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Operations Research
Lecture 3:
Linear Programming:
Mathematical Models
(Part II)
Instructors:
Dr. Safaa Amin
Dr. Doaa Ezzat
width 9 7 5
Min Number of
rolls:
200 120 450
2
Rolls of paper having a fixed length and width 20 feet are
being manufactured by a paper company. These rolls have
to be cut with different knife setting to satisfy the
following demand:
Obtain the linear programming formulation of the problem
to determine the cutting pattern, so that the demand is
satisfied and wastage of paper is minimized (Formulate
only the linear problem model)
Example 9: Trim Loss Problem
Trim Loss Model
3
The different knife setting are:
20 feet
9 9 2 Loss=2
K1
9 7 4 Loss=4
K2
5 5 5 Loss=0
K3
9 5 1 Loss=1
K4
5
5
5 5 3 Loss=3
K5
7 7 1 Loss=1
K6
7
5
Trim loss Model cont…
K6
K5
K4
K3
K2
K1
1
2
2
4
0
0
Width 5
2
1
0
0
1
0
Width 7
0
0
1
0
1
2
Width 9
1
3
1
0
4
2
Loss
Width 5 Requirement
Minimize: 𝑍 = 2𝑥1 + 4𝑥2+0𝑥3 + 𝑥4 + 3𝑥5 + 𝑥6
Let 𝑥1 the number of rolls that will be cut by knife setting K1
Let 𝑥𝑖 the number of rolls that will be cut by knife setting Ki, i=1,2…6
Subject to: 4𝑥3 + 2𝑥4 + 2𝑥5 + 𝑥6 ≥ 450
𝑥2 + 𝑥5 + 2𝑥6 ≥ 120
2𝑥1 + 𝑥2 + 𝑥4 ≥ 200
Width 7 Requirement
Width 9 Requirement
With all Variable Non-negative and integer
Example 10: Man Power Model
week 1 2 3 4 5
No. of cans 280 298 305 360 400 5
A Company, engaged in producing tinned food, has 300 trained employees on the rolls, each
of whom can produce one can of food in a week, due to developing taste of the public for
this kind of food, the company plans to add to the existing labour force by employing 150
persons, in a phased manner, over the next 5 weeks. The newcomers would have to undergo
a two-weeks training program before being put to work. The training is to be given by
employees from among the existing ones and it is known that one employee can train three
trainees. Assume the training is off-the-job. However, the trainees would be remunerated at
the rate of $300 per week, the same rate as for the trainers. The company has booked the
following orders to supply during the next 5 weeks.
Formulate only the L.P. model to develop a training schedule that minimizes the labour cost
over the five weeks period.
• Let 𝑥𝑖 the Number of employee starting training at week i
• Minimize: Z=300[5 𝑥1+ 4 𝑥2 + 3 𝑥3 + 2 𝑥4 + 𝑥5]
• Subject to: 𝑥1+ 𝑥2 + 𝑥3 + 𝑥4 + 𝑥5 = 150
• Week1: 300 −
𝑥1
3
≥ 280
• Week2: 300 −
𝑥1
3
−
𝑥2
3
≥ 298
• Week3: 300 + 𝑥1 −
𝑥2
3
−
𝑥3
3
≥ 305
• Week4: 300 + 𝑥1 + 𝑥2 −
𝑥3
3
−
𝑥4
3
≥ 360
• Week5: 300 + 𝑥1 + 𝑥2 + 𝑥3 −
𝑥4
3
−
𝑥5
3
≥ 400
• With all variables non-negative and integer
w1 w2 w3 w4 w5
𝑥1
𝑥2
𝑥3 𝑥4
𝑥5
Employee starting at week 1 would
get salary for all the five weeks
There are 300 trained
employees available. Out of
𝑥1
3
will be required to train
𝑥1trainees
Example 11: Product Mix Model
Part A Part B Cost/hour
Machining capacity 25/hr 40/hr 20
Boring capacity 28/hr 35/hr 14
Polishing capacity 35/hr 25/hr 17
7
•A firm manufactures two items. It purchases castings which are then
machined, bored and polished. Castings for item A and B costs $2 and $3
respectively and are sold at $5 and $6 respectively. Running costs of the
three machines are $20, $14 and $17 per hour respectively. Capacities of
the machines are as follows:
Formulate only the L.P. model to determine the product mix that
maximizes the profit.
