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Systematic position: Kingdom Plantae Subkingdom Tracheobionta (Vascular plants) Superdivision Spermatophyta (Seed plants) Division Gnetophyta (Mormon tea and other gnetophytes) Class Gnetopsida Order Ephedrales Family Ephedraceae (tea family) Genus Ephedra L. Common name Jointfir There are 35 to 40 species in the world. These are wide spread in both in eastern and western hemispheres Morphology: A. Root : Branched root, tap root are present these are characteristic xerophytes, no report of mycorrhize. B. Stem: Woody green branched distinctly joined apparently nodes and inter nodes, branches are photosynthetic. Inter nodes are elongated by the activity of basal meristem. C. Leaves: Small scaly leaves are present, scale leaves are joined to form sheath, Brown leaves are non photosynthetic leaves. Anatomy: A. Root : It shows usually Gymnosperm structure. Cortex, endoderm, inner periderm, vascular camblum, primary and secondary xylem was present. B. Stem: 1. Primary structure: Transverse structure shows ridges and grooves. cortex clorenchyma elongated, endoderm is present in single layer. 2. Secondary structure: Parenchymalous cells present between the vascular bundles to form a ring of cambium, ray initials and fusiform initial are present. C. Leaves: Transverse structure of leaves shows epidermis, cuticle, xylem, phloem, air space, spongy parenchyma tissues. The vascular bundles are collateral closed and primary phloem and primary xylem are also present. Adaptations: Mostly xerophytes scrubs or woody climbers Ephedra Pedunculata. Most species of ephedra are branched scrubs, commonly climbing over vegetation many species spread by rhizomes Ephedra Trifura. Under favorable condition it grows tree like habitat. Ephedra Foliata - scrambling scrub, Ephedra Compacta - Branching type, Ephedra Camphylophoda - Spendulus branches, Ephedra Intermedia - Shoot, Ephedra Saxatilis - scrub. Values and functions: In pharmaceutical industries it works as to access Ephedra drug materials. Traditionally it is used by indigenous people for medicinal treatments of asthma, hay fever and cold. Alkaloids obtained from the species of Ephedra is used in herbal medicine. Solution Systematic position: Kingdom Plantae Subkingdom Tracheobionta (Vascular plants) Superdivision Spermatophyta (Seed plants) Division Gnetophyta (Mormon tea and other gnetophytes) Class Gnetopsida Order Ephedrales Family Ephedraceae (tea family) Genus Ephedra L. Common name Jointfir There are 35 to 40 species in the world. These are wide spread in both in eastern and western hemispheres Morphology: A. Root : Branched root, tap root are present these are characteristic xerophytes, no report of mycorrhize. B. Stem: Woody green branched distinctly joined apparently nodes and inter nodes, branches are photosynthetic. Inter nodes are elongated by the activity of basal meristem. C. Leaves: Small scaly leaves are present, scale leaves are joined to form sheath, Brown leaves are non photosynthetic leaves. A.

Systematic positionKingdom PlantaeSubkingdom Tracheobionta (Vas.pdf

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Query to list out all the languages in the table LANGUAGES.SELECT .pdf

