1. 2.3 Evaluating Expressions
Page 100 # 5, 6cd, 8, 10, 12-14
5.) a. 24 b. c. d.
6.) c. -3 + 3 · (5 + 11) = 45 d. 25 – (5 + 4 · 5) = 0
8.) She added first
10.) a. 32 b. 0 c. 0 d. 5 e. 60 f. -4
12.)C
13.) a. 0 b. 0 c. 0 d. 0 e. 0
f. The answer to all cases is 0. There is no sixth case because the only way for the
product to be 0 is for one of the differences in parentheses to be 0, and all such cases are
represented.
14.) a. 3, 3 b. 6, 6 c. 12, 12 d. 1, 2, 3, 4, 5