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Memorial calculo método matemático
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Jonathas Orla Construtora
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Memorial calculo método matemático
1.
Memorial Calculo Método
Matemático. Calculo da Resistência Media de Dosagem. 𝑓𝑐𝑚𝑗 = 𝑓𝑐𝑘 + 1,65 × 𝑆𝑑 𝑓𝑐𝑚𝑗 = 20 + 1,65 × 5,5 𝑓𝑐𝑚𝑗 = 29,075 𝑚𝑝𝑎 Lei de Abrams 𝑓𝑐𝑗 = 𝐾1 𝐾2 𝑎 𝑐 29,075 = 108,3825994 20,46712911 𝑎 𝑐 𝑎 𝑐 = 0,4359 Calculo Incógnita K1 𝐾1 = 10 (1 3 ×((log𝑓𝑐𝑗1+log𝑓𝑐𝑗2+log𝑓𝑐𝑗3)−𝑏×( 𝑎 𝑐1 + 𝑎 𝑐2 + 𝑎 𝑐3 ))) 𝐾1 = 10 (1 3 ×((log25,23+log19,73+log10,2)+1,31105692918552×(0,46+0,61+0,76))) 𝐾1 = 108,3825994 Calculo Incógnita K2 𝐾2 = 101,31105692918552 𝐾2 = 20,46712911 Calculo Incógnita b 𝑏 = log 𝑓𝑐𝑗1 × (2 × 𝑎 𝑐1 − 𝑎 𝑐2 − 𝑎 𝑐3 ) + log 𝑓𝑐𝑗2 × (2 × 𝑎 𝑐2 − 𝑎 𝑐1 − 𝑎 𝑐3 ) + log 𝑓𝑐𝑗3 (2 × 𝑎 𝑐3 − 𝑎 𝑐1 − 𝑎 𝑐2 ) 2 × ( 𝑎 𝑐1 2 + 𝑎 𝑐2 2 + 𝑎 𝑐3 2 ) − 2 × ( 𝑎 𝑐1 × 𝑎 𝑐2 + 𝑎 𝑐1 × 𝑎 𝑐3 + 𝑎 𝑐2 × 𝑎 𝑐3 ) 𝑏 = log 25,23 × (2 × 0,46− 0,61 − 0,76) + log 19,73 × (2 × 0,61 − 0,46 − 0,76) + log 10,2(2 × 0,76 − 0,46 − 0,61) 2 × (0,462 + 0,612 + 0,762) − 2 × (0,46 × 0,61 + 0,46 × 0,76 + 0,61 × 0,76) 𝑏 = -1,31105692918552
2.
Lei de
Lyse Calculo Proporção de Agregado. 𝑚 = 𝐾3 + 𝐾4 × 𝑎 𝑐 𝑚 = −1,1 + 10 × 0,4359 𝑚 = 3,259 Calculo Incógnita K2 𝐾3 = 5 − [ 𝐾4 × ( 𝑎 𝑐1 + 𝑎 𝑐2 + 𝑎 𝑐3 ) 3 ] 𝐾3 = 5 − [ 10 × (0,46 + 0,61 + 0,76) 3 ] 𝐾3 = -1,1 Calculo Incógnita K4 𝐾4 = (3,5 × 𝑎 𝑐1 + 5 × 𝑎 𝑐2 + 6,5 × 𝑎 𝑐3 ) − 5 × ( 𝑎 𝑐1 + 𝑎 𝑐2 + 𝑎 𝑐3 ) ( 𝑎 𝑐1 2 + 𝑎 𝑐2 2 + 𝑎 𝑐3 2 ) − ( 𝑎 𝑐1 + 𝑎 𝑐2 + 𝑎 𝑐3 ) 2 3 𝐾4 = (3,5 × 0,46 + 5 × 0,61 + 6,5 × 0,76) − 5 × (0,46 + 0,61 + 0,76) (0,462 + 0,612 + 0,762) − (0,46 + 0,61 + 0,76)2 3 𝐾4 = 10 Lei de Molinari Calculo Consumo de Cimento. 𝐶 = 1000 𝐾5 + 𝐾6 × 𝑚 𝐶 = 1000 0,416546568 + 0,469791864 × 3,259 𝐶 = 513,4529 Kg/m³
3.
Calculo Incógnita K5 𝐾5
= [( 1000 3 ) × ( 1 𝐶1 + 1 𝐶2 + 1 𝐶3 )] − 5 × 𝐾6 𝐾5 = [( 1000 3 ) × ( 1 480,44234 + 1 367,0640 + 1 286,46804 )] − 5 × 0,469791864 𝐾5 = 0,416546568 Calculo Incógnita K6 𝐾6 = ( 1000 3 ) × ( 1 𝐶3 − 1 𝐶1 ) 𝐾6 = ( 1000 3 ) × ( 1 286,46804 − 1 480,44234 ) 𝐾6 = 0,469791864
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