Sap : diminish , Undermine 4.Satiate : Satisfy fully 5.Savor : enjoy 6.Sear : char or burn , 7. Scad : great quantity 8.Spate: sudden flood 9.Sodden : Soaked , dull 10.Snivel : whine, to complain 11. Smirk : concited smile. 2.Slacken : slowup, loosen 13.Sineway: tough, setstrong and firm 14Shyster : lawyer using Questionable methods 15.Shard : fragment , generally of pottery 16.Stanch:Check flow of blood. 17.Stint : be thrifly, set limits 18.Stolid : dull , impassive 19. subside : settleddown, reduce 20.Sylvan: pertaining to the woods 21.Sybarite : lover of luxury. 22.Swindles : cheat
26. Difficult words and their meanings ... 1.Rankle=irritate,fester 2.Rancid=having bad odor 3.Raspy=harsh 4.Revage=plunder,despoil 5.Ravenous=extremely hungry 6.Realm=area of work 7.Renege=deny 8.Repast=meal,feast 9.Regal=royal 10.Rig=fix,manipulate 11.Roster=list 12.Reek=emit(odor) 13.Reiterate=repeat 14.Remorse=guilt,self-reproach 15.Regicide=murder of a king or queen 16.Refectory=dining hall 17.Redoient=fragrant,odorous, 18.Retinue=following,attendants 19.Ruse=trick 20.Ruffian=bully,scoundrel
27. How many times does the hands of a clock make right angle? Let us take from 6 am to 6 pm. At 6.15 it is almost right angle (not exact), similarly at about 6.45 also there is a right angle. Thus we have 2 occasions between 6 and 7. We should have 12 hours so 24 occasions when it can be in right angle. But between 9 to 10 we have only 1 such occasion (9.30), again from 3 to 4, we have only one such case. Thus in 12 hours we have only 22 right angles. Answer
28. Why is it so? We can understand that by the time the minute hand covers 55 minutes, there is one hour (60 minutes). Thus there is a gap of 5 minutes. We can see that at times like 9 and 3 there is a problem. 9 am is counted in 8 to 9 (8.25 and 8.59) to count right angle. And so is the case with 3 pm). If it is asked what is the exact time of right angle, use 60/11 as a formula to find exact time.
29. How many times do we have a straight angle between two hands of a clock from 6 am to 6 pm in a day? Ideally it should be 12 (but it will not be 12) . start at 6, 7.05, 8.10, 9.15, 10.20, 11.25, 12.30, 1.35, 2.40, 3.45, 4.50, 5.55, 6. thus we have 13 such occasions when we have straight angle.
30. A watch which gains uniformly,is 5 min,slow at 8 o'clock in the morning on sunday and it is 5 min.48 sec.fast at 8 p.m on the following sunday. when was it correct? The watch has actually covered 10 min. 48 sec. In a span of 180 hours. We want to know about the exact time when it had crossed only 5 minutes. So solve it using following formula : 5/ 10.8 (180) = 82.8 thus exact time is : 82/24 = 3 day + 10 hours Wednesday : 6 pm + 48 minutes. Answer
31. Explanation Actually 180 is hours (from 8am to 8pm on next Sunday). Actually 82.8 is in hours, to convert it into days, we have devided 82/24, we get 3 rd day + 10 hours. Why did we use : 10. 8 : note: we converted 10.48 in decimal : 48/60 = .8 so it was 10.8
37. Reluctant : Keen : : Remarkable : ? (A)Usual (B)Restrained (C)Striking (D)Evolution Reluctant = not interested keen = interested (so they are opposite) the opposite of remarkable is usual
38. Sculptor : Statue : : Poet : ? (A)Canvas (B)Pen (C)Verse (D)Chisel Sculptor makes statue Poet makes Verse
39. Pesticide : Crop : :Antiseptic : ? (A)Wound (B)Clothing (C)Bandage (D)Bleeding Wound pesticide is used to destroy antibodies in crop, the same role is played by antiseptic on wound
42. Quail : Partridges : : Yak : ? (A)Cows (B)Deer (C)Oxen (D)Antelope Similar to them is the relation between Yak and Oxen
43. Bank : River : : Coast : ? (A)Flood (B)Waves (C)Sea (D)Beach Sea (Coast is the border of Sea, just like a bank is the border of river)
44. What is the opposite of the following words Jaded (to mock / discourage) : Motivate / stimulate .Jaundiced (biased) = Unbiased .Jaunty (unbalanced, excited) = sedate (calm) Jeopardy (to put in danger) = Safety Jettison (to throw out of ship) x Salvage (to save)
45. Antonyms : LACHRYMOSE (which produces tears) = CHEERING (removes tears) LACKADAISICAL (lazy)= AMBITIOUS LACONIC (in a few words) = VERBOSE (in lot of words) LAMPOON (to ridicule) =PRAISE LANGUOR (in depression) = VITALITY (in youth and zeal) LAVISH (who spends a lot) = FRUGAL (spending less) .LAUDATORY (remarkable) = DEFAMATORY (infamous) LECHERY (without character)= PURITY LETHARGIC (lazy)= INVIGORATING (full of zeal ) LEVITY (lightly)= SOLEMNITY (serious) LIMPID (clear) X TURBID (dirty) LOATH (to hate)= EAGER (keen) .LOQUACIOUS (talkative) = TACITURN (laconic) LUGUBRIOUS (mournful, sad) =CHEERFUL .LURID (colourful) = DULL
57. How is M related to N ? 1. P who has only 2 kids: M& N. P is the mother in law of Q, who is sister in law of N 2. R, the sister in law of M, is the daughter in law of S, who has only 2 kids – M and N. From the first statement it is clear that M is Man. (M is husband of Q) from second statement it is clear than N is also Man (N is husband of R). thus M is brother of N But for getting the answer, first statement is sufficient, so take care in exam, write only 1 st statement is sufficient to answer.
58. How is T related to the man in photograph? a. The man in photograph is the only son of T's grandfather b. The man in the photo has no brother / sister and his father is T's Grandfather. The answer can be drawn from either statement (alone). Thus we can use any of these statements to answer the question.
59. two whole numbers whose sum is 64 cant be in the ratio ? Options : 3:5, 1:7 3:4 9:7 answer : as you can see that the sum of 3 and 4 is 7, which cant divide 64, so this is the answer.
60. If a carton containing dozen mirrors is dropped, which of the following cant be the ratio of broken mirrors to unbroken mirrors? Options : 2:1 3:1 3:2 7:5 again 3+2 is 5, which cant divide 12 so this cant be the ratio of broken to unbroken mirrors. So answer is 3:2
61. A father's age was 5 times son's age Five years ago. It will be 3 times after 2 years. What is the ratio of their present age? Father = X, Son = Y Now (X-5) = 5 (Y-5) (from first statement) (X+2)=3(Y+2) solving these two equations, we get : X-5Y=-20 and X-3Y=4 , so Y = 12 X=40 thus their ratio is : 10:3 answer
62. Vinay got thrice as many marks in maths as in English. The proportion of marks in Maths and History is 4:3. If total marks in Maths, english, and History are 250, what are his marks in English? M: E = 3:1, M:H = 4:3, taking M as common and using cross multiplication, M : E : H : 12: 4:9 total = 25 M = 12/25 * 250 = 120 E = 4/25 * 250 = 40 H = 9/25*250 = 90 answer
63. Data sufficiency question : out of which of the two option, can you get the answer ? Question : 1. What is the rank of Mayank in the class ? Options : a. Swati is 5 th from the bottom, and she is 30 places behind Mayank b. There are 40 students after Mayank.
