A volume of 0.0125 m3 at a temperature of 1300C and pressure at 90kPa has the temperature increased by 150oF. What is the new volume? Solution increase in temperature = 150 F = 65.556 C As process is not mentioned, considering isobaric process (p=Constant) New volume = Vf = (Tf*Vi/Ti) = 0.0125 * (1300+65.556)/1300 = 0.01313 m3.