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8.3 notes                                                 December 21, 2012




            8.3 Combinations

            In permutations, order is important.
            Questions involving arrangements of  letters, digits, 
            or people in positions are always permutation questions.

            Sometimes we wish to just find how many ways to
            "choose" objects without arranging them.

            Look at the difference between the next 2 examples.




                                May 3­1:44 PM

                                                                              1
8.3 notes                                                          December 21, 2012




            Example 1) How many ways can you choose a student council
               of President, Vice­President, Secretary, and Treasurer out of
               9 candidates?




            Example 2) How many ways can I choose a committee of 4 people
                 out of 9 people?
            In this example the choice of Tom, Joe, Sue, Betty is 
            no different that Joe, Betty, Tom, Sue. 
            How many ways can you arrange the SAME 4 people?
            Therefore we modify the Permutation formula to produce the 
            answer to this COMBINATION question.




                                      May 3­1:47 PM

                                                                                       2
8.3 notes                                               December 21, 2012




            If order does NOT matter, then we have a 
            COMBINATION.
            The formula for combinations is:

            n   Cr =


                The r! in the denominator is the arrangements
                of the identical items which is no longer 
                important.




                                May 3­1:56 PM

                                                                            3
8.3 notes                                        December 21, 2012




       Calculate the following (without a calculator):

       8    C2  =         8   C6  = 


       7    C3   =        7   C4  =


       What do you notice? This should make sense
       when you look at the formula.




                               May 3­1:59 PM

                                                                     4
8.3 notes                                                December 21, 2012




            Therefore, what would    14 C3      equal?
                                    14   C11




                                    May 3­2:01 PM

                                                                             5
8.3 notes                                     December 21, 2012




             Combination Question Practice:
      1)




        2)




                              May 3­2:10 PM

                                                                  6
8.3 notes                    December 21, 2012




            Dec 21­1:07 PM

                                                 7
8.3 notes                    December 21, 2012




            Dec 21­1:08 PM

                                                 8
8.3 notes                                          December 21, 2012




            FINAL THOUGHT: Should it be called a
                  COMBINATION LOCK ???




            HOMEWORK:
            Supplementary sheet, next page.
            Page 727 #4,5a)c), 9, 10, 13,
              14, 15a)c)
              mult. ch. #1,3.




                              May 3­2:20 PM

                                                                       9

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8.3 combinations 21st december 2012

  • 1. 8.3 notes December 21, 2012 8.3 Combinations In permutations, order is important. Questions involving arrangements of  letters, digits,  or people in positions are always permutation questions. Sometimes we wish to just find how many ways to "choose" objects without arranging them. Look at the difference between the next 2 examples. May 3­1:44 PM 1
  • 2. 8.3 notes December 21, 2012 Example 1) How many ways can you choose a student council    of President, Vice­President, Secretary, and Treasurer out of    9 candidates? Example 2) How many ways can I choose a committee of 4 people out of 9 people? In this example the choice of Tom, Joe, Sue, Betty is  no different that Joe, Betty, Tom, Sue.  How many ways can you arrange the SAME 4 people? Therefore we modify the Permutation formula to produce the  answer to this COMBINATION question. May 3­1:47 PM 2
  • 3. 8.3 notes December 21, 2012 If order does NOT matter, then we have a  COMBINATION. The formula for combinations is: n Cr = The r! in the denominator is the arrangements of the identical items which is no longer  important. May 3­1:56 PM 3
  • 4. 8.3 notes December 21, 2012 Calculate the following (without a calculator): 8 C2  = 8 C6  =  7 C3   = 7 C4  = What do you notice? This should make sense when you look at the formula. May 3­1:59 PM 4
  • 5. 8.3 notes December 21, 2012 Therefore, what would    14 C3      equal? 14 C11 May 3­2:01 PM 5
  • 6. 8.3 notes December 21, 2012 Combination Question Practice: 1) 2) May 3­2:10 PM 6
  • 7. 8.3 notes December 21, 2012 Dec 21­1:07 PM 7
  • 8. 8.3 notes December 21, 2012 Dec 21­1:08 PM 8
  • 9. 8.3 notes December 21, 2012 FINAL THOUGHT: Should it be called a COMBINATION LOCK ??? HOMEWORK: Supplementary sheet, next page. Page 727 #4,5a)c), 9, 10, 13, 14, 15a)c) mult. ch. #1,3. May 3­2:20 PM 9