Online storefront creation: A business creates an online storefront, which serves as its virtual shop where customers can browse products or services, place orders, and make payments.
Product listing: The business lists its products or services on the online storefront, along with relevant information such as price, product description, and images.
Payment gateway integration: The business integrates a payment gateway into its online storefront, which allows customers to securely make payments online using credit cards, debit cards, or other payment methods.
Order processing: When a customer places an order, the business receives the order information through the online storefront. The business then processes the order, which may involve verifying the availability of the product, preparing the product for shipping, and generating a shipping label.
Shipping and delivery: The business ships the product to the customer's address using a third-party logistics provider or its own delivery service. The customer is provided with tracking information to monitor the status of the shipment.
Customer service: The business provides customer service to address any issues or concerns that the customer may have regarding the product or service.
Example:
Let's take the example of a clothing store that sells its products online through its e-commerce website. The store creates an online storefront and lists its products, which include dresses, shirts, pants, and accessories. Customers can browse the products, select the items they wish to purchase, and make payments online using a payment gateway such as PayPal or Stripe.
Once the order is received, the store processes the order and prepares the product for shipping. The product is then shipped to the customer's address using a logistics provider such as FedEx or UPS. The customer can track the shipment using the tracking information provided by the store.
If the customer is not satisfied with the product, they can contact the store's customer service and initiate a return or exchange. The store handles the return or exchange process and ensures that the customer is satisfied with their purchase.
The following code is an implementation of the producer consumer pro.pdfmarketing413921
The following code is an implementation of the producer consumer problem using a software
locking mechanism. Your tasks here require you to debug the code with the intent of achieving
the following tasks:
Task 1: Identifying the critical section
Task 2: Identify the software locks and replace them with a simplified mutex lock and unlock.
HINT: The code provided relies heavily on the in and out pointers of the buffer. You should
make the code run on a single count variable.
#include
#include
#include
#include
#define MAXSIZE 100
#define ITERATIONS 1000
int buffer[MAXSIZE]; // buffer
int nextp, nextc; // temporary storage
int count=0;
void printfunction(void * ptr)
{
int count = *(int *) ptr;
if (count==0)
{
printf(\"All items produced are consumed by the consumer \ \");
}
else
{
for (int i=0; i<=count; i=i+1)
{
printf(\"%d, \\t\",buffer[i]);
}
printf(\"\ \");
}
}
void *producer(void *ptr)
{
int item, flag=0;
int in = *(int *) ptr;
do
{
item = (rand()%7)%10;
flag=flag+1;
nextp=item;
buffer[in]=nextp;
in=((in+1)%MAXSIZE);
while(count <= MAXSIZE)
{
count=count+1;
printf(\"Count = %d - incremented at producer\ \", count);
}
} while (flag<=ITERATIONS);
pthread_exit(NULL);
}
void *consumer(void *ptr)
{
int item, flag=ITERATIONS;
int out = *(int *) ptr;
do
{
while (count >0)
{
nextc = buffer[out];
out=(out+1)%MAXSIZE;
printf(\"\\tCount = %d - decremented at consumer\ \", count, flag);
count = count-1;
flag=flag-1;
}
if (count <= 0)
{
printf(\"consumer made to wait...faster than producer.\ \");
}
}while (flag>=0);
pthread_exit(NULL);
}
int main(void)
{
int in=0, out=0; //pointers
pthread_t pro, con;
// Spawn threads
pthread_create(&pro, NULL, producer, &count);
pthread_create(&con, NULL, consumer, &count);
if (rc1)
{
printf(\"ERROR; return code from pthread_create() is %d\ \", rc1);
exit(-1);
}
if (rc2)
{
printf(\"ERROR; return code from pthread_create() is %d\ \", rc2);
exit(-1);
}
// Wait for the threads to finish
// Otherwise main might run to the end
// and kill the entire process when it exits.