64. Solution From the first statement, or from second statement, we can get the rank from bottom, but not from top. We dont know how many students are there in the class. So we are NOT able to get answer from any of these two statements. Answer
65. Data sufficiency question : from which of the following can we draw the answer ? Question : What is the volume of the cubical pot? Options : 1. the depth of the pot is equal to its width and the diagonal of the cubical pot is more than double the width. 2. The size of maximum size of ball that can be put in this pot is almost 80% of volume of this pot.
66. Solution Answer cannot be drawn. None of the statement gives some help in finding volume of the cubical pot.
67. Data sufficiency question ? Question : How many Sons does X has ? Options : 1. In the garden A was shouting X as father 2. X says that he has 1 offspring
69. Data sufficiency question Question : How many persons are sitting in a roundtable?. Options : 1. There are 3 persons to the right of X 2. Y has 2 persons to his left and 2 to his right.
71. Data sufficiency question ? Q : which direction is Ankit facing ? Options : 1. The rays of Sun are falling to the Right of Ankit. 2. It is morning time now.
72. Answer Combining both the options, we can draw the answer. Ankit is North facing as his shadow is toward left and rays of Sun are towards right. .
73. Two equal glasses are respectively 1/3 and ¼ full of milk. They are then filled up with water and the contents mixed in a tumbler. The ratio of milk and water in the tumbler is ? Let us assume that both the glasses have (3*4) = 12 liters of capacity. The first has 4 liters of milk and 2 nd glass has 3 liters of milk. Combined together they have 7 liters of milk and 17 liters of water. Thus the ratio of milk and water is : 7:17 answer
74. The incomes of A and B are in the ratio of 3:2, and their expenditures are in the ratio 5:3. if each saves Rs. 1000, what is the income of A? Incomes are in ratio of X and expenditures are in the ratio of Y. 3X-5Y = 1000 2X-3Y=1000 -Y=-1000, X = 2000 thus incomes of A and B : 6000 and 4000 and expenditures are : 5000 and 3000 answer.
75. A sum of Rs. 1300 is divided between A,B,C,D such that A's share divided by B's share = B's share / C's share = C's share / D's share = 2/3 In such questions, start from Last – and take cube of the last number to start with – assuming that value for the last variable. (cube , if there are 3 iteration, if there are 4 iterations, take quadruple) Let us start from D, assume it to be 27, now C is 18 now accordingly : B is 12. now A is 8 the numbers are : 8, 12,18,27 thus A should get : 8/ 65 *1300 = 160
76. Find the third proportion to 9 : 12? 9:12 :: 12:X multiply 9 by X and 12 to 12. 9X = 144 X = 16 answer
77. Ankit looks at a photograph and says : “It is the photo of the only daughter of the maternal Grandfather of the only son of brother in law of only son of my maternal grand father.” whose photograph was it ? For this question, solve from last. Convert each clause into a single word and move forward. Only son of my maternal granfather = Mama (maternal uncle) Brother in law of Mama = Papa (father). So on.... you will find the photo is that of Ankit's Mother. Answer
78. In a class out of 24 students 14 passed in Enlgish, 14 passed in Hindi, 12 passed in Both the papers. How many failed in both the papers? For such questions, prepare a venn diagram to solve it . Answer is 8. See it in next slide :
79. Total = 24, out of box = 24-16 =8 = failed in both. 12 English Hindi 2 2 2
80. A:B = 2:3, B:C=5:7, find A:B:C Here B is common. So cross multiply to solve it. Thus 5 must be multiplied to 2:3 and 3 must be multiplied to 5:7 answer : A:B:C= 10:15:21 answer
81.
82. Mayank has 20 shares of RIL and market price of one share is 1060. How much money will he get by selling them. Brokerage rate is 1%? Sale price = 1060*20 = 21200 less 1% brokerage = 212 net amount = 20988 answer
83. Atal does a work in 6 hours and Sonia does the same work in 9 hours. They work together. How much time will they take? 1/6 + 1/9 = (9+6) / 54 now multiply it by ½ ( as there are two persons here) : 15/54 * ½ = 15/108 now reverse it : 108/15 = 36/5
84. A,B,C together complete a work in 6 days. A and B together do the same work in 10 days. How much time will C alone take to do the work? 1/6 – 1/10 = (10-6) / (10*6) = 4/60 = 1/15 reverse it : 15. so C alone will take 15 days to complete the work.
85. Divide 27x^3 – 8 y^3 by 3x-2y (3x-2y)^3 = 27x^3 – 8 y^3 so remove its one power we get : (3x-2y )^2 we get : 9x^2-6xy+4y^2 answer
86. Mayank shows a photograph and says that the mother of this person is the wife of the person who is father of the person, to whom a girl calls mother, the the brother of that girl calls Mayank his father. Whose photograph is that (relation with Mayank)? Mayank's brother in Law
87. Ram gives to Shyam all the money that he has in his pocket. Shyam adds that much more from his pocket and gives to Ravi, who further adds that much amount and gives that to Kavi, who triples this money and gives to Raju. Raju gives 10 times this amount to Mohan. Mohan gives 90% amount of this to Niru and retains Rs. 120. what is the ratio of this amount to Ram's original amount ? Answer : 10:1 answer
88. The Emperor Augustus, it appears, commissioned an idealized sculpture portrait, the features of which are so unrealistic that they have constituted what one scholar calls an "artificial face." - correct it The Emperor Augustus, it appears, commissioned an idealized sculpture portrait, the features of which are so unrealistic as to constitute what one scholar calls an "artificial face."
89. A recent national study of the public schools shows that there are now one microcomputer for every thirty-two pupils, four times as many than there were four years ago. - correct it A recent national study of the public schools shows that there is now one microcomputer for every thirty-two pupils, four times as many as than there were four years ago.
90. Never before had taxpayers confronted so many changes at once as they had in the Tax Reform Act of 1986. Never before had taxpayers confronted so many changes at once as they in the Tax Reform Act of 1986. (as per past perfect tense, we are using had with the first part – so there is no need with the 2 nd part)
91. Correct it : As have many self-taught artists, Perle Hessing did not begin to paint until she was well into middle age. Like many self-taught artists, Perle Hessing did not begin to paint until she was well into middle age.
92. Statements: I. All pilots are experts. II. All authors are pilots. Conclusions: I. All authors are experts. II. No expert in an author. Only 1 st conclusion is valid conclusion.