8
Product Mix Model
Part B($)
Part A($)
20/40=0.5
20/25 =0.8
Machining cost
14/35=0.4
14/28=0.5
Boring cost
17/25=0.7
17/35
Polishing cost
3
2
Casting cost
4.6
3.8
Total cost
6
5
Selling Price
1.4
1.2
Profit
Let 𝑥1and 𝑥2 the number of units of A and B to be
manufactured per hour
Maximize: Z=1.2 𝑥1 + 1.4𝑥2
8
1
25
𝑥1 +
1
40
𝑥2 ≤ 1
1
28
𝑥1 +
1
35
𝑥2 ≤ 1
1
35
𝑥1 +
1
25
𝑥2 ≤ 1
𝑥1𝑎𝑛𝑑 𝑥2 ≥ 0
Constraints are on the capacities of the
machines. For one hour running of each
machine
Part A Part B Cost/hour
Machining
capacity
25/hr 40/hr 20
Boring
capacity
28/hr 35/hr 14
Polishing
capacity
35/hr 25/hr 17
Example 12: Investment Model
Type of Loan Interest rate
(%)
Bad debt
(probability)
Persnal 17 0.10
Car 14 0.07
Housing 11 0.05
Agriculture 10 0.08
Commercial 13 0.06
9
•A bank is in the process of formulating its loan policy involving a maximum
of $600 million. Table below gives the relevant types of loans. Bad debts are
not recoverable and produce no interest revenue. To meet competition from
other banks, the following policy guidelines have been set: at least 40% of the
funds must be allocated to the agricultural and commercial loans. Funds
allocated to the houses must be at least 50% of all loans given to personal,
car. The overall bad debts on all loans may not exceed 0.06. Formulate the
Linear Program Model to determine the optimal loan allocation.
• Decision Variables:
• Let 𝑥1: 𝑡ℎ𝑒 𝑎𝑚𝑜𝑛𝑡 𝑜𝑓 𝑚𝑜𝑛𝑒𝑦 𝑎𝑙𝑙𝑜𝑐𝑎𝑡𝑒𝑑 𝑡𝑜 𝑝𝑒𝑟𝑠𝑜𝑛𝑎𝑙 𝐿𝑜𝑎𝑛
• Let 𝑥2: 𝑡ℎ𝑒 𝑎𝑚𝑜𝑛𝑡 𝑜𝑓 𝑚𝑜𝑛𝑒𝑦 𝑎𝑙𝑙𝑜𝑐𝑎𝑡𝑒𝑑 𝑡𝑜 𝐶𝑎𝑟 𝐿𝑜𝑎𝑛
