This document discusses how polynomials can be used to represent various financial concepts like revenue, blood flow, and area or perimeter. It provides two examples of using polynomials to solve financial problems: (1) calculating the value of an investment of $200 growing at 10% interest after one year, and (2) solving a polynomial equation derived from a word problem involving time. Polynomials are useful for managing finances by representing savings, bills, and other regular monetary amounts and rates of change.
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Assignment week 4
1. Running Head: FINANCIAL POLYNOMIALS 1
FINANCIAL POLYNOMIALS
ANNETTA GUZMAN
MAT221 INTRODUCTION TO ALGEBRA
PROF CAROL HANNAHS
MARCH 31, 2014
2. RUNNING HEADER
FINANCIAL POLYNOMIALS
Polynomials are an expression of several things, such as quantities of revenue, volume of blood
flowing through an artery and perimeter and or area. This is probably the only time I can relate algebra to
my life since I have been in the medical field for several years. The reason I like this subject best is I
have to manage money with savings and paying bills on a regular basis. Polynomials represent all these
subjects I work with in my life on a regular basis.
What I used in this first equation is from page 304 problem 90:
P(1+r/2)(1+r/2) Now I make this fraction into a decimal ½=.5
P(1+.5r)(1+.5r) FOIL
P(1+R+.25 r^2)
I will now combine the like terms
P(1+r+.25 r^2) Distributive property
P+Pr+.25 P r^2
Substitute P=200 r=.10
200 + 200(.10) +.25(200)(.10)^2
200+20+.25(200)(.01)
200+20+.5=$220.5 after one year
3. RUNNING HEADER
Next, the polynomial formula with two different sets of numerical information will be solved. In
these types of problems, a single numeric value will be found that represents the total. Numbers are said
to be in descending order when they are arranged from the largest to the smallest number.
Page 311 problem 70
(t^2-5t-36) / (t-9) the expanded formula
t-9=0//+9 Values are substituted into the formula
(t^2 –(5*t-36) / (t-9) =0 Exponents and Multiplication Combined like terms
T^2-5*t-36=0 Finish order of operations with addition
(-5)^2-(-36*1*4)
=169
T = (169^2+5)/(1-2) or t=(5-169^2)/ (1*2)
T=9 or T=4
T= -4