pthread_join(pro, NULL);
pthread_join(con, NULL);
printfunction(&count);
}
Solution
#include
#include
#include
#include
#define MAXSIZE 100
#define ITERATIONS 1000
int buffer[MAXSIZE]; // buffer
int nextp, nextc; // temporary storage
int count=0;
void printfunction(void * ptr)
{
int count = *(int *) ptr;
if (count==0)
{
printf(\"All items produced are consumed by the consumer \ \");
}
else
{
for (int i=0; i<=count; i=i+1)
{
printf(\"%d, \\t\",buffer[i]);
}
printf(\"\ \");
}
}
void *producer(void *ptr)
{
int item, flag=0;
int in = *(int *) ptr;
do
{
item = (rand()%7)%10;
flag=flag+1;
nextp=item;
buffer[in]=nextp;
in=((in+1)%MAXSIZE);
while(count <= MAXSIZE)
{
count=count+1;
printf(\"Count = %d - incremented at producer\ \", count);
}
} while (flag<=ITERATIONS);
pthread_exit(NULL);
}
void *consumer(void *ptr)
{
int item, flag=ITERATIONS;
int out = *(int *) ptr;
do
{
while (count >0)
{
nextc = buffer[out];
out=(out+1)%MAXSIZE;
printf(\"\\tCount = %d - decreme.
Using an Array include ltstdiohgt include ltmpih.pdfgiriraj65
Using an Array:
#include <stdio.h>
#include <mpi.h>
int main(int argc, char** argv) {
int rank, size;
MPI_Init(&argc, &argv);
MPI_Comm_rank(MPI_COMM_WORLD, &rank);
MPI_Comm_size(MPI_COMM_WORLD, &size);
// Define topology
int topology[5][2] = {{1, 4}, {0, 2, 3}, {1,-1}, {0, 4}, {0, 3}};
// Initialize index and edge arrays
int index[5] = {0};
int edges[5][3] = {{0}};
// Add edges into index array
int i =0;
int j =0;
for (i = 0; i < 5; i++)
{
index[i] = sizeof(topology[i]) / sizeof(int);
for (j = 0; j < index[i]; j++)
{
edges[i][j] = topology[i][j];
}
}
// Display topology for each process
for (i = 0; i < size; i++)
{
if (rank == i)
{
printf("Process %d has %d neighbors: ", i, index[i]);
for (j = 0; j < index[i]; j++)
{
printf("%d ", edges[i][j]);
}
printf("n");
}
MPI_Barrier(MPI_COMM_WORLD);
}
MPI_Finalize();
return 0;
}
MPI Functions:
#include <mpi.h>
#include <stdio.h>
int main(int argc, char** argv)
{
int rank, size;
MPI_Init(&argc, &argv); // Initialize MPI
MPI_Comm_rank(MPI_COMM_WORLD, &rank); // Get the rank of the current process
MPI_Comm_size(MPI_COMM_WORLD, &size); // Get the total number of processes
int nnodes = 5; // Number of nodes in the topology
int nedges = 8; // Number of edges in the topolofy
// Index of the first edge for each node
int index[5] = {2, 5, 6, 8, 9};
int edges[9] = {4, 1, 0, 2, 3, 1, 4, 0, 3}; // List of all edges
MPI_Comm graph_comm; // Create a new communicator for the graph topology
MPI_Graph_create(MPI_COMM_WORLD, nnodes, index, edges, 0, &graph_comm); // Create the
graph topology
int count; // Number of neighbors
int* neighbors; // Neighbor Ranks
MPI_Graph_neighbors_count(graph_comm, rank, &count); // Get the number of neighbors for the
current process
neighbors = (int*) malloc(count * sizeof(int)); // Allocate memory for the array of neighbor ranks
MPI_Graph_neighbors(graph_comm, rank, count, neighbors); // Get the neighbor ranks for the
current process
// Display process and the node in the topologies neighbors
printf("Process %d has %d neighbors:", rank, count);
int i;
for (i = 0; i < count; i++)
{
printf(" %d", neighbors[i]); // Print the neighbor ranks
}
printf("n");
MPI_Finalize();
return 0;
}
ive provided my own code above in case that helps or makes it easier on you guys.
My output isnt quite right ive been at it for a while if someone could fix the output and explain it to
me id be very happy :)
4. Use Graph topology to create following one. Once you create your topology, use one process
(e.g., process 0 ) to display the number of neighbors and its neighbors at each node (i.e.,
process). Use following two methods to check your topology. (20 points) i) Use two arrays, index
and edges, to display number of neighbors and its neighbors for each node. ii) Use two functions
in MPI, "MPI Graph neighbors count" and "MPI Graph neighbors". llinn@scholar-fe06: /470 $
mpirun -n 5 ./hmwk5q4-b Process 0 has 2 neighbors: 41 Process 1 has 3 neighbors: 023 Process
2 has 1 neighbors: 1 Process 3 has 2 neighbors: 40.
Online storefront creation: A business creates an online storefront, which serves as its virtual shop where customers can browse products or services, place orders, and make payments.