• Let 𝑥3: 𝑡ℎ𝑒 𝑎𝑚𝑜𝑛𝑡 𝑜𝑓 𝑚𝑜𝑛𝑒𝑦 𝑎𝑙𝑙𝑜𝑐𝑎𝑡𝑒𝑑 𝑡𝑜 𝐻𝑜𝑢𝑠𝑒 𝐿𝑜𝑎𝑛
• Let 𝑥4: 𝑡ℎ𝑒 𝑎𝑚𝑜𝑛𝑡 𝑜𝑓 𝑚𝑜𝑛𝑒𝑦 𝑎𝑙𝑙𝑜𝑐𝑎𝑡𝑒𝑑 𝑡𝑜 𝐹𝑎𝑟𝑚𝑖𝑛𝑔 𝐿𝑜𝑎𝑛
• Let 𝑥5: 𝑡ℎ𝑒 𝑎𝑚𝑜𝑛𝑡 𝑜𝑓 𝑚𝑜𝑛𝑒𝑦 𝑎𝑙𝑙𝑜𝑐𝑎𝑡𝑒𝑑 𝑡𝑜 𝑐𝑜𝑚𝑚𝑒𝑟𝑐𝑖𝑎𝑙 𝐿𝑜𝑎𝑛
10
Investment Model
• Objective is to Maximize the net return
• 𝑛𝑒𝑡 𝑟𝑒𝑡𝑢𝑟𝑛 = 𝑡𝑜𝑡𝑎𝑙 𝑖𝑛𝑡𝑒𝑟𝑒𝑠𝑡 − 𝑙𝑜𝑠𝑡 𝑏𝑎𝑑 𝑑𝑒𝑏𝑡
• 𝑡𝑜𝑡𝑎𝑙 𝑖𝑛𝑡𝑒𝑟𝑒𝑠𝑡=0.17(0.90𝑥1) + 0.14 0.93𝑥2 + 0.11 0.95𝑥3
+ 0.1 0.92𝑥4 + 0.13(0.94𝑥5)
• Lost Bad debt= 0.1𝑥1 + 0.07𝑥2 + 0.05𝑥3 + 0.08𝑥4 + 0.06𝑥5
11
Type of Loan Interest
rate (%)
Bad debt
(probabilit
y)
Good
standing
Loan
Persnal 17 0.10 0.90
Car 14 0.07 0.93
Housing 11 0.05 0.95
Agriculture 10 0.08 0.92
Commercial 13 0.06 0.94
• Subject to: 𝑥1 + 𝑥2+𝑥3 + 𝑥4 + 𝑥5 ≤ 600
• 𝑥4 + 𝑥5 ≥ 0.4 𝑥1 + 𝑥2+𝑥3 + 𝑥4 + 𝑥5
• 𝑥3 ≥ 0.5 𝑥1 + 𝑥2
• 0.1𝑥1 + 0.07𝑥2 + 0.05𝑥3 + 0.08𝑥4 + 0.06𝑥5 ≤ 0.06 𝑥1 + 𝑥2+𝑥3 + 𝑥4 + 𝑥5
• With all variables nonnegative
12
Example 12: Investment Model
Example 13: Machining Model
13
Method
Input per run (units) Output per run
(units)
Raw material I Raw material II Part A Part B
1 7 5 6 4
2 4 7 5 8
3 2 9 7 3
•A factory manufactures a product each unit of which consists of 5
units of part A and 4 units of part B. the two parts A and B require
different raw materials of which 120 units and 240 units respectively
are available. These parts can be manufactured by three different
methods. Raw material requirements per production run and the
number of units for each part produced are given below.
Determine the number of production runs for each method so as to
maximize the total number of complete units of the final product.
