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Exercice 12
              a b
    (a)           = ad − bc
              c d

              c d
          −       = −[cb − ad] = ad − bc
              a b
          a b   a b    a   b
    (b)       +     =
          c d   e f   c+e d+f

                      ad − bc + af − be = a(d + f ) − b(c + e)
                                        = ad + af − bc − be

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Ch11 12

  • 1. Exercice 12 a b (a) = ad − bc c d c d − = −[cb − ad] = ad − bc a b a b a b a b (b) + = c d e f c+e d+f ad − bc + af − be = a(d + f ) − b(c + e) = ad + af − bc − be