A box contain 4 blue marbles, 1 red marbles, and 6 green marble. Two marbles are selected at random from the box. If X is a random variable that counts the number of blue marbles selected, find the probability that one blue marble is chosen. Solution Total=4+1+6=11 The probability is (1C4* 1C7)/2C11 =(4*7)/(11*10/2) =0.5090909.