Example 13
• Let 𝑥1: the number of runs of Method1
• Let 𝑥2: the number of runs of Method2
• Let 𝑥3: the number of runs of Method3
• The Number of Part A unit to be produced 6 𝑥1+5 𝑥2 + 7𝑥3
• The Number of Part B unit to be produced 4 𝑥1+8 𝑥2 + 3𝑥3
• The Number of complete units to be produced
Y=Min(
6 𝑥1+5 𝑥2+7𝑥3
5
,
4 𝑥1+8 𝑥2+3𝑥3
4
)
14
Method
Input per run (units) Output per run
(units)
Raw material I Raw material II Part A Part B
1 7 5 6 4
2 4 7 5 8
3 2 9 7 3
• Maximize Z=Y
• Subject to:
• 7 𝑥1+4 𝑥2 + 2𝑥3 ≤ 120
• 5 𝑥1+7 𝑥2 + 9𝑥3 ≤ 240
• With all variables Non-negative and integer
15
Method
Input per run (units) Output per run
(units)
Raw material I Raw material II Part A Part B
1 7 5 6 4
2 4 7 5 8
3 2 9 7 3
16

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OR_L03.pdf

  • 1. Operations Research Lecture 3: Linear Programming: Mathematical Models (Part II) Instructors: Dr. Safaa Amin Dr. Doaa Ezzat
  • 2. width 9 7 5 Min Number of rolls: 200 120 450 2 Rolls of paper having a fixed length and width 20 feet are being manufactured by a paper company. These rolls have to be cut with different knife setting to satisfy the following demand: Obtain the linear programming formulation of the problem to determine the cutting pattern, so that the demand is satisfied and wastage of paper is minimized (Formulate only the linear problem model) Example 9: Trim Loss Problem
  • 3. Trim Loss Model 3 The different knife setting are: 20 feet 9 9 2 Loss=2 K1 9 7 4 Loss=4 K2 5 5 5 Loss=0 K3 9 5 1 Loss=1 K4 5 5 5 5 3 Loss=3 K5 7 7 1 Loss=1 K6 7 5
  • 4. Trim loss Model cont… K6 K5 K4 K3 K2 K1 1 2 2 4 0 0 Width 5 2 1 0 0 1 0 Width 7 0 0 1 0 1 2 Width 9 1 3 1 0 4 2 Loss Width 5 Requirement Minimize: 𝑍 = 2𝑥1 + 4𝑥2+0𝑥3 + 𝑥4 + 3𝑥5 + 𝑥6 Let 𝑥1 the number of rolls that will be cut by knife setting K1 Let 𝑥𝑖 the number of rolls that will be cut by knife setting Ki, i=1,2…6 Subject to: 4𝑥3 + 2𝑥4 + 2𝑥5 + 𝑥6 ≥ 450 𝑥2 + 𝑥5 + 2𝑥6 ≥ 120 2𝑥1 + 𝑥2 + 𝑥4 ≥ 200 Width 7 Requirement Width 9 Requirement With all Variable Non-negative and integer
  • 5. Example 10: Man Power Model week 1 2 3 4 5 No. of cans 280 298 305 360 400 5 A Company, engaged in producing tinned food, has 300 trained employees on the rolls, each of whom can produce one can of food in a week, due to developing taste of the public for this kind of food, the company plans to add to the existing labour force by employing 150 persons, in a phased manner, over the next 5 weeks. The newcomers would have to undergo a two-weeks training program before being put to work. The training is to be given by employees from among the existing ones and it is known that one employee can train three trainees. Assume the training is off-the-job. However, the trainees would be remunerated at the rate of $300 per week, the same rate as for the trainers. The company has booked the following orders to supply during the next 5 weeks. Formulate only the L.P. model to develop a training schedule that minimizes the labour cost over the five weeks period.
  • 6. • Let 𝑥𝑖 the Number of employee starting training at week i • Minimize: Z=300[5 𝑥1+ 4 𝑥2 + 3 𝑥3 + 2 𝑥4 + 𝑥5] • Subject to: 𝑥1+ 𝑥2 + 𝑥3 + 𝑥4 + 𝑥5 = 150 • Week1: 300 − 𝑥1 3 ≥ 280 • Week2: 300 − 𝑥1 3 − 𝑥2 3 ≥ 298 • Week3: 300 + 𝑥1 − 𝑥2 3 − 𝑥3 3 ≥ 305 • Week4: 300 + 𝑥1 + 𝑥2 − 𝑥3 3 − 𝑥4 3 ≥ 360 • Week5: 300 + 𝑥1 + 𝑥2 + 𝑥3 − 𝑥4 3 − 𝑥5 3 ≥ 400 • With all variables non-negative and integer w1 w2 w3 w4 w5 𝑥1 𝑥2 𝑥3 𝑥4 𝑥5 Employee starting at week 1 would get salary for all the five weeks There are 300 trained employees available. Out of 𝑥1 3 will be required to train 𝑥1trainees
  • 7. Example 11: Product Mix Model Part A Part B Cost/hour Machining capacity 25/hr 40/hr 20 Boring capacity 28/hr 35/hr 14 Polishing capacity 35/hr 25/hr 17 7 •A firm manufactures two items. It purchases castings which are then machined, bored and polished. Castings for item A and B costs $2 and $3 respectively and are sold at $5 and $6 respectively. Running costs of the three machines are $20, $14 and $17 per hour respectively. Capacities of the machines are as follows: Formulate only the L.P. model to determine the product mix that maximizes the profit.