93. Statements: I. Some doctors are institutes. II. Some crooks are institutes. Conclusions: I. All institutes are doctors. II. Some institutes are crooks. Only 2 nd conclusion is valid conclusion
94. If the positions of the fifth and the twelfth letters of the word GLORIFICATIONS are interchanged and likewise the positions of the fourth and fourteenth letters, the third and tenth letters, the second and eleventh letters, the first and thirteenth letters, are interchanged, then which of the following will be the twelfth letter from the right end? Answer : T
95. Ostrich is related to Antelope in the same way as Egret is related to (a) Cow (b) Buffalo (c) Camel (d) Zebra Buffalo (both depend on each other)
96. Hong Kong is related to China in the same way as Vatican is related to..?... (a) Canada (b) Mexico (c) North America (d) Rome
97. Solution Hongkong is part of China, similarly Vetican is a part of Rome.
98. Forfeit is related to Surrender in the same way as Remit is related to (a) Perceive (b) Confiscate (c) Exempt (d) Refrain
100. Who is paternal uncle of Pavan? I. Pavan is brother of Poornima, who is daughter of Meena, who is sister of Kumar, who is brother Smrithi. II. Prithvi is brother of Indrajith, who is husband of Poornima, who is mother of Ganga, who is sister of Pavan. From 2 nd statement – it is clear that uncle of Pavan is Prithvi, but 1 st statement doesnt give us this answer.
101. What is Milan’s rank in the class of 44 students? I. Ramesh, whose rank is 17th in the class, is ahead of Shyam by 6 ranks, Shyam being 7 ranks ahead of Milan. II. Suketu is 26 ranks ahead of Milan and Shyamala is 6 ranks behind Milan while Savita stands exactly in the middle of Shyamala and Suketu in ranks, her rank being 17th Answer can be drawn from any statement.
102. Four of the following five have similar relationship and hence form a group. Which one does not belong to the group? (a) BROTHER : DORVEHT (b) ENGLISH : GGNNSIJ (c) ANOTHER : CONVEHT (d) BETWEEN : DTEZEEP (e) HUSBAND:JSUDNAF D is not proper. In Brother – two step to B, OR instead of RO, two step to T, EH instead of HE, two steps to R, we get DORVEHT. Similarly we have to solve all the options.
103. Which of the following relates to FLOWER in the same way as RTERBN relates to SECTOR? (a) RWLGPF (b) EOFKUQ (c) EOFMXS (d) RWLEND R then W, then L, now from behing, E instead of F, N instead of O, D instead of E. We get : RWLEND
104. Who among the following British Governor- Generals shifted India’s capital from Calcutta to Delhi in 1911? a) Lord Louis Mountbatten b) Lord Canning c) Lord Hardinge d) Warren Hastings ANSWER : LORD HARDINGE
105. “ Golden Handshake” is the term associated with a) Share market b) Retirement benefits c) Voluntary retirement benefits d) Smuggling VOLUNTARY RETIREMENT BENEFITSI
106. Which of the following is the first surface- to- surface missile in India? a) Prithvi b) Trishul c) Agni d) Naag PRITHVI
107. Mist is caused by a) Dry ice b) Ice at low temperature c) Water vapours at low temperature d) Carbon- monoxide in solid form WATER VAPOURS AT LOW TEMPERATURE
108. Who among the following was the author of “Rajtarangini”, commonly regarded as the first genuine history of India written by an Indian? a) Banbhatta b) Ravikirti c) Pushpadanta d) Kalhana KALHANA
109. Which of the following Articles of the Indian Constitution deal with the Directive Principles of State Policy? a) 26 to 41 b) 31 to 56 c) 36 to 51 d) 41 to 66 36 TO 51
110. The Chinese pilgrim Fa – Hien visited India during the reign of a) Kanishka b) Chandragupta I c) Chandragupta II d) Harshavardhana Chandragupta II
111. The Indian Navy’s only sailing ship, which returned to Kochi after a 10- month voyage around the globe is, a) INS Vibhuti b) INS Tarangini c) INS Prabhat d) INS Viraat INS Tarangini
112. Correct it : It being an important (a)/ letter, the draft had to be (b)/ seen by the Governor (c)/ itself for approval. It being an important (a)/ letter, the draft had to be (b)/ seen by the Governor (c)/ himself for approval.
113. Correct it : Irrespective of either (a)/ Vijay or Sanjay goes (b)/ the overdue payment (c)/ cannot be collected. (d)/ No error. Irrespective of whether (a)/ Vijay or Sanjay goes (b)/ the overdue payment (c)/ cannot be collected. (d)/ No error.
114. In a certain code language, ‘3a, 2b, 7c’ means ‘Truth is Eternal’; ‘7c, 9a, 8b, 3a’ means ‘Enmity is not Eternal’ and 6a, 4d, 2b, 8b’ means ‘Truth does not perish’. Which of the following means ‘enmity’ in that language? Is and eternal are common in first two lines, so are 7c and 3a. From the first two lines, we find that enmity + not means = 8b+9a from this and third sentence, we find Not is common, which is 8b. Thus 9a is left out, thus ENMITY = 9A (answer)
115. In a certain code language, ‘po ki top ma’ means ‘Usha is playing cards’; ‘Kop ja ki ma’ means ‘Asha is playing tennis’; ki top sop ho’ means ‘they are playing football’; and ‘po sur kop’ means ‘cards and tennis’. Which word in that language means ‘Asha’? In the first 2 sentences IS PLAYING are common, ki ma are also common. Asha + tennis = kop + ja . Let us compare this with po sur kop , where kop is for tennis ( cards and tennis ). Thus Asha = ja (answer)
116. A long rope has to be cut to make 23 small pieces. If it is double folded to start with how many times does it need to be cut? Options : 9,12,11,10 11 as after cutting 11, we are able to get its double 22 pieces – and one last piece – which is at fold (one piece).
117. There are 19 hockey players in a club. On a particular day 14 were wearing the hockey shirts prescribed, while 11 were wearing the prescribed hockey pants. None of them was without either hockey pants or hockey shirts. How many were in complete hockey uniform? 14 + 11 – 19 = 6 answer
118. In a class room three fourth of the boys are above 160 cm in height and they are 18 in number. Also out of the total strength, the boys form only two third and the rest are girls. The total number of girls in the class is 18 are 3/4 th of boys, so total number of boys is : 18 * 4/3 = 24 (total number of boys) of the total strength the ratio of boys and girls is 2:1, so number of girls is 12. answer
119. ‘A’ is east of ‘B’ and west of ‘C’. ‘H’ is South-West of ‘C’, ‘B’ is South-East of ‘X’. which is farthest West? When you put them on a map : B A C (from west to East) south to them is H and X is further North West of B. with the information given, it seems that X is the farthest West.
120. A girl earns twice as much in December as in each of the other months. What part of her entire year’s earning does she earn in December? Let us assume that she earns 1 in each month, but in December she earns 2. Total income = 11*1 + 2 = 13 thus she earns : 2/13 of her total income in December month alone.