Product listing: The business lists its products or services on the online storefront, along with relevant information such as price, product description, and images.
Payment gateway integration: The business integrates a payment gateway into its online storefront, which allows customers to securely make payments online using credit cards, debit cards, or other payment methods.
Order processing: When a customer places an order, the business receives the order information through the online storefront. The business then processes the order, which may involve verifying the availability of the product, preparing the product for shipping, and generating a shipping label.
Shipping and delivery: The business ships the product to the customer's address using a third-party logistics provider or its own delivery service. The customer is provided with tracking information to monitor the status of the shipment.
Customer service: The business provides customer service to address any issues or concerns that the customer may have regarding the product or service.
Example:
Let's take the example of a clothing store that sells its products online through its e-commerce website. The store creates an online storefront and lists its products, which include dresses, shirts, pants, and accessories. Customers can browse the products, select the items they wish to purchase, and make payments online using a payment gateway such as PayPal or Stripe.
Once the order is received, the store processes the order and prepares the product for shipping. The product is then shipped to the customer's address using a logistics provider such as FedEx or UPS. The customer can track the shipment using the tracking information provided by the store.
If the customer is not satisfied with the product, they can contact the store's customer service and initiate a return or exchange. The store handles the return or exchange process and ensures that the customer is satisfied with their purchase.
The following code is an implementation of the producer consumer pro.pdfmarketing413921
The following code is an implementation of the producer consumer problem using a software
locking mechanism. Your tasks here require you to debug the code with the intent of achieving
the following tasks:
Task 1: Identifying the critical section
Task 2: Identify the software locks and replace them with a simplified mutex lock and unlock.
HINT: The code provided relies heavily on the in and out pointers of the buffer. You should
make the code run on a single count variable.
#include
#include
#include
#include
#define MAXSIZE 100
#define ITERATIONS 1000
int buffer[MAXSIZE]; // buffer
int nextp, nextc; // temporary storage
int count=0;
void printfunction(void * ptr)
{
int count = *(int *) ptr;
if (count==0)
{
printf(\"All items produced are consumed by the consumer \ \");
}
else
{
for (int i=0; i<=count; i=i+1)
{
printf(\"%d, \\t\",buffer[i]);
}
printf(\"\ \");
}
}
void *producer(void *ptr)
{
int item, flag=0;
int in = *(int *) ptr;
do
{
item = (rand()%7)%10;
flag=flag+1;
nextp=item;
buffer[in]=nextp;
in=((in+1)%MAXSIZE);
while(count <= MAXSIZE)
{
count=count+1;
printf(\"Count = %d - incremented at producer\ \", count);
}
} while (flag<=ITERATIONS);
pthread_exit(NULL);
}
void *consumer(void *ptr)
{
int item, flag=ITERATIONS;
int out = *(int *) ptr;
do
{
while (count >0)
{
nextc = buffer[out];
out=(out+1)%MAXSIZE;
printf(\"\\tCount = %d - decremented at consumer\ \", count, flag);
count = count-1;
flag=flag-1;
}
if (count <= 0)
{
printf(\"consumer made to wait...faster than producer.\ \");
}
}while (flag>=0);
pthread_exit(NULL);
}
int main(void)
{
int in=0, out=0; //pointers
pthread_t pro, con;
// Spawn threads
pthread_create(&pro, NULL, producer, &count);
pthread_create(&con, NULL, consumer, &count);
if (rc1)
{
printf(\"ERROR; return code from pthread_create() is %d\ \", rc1);
exit(-1);
}
if (rc2)
{
printf(\"ERROR; return code from pthread_create() is %d\ \", rc2);
exit(-1);
}
// Wait for the threads to finish
// Otherwise main might run to the end
// and kill the entire process when it exits.
pthread_join(pro, NULL);
pthread_join(con, NULL);
printfunction(&count);
}
Solution
#include
#include
#include
#include
#define MAXSIZE 100
#define ITERATIONS 1000
int buffer[MAXSIZE]; // buffer
int nextp, nextc; // temporary storage
int count=0;
void printfunction(void * ptr)
{
int count = *(int *) ptr;
if (count==0)
{
printf(\"All items produced are consumed by the consumer \ \");
}
else
{
for (int i=0; i<=count; i=i+1)
{
printf(\"%d, \\t\",buffer[i]);
}
printf(\"\ \");
}
}
void *producer(void *ptr)
{
int item, flag=0;
int in = *(int *) ptr;
do
{
item = (rand()%7)%10;
flag=flag+1;
nextp=item;
buffer[in]=nextp;
in=((in+1)%MAXSIZE);
while(count <= MAXSIZE)
{
count=count+1;
printf(\"Count = %d - incremented at producer\ \", count);
}
} while (flag<=ITERATIONS);
pthread_exit(NULL);
}
void *consumer(void *ptr)
{
int item, flag=ITERATIONS;
int out = *(int *) ptr;
do
{
while (count >0)
{
nextc = buffer[out];
out=(out+1)%MAXSIZE;
printf(\"\\tCount = %d - decreme.