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public class LunarLander { double currentFuelFlowRate; double verticalSpeed; double altitude; double amountOfFuel; double massOfTheLander; double maxFuelConsumptionRate; double maxThrust; /* constructor to initialize member variales*/ public LunarLander(double al, double fuel, double mass, double rate, double thrust) { currentFuelFlowRate=0.0; verticalSpeed=0.0; altitude=al; amountOfFuel=fuel; massOfTheLander=mass; maxFuelConsumptionRate=rate; maxThrust=thrust; } /* functions to get the values of instance variables*/ public double getCurrentFuelFlowRate() { return currentFuelFlowRate; } public double getVerticalSpeed() { return verticalSpeed; } public double getAltitude() { return altitude; } public double getAmountOfFuel() { return amountOfFuel; } public double getMassOfTheLander() { return massOfTheLander; } public double getMaxFuelConsumptionRate() { return maxFuelConsumptionRate; } public double getMaxThrust() { return maxThrust; } /* updates the value of currentFuelFlowRate*/ public void setCurrentFuelFlowRate(double rate) { currentFuelFlowRate=rate; } /* simulating the passage for a small amount of time t*/ public void setPassage(double t) { if(currentFuelFlowRate>0) { if(amountOfFuel==0) { currentFuelFlowRate=0; } } /* velocity is the verticalSpeed*/ double f=maxThrust*currentFuelFlowRate; double m=massOfTheLander; verticalSpeed=t*((f/m)-1.62); //v is verticalSpeed altitude=t*verticalSpeed; //ship is landed if(altitude<0) { altitude=0; verticalSpeed=0; } //r is currentFuelFlowRate //c is maxFuelConsumptionRate double changeInRemainFuel=t*currentFuelFlowRate*maxFuelConsumptionRate; amountOfFuel=amountOfFuel-changeInRemainFuel; if(amountOfFuel<0) { amountOfFuel=0; } } } //////////////////////////////////////////////////////// public class LunarLanderDemo { public static void main(String[] args) { LunarLander L=new LunarLander(1000,1700,900,10,5000); /*give values between 0.0 , 1.0*/ L.setCurrentFuelFlowRate(0.6); L.setPassage(0.1); System.out.println(\"Simulation of Lunar Lander Passage at 0.1 seconds\"); System.out.println(\"Current Fuel Flow Rate: \"+L.getCurrentFuelFlowRate()); System.out.println(\"Vertical Speed: \"+L.getVerticalSpeed()); System.out.println(\"Altitude: \"+L.getAltitude()); System.out.println(\"Amount of Fuel: \"+L.getAmountOfFuel()); L.setCurrentFuelFlowRate(0.3); L.setPassage(0.09); System.out.println(\"Simulation of Lunar Lander Passage at 0.09 seconds\"); System.out.println(\"Current Fuel Flow Rate: \"+L.getCurrentFuelFlowRate()); System.out.println(\"Vertical Speed: \"+L.getVerticalSpeed()); System.out.println(\"Altitude: \"+L.getAltitude()); System.out.println(\"Amount of Fuel: \"+L.getAmountOfFuel()); } } Solution public class LunarLander { double currentFuelFlowRate; double verticalSpeed; double altitude; double amountOfFuel; double massOfTheLander; double maxFuelConsumptionRate; double maxThrust; /* constructor to initialize member variales*/ public LunarLander(double al, double fuel, double mass, double rate.

public class LunarLander { double currentFuelFlowRate; d.pdf

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Cooling. The reaction is giving off energy(heat) .pdf