121. One watch is 1 minute slow at 1 pm on Tuesday and 2 minutes fast at 1 pm on Thursday. When did it show the correct time? 48 hours have passed and in this duration the watch has gained 3 minutes. We want to know when the watch gained 1 minute. So it should be : 1/3 * 48 = 16 hours. Thus the watch gave correct time on : 1+16 hours = 5 AM on Wednesday answer
122. Which number when placed at the sign of interrogation shall complete the matrix? 6 6 8 5 7 5 4 3 ? 120 126 320
123. solution Here you can see that when you multiply 6*5*4 , you get 120 and so on, thus you have to put 8 in place of interrogation sign (?) so make this matrix perfect. Answer.
124. In the sequence given below the sum of the two digits which immediately precede the digit ‘4′ exceeds the sum of the two digits which immediately follow the digit 4 and sum of the two digits which immediately follow the digit 6 exceeds the sum of the two digits which immediately precede the digit 6. How many such 4’s and 6’s together are there? 54462635642843766483 1) . Let us start with 4 after 54, sum of 54 is 9, and sum of 62 is 8, thus our condition is fulfilled. 2) . 4 (56 =11, 28=10) 3) . 4 (66 * 83) so 3 is answer (only 3 conditions by 4, no condition is fulfilled by any 6)
125. Below are given six three-digit numbers. The digits comprise ofnumeric and letters. The letter indicates its serial order in the English alphabet. What will be the middle digit of the 4th number when the numbers are arranged in the descending order after interchanging numeric in each number without altering the place of letter in the number? 19F, 2H9, 98B, D76, 7A6, 61E We have to interchange numeric first : 91F,9H2,89B,D67,6A7,16E now convert letters into numerics : 916,982,892,567,617,165 Now we have to put them in descending order : 982,916,892,617,567,165 the middle one of 4 th number is A (617 , 1=A) answer
126. In a code language any letter which is immediately after or before a vowel in the English alphabet is substituted by that vowel and any vowel i.e. A, E, I, O and U is substituted by the letter immediately following that vowel in the English alphabet. How can the word FEVERISH be written in that code language? FEVERISH : instead of F, write E, instead of E write F, U for V, F for E, no change in R, J instead of I, no change in S, I for H. So answer : EFUFRJSI answer
127. How many pairs of letters are there in the word SPONTANEOUS which have number of letters between them in the word one less than the number of letters between them in English alphabet? 1). P and T have gap of 2, in alphabet they have gap of : 3. 2). U and S have no gap, in alphabet they have gap of 1. so answer is 2.
128. In the following question one term in the number series is wrong. Find out the wrong term. 11, 5, 20, 12, 40, 26, 74, 54 Here we have two series : 11*2 – 2 = 20 20*2 – 2 = 38 38*2 – 2 = 74 second series is : 5*2 + 2 = 12 12*2+2 = 26 26*2+2 = 54 so instead of 40, we should have 38. answer.
129. More material on reasoning : Click here : http://www.scribd.com/doc/23610014/Reasoning-e-Book
130. Mayank has three children — Sangeeta, Vimal and Ashish. Ashish married Monika, the eldest daughter of Mr. and Mrs. Roy. The Roys married their youngest daughter to the eldest son of Mr. and Mrs. Sharma,, and they had.two children named Amit and Shashi. The Roys have two more children, Roshan.and Vandana, both elder to Veena. Sameer and Ajay are sons of Ashish and Monika. Rashmi is the daughter of Amit. What is the surname of Rashmi ? Sharma (answer)
131. Six lectures A, B, C, D, E and F are to be organised in a span of seven days -from Sunday to Sunday ,-only one,lecture on each day in accordance with the following rules (i) A should not be organised on Thursday. (ii) C should be organised immediately after F. (iii) There should be a gap of two days between E and D. (iv) One day there will be no lecture (Friday is not that day), just before that day D will be organised. (v) B should be organised on Tuesday and should not be followed by D. On which day there is no lecture ? Tentative schedule : S=d M=no T=b W=e T=fF=c S=a On Monday – there is no lecture.
132. There are five persons P, Q, R,S and T. One is football player, one is chess player and one is hockey player. P and S are unmarried and they dont participate in any game. None of the ladies plays chess or football. There is a married couple in which T is the husband. Q is the brother of R and is not a a chess player nor a hockey player. Who is the football player ?
133. Solution P & S dont play so remove them. We have QRT left. One of them is lady, she must be R (as T and Q are men). T and Q play two games - chess and football (as these are not played by ladies). Thus T plays chess and Q plays football and R plays hockey. Answer
134. Of the five boys A, B, C, D and E two are good, one is poor and two are average in studies. Two of them study in post-graduate classes and three in under-graduate classes. One comes from a rich family, two from middle-class families and two from poor families. One of them is interested in music, two in acting and one in sports. Of those studying in under-graduate Classes, two are average.and one is poor in studies. Of the two boys interested in acting, one is a post graduate student. The one interested in music comes from a middle-class family. Both the boys interested in acting are not industrious. The two boys coming from middle-class families are average in studies and one of them is interested in acting. The boy interested in sports comes from a poor family, while the one interested in music is industrious. E is industrious, good in studies, comes from a poor family and is not interested in acting, music or sports. C is poor in studies inspite of being industrious. A comes from a rich family and is not industrious but good in studies. B is industrious and comes from a middle-class family. Name the boy interested in sports.
135. Solution A=rich,non industrius , good in study,acting B=UGmiddle class, industrious , avg. In study ,music C= UGindustrious, poor in study (sports) D= UGmiddle, not-industrious,average in study (acting) E=poor,industrius,good in study, not -(M,S)
137. A girl leaves from her, home. She first walks 80 metres in North-west direction and then 30 metres in South-West direction Next, she walks,30 metres in South-east direction. Finally, she turns back towards her house. In which direction is she moving now ? Draw the map and solve it – the direction will be approximately EAST. ANSWER.
138. A walks 10 metres in front and 10 metres to the right. Then every time turning to his left, he walks 5, 15 and 15 metres respectively. How far is he now from his starting point ? DRAW THE MAP AND SOLVE IT ANSWER = 5 METERS.
139. A child is looking for his father. He went 90 metres in the East before turning to his right. He went 20 metres before turning to his right again to look for his father at his uncle's place 30 metres from this point. His father was not there. From here he went 100 metres to the North before meeting his father in a street. How far did the son meet his father from the starting point ? DEDUCT 30 FROM 90 AND 20 FROM 100 FIND SQUARES OF 60 AND 80 AND ADD THEM, YOU GET 10000, SQ.ROOT OF WHICH IS 100. ANSWER IS 100 M.
