Composition Stoichiometry

     Percent Composition
              &
      Chemical Formulas
• Law of Definite Proportions
  – In samples of any chemical compound, the masses of
    the elements are always in the same proportions.
  – Compares the different elements in a single
    compound
  – H2O
     • mass of H : mass of O is always the same
• Law of Multiple Proportions
  – Whenever the same two elements form more than
    one compound, the different masses of one element
    that combine with the same mass of the other element
    are in the ratio of small whole numbers
  – Compares the same elements found in different
    compounds
  – H2O and H2O2
     • Mass of O in H2O : mass of O in H2O2 = small whole number
Percent Composition
• Percent composition
  – Percent by mass of each element in the
    compound
  – Always the same for a given compound
Percent Composition from Mass
             Data
• The number of grams of the element
  divided by the mass in grams of the
  compound

                   mass of element
% mass of element                  100
                  mass of compound
When a 13.60-g sample of a compound containing only
 magnesium and oxygen is decomposed, 5.40 g of oxygen
 is obtained. What is the percent composition of this
 compound?
Mass of oxygen = 5.40 g
Mass of magnesium = 13.60 g – 5.40 g = 8.20 g
Mass of compound = 13.60 g

         mass of Mg         8.20g
%Mg                     100        100 60.3% Mg
       mass of compound     13.60g

         mass of O          5.40g
%O                     100        100 39.7% O
      mass of compound     13.60g
Percent Composition from
         Chemical Formula
 • Number of grams of element in 1 mole of
   compound divided by the molar mass of
   the compound times 100


       mass of elementin 1 molof compound
% mass                                    100
             molarmass of compound
Calculate the percent composition of propane (C3H8).



C:     3       x      12.0g   =     36.0g / 44.0 X 100 = 81.8%C
H:     8       x      1.0g    =      8.0g / 44.0 X 100 = 18.2%H
                                    44.0g



 Number of
   atoms of
element from
   formula                            Molar mass of
                   Molar mass of       compound
                   element from
                   periodic table
• Hydrates
  – A compound that has a specific number of
    water molecules bound to each formula unit
  – When writing the formula, use a dot to
    connect the formula of the compound and the
    number of water molecules per formula unit
    • CuSO4 5H2O
  – When naming a hydrate, name the compound
    then use a prefix followed by the word
    “hydrate” to indicate the number of water
    molecules per formula unit
    • Copper(II) sulfate pentahydrate
• Finding the percent of water in a hydrate




              mass of water
% H 2O                        100
              mass of hydrate
Calculate the percent by mass of water in washing
  soda, sodium carbonate decahydrate.

Formula of compound = Na2CO3 10 H2O
Na : 2      23.0g      46.0g
C   : 1     12.0g      12.0g
O : 3       16.0g      48.0g
H 2O :10    18.0g      180.g 286g 100 62.9%H 2O
           T otal      286g

Composition stoichiometry

  • 1.
    Composition Stoichiometry Percent Composition & Chemical Formulas
  • 2.
    • Law ofDefinite Proportions – In samples of any chemical compound, the masses of the elements are always in the same proportions. – Compares the different elements in a single compound – H2O • mass of H : mass of O is always the same • Law of Multiple Proportions – Whenever the same two elements form more than one compound, the different masses of one element that combine with the same mass of the other element are in the ratio of small whole numbers – Compares the same elements found in different compounds – H2O and H2O2 • Mass of O in H2O : mass of O in H2O2 = small whole number
  • 3.
    Percent Composition • Percentcomposition – Percent by mass of each element in the compound – Always the same for a given compound
  • 4.
    Percent Composition fromMass Data • The number of grams of the element divided by the mass in grams of the compound mass of element % mass of element 100 mass of compound
  • 5.
    When a 13.60-gsample of a compound containing only magnesium and oxygen is decomposed, 5.40 g of oxygen is obtained. What is the percent composition of this compound? Mass of oxygen = 5.40 g Mass of magnesium = 13.60 g – 5.40 g = 8.20 g Mass of compound = 13.60 g mass of Mg 8.20g %Mg 100 100 60.3% Mg mass of compound 13.60g mass of O 5.40g %O 100 100 39.7% O mass of compound 13.60g
  • 6.
    Percent Composition from Chemical Formula • Number of grams of element in 1 mole of compound divided by the molar mass of the compound times 100 mass of elementin 1 molof compound % mass 100 molarmass of compound
  • 7.
    Calculate the percentcomposition of propane (C3H8). C: 3 x 12.0g = 36.0g / 44.0 X 100 = 81.8%C H: 8 x 1.0g = 8.0g / 44.0 X 100 = 18.2%H 44.0g Number of atoms of element from formula Molar mass of Molar mass of compound element from periodic table
  • 8.
    • Hydrates – A compound that has a specific number of water molecules bound to each formula unit – When writing the formula, use a dot to connect the formula of the compound and the number of water molecules per formula unit • CuSO4 5H2O – When naming a hydrate, name the compound then use a prefix followed by the word “hydrate” to indicate the number of water molecules per formula unit • Copper(II) sulfate pentahydrate
  • 9.
    • Finding thepercent of water in a hydrate mass of water % H 2O 100 mass of hydrate
  • 10.
    Calculate the percentby mass of water in washing soda, sodium carbonate decahydrate. Formula of compound = Na2CO3 10 H2O Na : 2 23.0g 46.0g C : 1 12.0g 12.0g O : 3 16.0g 48.0g H 2O :10 18.0g 180.g 286g 100 62.9%H 2O T otal 286g