saad from university of arid agricultural Rawalpindi, student of M.B.A.

3.  A data has been collected with the help of questionnaire from the students of
different age, group at university of arid agriculture.
 The questionnaire has been divided into two sections, which indicate the gender,
course, CGPA and interest of the students.
 The accumulative response is positive which shows that it is a good.

4. Q:1 Would you like to try such products?
Q:2 Would you buy such products if you happened to see it in a store?
Q:3 Would you actively seek out such products in a store in order to purchase it?
Q:4 I would favor such Marketing Campaign?
Q:5 It is good Marketing Campaign?
Q:6 Such Marketing Campaigns are beneficial for society?
Q:7 This marketing campaign has attractive contents?
Q:8 This marketing campaign has excellent execution?
Q:9 I like this campaign?

5.  Frequency Distribution
 Cumulative frequency distribution
 Graphical representation of data
 Measure of central tendency
• Mean
• Median
• Mode
• Percentile
• Quartile
 Measure of dispersion:
• Range
• Variance
• Standard Deviation
• Co-efficient of variance
 Relative Measure
• Z-Score
• Outlier

6. Q:1 Would you like to try such products?
Would you like to try such products?
Classes
Frequency Relative
frequency
Percent
frequency
Cumulative
Frequency
Cumulative
Percent
Strongly
Disagree
3 0.06 6.0
3
6.0
Disagree 11 0.22 22.0 14 28.0
Neutral 13 0.26 26.0 27 54.0
Agree 17 0.34 34.0 44 88.0
Strongly
Agree
6 0.12 12.0
50
100.0
Total 50 1.0 100.0
•Frequency distribution :
Cross Tabulation With respect to class:
Would you like to try such products? * Class Crosstabulation
Questions
Class Total
BBA MBA MS MDM OTHERS
Strongly Disagree 0 3 0 0 0 3
Disagree 0 6 2 3 0 11
Neutral 2 5 1 2 3 13
Agree 0 15 0 2 0 17
Strongly Agree 0 4 0 2 0 6
Total 2 33 3 9 3 50

7. Bar Graph and Pie chart:
Histogram and Dot plot:

8. Interpretation:
In the above we analyze the 50 student about their class who gave the opinion about the “Would you like to try such
products” in it we collect the data from MBA, MDM, BBA, MS and Others And conclude that many student like the product.
Particulars Formulas Analysis
Mean 3.2400
Median Middle Value or Average middle Value 3.00
Mode Most Repeated Value 4.00
Percentile(m=64) 4.00
Quartile
Q1
Q2
Q3
25%
50%
75%
2.00
3.00
4.00
Five Number summary Minimum value
Q1
Q2
Q3
Maximum Value
1.00
2.00
3.00
4.00
5.00
Range range = xmaximum – xminimum
4.00
Variance 1.247
Standard Deviation 1.1168
Co-efficient of Variance 34.50%
Z-score Give the below in the table
Outlier Analyze With the Help of Z-Score There is no outlier in the given
output

9. -.21489 -.21489 -2.0056 1.57587 .68049
-.21489 -.21489 .68049 .68049 -1.11027
-.21489 .68049 -.21489 -.21489 -.21489
-.21489 -2.00565 1.57587 .68049 -1.11027
-.21489 -1.11027 -1.11027 -.21489 1.57587
-.21489 .68049 .68049 .68049 1.57587
-1.11027 .68049 .68049 .68049 -1.11027
.68049 1.57587 .68049 -1.11027 .68049
-1.1102 -1.11027 -2.00565 .68049 -.21489
-1.11027 .68049 1.57587 .68049 -1.11027