140. A father tells his son, "I was of your present age when you were born." If the father is 44 now, how old was the boy 5 years back ? THE AGE OF SON IS 22 YEARS NOW. SO HIS AGE 5 YEARS BACK WAS 17 YEARS. ANSWER
141. In a certain code '13' means 'stop smoking' and '59' means 'injurious habit' What is the meaning of '9' and '5' respectively in that code ? I. '157' means 'stop Bad habit'. II., '839'means 'smoking is injurious'. How do you get answer ? Solution : solution can be obtained from any of these two hints. If you take first hint, 59 and 157 have 5 as common number. The common number denotes habit. Thus 5 means Habit. If you take 2 nd hint, 9 is common between 59 and 839 and the common word is injurious, thus 9 means injurious. Thus you can use either of these two statements to answer.
142. WHAT IS THE PUNCHLINE OF BANK OF INDIA RELATIONSHIP BEYOND BANKING
143. WHAT IS THE PUNCHLINE OF CITIBANK CITI NEVER SLEEPS
144. WHAT IS THE PUNCHLINE OF KOTAK MAHINDRA BANK LETS MAKE MONEY SIMPLE
145. WHAT IS THE PUNCHLINE OF SBI WITH YOU ALL THE WAY
146. WHAT IS THE PUNCHLINE OF DENA BANK TRUSTED FAMILY BANK
147. WHAT IS THE PUNCHLINE OF INDIA INFOLINE ITS ALL ABOUT MONEY HONEY
148.
149. WHO IS CEO OF KOTAK MAHINDRA BANK ? UDAI KOTAK
170. A, B, C, D, E, and F are a group of friends. There are two housewives, one professor, one engineer, one accountant and one lawyer in the group. There are only two married couples in the group. The lawyer is married to D, who is a housewife. No woman in the group is either an engineer or an accountant. C, the accountant, is married to F, who is a professor. A is married to a housewife. E is not a housewife. What is E's profession? Males :C (accountant), A, (E) Lawyer females : D(housewife),F (professor), (B) Housewife Thus E is a lawyer, as all other professions are occupied.
171. Five women decided to go shopping to The Loot Bikaner. They arrived at the the Loot showroom in the following order: 1. Archana, 2. Chellamma, 3. Dhenuka, 4. Helen, and 5. Shahnaz. Each woman spent at least Rs.1000. Below are some additional facts about how much they spent during their shopping spree. i. The woman who spent Rs. 2234 arrived before the lady who spent Rs. 1193. ii. One woman spent Rs. 1340 and she was not Dhenuka. iii. One woman spent Rs. 1378 more than Chellamma. iv. One woman spent Rs. 2517 and she was not Archana. v. Helen spent more than Dhenuka. vi. Shahnaz spent the largest amount and Chellamma the smallest. Questions : The woman who spent Rs. 1193 & when did she come? A=1340, C = 1193, S=2573, H= 2517,D=2234 1193 is smallest, so it was spent by Chellamma. She is 2 nd to come. Answer
172. Let A and B be two solid spheres such that the surface area of B is 300% higher than the surface area of A. The volume of A is found to be k% lower than the volume of B. The value of k must be
173. solution Surface area of sphere : 4pi*r*r if we assume smaller sphere of R=1 and larger sphere of R=2, then our condition is fulfilled. Now find volume of the two spheres : 4/3*pi*r*r*r so the ratio of the bigger and smaller spheres are : 8:1 thus volume of A is lower by : 7/8*100 = 85% anwer
174. There are 8436 steel balls, each with a radius of 1 centimeter, stacked in a pile, with 1 ball on top, 3 balls in the second layer, 6 in the third layer, 10 in the fourth, and so on. The number of horizontal layers in the pile is Solution : first pile : 1, 2 nd pilw ; 6 3rd pile : let us add the series : 1+3+6+10+15+21+28+36...... there are two series : 1, 1+2, 3+3,6+4 .... ,
175. The 288th term of the series a, b, b, c, c, c, d, d, d, d, e, e, e, e, e, f, f, f, f, f, f.... should be : We can see the series is : 1,3,4, (a is 1, b is 2, c is 3 ,,, so on apply formula of Total of arithematic progression: Tn = n/2(2A+(n-1)d) 288=n/2 (2+nd-d) use options to solve questions earliers.
176. A shopkeeper increases price of an item by 20% and then gives a discount of 20% on new price. What is the net impact ? Let us assume that initial price is 100, new price is 120 now 20% discout is applied from 120 120 -24 = 96 thus we can see that there is a net impact of - 4%. in short : 20% multiplied to 20% gives -4% ans.
177. There are certain words written randomly, can you infer what will come next : A8R L24M X72H ....? Try to find some pattern : A = 1, L = 12, X = 24 next : K numberic : 8 * 3 = 24, now 24*3 = 72, next :216 R = 18, M = 13, H 8, next : C we can say next code : K216C answer
178. We use + for multiply, - for divide, / for subtraction and * for addition. Following BODMAS, what should be the answer : for the following : 3* 5-1/4+2 = answer : 0 2* 3* 4/ 2 – 1 +2+2 = =1 answer 2-2+3-4/ 4 *2 = =- 5.25 answer
179. 20 persons came to a party and each person shook hand with each other person. How many handshakes were there? Start with small number to validate and understand. Suppose there are 4 persons, first will shake hand with 3, second will shake hand with 2, third will shake hand with 1. we have : 3+2+1 = 6. thus we can say : N * (N -1) / 2= 6 similarly here : (20 * (20-1)/ 2 = 190 answer
180. How many zeroes are there when you count from 1 to 100? One each from 10 to 90 : + 2 in 100 = 11 zeros.
181. You take up all those positive numbers which are ending with 2 and are less than 100 and are divisible by 3. How many such numbers are there? 12, 42, 72 thus we have 3 such numbers.
182. We have 0,1,2,3,4 as digits. How many 5 digit numbers can we make out of these. Repeatition is not allowed? For the first number, you have 4 options (zero not be used) : for 2 nd number you have 4 options again (the first number will not be used) , for 3 rd number we have 3 options, so on = 4*4*3*2*1 = 96 answer
183. Raju had to add two digits, but by mistake he multiplied these two digits and got 56. He was again asked to add these two digits, but this time he squared up these numbers and found their difference, it was 15. what will you get if you find the correct answer ? X* Y = 56 X^2 – Y^2 = 15 (x+Y) (X-Y) = 15 now try with options at this stage. Take factors of 56, which are : 2*2*2*7 the factors could be : 4*14 or 8*7 so X = 8 and Y = 7, their difference is 1 and X +Y = 15, so the correct answer is 15. answer .
184. In order to go to his office from home, Vivek goes first to his right then he turns towards left three times. Then he again turns to his right. He has to again turn left 2 times to enter his office, which is North facing. What direction is his house facing? Total left turns : 3 + 2 = 5 total right turns : 1 + 1 = 2 net : 3 left turns. Now from office, he will take net 3 right turns to enter his home. He will be west facing while entering home, so home will be East facing. Answer : east facing.