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Tic Tac Toe in PHP\'; for($i=0; $i<$size; $i++) { for($j=0; $j<$size; $j++) { $count++; $retVal.=\'\'; } $retVal.=\' \'; } $retVal.=\'\'; echo $retVal; } function genBox2($size,$arr) { global $bsize,$playerToken,$myToken,$gameOver,$winArr,$rowArr,$colArr,$digArr,$vals,$s1,$s2,$s 3,$s4,$s5,$s6,$s7,$s8,$s9; $count=0; $retVal=\'\'; for($i=0; $i<$size; $i++) { for($j=0; $j<$size; $j++) { $count++; $retVal.=\'\'; } $retVal.=\' \'; } $retVal.=\'\'; echo $retVal; } function isEmpty($who) { if($who==\"\") return 1; else return 0; } function move($bsize,$arr) { global $bsize,$playerToken,$myToken,$gameOver,$winArr,$rowArr,$colArr,$digArr,$vals,$s1,$s2,$s 3,$s4,$s5,$s6,$s7,$s8,$s9; $count=0; $maxCount=0; $pos=0; $retVal=0; # Build Row Array for($i=0; $i<$bsize; $i++) { $maxCount=0; $fullCounter=0; for($j=0; $j<$bsize; $j++) { $count++; $who=$arr[$count-1]; if($who==$playerToken) { $maxCount++; $fullCounter++; } if($who==$myToken) $fullCounter++; } $rowArr[$i]=$maxCount; if($fullCounter==$bsize) $rowArr[$i]=-1; } # Building Column Array for($i=0; $i<$bsize; $i++) { $count=$i+1; $maxCount=0; $fullCounter=0; for($j=0; $j<$bsize; $j++) { $who=$arr[$count-1]; if($who==$playerToken) { $maxCount++; $fullCounter++; } if($who==$myToken) $fullCounter++; $count+=$bsize; } $colArr[$i]=$maxCount; if($fullCounter==$bsize) $colArr[$i]=-1; } # Building Diagonal Array for($i=0; $i<2; $i++) { if($i==0) $count=$i+1; else $count=$bsize; $maxCount=0; $fullCounter=0; for($j=0; $j<$bsize; $j++) { $who=$arr[$count-1]; if($who==$playerToken) { $maxCount++; $fullCounter++; } if($who==$myToken) $fullCounter++; if($i==0) $count+=$bsize+1; else $count+=$bsize-1; } $digArr[$i]=$maxCount; if($fullCounter==$bsize) $digArr[$i]=-1; } # Finding Max Values $maxRow=myMax(0,$bsize,\"row\",$rowArr); $maxCol=myMax(0,$bsize,\"col\",$colArr); $maxDig=myMax(0,$bsize,\"dig\",$digArr); $maxArrs[0]=myMax(1,$bsize,\"row\",$rowArr); $maxArrs[1]=myMax(1,$bsize,\"col\",$colArr); $maxArrs[2]=myMax(1,$bsize,\"dig\",$digArr); //$maxArrs=array(max(1,$bsize,\"row\",$rowArr),max(1,$bsize,\"col\",$colArr),max(1,$bsize,\" dig\",$digArr)); if(myMax(0,$bsize,\"x\",$maxArrs)==0) $pos=$bsize*($maxRow+1)-$bsize; if(myMax(0,$bsize,\"x\",$maxArrs)==1) $pos=$maxCol; if(myMax(0,$bsize,\"x\",$maxArrs)==2) if($maxDig==0) $pos=$maxDig; else $pos=$bsize-1; $retFlag=0; for($y=0; $y<$bsize; $y++) { if(!$retFlag) { if($arr[$pos]==\"\") { $retVal=$pos; $retFlag=1; } if(myMax(0,$bsize,\"x\",$maxArrs)==0) $pos++; if(myMax(0,$bsize,\"x\",$maxArrs)==1) $pos+=$bsize; if(myMax(0,$bsize,\"x\",$maxArrs)==2) if($maxDig==0) $pos+=$bsize+1; else $pos+=$bsize-1; } } return $retVal; } function myMax($what,$bsize,$type,$arr) { global $bsize,$playerToken,$myToken,$gameOver,$winArr,$rowArr,$colArr,$digArr,$vals,$s1,$s2,$s 3,$s4,$s5,$s6,$s7,$s8,$s9; $max=-1; $maxIndex=-1; if($type!=\"dig\") { for($i=0; $i<$bsize; $i++) { if($arr[$i]>$max) { $max=$arr[$i]; $maxIndex=$i; } } } if($type==\"dig\") { for($i=0; $i<2; $i++) { if($arr[$i]>$max) { $ma.

php global $bsize,$playerToken,$myToken,$gameOver,$winArr,$rowAr.pdf

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c. cytochrome C It is the enzyme involved in the .pdf

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Ka=-log(Ka)=-log(5.6*10^-10)=9.25 According to Henderson Hasselbalch Equation pH = pka + log[salt]/[acid] pH = 9.25 log[Nh3]/[Nh4+] = 9.25+log(0.2/0.6) pH=8.77 (2) NH3 + HCl =======> NH4Cl I 0.2 0.10 0.6 C 0.2-0.1 -0.1 +0.1 E 0.1 0 0.7 pH = pka + log[salt]/[acid] pH = 9.25 log[Nh3]/[Nh4+] = 9.25+log(0.1/0.7) pH=8.40 (3) NH4Cl + NaOH =============> NH3 + NaCl + H2O I 0.6 0.20 0.2 C -0.20 -0.20 +0.20 E 0.4 0 0.4 pH = pka + log[salt]/[acid] pH = 9.25 log[Nh3]/[Nh4+] = 9.25+log(0.4/0.4) = 9.25 Solution Ka=-log(Ka)=-log(5.6*10^-10)=9.25 According to Henderson Hasselbalch Equation pH = pka + log[salt]/[acid] pH = 9.25 log[Nh3]/[Nh4+] = 9.25+log(0.2/0.6) pH=8.77 (2) NH3 + HCl =======> NH4Cl I 0.2 0.10 0.6 C 0.2-0.1 -0.1 +0.1 E 0.1 0 0.7 pH = pka + log[salt]/[acid] pH = 9.25 log[Nh3]/[Nh4+] = 9.25+log(0.1/0.7) pH=8.40 (3) NH4Cl + NaOH =============> NH3 + NaCl + H2O I 0.6 0.20 0.2 C -0.20 -0.20 +0.20 E 0.4 0 0.4 pH = pka + log[salt]/[acid] pH = 9.25 log[Nh3]/[Nh4+] = 9.25+log(0.4/0.4) = 9.25.

