The document describes a mass attached to a spring that oscillates around its equilibrium point at x=0. It provides statements about the velocity and spring force at different points in the oscillation cycle and identifies which statements are correct. Specifically: - The velocity of the mass is greatest at x=0 when oscillating, as the spring force decreases as the mass approaches equilibrium, causing an acceleration. - The spring force is zero at x=0, as the mass passes through equilibrium the direction of the spring force changes. - The spring force decreases as the mass approaches x=0, as the stretch in the spring decreases according to Hooke's Law.

1. Learning Object 1
Sharon Kay 32052136 LE2
Question:
A massis attachedto a springand whenat restisat positionx=0(the equilibriumpoint).Whichof the
followingstatementsare correct?
A) The velocityof the massis greatestat the midwaypoint betweenx=0andx max (the amplitude)
B) The velocityof the massis greatestat x max (the amplitude).
C) The velocityof the massis greatestat x=0 whenoscillating.
D) The velocityof the massis notinfluencedbythe distance of the massrelativetoitsequilibrium
point.
E) The springforce is zeroat x=0.
F) The springforce decreasesasthe massapproachesx max.
G) The springforce decreasesasthe massapproachesx=0.
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Solutionon next page

2. Solution:
C,E,G
C) The springforce decreasesasthe blockreachesequilibrium(x=0) sothere islessopposingforce to
the motionof the mass,which causesan accelerationinthe block.
E) Asthe masspassesthroughits equilibrium, the springforce changesdirection.Atthisinstantof
change in force directionthere issaidtobe no springforce.
G) As the massapproachesx=0, the stretch inthe springdecreasesaswell asthe springforce.Thiscan
be explainedwithHooke’sLaw:Springforce =-k (x)