10. In the above we describe the opinion of the Student from which we collect the information about the
“Would you like to try such products?” In the tabular and graphical form.
Now we go our next Question which is
Q:2 Would you buy such products if you happened to see it in a store?
Frequency Distribution :
Would you buy such products if you happened to see it in a store?
Frequency
Relative
Frequency
Percent
frequency
Cumulative
Frequency
Cumulative
percent
Strongly Disagree 1 0.02 2 1 2
Disagree 5 0.10 10 6 12
Neutral 16 0.32 32 22 44
Agree 23 0.46 46 45 90
Strongly Agree 5 0.10 10 50 100
Total 50 1.00 100
Cross Tabulation With Respect to Class:
Questions
Class Total
BBA MBA MS MDM OTHERS
Strongly Disagree 0 1 0 0 0 1
Disagree 0 2 1 1 1 5
Neutral 1 11 2 2 0 16
Agree 1 14 0 6 2 23
Strongly Agree 0 5 0 0 0 5
Total 2 33 3 9 3 50

11. Bar Graph and Pie chart:
Histogram and Dot Plot:

12. Interpretation:
In the above we analyze the 50 student about their class who gave the opinion about the “Would you buy such products if you
happened to see it in a store?” in it we collect the data from MBA, MDM, BBA, MS and Others And conclude that many student
like the product.
Particulars Formulas Analysis
Mean 3.5200
Geometric Mean
Harmonic mean
Median Middle Value or Average middle Value 4.00
Mode Most Repeated Value 4.00
Percentile(m=67) 4.00
Quartile
Q1
Q2
Q3
25%
50%
75%
3.00
4.00
4.00
Five Number summary Minimum value
Q1
Q2
Q3
Maximum Value
1.00
3.00
4.00
4.00
5.00
Range range = xmaximum – xminimum
4.00
Variance 0.785
Standard Deviation .8861
Co-efficient of Variance 25.17%
Z-score Give the below in the table
Outlier Analyze With the Help of Z-Score There is no outlier in the
given output

13. -.58679 -.58679 -1.71524 .54165 .54165
-.58679 .54165 1.67010 .54165 .54165
.54165 -2.84368 .54165 -.58679 -1.71524
-1.71524 -.58679 .54165 .54165 -.58679
.54165 .54165 -.58679 .5416 1.67010
.54165 .54165 .54165 .54165 -1.71524
.54165 1.67010 -.58679 -.58679 -.58679
.54165 -.58679 .54165 -.58679 -.58679
-.58679 -.58679 -1.71524 .54165 .54165
-.58679 1.67010 1.67010 .54165 .54165

14. Q:3 Would you actively seek out such products in a store in order to purchase it?
Would you actively seek out such products in a store in order to purchase it?
Question
Frequency Relative
Frequency
Percent
Frequency
Cumulative
Frequency
Cumulative
Percent
Strongly
Disagree
4 0.08 8.0
4
8.0
Disagree 8 0.16 16.0 12 24.0
Neutral 17 0.34 34.0 29 58.0
Agree 13 0.26 26.0 42 84.0
Strongly agree 8 0.16 16.0 50 100.0
Total 50 1.0 100.0
•Frequency Distribution:
Would you actively seek out such products in a store in order to purchase it?
Questions
Class Total
BBA MBA MS MDM OTHERS
Strongly Disagree 0 3 1 0 0 4
Disagree 1 3 1 2 1 8
Neutral 0 14 0 2 1 17
Agree 1 9 0 2 1 13
Strongly agree 0 4 1 3 0 8
Total 2 33 3 9 3 50
•Cross Tabulation:

15. •Bar graph and Pie chart:
•Histogram And Dot Plot:

16. Interpretation:
The above graph and table shown the response of the students about the actively Seek out the goods. In the store or not and we
analyze that Neutral Student are more in it which means they neither interested active seek out the Goods.
Particulars Formulas Analysis
Mean 3.2600
Harmonic mean
Median Middle Value or Average middle Value 3.00
Mode Most Repeated Value 3.00
Percentile(m=67) 3.00
Quartile
Q1
Q2
Q3
25%
50%
75%
2.7500
3.00
4.00
Five Number summary Minimum value
Q1
Q2
Q3
Maximum Value
1.00
2.7500
3.00
4.00
5.00
Range range = xmaximum – xminimum
4.00
Variance 1.399
Standard Deviation 1.1572
Co-efficient of Variance 35.50%
Z-score Give the below in the table
Outlier Analyze With the Help of Z-Score There is no outlier in the
given output