185. Kapil says that his birthday is after 26 February, but his friend Mayank says that it is before 1 March. His another friend Vivek says that it is between 25 and 28. When is the birth day of Kapil? 27 February. Answer
186. Mayank swims across a river a distance of 200 meters 12 minutes, but he can also swim with the current in water same distance in 5 minutes. What is his speed in still water? Formula = (Distance ) / (Time ) = speed while going accross the river, the speed is : X-Y= a ( 200/12)= 16.66 , where X is Mayank's speed and Y = water's speed while with the water, the speed is X + Y = b (200/5) = 40 the speed of Mayank is average of 40 and 16.66 = 28.33 and the speed of water is (40-16.66)/2 = 11.66 m. Per minute. answer
187. WHO HAS TAKEN HIGHEST NUMBER OF WICKETS IN 1 DAY AND TEST CRICKET? M . MURALIDHARAN OF SRILANKA
194. A,B,C speak one statement true and one false. A says to B : “I am a thief.” 2. “You are a Doctor.” B: “Yes, I am a doctor” “C is a thief.” C adds : 1. “ I am a theif.” “B is a Doctor.” Who is theif ? Let us suppose A's 1 st statemet is right, 2 nd statement is wrong. Thus B's 1 st statement is false and 2 nd right. C's 2 nd statement is false, thus 1 st is correct. Here there are two theifs – A and C. If we assume A's 2 nd statement to be correct, then A is not a theif, and no one is a theif. Thus either no one is theif or A+C both are theives. Logically , NO ONE is theif here.
195. A had to buy some nuts. He buys half the nuts required. He takes them and his son steals half of these. Out of remaining, his daughter steals half. Now when A is fired by his boss that he had brought exactly 70 less than what was required. What is the ratio of nuts brought and to be brought? Suppose he buys 24 nuts instead of 48. his son takes away 12 and his daughter takes away 6 out of the remaining. He finally has 42 less than required. Thus original requirements : 70/42* 48 = 80 thus ratio is : 1:8 answer (you may assume any numbers but answer will be same).
196. A,B,C each deposit Rs. 1000 in a partnership. Out of this A takes away half of his capital after 6 months, B takes away 25% of capital 4 months before the year end. And C doubled his money after 3 months. Out of profit of 82000 how much will A get? A _ (6*1000) + (6*500) = 9000 B= (8*1000) + (750*4) = 11000 c = (3*1000) + (9*2000) = 21000 their profit sharing ratio : 9:11:21 A will get : 9/(9+11+21) * 82000 = 18000 answer.
197. Who is Noble peace prize winner for 2009? Barak Obama
209. HOW MANY CENTURIES HAVE BEEN HIT BY TENDULKAR ? 45 IN ONE DAY 46 TEST MATCHES (46TH AGAINST BANGLADESH ON 21 DECEMBER 2009)
210. Which of these is correct ? a. Having completed his lunch, a dog bit Mohan, who went to market. b. Having completed his lunch, Mohan went to market, where he was bite by a dog. c. Having completed his lunch, Mohan went to market, where he was bitten by a dog. Answer : C.
211. Which of these is correct? 1. although he worked very hard, but he has failed. 2. although he had worked hard, yet he had been failed. 3. although he worked very hard, yet he failed. Answer : 3
212. Which of these is correct? 1. He reached station before the train had reached 2. he had reached the station, where train had reached after him. 3. he had reached the station before the train. Answer : 3.
213. Fill in the blank : I prefer tea _____ coffee options : from, then, than, to, on ANSWER : TO
214.
215.
216. Ram and Shyam had equal money, which they deposited in two different banks. One got 10% simple interest, but the other got 5% half yearly compounding interest. At the end of 2 years, their amounts had difference of Rs. 10, what was the original amount deposited by them? Let us suppose they deposited 100 each. First person will get : 100+10+10 = 120 2 nd person will get : 100 + 5 + 5.25 + 5.5125 + 5.79 or 5.80 = 121.56 the difference is 1.56, if difference is 10, the principal should be : 10/1.56* 100 = 600 by each approx.
217. A shopkeeper uses weight of 900 grams instead of 1000 grams (1kg) while selling. He sells at his cost + 10%, what is his actual profit in %? He sells 900 grams when he is charging for 1000 grams. Suppose he purchased 900 for Rs. 900. His cost is 900, but he is charging for 1000 + 10% = 1100 his profit is 200 on 900, or 200/900 *1000 = 22.2% answer
218. A circle (of maximum size possible) is inserted inside a squre. How much of the area of square is still left out of total area in %? Let us suppose that the side of square is 14. area of square is 14*14 = 196 area of circle : 22/7*7*7 = 154 area left : 196-154 = 42 in % = 42/196 *100 = 21% approx. Answer you can assume any value instead of 14 and try to work out the %, the answer will be the same.
219. Out of the following chart, please, tell how many female students got between 50 - 60% in PGPSE ?
220. Solution... We can see that 12 girls got more than 60% marks. 40 – 12 – 2 = 26 got between 50 to 60%. answer
221. Based on the data given below, find out sale of Raju TV store. 1990 was the first year, when Raju TV sold 100 TV. Every person who buys TV buys again after 4 years. Raju sells 400, 600, 800 TV in 94, 98, 99 respectively. There was no new customer in 2000, but the sale was simple average of sale of 1990 and 1994. How many TV did Raju TV sold in 1996.
222. solution.... Average of 1990 and 1994 = 250 no new customer in 2000, so 250 TV will be sold as repeat customers. Thus sale in 1996 = 250 TV.
223. Ram, Ajay and Ravi (3 friends) are experts in three games – cricket, hockey and golf. One of these live in Delhi, and other two live in Mumbai. The person who lives in Delhi doesnt like Golf. Hockey player lives in Mumbai. The person whose name is smallest is also the best player of Golf. Ajay daily goes to his friend's home. Ravi has to visit Mumbai twice a year. Who plays cricket? Ajay lives in Mumbai (he cant be Delhi, as he daily visits his friend). The person who lives in Delhi doesnt like Golf, he also cant play Hockey (Hockey player is in Mumbai), so that persn plays Cricket. So the person who lives in Delhi plays criciket. Ravi visits Mumbai,so he lives in Delhi. Ravi plays Cricket.
224. Nanu's maternal grand father, and maternal grand mother both are doctors. His father is Engineer, but his mother is Professor. A is elder to C, but Younger to B. D is wife of A. E is husband of B. The eldest person is a male but he is neither A nor Nanu. Out of two ladies, the elder is Doctor and younger is professor. Who is Engineer. Which statement is redudant? A is engineer (as he is the second male in hierarchy). The last statement : out of two ladies, the elder is doctor and younger is professor, is redudant – as it is not required).