  • 8. 8 Product Mix Model Part B($) Part A($) 20/40=0.5 20/25 =0.8 Machining cost 14/35=0.4 14/28=0.5 Boring cost 17/25=0.7 17/35 Polishing cost 3 2 Casting cost 4.6 3.8 Total cost 6 5 Selling Price 1.4 1.2 Profit Let 𝑥1and 𝑥2 the number of units of A and B to be manufactured per hour Maximize: Z=1.2 𝑥1 + 1.4𝑥2 8 1 25 𝑥1 + 1 40 𝑥2 ≤ 1 1 28 𝑥1 + 1 35 𝑥2 ≤ 1 1 35 𝑥1 + 1 25 𝑥2 ≤ 1 𝑥1𝑎𝑛𝑑 𝑥2 ≥ 0 Constraints are on the capacities of the machines. For one hour running of each machine Part A Part B Cost/hour Machining capacity 25/hr 40/hr 20 Boring capacity 28/hr 35/hr 14 Polishing capacity 35/hr 25/hr 17
  • 9. Example 12: Investment Model Type of Loan Interest rate (%) Bad debt (probability) Persnal 17 0.10 Car 14 0.07 Housing 11 0.05 Agriculture 10 0.08 Commercial 13 0.06 9 •A bank is in the process of formulating its loan policy involving a maximum of $600 million. Table below gives the relevant types of loans. Bad debts are not recoverable and produce no interest revenue. To meet competition from other banks, the following policy guidelines have been set: at least 40% of the funds must be allocated to the agricultural and commercial loans. Funds allocated to the houses must be at least 50% of all loans given to personal, car. The overall bad debts on all loans may not exceed 0.06. Formulate the Linear Program Model to determine the optimal loan allocation.
  • 10. • Decision Variables: • Let 𝑥1: 𝑡ℎ𝑒 𝑎𝑚𝑜𝑛𝑡 𝑜𝑓 𝑚𝑜𝑛𝑒𝑦 𝑎𝑙𝑙𝑜𝑐𝑎𝑡𝑒𝑑 𝑡𝑜 𝑝𝑒𝑟𝑠𝑜𝑛𝑎𝑙 𝐿𝑜𝑎𝑛 • Let 𝑥2: 𝑡ℎ𝑒 𝑎𝑚𝑜𝑛𝑡 𝑜𝑓 𝑚𝑜𝑛𝑒𝑦 𝑎𝑙𝑙𝑜𝑐𝑎𝑡𝑒𝑑 𝑡𝑜 𝐶𝑎𝑟 𝐿𝑜𝑎𝑛 • Let 𝑥3: 𝑡ℎ𝑒 𝑎𝑚𝑜𝑛𝑡 𝑜𝑓 𝑚𝑜𝑛𝑒𝑦 𝑎𝑙𝑙𝑜𝑐𝑎𝑡𝑒𝑑 𝑡𝑜 𝐻𝑜𝑢𝑠𝑒 𝐿𝑜𝑎𝑛 • Let 𝑥4: 𝑡ℎ𝑒 𝑎𝑚𝑜𝑛𝑡 𝑜𝑓 𝑚𝑜𝑛𝑒𝑦 𝑎𝑙𝑙𝑜𝑐𝑎𝑡𝑒𝑑 𝑡𝑜 𝐹𝑎𝑟𝑚𝑖𝑛𝑔 𝐿𝑜𝑎𝑛 • Let 𝑥5: 𝑡ℎ𝑒 𝑎𝑚𝑜𝑛𝑡 𝑜𝑓 𝑚𝑜𝑛𝑒𝑦 𝑎𝑙𝑙𝑜𝑐𝑎𝑡𝑒𝑑 𝑡𝑜 𝑐𝑜𝑚𝑚𝑒𝑟𝑐𝑖𝑎𝑙 𝐿𝑜𝑎𝑛 10 Investment Model
