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apexjaipur
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dy = -2.4 .pdf
dy = -2.4 Solution dy = -2.4.
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dy = -2.4 .pdf
1.
dy = -2.4 Solution dy
= -2.4
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![[PDF]Solution [PDF].pdf](https://cdn.slidesharecdn.com/ss_thumbnails/pdfsolutionpdf-230412010219-eebd3c96-thumbnail.jpg?width=640&height=640&fit=bounds)
![pOH = -log[OH-] = -log(0.061) = 1.21 pH = 14 - pO.pdf](https://cdn.slidesharecdn.com/ss_thumbnails/poh-logoh-log0-230412010218-75361cc2-thumbnail.jpg?width=640&height=640&fit=bounds)
