Peso del tablero
119 cm
179 cm
6 cm
V=a.b.c=(179cm)(6cm)(119cm)
V=0.13𝑚3
W=ρVg=(1200
𝑘𝑔
𝑚3
)( 13𝑚3)(9.8
𝑚
𝑠2
)
W=1502.99N
Barras de 115 cm y 30.5 cm
Espesoresde lasbarras =4.3 cm
115 cm
a
119 cm
30.5 cm b
cos 𝛼 =
1152 + 1192 − 30.52
2(115)(119)
α= 14.85 grados
cos 𝛼=
𝑎
115
b=119-111.16
a= 111.16 cm b=7.84cm
Barra e 115 cm
V=a.b.c=(115cm)(4.3cm)(111.16cm)
V=0.05𝑚3
W=ρVg=(1200
𝑘𝑔
𝑚3
)( 0.05𝑚3)(9.8
𝑚
𝑠2
)= 646.43 N
Barra de 30.5cm
V=a.b.c=(30.5cm)(4.3cm)(7.84cm)
V=1.03 + 10−3 𝑚3
W=ρVg=(1200
𝑘𝑔
𝑚3
)( 1.03 + 10−3 𝑚3)(9.8
𝑚
𝑠2
)=12.09 N
Barras de 94 cm y 48 cm
Espesoresde lasbarras =4.3cm
94 cm
c
119 cm
d
48 cm
cos 𝛼 =
942 + 1192 − 482
2(94)(119)
α= 22.33 grados
cos 𝛼=
𝑐
115
d=119-86.94
c= 86.94 cm d=32.05 cm
Barra de 94cm
V=a.b.c=(94cm)(4.3cm)(86.94cm)
V=0.04𝑚3
W=ρVg=(1200
𝑘𝑔
𝑚3
)( 0.04𝑚3)(9.8
𝑚
𝑠2
)= 413.26 N
Barra de 48cm
V=a.b.c=(48cm)(4.3cm)(32.05cm)
V=6.61 + 10−3 𝑚3
W=ρVg=(1200
𝑘𝑔
𝑚3
)( 6.61 + 10−3 𝑚3)(9.8
𝑚
𝑠2
)=77.79 N

Calculos de mecanucas de solidos

  • 1.
    Peso del tablero 119cm 179 cm 6 cm V=a.b.c=(179cm)(6cm)(119cm) V=0.13𝑚3 W=ρVg=(1200 𝑘𝑔 𝑚3 )( 13𝑚3)(9.8 𝑚 𝑠2 ) W=1502.99N Barras de 115 cm y 30.5 cm Espesoresde lasbarras =4.3 cm 115 cm a 119 cm 30.5 cm b cos 𝛼 = 1152 + 1192 − 30.52 2(115)(119) α= 14.85 grados cos 𝛼= 𝑎 115 b=119-111.16 a= 111.16 cm b=7.84cm Barra e 115 cm V=a.b.c=(115cm)(4.3cm)(111.16cm) V=0.05𝑚3 W=ρVg=(1200 𝑘𝑔 𝑚3 )( 0.05𝑚3)(9.8 𝑚 𝑠2 )= 646.43 N
  • 2.
    Barra de 30.5cm V=a.b.c=(30.5cm)(4.3cm)(7.84cm) V=1.03+ 10−3 𝑚3 W=ρVg=(1200 𝑘𝑔 𝑚3 )( 1.03 + 10−3 𝑚3)(9.8 𝑚 𝑠2 )=12.09 N Barras de 94 cm y 48 cm Espesoresde lasbarras =4.3cm 94 cm c 119 cm d 48 cm cos 𝛼 = 942 + 1192 − 482 2(94)(119) α= 22.33 grados cos 𝛼= 𝑐 115 d=119-86.94 c= 86.94 cm d=32.05 cm Barra de 94cm V=a.b.c=(94cm)(4.3cm)(86.94cm) V=0.04𝑚3 W=ρVg=(1200 𝑘𝑔 𝑚3 )( 0.04𝑚3)(9.8 𝑚 𝑠2 )= 413.26 N Barra de 48cm V=a.b.c=(48cm)(4.3cm)(32.05cm) V=6.61 + 10−3 𝑚3 W=ρVg=(1200 𝑘𝑔 𝑚3 )( 6.61 + 10−3 𝑚3)(9.8 𝑚 𝑠2 )=77.79 N