  • 11. • Objective is to Maximize the net return • 𝑛𝑒𝑡 𝑟𝑒𝑡𝑢𝑟𝑛 = 𝑡𝑜𝑡𝑎𝑙 𝑖𝑛𝑡𝑒𝑟𝑒𝑠𝑡 − 𝑙𝑜𝑠𝑡 𝑏𝑎𝑑 𝑑𝑒𝑏𝑡 • 𝑡𝑜𝑡𝑎𝑙 𝑖𝑛𝑡𝑒𝑟𝑒𝑠𝑡=0.17(0.90𝑥1) + 0.14 0.93𝑥2 + 0.11 0.95𝑥3 + 0.1 0.92𝑥4 + 0.13(0.94𝑥5) • Lost Bad debt= 0.1𝑥1 + 0.07𝑥2 + 0.05𝑥3 + 0.08𝑥4 + 0.06𝑥5 11 Type of Loan Interest rate (%) Bad debt (probabilit y) Good standing Loan Persnal 17 0.10 0.90 Car 14 0.07 0.93 Housing 11 0.05 0.95 Agriculture 10 0.08 0.92 Commercial 13 0.06 0.94
  • 12. • Subject to: 𝑥1 + 𝑥2+𝑥3 + 𝑥4 + 𝑥5 ≤ 600 • 𝑥4 + 𝑥5 ≥ 0.4 𝑥1 + 𝑥2+𝑥3 + 𝑥4 + 𝑥5 • 𝑥3 ≥ 0.5 𝑥1 + 𝑥2 • 0.1𝑥1 + 0.07𝑥2 + 0.05𝑥3 + 0.08𝑥4 + 0.06𝑥5 ≤ 0.06 𝑥1 + 𝑥2+𝑥3 + 𝑥4 + 𝑥5 • With all variables nonnegative 12 Example 12: Investment Model
  • 13. Example 13: Machining Model 13 Method Input per run (units) Output per run (units) Raw material I Raw material II Part A Part B 1 7 5 6 4 2 4 7 5 8 3 2 9 7 3 •A factory manufactures a product each unit of which consists of 5 units of part A and 4 units of part B. the two parts A and B require different raw materials of which 120 units and 240 units respectively are available. These parts can be manufactured by three different methods. Raw material requirements per production run and the number of units for each part produced are given below. Determine the number of production runs for each method so as to maximize the total number of complete units of the final product.
  • 14. Example 13 • Let 𝑥1: the number of runs of Method1 • Let 𝑥2: the number of runs of Method2 • Let 𝑥3: the number of runs of Method3 • The Number of Part A unit to be produced 6 𝑥1+5 𝑥2 + 7𝑥3 • The Number of Part B unit to be produced 4 𝑥1+8 𝑥2 + 3𝑥3 • The Number of complete units to be produced Y=Min( 6 𝑥1+5 𝑥2+7𝑥3 5 , 4 𝑥1+8 𝑥2+3𝑥3 4 ) 14 Method Input per run (units) Output per run (units) Raw material I Raw material II Part A Part B 1 7 5 6 4 2 4 7 5 8 3 2 9 7 3
  • 15. • Maximize Z=Y • Subject to: • 7 𝑥1+4 𝑥2 + 2𝑥3 ≤ 120 • 5 𝑥1+7 𝑥2 + 9𝑥3 ≤ 240 • With all variables Non-negative and integer 15 Method Input per run (units) Output per run (units) Raw material I Raw material II Part A Part B 1 7 5 6 4 2 4 7 5 8 3 2 9 7 3
  • 16. 16