Ka=-log(Ka)=-log(5.610^-10)=9.25 According to Henderson Hasselb.pdf

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C is wrong 14 7N contains 7 protons and 7 neutron.pdf

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1. The following are the main types of service providers to a mutual fund: Service provider refers to the sponsor of funds. From the public who are ready to invest, the fund sponsor raises funds. The fund sponsor is one among the following: The duty of the sponsor is to invest the funds of the investor in stocks, bonds, and shares according to the preference of the investors. If the investors demand for 100% safety of the invested funds, the fund sponsor invests in such shares or bonds. If the investor is ready to meet risks even to 100%, then the fund sponsor will invest accordingly. For this service, the investor has to pay the fund sponsor up to a certain limit. 2. Determining the fees of mutual fund advisor: There are certain restrictions that are imposed by SEBI. An advisor has to follow the same in order to claim his fees. Mutual fund distributors are generally exempted from being registered as investment advisors. For a no-load large-cap fund, the percentage of fees is 0.95 whereas for small cap funds it is 1.20%. Therefore, if the advisor charges more than the specified percentage, the shareholders can challenge that the fees is excessive. 3. Differences between mutual funds and closed-end funds: One of the major differences between the mutual funds and the closed-end funds is in the date of maturity. A mutual fund can be withdrawn whenever the funds are required. However, it is not the case in closed-end funds. In closed-end funds, the funds can be taken only at its date of maturity. Some funds can be taken before the date of maturity. However, the rate of interest will either be very little or even nil. The closed-end funds have declined in popularity because of the returns and the maturity date. Investing in this leads to overtrading and poor returns. 4. Differences between ETFs and UITs from index mutual funds: ETF is similar to closed-end funds. They trade closer to NAVs and therefore can be created and retired whenever required. Mostly ETFs are passively managed with the help of indexes. However, there are actively managed investments too. They are allowed to sell short and buy on margin. They are even allowed to purchase a single share. UITs are sold by investment advisors rather than purchasing from a secondary market. This does not have a board of directors and is registered with Securities and Exchange Board. This portfolio has different types of securities too. Index mutual fund is a type of mutual fund in which a sale and buy index is set. When the rate falls down to the set index, the funds are sold/bought on its own. Solution 1. The following are the main types of service providers to a mutual fund: Service provider refers to the sponsor of funds. From the public who are ready to invest, the fund sponsor raises funds. The fund sponsor is one among the following: The duty of the sponsor is to invest the funds of the investor in stocks, bonds, and shares according to the preference of the investors. If the investors demand.

1.The following are the main types of service providers to a mutua.pdf

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D. planned and directed means to improve the functioning of the clie.pdf

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domain - -x-1 0 = x+10 =x-1i.e. (-inf,-1)range-(-in.pdf

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B.both are correctSolutionB.both are correct.pdf

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C. Keystroke loggers are a form of malware that records every key the computer user presses to harvest usernames, passwords, social security numbers, and other confidential information and then send that data to the person who caused the malware installation. Solution C. Keystroke loggers are a form of malware that records every key the computer user presses to harvest usernames, passwords, social security numbers, and other confidential information and then send that data to the person who caused the malware installation..