225. 118, 66, 252, 137 .... Look at the series, you find that 66 has been computed from 118 as under : 1^3+1^3+8^2 = 66, similarly 6^3 + 6^2 = 252 so : 137 = 1^3 + 3^3 +7^2 = 77 answer
226. What will come next :;;; 1,8,27,64... so on??? 1^3 = 1, 2^3 = 8, 3^3 = 27, 4^3 = 64, 5^3 = 125, thus answer is 125.
227. A went to buy 2 shirts and 1 trousers. He carried Rs. 1000 with him (just sufficient) . The ratio of prices of shirt and trouser is : 7:6. however, he purchased 2 trousers and 1 shirt and returned back with Rs. 50 also. What will he pay, if he buys 2 shirts and 3 trousers? 2 Shirt + 1 Trousers = 1000 1 shirt + 2 trousers = 950 1 shirt – 1 trousers = 50, Now from 1 st equation: 2 trousers + 1 trousers + Rs. 100 = 900 thus 1 trousers = 300 and 1 shirt = 350. he will spend 700+900 = 1600 answer.
228. X has to organise his lecture plan. He has to teach entrepreneurship, Planning, Finance, and Law on 4 days and one day is for IT. IT must be before Law, but Planning should not be on the 1 st day. Finance and IT must be on any of the last 3 days. Prepare complete schedule. Solution: Last day : law, 2 nd last IT, 3 rd last : Finance, 4 th last : Plannning; the first day : Entrepreneurship. It is better to solve the last day first in this types of questions. Answer.
229. A,B,C,D are working on a project with different names. W is not A, B is not Y or Z. D and E have no relation to C and W Who is A? Answer cannot be determined / data inadequate
230. There are two numbers whose HCF and LCM are 8 and 25, what are those numbers? No such numbers are possible as LCM 25 is not divisible by 8, LCM is always divisible by HCF. Answer
231. Mayank Bothra wants to bring tiles for his room. His room's size is 28 feet by 20 feet. What should the size of square tile, so that minimum number of tiles are used? Find HCF of 28 and 20. The HCF is 4, so the size of tile should be 4 feet by 4 feet. The total number of tiles required will be : (28*20)/(4*4) = 35 tiles answer
232. A monkey is trying to climb a Date tree. He climbs 4 feet in 2 minutes, but in the next 1 minute, he slips by 3 feet. When will he reach at the top of this Date tree which is 36 feet high? Actually he travels 1 feet in 3 minutes. He has to travel (36-4) = 32 feet, which will take 32*3 = 96 minutes. Then in the next 2 minutes he will be at the top of the tree. Thus he will take 98 minutes in all.
233. Mayank Bothra buys apples @ 4 for Rs. 3 and sells them @ 3 for Rs. 4. what is his profitability? There are two important numbers 3 and 4, so let us take LCM of 3 and 4, this is 12. let us assume Mayank got 12 apples. He had to pay 9 to buy 12 apples. Now he goes to sell them, he gets Rs. 16 when he sells them. His profit is (16-9) – 7, so his profitability is 7/9 *100 = 77.77% answer
234. Naresh Jain makes payment to a shopkeeper. By mistake the shopkeeper reveses the digits of the amount to be paid and takes Rs. 54 more than what was required. What was the actual payment due? Hit and try for this type of question. Try for 39 and 93. 93-39 = 54. The shopkeeper has taken 93 instead of 39. So the amount due was 39. answer
235. A and B run opposite to an elevator. The ratio of the speed of elevator, A and B is : 1:6:3 Elevator is going up, but A and B are coming down. A takes 1 minute and B takes 2.5 minutes to come down. How much time will they take if elevator was not moving? If elevator is not moving, they will take less time. Look at the speed ratios. A will take 1/6 time less – so he will take 60 seconds – 10 seconds= 50 seconds and B will take 1/3 time less, so he will take : 150 seconds – (150*1/3) = = 100 seconds. Answer. 2.5 minutes = 150 seconds
236. Ajay has to pay to Mayank Rs. 1100 after 1 year. What should he pay now and settle the accounts? Rate of interest is 10% We have to find the present value of 1100 formula of present value is (Amount * 100)/ (100 + rate of interest * no. Of years) = (1100 * 100) / (100 +100) = 1000
237. A, B,C, & D start a game. In the beginning all of them had equal amount. The winner has to collect half the amount of all other players. In the first round C wins. In the 2 nd round B wins and in the 3 rd round B again wins. At this time, their scores are : A : 50, B : 1250, C : 250 D : ? What was the score of each of these in the beginning ? The score of D should be equal to that of A = 50. Now add the score of all of these, we get 1600. Thus each of these should have score of 1600/4 = 400 answer
238. A thief steels a necklace and runs @ 10 Km per hour at 3 pm. After 18 minutes, a policeman starts chasing him @ 15 km per hour. Whenwill the thief be caught? At the speed of 10, the thief would have run 10 *18/60 = 3 Km. So policeman has to chase him for this distance to start : 3 / (15-10) * 1/60 =
239. Mayank Bothra wants to get his room coloured. His room is 10 Ft by 20 Ft. Assuming that colouring costs Rs. 100 per sq. ft., how much will Mayank pay (for four walls), height of walls is 10 feet? The side towards length : 20*10 = 200 the side towards width : 10*10 = 100 total 4 walls (200*2+100*2 )=600 ft. Total payment : 600*100=Rs. 60000 ans.
240. Rishi has put his icecream in a rectangular bowl of 10*20 inch with depth of 5 inch. Now he wants to make a round ball out of this. What will be the diameter of this ball? Total quantity of icecream = 10*20*5 = 1000 cubic inch volume of sphere : = 4/3*pi*radius^3 = 4/3 22/7*r*r*r = 1000 r= cubic root of (21000/88) r= 6.5 approx. Or diameter= 13 inch approx. Answer
241. In a typcial coding exercise, a person says that RAM= 32, and SITA= 49, what will be KRISHNA In that code? RAM = R= 18, A=1, M = 13 so adding these RAM = 32 SITA, S=19, I=9, T=20,A=1 Adding these we get 49, so KRISHNA should be : K=11,R=18,I=9,S=19,H=8,N=14,A=1 TOTAL = 80 ANSWER
242. If Earth:Moon, and Sun:mercury, what should be X: Titan The Moon rotates round the Earth, Mercury rotates round the Sun, Titan rotates round the Saturn. So X = Saturn.
243. Rishi has a white cube of 5 inch dimensions. He cuts it to make smaller cubes of 1 inch each. Before this he dips the cube to colour one of its dimension as red. Now how many cubes will have red as a colour on one side? The cube is cut into dimension of 1 inch each. Thus (5*5*5)/(1*1*1) = 125 thus we have now total 125 small cubes. Out of these 125, 25 cubes are such which have one dimension as red.