17. 1.42993 -1.31993 .51331 -.40331 -.40331
-1.31993 .51331 -.40331 -.40331 -.40331
.51331 -1.31993 .51331 .51331 1.42993
-.40331 -.40331 1.42993 .51331 .51331
-.40331 .51331 .51331 1.42993 -2.23655
.51331 -.40331 .51331 -.40331 1.42993
1.42993 -.40331 -2.23655 -.40331 1.42993
-.40331 -.40331 -.40331 -.40331 1.42993
.51331 .51331 .51331 1.42993 -.40331
-1.31993 -2.23655 .51331 -1.31993 -.40331

18. Q:4 I would favor such Marketing Campaign.
I would favor such Marketing Campaign.
Frequency Relative
Frequency
Percent
Frequency
Cumulative
Frequency
Cumulative
Percent
strongly
disagree
6 0.12 12.0
6
12.0
disagree 7 0.14 14.0 13 26.0
Neutral 14 0.28 28.0 27 54.0
Agree 14 0.28 28.0 41 82.0
Strongly
agree
9 0.18 18.0
50
100.0
Total 50 1.0 100.0
•Frequency Distribution:
I would favor such Marketing Campaign. * Class Cross tabulation
Question
Class Total
BBA MBA MS MDM OTHERS
strongly disagree 0 2 1 2 1 6
disagree 1 4 1 0 1 7
Neutral 0 10 0 4 0 14
Agree 0 12 0 1 1 14
Strongly agree 1 5 1 2 0 9
Total 2 33 3 9 3 50
•Cross Tabulation with Respect to Class:

19. •Bar Graph and Pie chart:
•Histogram and Dot Plot:

20. Particulars Formulas Analysis
Mean 3.2600
Geometric Mean
Harmonic mean
Median Middle Value or Average middle Value 3.00
Mode Most Repeated Value 3.00
Percentile(m=67) 3.0300
Quartile
Q1
Q2
Q3
25%
50%
75%
2.00
3.00
4.00
Five Number summary Minimum value
Q1
Q2
Q3
Maximum Value
1.00
2.00
3.00
4.00
5.00
Range range = xmaximum – xminimum
4.00
Variance 1.584
Standard Deviation 1.2586
Co-efficient of Variance 38.61%
Z-score Give the below in the
table
Outlier Analyze With the Help of Z-Score There is no outlier in
the given output
Interpretation:
In it we take the Suggestion from the Student about the Product, and the result is mostly agree or neutral. Which help us to makes the
decision making.

21. 1.38249 -1.00111 -1.00111 -.20658 -1.00111
-.20658 .58795 .58795 .58795 .58795
1.38249 -1.79564 -.20658 -.20658 .58795
-1.00111 -1.79564 1.38249 -1.00111 -.20658
-1.79564 -.20658 -1.79564 1.38249 1.38249
.58795 -.20658 -1.00111 -.20658 -1.79564
-.20658 1.38249 -.20658 1.38249 .58795
-.20658 -.20658 .58795 -.20658 1.38249
-1.79564 -.20658 .58795 .58795 .58795
-1.00111 .58795 .58795 .58795 1.38249

22. Q:5 It is good Marketing Campaign.
It is good Marketing Campaign.
Question:
Frequency Relative Frequency Percent Frequency Cumulative
frequency
Cumulative
Percent
strongly disagree 7 0.14 14.0 7 14.0
Disagree 5 0.10 10.0 12 24.0
Neutral 10 0.20 20.0 22 44.0
Agree 22 0.44 44.0 44 88.0
Strongly Agree 6 0.12 12.0 50 100.0
Total 50 1.0 100.0
•Frequency Distribution:
It is good Marketing Campaign. * Class Cross tabulation
Question:
Class Total
BBA MBA MS MDM OTHERS
strongly disagree 1 4 0 2 0 7
disagree 0 2 1 0 2 5
Neutral 0 8 1 1 0 10
Agree 1 15 1 4 1 22
Strongly Agree 0 4 0 2 0 6
Total 2 33 3 9 3 50
• Cross tabulation With respect to Class:

23. Bar Graph And Pie chart:
•Histogram and Dot Plot:

24. Particulars Formulas Analysis
Mean 3.3000
Geometric Mean
Harmonic mean
Median Middle Value or Average middle Value 4.00
Mode Most Repeated Value 4.00
Percentile(m=43) 4.00
Quartile
Q1
Q2
Q3
25%
50%
75%
2.7500
4.00
4.00
Five Number summary Minimum value
Q1
Q2
Q3
Maximum Value
1.00
2.7500
4.00
4.00
5.00
Range range = xmaximum – xminimum
4.00
Variance 1.520
Standard Deviation 1.2330
Co-efficient of Variance 37.36%
Z-score Give the below in the table
Outlier Analyze With the Help of Z-Score There is no outlier in the
given output
Interpretation:
In it we take the opinion from the students about the campaign of the product, and we conclude that many students agree from the
marketing campaign about the product and we show it graph and table in the above.

25. .56770 -1.86530 -1.86530 -.24330 -.24330
-.24330 .56770 .56770 .56770 .56770
1.37870 -1.86530 .56770 .56770 .56770
-1.05430 -1.86530 -.24330 -.24330 .56770
-1.05430 .56770 .56770 .56770 1.37870
.56770 -1.05430 .56770 .56770 -1.86530
.56770 1.37870 .56770 .56770 -.24330
.56770 -1.86530 -1.86530 -.24330 1.37870
-1.05430 -1.05430 .56770 -.24330 1.37870
-.24330 1.37870 .56770 -.24330 .56770

26. Q:6 Such Marketing Campaigns are beneficial for society.
Such Marketing Campaigns are beneficial for society.
Question:
Frequency Relative
Frequency
Percent
Frequency
C.F Cumulative
Percent
Strongly disagree 3 0.06 6.0
3
6.0
disagree 5 0.10 10.0 8 16.0
Neutral 18 0.36 36.0 26 52.0
Agree 15 0.30 30.0 41 82.0
Strongly agree 9 0.18 18.0 50 100.0
Total 50 1.00 100.0
Questions Class Total
BBA MBA MS MDM OTHERS
Strongly disagree 0 2 0 1 0 3
disagree 1 3 1 0 0 5
Neutral 0 12 1 3 2 18
Agree 0 11 1 2 1 15
Strongly agree 1 5 0 3 0 9
Total 2 33 3 9 3 50
•Frequency Distribution:
•Cross Tabulation:

27. •Bar Graph and pie chart:
•Dot Plot and Histogram:

28. Particulars Formulas Analysis
Mean 3.4400
Geometric Mean
Harmonic mean
Median Middle Value or Average middle Value 3.00
Mode Most Repeated Value 3.00
Percentile(m=67) 4.00
Quartile
Q1
Q2
Q3
25%
50%
75%
3.00
3.00
4.00
Five Number summary Minimum value
Q1
Q2
Q3
Maximum Value
1.00
3.00
3.00
4.00
5.00
Range range = xmaximum – xminimum
4.00
Variance 1.190
Standard Deviation 1.091
Co-efficient of Variance 31.72%
Z-score Give the below in the
table
Outlier Analyze With the Help of Z-Score There is no outlier in the
given output
Interpretation:
In the above we shows the reaction of students about Marketing Campaigns are beneficial for society and we conclude that many
student are agree of such kind of marketing campaign.

