5. Multiply *distributive* Then you multiply the 2x and the 1x and the -1 and the 1x in the problem. You put that 2x^2 under the 2x^2 and the -1x under the 5x in the problem to subtract.
6. Subtract Change the sign of the 1x and subtract the 5x and the -1x. The remaining number will be 6x.
8. Repeat Divide the 2x into the 6x and you will get 3. Multiply the 2x and the 3 and the -1 by the 3 and you get 6x-3. Subtract the numbers and change the signs and you get a remainder of 0. The answer to the problem is 1x+3.