Using an Array include ltstdiohgt include ltmpih.pdfgiriraj65
Using an Array:
#include <stdio.h>
#include <mpi.h>
int main(int argc, char** argv) {
int rank, size;
MPI_Init(&argc, &argv);
MPI_Comm_rank(MPI_COMM_WORLD, &rank);
MPI_Comm_size(MPI_COMM_WORLD, &size);
// Define topology
int topology[5][2] = {{1, 4}, {0, 2, 3}, {1,-1}, {0, 4}, {0, 3}};
// Initialize index and edge arrays
int index[5] = {0};
int edges[5][3] = {{0}};
// Add edges into index array
int i =0;
int j =0;
for (i = 0; i < 5; i++)
{
index[i] = sizeof(topology[i]) / sizeof(int);
for (j = 0; j < index[i]; j++)
{
edges[i][j] = topology[i][j];
}
}
// Display topology for each process
for (i = 0; i < size; i++)
{
if (rank == i)
{
printf("Process %d has %d neighbors: ", i, index[i]);
for (j = 0; j < index[i]; j++)
{
printf("%d ", edges[i][j]);
}
printf("n");
}
MPI_Barrier(MPI_COMM_WORLD);
}
MPI_Finalize();
return 0;
}
MPI Functions:
#include <mpi.h>
#include <stdio.h>
int main(int argc, char** argv)
{
int rank, size;
MPI_Init(&argc, &argv); // Initialize MPI
MPI_Comm_rank(MPI_COMM_WORLD, &rank); // Get the rank of the current process
MPI_Comm_size(MPI_COMM_WORLD, &size); // Get the total number of processes
int nnodes = 5; // Number of nodes in the topology
int nedges = 8; // Number of edges in the topolofy
// Index of the first edge for each node
int index[5] = {2, 5, 6, 8, 9};
int edges[9] = {4, 1, 0, 2, 3, 1, 4, 0, 3}; // List of all edges
MPI_Comm graph_comm; // Create a new communicator for the graph topology
MPI_Graph_create(MPI_COMM_WORLD, nnodes, index, edges, 0, &graph_comm); // Create the
graph topology
int count; // Number of neighbors
int* neighbors; // Neighbor Ranks
MPI_Graph_neighbors_count(graph_comm, rank, &count); // Get the number of neighbors for the
current process
neighbors = (int*) malloc(count * sizeof(int)); // Allocate memory for the array of neighbor ranks
MPI_Graph_neighbors(graph_comm, rank, count, neighbors); // Get the neighbor ranks for the
current process
// Display process and the node in the topologies neighbors
printf("Process %d has %d neighbors:", rank, count);
int i;
for (i = 0; i < count; i++)
{
printf(" %d", neighbors[i]); // Print the neighbor ranks
}
printf("n");
MPI_Finalize();
return 0;
}
ive provided my own code above in case that helps or makes it easier on you guys.
My output isnt quite right ive been at it for a while if someone could fix the output and explain it to
me id be very happy :)
4. Use Graph topology to create following one. Once you create your topology, use one process
(e.g., process 0 ) to display the number of neighbors and its neighbors at each node (i.e.,
process). Use following two methods to check your topology. (20 points) i) Use two arrays, index
and edges, to display number of neighbors and its neighbors for each node. ii) Use two functions
in MPI, "MPI Graph neighbors count" and "MPI Graph neighbors". llinn@scholar-fe06: /470 $
mpirun -n 5 ./hmwk5q4-b Process 0 has 2 neighbors: 41 Process 1 has 3 neighbors: 023 Process
2 has 1 neighbors: 1 Process 3 has 2 neighbors: 40.
2. C PROGRAMMING
Type casting :
There are two types of type casting.