29. 1.42993 -1.31993 .51331 -.40331 -.40331
-1.31993 .51331 -.40331 -1.31993 -.40331
.51331 -1.31993 .51331 -.40331 -.40331
-.40331 -.40331 .51331 1.42993 1.42993
1.42993 .51331 .51331 -.40331 1.42993
.51331 -.40331 1.42993 -.40331 1.42993
-.40331 -.40331 .51331 -.40331 -2.23655
-.40331 -.40331 .51331 1.42993 .51331
.51331 -2.23655 -2.23655 .51331 1.42993
-1.31993 .51331 -.40331 .51331 -.40331

30. Q:7 This marketing campaign has attractive contents
This marketing campaign has attractive contents.
Questions Frequency Relative
Frequency
Percent
frequency
Cumulative
Frequency
Cumulative
percent
Strongly disagree 2 0.04 4.0 2 2
disagree 6 0.12 12.0 8 16
Neutral 18 0.36 36.0 26 52
Agree 18 0.36 36.0 44 88
Strongly agree 6 0.12 12.0 50 100
Total 50 1.00 100.0
This marketing campaign has attractive contents. * Class Cross tabulation
Questions: Class Total
BBA MBA MS MDM OTHERS
Strongly disagree 0 1 0 1 0 2
disagree 0 3 1 0 2 6
Neutral 1 13 1 3 0 18
agree 0 12 1 4 1 18
Strongly agree 1 4 0 1 0 6
Total 2 33 3 9 3 50
Frequency Distribution:
Cross tabulation:

31. •Bar Graph and Pie chart
•Histogram and Dot plot:

32. Interpretation:
In the above we take opinion from the students and in position of to take the decision that many student agree or strongly agree about the
marketing campaign has attractive context.
Particulars Formulas Analysis
Mean 3.3400
Geometric Mean
Harmonic mean
Median Middle Value or Average middle Value 3.00
Mode Most Repeated Value 3.00
Percentile(m=87) 4.3700
Quartile
Q1
Q2
Q3
25%
50%
75%
3.00
3.00
4.00
Five Number summary Minimum value
Q1
Q2
Q3
Maximum Value
1.00
3.00
3.00
4.00
5.00
Range range = xmaximum – xminimum
4.00
Variance .980
Standard Deviation .9897
Co-efficient of Variance 29.63%
Z-score Give the below in the table
Outlier Analyze With the Help of Z-Score There is no outlier in the
given output

33. 1.61658 -.40415 -1.41451 -.40415 -.40415
-.40415 1.61658 .60622 .60622 1.61658
-1.41451 -.40415 -1.41451 -.40415 .60622
.60622 .60622 -.40415 -.40415 1.61658
.60622 1.61658 .60622 -.40415 -.40415
.60622 .60622 .60622 -.40415 .60622
-1.41451 .60622 -.40415 -.40415 -2.42487
-1.41451 -.40415 .60622 -.40415 .60622
-.40415 -2.42487 -.40415 1.61658 .60622
.60622 -.40415 -.40415 .60622 .60622

34. Q:8 This marketing campaign has excellent execution.
This marketing campaign has excellent execution.
Questions Frequency Relative
Frequency
Percent
Frequency
Cumulative
Frequency
Cumulative
Percent
strongly disagree 3 0.06 6.0 3 6
disagree 7 0.14 14.0 10 20
Neutral 13 0.26 26.0 23 46
Agree 17 0.34 34.0 40 80
Strongly agree 10 0.20 20.0 50 100
Total 50 1.00 100.0
This marketing campaign has excellent execution. * Class Cross tabulation
Questions: Class Total
BBA MBA MS MDM OTHERS
strongly disagree 1 1 0 1 0 3
disagree 0 1 2 2 2 7
Neutral 1 10 1 1 0 13
Agree 0 13 0 3 1 17
Strongly agree 0 8 0 2 0 10
Total 2 33 3 9 3 50
Frequency Distribution:
Cross tabulation:

35. •Bar Graph and Pie chart:
•Histogram and Dot Plot:

36. Particulars Formulas Analysis
Mean 3.4800
Geometric Mean
Harmonic mean
Median Middle Value or Average middle Value 4.00
Mode Most Repeated Value 4.00
Percentile(m=31) 3.00
Quartile
Q1
Q2
Q3
25%
50%
75%
3.00
4.00
4.00
Five Number summary Minimum value
Q1
Q2
Q3
Maximum Value
1.00
3.00
4.00
4.00
5.00
Range range = xmaximum – xminimum
4.00
Variance 1.316
Standard Deviation 1.1471
Co-efficient of Variance 32.96%
Z-score Give the below in the table
Outlier Analyze With the Help of Z-Score There is no outlier in the given
output
Interpretation:
In the above we plot the suggestion of the students about the marketing campaign has excellent execution. And at the end we conclude that
many student are the favor of the Agree to the execution of the marketing.

37. -.41843 -2.16191 .45330 -.41843 .45330
-1.29017 1.32504 .45330 .45330 1.32504
-1.29017 -1.29017 -.41843 .45330 -.41843
.45330 -.41843 1.32504 -.41843 .45330
.45330 .45330 .45330 .45330 1.32504
.45330 1.32504 -.41843 .45330 -2.16191
-1.29017 1.32504 -.41843 1.32504 1.32504
-1.29017 .45330 1.32504 -.41843 .45330
.45330 -.41843 -1.29017 -1.29017 1.32504
-.41843 -2.16191 .45330 -.41843 -.41843

38. Q:9 I like this campaign.
I like this campaign.
Questions Frequency Relative
Frequency
Percent
Frequency
Cumulative
Frequency
Cumulative
Percent
strongly disagree 5 0.10 10.0 5 10
Disagree 4 0.08 8.0 9 18
Neutral 14 0.28 28.0 23 46
Agree 16 0.32 32.0 39 78
strongly agree 11 0.22 22.0 50 100
Total 50 1.00 100.0
I like this campaign. * Class Cross tabulation
Questions Class Total
BBA MBA MS MDM OTHERS
strongly disagree 1 4 0 0 0 5
Disagree 0 3 0 0 1 4
Neutral 0 12 1 0 1 14
Agree 1 9 2 3 1 16
strongly agree 0 5 0 6 0 11
Total 2 33 3 9 3 50
Frequency Distribution:
•Cross tabulation:

39. •Bar Graph and Pie chart:
•Histogram and Dot Plot:

40. Particulars Formulas Analysis
Mean 3.4800
Geometric Mean
Harmonic mean
Median Middle Value or Average middle Value 4.00
Mode Most Repeated Value 4.00
Percentile(m=46) 3.4600
Quartile
Q1
Q2
Q3
25%
50%
75%
3.00
4.00
4.00
Five Number summary Minimum value
Q1
Q2
Q3
Maximum Value
1.00
3.00
4.00
4.00
5.00
Range range = xmaximum – xminimum
4.00
Variance 1.479
Standard Deviation 1.2162
Co-efficient of Variance 34.95%
Z-score Give the below in the table
Outlier Analyze With the Help of Z-Score There is no outlier in the
given output
Interpretation:
In it we take the opinion of the student that the like the marketing campaign of the product or not, and at the end we conclude that many student
are in the Favor of the Marketing and they like the such type of Marketing campaign.

41. .42756 -2.03911 -2.03911 .42757 .42756
-.39467 -1.21689 .42756 -.39467 1.24978
1.24978 -2.03911 -.39467 -.39467 .42756
-1.21689 -2.03911 1.24978 .42756 1.24978
-.39467 1.24978 1.24978 -.39467 .42756
.42756 -.39467 -.39467 -2.03911 1.24978
.42756 1.24978 -.39467 -.39467 -1.21689
-.39467 -.39467 1.24978 .42756 .42756
.42756 -.39467 -.39467 -1.21689 1.24978
.42756 .42756 .42756 -.39467 1.24978