244. A group leader puts his group in rows and columns. He finds that the number of rows and columns are equal. He finds that 20 more persons have to come. If he puts these 20 persons, there is one more complete row or one more column. What is the number of persons in his group? It is clear that there are 20 rows and 20 columns, so total number of persons is 400. add 20 more persons to it, you get : 20*20 = 400 + 20 = 420 answer
245. Mayank has some money in his pocket. He gives me half of this. Now he spends 75% of the remaining on purchasing a shoe. He then realises that he has to buy a T shirt also. So he spends 80% of the remaining on a T-shirt. He is now thirsty and so spends 20% on a mineral water bottle. He is left with Rs. 40. How much did he have in the beginning? Start from last, multiply each value by 100/ (100-what % is spent) : 40*100/80 = 50 50*100/20 = 250 250*100/25 = 1000 1000*100/50 = 2000 thus he had 2000 in the beginning
246. Mayank Bothra has prepared a software, which puts the letters in alphabetic order, but one at a time in 1 second. How much time will the software take to put T I G E R in ascending or descending order? T I G E R first of all E will be put in the beginning then G will be put after E. Then I will be put after G and then R will be put before T. Total time : 4 seconds. In descending order : 1 second only (as only R has to be put after T)
247. What is BODMAS? B= BRACKET O = OF D=DIVISION M=MULTIPLY A = ADDITION S=SUBTRACT apply these in this sequence only. So 9+9/9-2*1of (2-3*1/3) = 9+1-2= 8
248. Which is bigger : 12/13 14/16 16/19 23/29 let us compare 12/13 and 14/16, logically 12/13 should be bigger (gap between 13 and 12 is only 1). still : cross multiply : 12*16 and 13*14 , which is bigger? = 12*16 is bigger so 12/13 is bigger. Similarly we have to compare all the values and find the biggest number.
249. What will come next in the series : ANW, DKT, GFQ, ....? The series is : A – D – G so next digit should be : J (gap of + 2) next series is : N-K-F so next : Y (increasing gap -2,-4,-6) next series : W-T-Q = N (gap of -2) so answer : JYN answer
250. A goes from X to Y at 10 am and will reach at 12 and B goes from Y to X at 9 and will reach at 12. when will they cross each other? A travels for 2hours, B for 3 hours. Let us assume that the distance is (2*3) = 6 KM. A travels @ 3 KM per hour and B @ 2 km per hour. At 9 B starts, till 10 he covers 2 KM. Now gap between A and B is 4 Km. Divide 4 by (2+3) = 4/5 = .8 , so they will meet at 10 + (.8 * 60) = 48 minutes. So They wil meet at 10 + 48 min. Ans
251. A puts an item at 10% discount, before doing this he had actually increased the marked price by 10%, what is the change in his revenue? Let us assume that the earlier marked price is 100. add 10% = 110, now A reduces it by 10% (10% discount on marked price) so he gets 110-11 = 99 thus there is 1% reduction in his revenue or (10% * 10% = 1%)
252. A takes up 2 types of rice – one at 10 per kg and another at 50 per kg, how should he mix these to get a profit of 20% when he sells them @ 30 per KG? Sale price is 30, so cost should be 30*100/120 = 25 in order to get the ratio of mixture, let us deduct 25 from 10 and 50, we get : 15 and 25, now reverse these ratio : 25:15 or 5:3, thus rice of the rate 10 should be 5/(5+3) = 5/8 and rice of rate 50 should be 3/8 or their ratio should be 5:3 answer.
253. A and B are partners and share profit in the capital ratio of 3:2, however, A withdraws his half of the money after 5 months, and B doubles his money after 8 months, what is the final profit sharing ratio? For first six months, the capitals are in the ratio of 3:2, but now there is some change. A withdraws 1.5 and after 2 more months, B adds 2 more. Thus (3*6months + 1.5*6months) : (2*8 months + 4*4months) 27: 32 answer
254. A:B = 2:3, C:D = 3:4, B:D = 3:2, what is A:C? In A:B and B:D, we have B common, so A:B:D = 2:3:2 We know that C:D is 3:4, so keep the value of D as 4, thus new ratio is : A:B:C:D = 4:6:3:4 thus A:C = 4:3 answer
255. A can complete a work in 20 days and B can do the same work in 30 days. Both work together for 1 day and get 500 as total amount, how should this money be divided between A and B? A: B should be 30:20 (reverse of 20:30 – the number of days taken by them in doing the work). Thus A should get : 300 and B 200 answer.
256. A,B,C start a work together. A can do it alone in 20, B in 30 and C in 40 days, in how many days will they finish the work? A's one day work : 1/20, B's one day's work : 1/30 and C's one day's work : 1/40, add them : 1/20 + 1/30 + 1/40 (6+4+3)/120 = 13/120 , now reverse it : 120/13 = 9.2 days or 10 days approx.
257. There are 720 students in an examination, out of them, 1/3 rd fail in English, 1/4 th fail in Mathematics, 1/8 th fail in both the paper. How many dont fail in any paper? Out of 720, 240 fail in English, and 180 fail in Mathematics and 90 fail in both the paper. Thus the total number of students who have failed in either paper : 240+180 – 90 = 330 thus the students who have not failed in any paper is : 720 – 330 = 390 answer
258. Kapil is 4 th from top and 106 th from bottom. How many students are there in total ? There are three students before Kapil, 105 below him and he himself so : 3+105+1 = 109 or 4+106 – 1 = 109 answer
259. A and B have salary in the ratio of 10:11, but their savings are in the ratio : 3:7, but now their salaries increase by 100% each. If earlier their total savings was Rs. 2100, what is their new savings, if they dont change their expenditure and they spend equal amounts? Their total savings : 2100, so A saves 3/10 *2100 = 630 and B saves : 7/10 * 2100 = 1470 difference of their savings is : 840, so A should earn 840 *10 = 8400 and spend (8400-630) = 7770 and B should earn 9240 and save (9240-1470) = 7770. thus their new incomes are : 16800 and 18480 and new savings are : (16800 – 7770) = 9030 and (18480-7770) = 10710 answer
260. A and B run a race and A gives B a start of 100 meters in 1000 meter race, still A wins by 1 second or 1 meters. What is the ratio of their speeds? B takes 1 second to cover 1 meters, so his speed is 3600 meters per KM or 3.6 km per hour. He has actually run 900 meters only. He should take 900/3600*60 = 15 minutes A has run 1000 meters in 14 minutes and 59 seconds. So his speed is 40 KM per hour approx. Thus the ratio of their speed is 40:36 or 10:9 answer
261. What is 10% of 30% of 1500? 30% of 1500 = 450 now 10% of 450 = 45 so answer is 45
262. Which is more 3^1/3 or 4^1/4? Let us take the two powers : 1/3 and 1/4, let us now get same powers. LCM of 3,4 is 12, so let us multiply them by 4/4 and 3/3, we get : 4/12 and 3/12. we can now solve the numerator powers : so answer is : 81^1/12 and 64^1/12 now we can see that 81^1/12 is bigger, so the answer is 3^1/3 is bigger than 4^1/4
263. Ravi sees a photo and says that “this is the photo of younger son of the brother of the grandson of the father of the brother of the mother of my sister”, whose photo was it? Answer : This is the photo of nephew of Ravi (son of Ravi's cousin) answer In order to solve such questions, start from last, and try to solve each relationship in simple terms or prepare a tree diagram from these statements. For example, : brother of the mother of my sister = maternal uncle – so similarly replace all these sentences.
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