1)Inmlicit type casting
2)Explicit type casting
Implicit type casting : it is done by compiler
#include<stdio.h>
int main(){
int x = 10; // integer x
char y = 'a'; // character c
// y implicitly converted to int. ASCII
// value of 'a' is 97
x = x + y;
// x is implicitly converted to float
float z = x + 1.0;
printf("x = %d, z = %f", x, z);
return 0;
3. C PROGRAMMING
Explicit typecasting :
it have to develop by user.
#include<stdio.h>
int main(){
double x = 1.2;
// Explicit conversion from double to int
int sum = (int)x + 1;
printf("sum = %d", sum);
return 0;
}
4. C PROGRAMMING
Dynamic memory allocation :
The concept of dynamic memory allocation in c language enables the C
programmer to allocate memory at runtime. Dynamic memory
allocation in c language is possible by 4 functions of stdlib.h header file.
1)malloc()
2)calloc()
3)realloc()
4)free()
5. C PROGRAMMING
malloc() allocates single block of requested memory.
calloc() allocates multiple block of requested memory.
realloc() reallocates the memory occupied by malloc() or calloc()
functions.
free() frees the dynamically allocated memory.
6. C PROGRAMMING
#include <stdio.h>
#include <stdlib.h>
int main() {
// This pointer will hold the
// base address of the block created
int* ptr;
int n, i;
// Get the number of elements for the array
printf("Enter number of elements:");
scanf("%d",&n);
printf("Entered number of elements: %dn", n);
// Dynamically allocate memory using malloc()
ptr = (int*)malloc(n * sizeof(int));
7. C PROGRAMMING
// Check if the memory has been successfully
// allocated by malloc or not
if (ptr == NULL) {
printf("Memory not allocated.n");
exit(0);}
else {
// Memory has been successfully allocated
printf("Memory successfully allocated using malloc.n");
// Get the elements of the array
for (i = 0; i < n; ++i) {
ptr[i] = i + 1;}
// Print the elements of the array
printf("The elements of the array are: ");
for (i = 0; i < n; ++i) {
printf("%d, ", ptr[i]); }}
return 0; }
8. C PROGRAMMING
Calloc() Example:
#include <stdio.h>
#include <stdlib.h>
int main(){
// This pointer will hold the
// base address of the block created
int* ptr;
int n, i;
// Get the number of elements for the array
n = 5;
printf("Enter number of elements: %dn", n);
// Dynamically allocate memory using calloc()
ptr = (int*)calloc(n, sizeof(int));
9. C PROGRAMMING
// Check if the memory has been successfully
// allocated by calloc or not
if (ptr == NULL) {
printf("Memory not allocated.n");
exit(0);}
else {
// Memory has been successfully allocated
printf("Memory successfully allocated using calloc.n");
// Get the elements of the array
for (i = 0; i < n; ++i) {
ptr[i] = i + 1;}
// Print the elements of the array
printf("The elements of the array are: ");
for (i = 0; i < n; ++i) {
printf("%d, ", ptr[i]);}}
return 0;}
10. C PROGRAMMING
Example : Realloc
#include <stdio.h>
#include <stdlib.h>
int main(){
// This pointer will hold the
// base address of the block created
int* ptr;
int n, i;
// Get the number of elements for the array
n = 5;
printf("Enter number of elements: %dn", n);
// Dynamically allocate memory using calloc()
ptr = (int*)calloc(n, sizeof(int));
11. // Check if the memory has been successfully
// allocated by malloc or not
if (ptr == NULL) {
printf("Memory not allocated.n");
exit(0);}
else {
// Memory has been successfully allocated
printf("Memory successfully allocated using calloc.n");
// Get the elements of the array
for (i = 0; i < n; ++i) {
ptr[i] = i + 1;}
// Print the elements of the array
printf("The elements of the array are: ");
for (i = 0; i < n; ++i) {
printf("%d, ", ptr[i]);}
12. C PROGRAMMING
// Get the new size for the array
n = 10;
printf("nnEnter the new size of the array: %dn", n);
// Dynamically re-allocate memory using realloc()
ptr = realloc(ptr, n * sizeof(int));
// Memory has been successfully allocated
printf("Memory successfully re-allocated using realloc.n");
// Get the new elements of the array
for (i = 5; i < n; ++i) {
ptr[i] = i + 1;
}
13. C PROGRAMMING
// Print the elements of the array
printf("The elements of the array are: ");
for (i = 0; i < n; ++i) {
printf("%d, ", ptr[i]);
}
free(ptr);
}
return 0;
}