2. Lesson objective:
At the end of this lesson, you will
understand how to solve problems involving
percent problems like problems involving
discounts, original price, rate of discount,
sale price, and mark-up price.
Solving Percentage Problems
4. The following terms are used in dealing
discount problems:
Discount (D) is a decrease in the price of
an item. It refers to the amount to be
deducted from the original price.
Original Price (OP) is the regular price
charged of the item.
Solving Percentage Problems
5. The following terms are used in dealing
discount problems:
Discount Rate (DR) is the percent taken
off from the original price.
Sale Price (SP) is the net price or
discounted price. It is the price of the
item after the discount has been
deducted..
Solving Percentage Problems
6. Remember:
Discount and Sale Price both represent
percentage;
Original price represents the base; and
Discount rate represents the rate.
Solving Percentage Problems
7. A. Solving for Discount and Sales Price
Example 1
A dress was sold for ₱500.00 at a 16%
discount. How much is the discount or how
much can be save? How much is the selling
price?
Given: DR=16%
OP= ₱500.00
D = ?
SP=?
Solving Percentage Problems
8. Using the discount (D) formula
Solution D= DR x OP
= ₱ 500.00 x 16%
= ₱ 500.00 x 0.16
D= ₱ 80.00
Using the sale price (SP) formula
SP = OP - D SP
= ₱ 500.00 - ₱80.00
SP= ₱ 420.00
Answer: The discount is ₱ 80.00 and the sale price
is ₱ 420.00.
Solving Percentage Problems
9. B. Solving for Original Price (OP)
Example 2
A wristwatch was sold for Php 2500.00
with a 20% discount. What was the original
price of the wristwatch?
Given: DR=20%
SP=2,500
OP =?
Solving Percentage Problems
10. Using the other formula for sale price.
Solution
SP = OP x (100– DR)
= OP x (100% - 20%)
2500 = OP x 80% Substitute the given.
2500 = OP x 0.80 Change 80% to decimal.
OP x 0.80 = 2500 Change and divide both
0.80 0.80 sides by 0.80.
OP= Php 3,125.00
Answer: The original price of the wristwatch is Php
3,125.00.
Solving Percentage Problems
11. In some instances, the seller add a
particular amount on the items or goods to
be sell for the profit.
From the original price, the amount added
is the markup price and the new amount is
called the selling price.
Markup and selling price represent both
the percentage, cost represent the base,
and the markup rate represent the rate.
Solving Percentage Problems
12. Here are the following terms that can
help you to understand this particular
topic.
Markup (M) is the increase in the price
of an item.
Markup Rate (MR) is the percent to be
added to the cost of item.
Cost (C ) is the original amount of the
item.
Solving Percentage Problems
13. C. Solving for Markup Price (M)
Example 3
To have the profit, the business woman adds a
markup price of Php 4.00 on all the plastic
products that bought in Divisoria. What is the
markup rate of the plastic bottle if the cost is
₱50.00? What will be the markup or selling price?
Given: M = Php 4.50
C = Php 50.00
MR =?
SP = ?
Solving Percentage Problems
14. Using the other formula for Markup price (M)
Solution
MR = M x 100%
C
= 4.50 x 100 Substitute the given.
50
= 0.09 x 100 Divide. Then multiply by 100.
MR = 9%
Answer: The markup rate of the plastic bottle is 9%.
Solving Percentage Problems
15. Using the other formula for Sale price (SP)
Solution
SP = C + M
= Php 50.00 + Php 4.50
SP= Php 54.50
Solving Percentage Problems
18. Directions: Find the discount (D) and the
sale price (SP) for each item.
Discount Sale Price
1. Regular price: Php 3, 500
Discount rate : 7%
2. Original price : Php 10, 000
Discount rate : 10%
3. Tag price : Php 18, 000
Discount rate : 5%
4. Marked price : Php 20, 000
Discount rate : 4%
5. Cost price : Php 465
Discount rate : 3%
Percentage, Base & Rate
Discount
Php 245
Php 1, 000
Php 900
Php 800
Php 13.95
Sale Price
Php 3, 255
Php 9, 000
Php 17, 100
Php 19, 200
Php 451.05
19. The following formula are used in solving
discount problems:
a. Discount
D = DR X OP
b. Original Price
D
DR
c. Discount Rate
D
OP
Solving Percentage Problems
X 100%
OP =
=
DR
20. The following formula are used in solving
discount problems:
a. Discount
D = DR X OP
b. Original Price
D
DR
c. Discount Rate
D
OP
Solving Percentage Problems
X 100%
OP =
=
DR
21. The following formula are used in solving
discount problems:
d. Sale Price
SP = OP - D
e. Sale Price (other formula)
SP = OP x (100% - DR)
f. Markup
M = C x MR
Solving Percentage Problems
22. The following formula are used in solving
discount problems:
g. Markup Rate
MR = M
C
h. Cost
C = M
MR
f. Selling Price
SP = C + M or SP = C x (100% + MR)
Solving Percentage Problems
23. Practice Exercises A
Find the discount and the sale price
1. Original Price: Php 12,000
Discount Rate: 25%
Discount: _____________
Sale Price: ____________
2. Regular Price: Php 5,600
Discount Rate: 4%
Discount: _____________
Sale Price: ____________
Solving Percentage Problems
24. Practice Exercises B
Solve the following:
1. The price of a motorbike is Php1,500. How
much do you need to pay if you get a 10%
discount?
SP = Php1,350
2. The price of a t-shirt is Php50. If you buy
more than 1 shirt, you will get 10% discount.
How much do you have to pay if you buy 8
shirts?
SP = 360
Solving Percentage Problems
25. 3. The cost price of a certain object is
Php1,500. The markup percent set by the
shopkeeper is 50%. Calculate the markup
price and selling price of the object.
Markup = Php750
Selling price = Php2,250
Solving Percentage Problems