C. Keystroke loggers are a form of malware that records every key th.pdf

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Ans.) Researchers have found much more proof that sexual orientation is to a great extent controlled by hereditary qualities, not decision. That can undermine a noteworthy contention against the LBGT people group that claims that these individuals are living \"unnaturally.\" According to latest research conducted and published in scientific journals the two areas of human genome - one on the X chromosome and one on chromosome 8. The relationship amongst science and sexual orientation is a subject of deep research and analysis. A straightforward and particular determinant for sexual orientation has not been indisputably illustrated; different studies indicate diverse, notwithstanding clashing positions, however researchers theorize that a blend of genetics, hormonal and social elements decide sexual orientation. Biological hypotheses for clarifying the reasons for sexual orientation are more popular and natural elements may include an intricate interaction of hereditary components and the early uterine, environment. These variables, which might be identified with the improvement of a hetero, gay person, promiscuous orientation, incorporate qualities, pre-birth hormones, and cerebrum structure. According to a study, every single grown-up twin in Sweden (more than 7,600 twins) found that same-sex conduct was clarified by both genetic elements and individual-particular natural sources, (for example, pre-birth environment, involvement with sickness and injury and also peer bunches and sexual encounters), while impacts of shared-environment factors, for example, familial environment and social demeanors had a weaker, yet noteworthy impact. Women demonstrated a factually non-critical pattern to weaker impact of genetic impacts, while men demonstrated no impact of shared ecological impacts. Chromosome linkage analysis of sexual orientation has shown the presence of different contributing hereditary elements all through the genome. In 1993 Dean Hamer and partners published their finding from a linkage examination of a specimen of 76 homo siblings and their families. The researcher found that the homo men had more homo male uncles and cousins on the maternal side of the family than on the fatherly side. Gay siblings who demonstrated this maternal family were then tried for X chromosome linkage, utilizing twenty-two markers on the X chromosome to test for comparable alleles. In another discovering, thirty-three of the forty kin sets tried were found to have comparable alleles in the distal district of Xq28, which was altogether higher than the normal rates of half for friendly siblings. This was prominently named the \" homo quality\" in the media, bringing on noteworthy discussion. Sanders et al. in 1998 investigated their comparative study, in which they found that 13% of uncles of homosexual siblings on the maternal side were homo person, contrasted and 6% on the fatherly side. Hence, it is concluded that up to some extent homosexuality or sex orient.

Ans.) Researchers have found much more proof that sexual orientation.pdf

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Amnion - Protection of embryo (It covers the embryo when first formed and filled with amniotic fluid) Chorion - Waste removal (The chorion is formed by two layers – trophoblast- outer layer and mesoderm- inner layer. The mesoderm will be in contact with the amnion and removes waste produced. The trophoblast provides the nutrients for the fetus during its confinement) Allantois - gas exchange ( is a sac-like structure below the chorion, which consists of all embryonic and extra-embryonic tissues) Yolk - Primary nutrition source. Albumen - Protein, nutrition. Solution Amnion - Protection of embryo (It covers the embryo when first formed and filled with amniotic fluid) Chorion - Waste removal (The chorion is formed by two layers – trophoblast- outer layer and mesoderm- inner layer. The mesoderm will be in contact with the amnion and removes waste produced. The trophoblast provides the nutrients for the fetus during its confinement) Allantois - gas exchange ( is a sac-like structure below the chorion, which consists of all embryonic and extra-embryonic tissues) Yolk - Primary nutrition source. Albumen - Protein, nutrition..

Amnion - Protection of embryo (It covers the embryo when first forme.pdf

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A. polar covalent NH3 H2O B. nonpolar covalent CH.pdf

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1.) If phi is thrival, kernal will be one to one. And kern = 9.pdf

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A Lewis acid is a species that can accept a pair of electrons from a Lewis base, which is a donator of electrons. In this reaction, AlCl3 is a strong lewis acid and accepts a lone pair of electrons from the Lewis base Cl-, thereby completing Aluminum\'s octet and forming AlCl4-. Solution A Lewis acid is a species that can accept a pair of electrons from a Lewis base, which is a donator of electrons. In this reaction, AlCl3 is a strong lewis acid and accepts a lone pair of electrons from the Lewis base Cl-, thereby completing Aluminum\'s octet and forming AlCl4-..

A Lewis acid is a species that can accept a pair .pdf

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