pOH = 14 - pH = 14 - 12.50 = 1.5 pOH = -log[OH-] = 1.5 M2 = [OH-] = 0.032 M V2 = 2.50 L M1 = 0.455 M M1V1 = M2V2 V1 = M2V2/M1 = 0.032 x 2.50 / 0.455 = 0.176 L Solution pOH = 14 - pH = 14 - 12.50 = 1.5 pOH = -log[OH-] = 1.5 M2 = [OH-] = 0.032 M V2 = 2.50 L M1 = 0.455 M M1V1 = M2V2 V1 = M2V2/M1 = 0.032 x 2.50 / 0.455 = 0.176 L.