SlideShare a Scribd company logo
1 of 41
Download to read offline
GMAT QUANTITATIVE REASONING
ELEMENTARY PROBABILITY
DATA SUFFICIENCY
Diagnostic Test
Question
What is the probability that two students selected to the
elocution competition are both boys?
Statement 1: The ratio of boys to girls in the class is 3 : 4
Statement 2: There are 11more girls in the class.
Step 1
Get clarity on when the data is sufficient
What is the probability that two students selected are both boys?
We will not even look at the statements while answering the following questions
When is the data sufficient and when not?
What is the probability that two students selected are both boys?
We will not even look at the statements while answering the following questions
When is the data sufficient and when not?
The data is sufficient if we are able
to get ONE value for the probability.
What is the probability that two students selected are both boys?
We will not even look at the statements while answering the following questions
When is the data sufficient and when not?
The data is sufficient if we are able
to get ONE value for the probability.
For instance, if we get more than one
value or if an unknown is part of the
expression, the data is NOT
sufficient.
What is the probability that two students selected are both boys?
We will not even look at the statements while answering the following questions
When is the data sufficient and when not? What expression will give the probability ?
The data is sufficient if we are able
to get ONE value for the probability.
For instance, if we get more than one
value or if an unknown is part of the
expression, the data is NOT
sufficient.
What is the probability that two students selected are both boys?
We will not even look at the statements while answering the following questions
When is the data sufficient and when not? What expression will give the probability ?
The data is sufficient if we are able
to get ONE value for the probability.
For instance, if we get more than one
value or if an unknown is part of the
expression, the data is NOT
sufficient.
Let the number of boys in the class
be ‘b’ and let there be ‘t’ total
students.
What is the probability that two students selected are both boys?
We will not even look at the statements while answering the following questions
When is the data sufficient and when not? What expression will give the probability ?
The data is sufficient if we are able
to get ONE value for the probability.
For instance, if we get more than one
value or if an unknown is part of the
expression, the data is NOT
sufficient.
Let the number of boys in the class
be ‘b’ and let there be ‘t’ total
students.
Probability that two students
selected are both boys =
b(b-1)
t(t-1)
Step 2
Let’s evaluate statement 1 alone
Statement 1: The ratio of boys to girls in the class is 3 : 4
What is the probability that two students selected are both boys?
· Ratio of boys to girls 3 : 4
Statement 1: The ratio of boys to girls in the class is 3 : 4
What is the probability that two students selected are both boys?
· Ratio of boys to girls 3 : 4
If there are 3k boys, there will be 4k
girls and a total of 7k students.
·
Statement 1: The ratio of boys to girls in the class is 3 : 4
What is the probability that two students selected are both boys?
· Ratio of boys to girls 3 : 4
If there are 3k boys, there will be 4k
girls and a total of 7k students.
·
We determined in the last slide that
for ‘b’ boys and ‘t’ total students, the
required probability is
b(b−1)
t(t−1)
·
Statement 1: The ratio of boys to girls in the class is 3 : 4
What is the probability that two students selected are both boys?
· Ratio of boys to girls 3 : 4
If there are 3k boys, there will be 4k
girls and a total of 7k students.
·
We determined in the last slide that
for ‘b’ boys and ‘t’ total students, the
required probability is
b(b−1)
t(t−1)
·
 the probability =
3k(3k−1)
7k(7k−1)
=
3(3k-1)
7(7k-1)
Statement 1: The ratio of boys to girls in the class is 3 : 4
What is the probability that two students selected are both boys?
· Ratio of boys to girls 3 : 4
If there are 3k boys, there will be 4k
girls and a total of 7k students.
·
We determined in the last slide that
for ‘b’ boys and ‘t’ total students, the
required probability is
b(b−1)
t(t−1)
·
 the probability =
3k(3k−1)
7k(7k−1)
=
3(3k-1)
7(7k-1)
Notice that the probability expression comprises a
‘k’ term.
The probability value will depend on the value that
k takes.
So, we CANNOT determine the probability uniquely.
Statement 1: The ratio of boys to girls in the class is 3 : 4
Statement 1 alone is NOT sufficient
What is the probability that two students selected are both boys?
· Ratio of boys to girls 3 : 4
If there are 3k boys, there will be 4k
girls and a total of 7k students.
·
We determined in the last slide that
for ‘b’ boys and ‘t’ total students, the
required probability is
b(b−1)
t(t−1)
·
 the probability =
3k(3k−1)
7k(7k−1)
=
3(3k-1)
7(7k-1)
Notice that the probability expression comprises a
‘k’ term.
The probability value will depend on the value that
k takes.
So, we CANNOT determine the probability uniquely.
Statement 1: The ratio of boys to girls in the class is 3 : 4
Eliminate choices A and D
Statement 1 alone is NOT sufficient
What is the probability that two students selected are both boys?
· Ratio of boys to girls 3 : 4
If there are 3k boys, there will be 4k
girls and a total of 7k students.
·
We determined in the last slide that
for ‘b’ boys and ‘t’ total students, the
required probability is
b(b−1)
t(t−1)
·
 the probability =
3k(3k−1)
7k(7k−1)
=
3(3k-1)
7(7k-1)
Notice that the probability expression comprises a
‘k’ term.
The probability value will depend on the value that
k takes.
So, we CANNOT determine the probability uniquely.
Statement 1: The ratio of boys to girls in the class is 3 : 4
Choices narrow down to B, C or E.
Eliminate choices A and D
Statement 1 alone is NOT sufficient
What is the probability that two students selected are both boys?
· Ratio of boys to girls 3 : 4
If there are 3k boys, there will be 4k
girls and a total of 7k students.
·
We determined in the last slide that
for ‘b’ boys and ‘t’ total students, the
required probability is
b(b−1)
t(t−1)
·
 the probability =
3k(3k−1)
7k(7k−1)
=
3(3k-1)
7(7k-1)
Notice that the probability expression comprises a
‘k’ term.
The probability value will depend on the value that
k takes.
So, we CANNOT determine the probability uniquely.
Step 3
Let’s evaluate statement 2 alone.
Statement 2 : There are 11more girls in the class.
What is the probability that two students selected are both boys?
There are 11 more girls in the class
Statement 2 : There are 11more girls in the class.
What is the probability that two students selected are both boys?
There are 11 more girls in the class
· If the number of boys is 10, there
will be 21 girls and 31 students.
Statement 2 : There are 11more girls in the class.
What is the probability that two students selected are both boys?
There are 11 more girls in the class
· If the number of boys is 10, there
will be 21 girls and 31 students.
Probability =
10×9
31×30
Statement 2 : There are 11more girls in the class.
What is the probability that two students selected are both boys?
There are 11 more girls in the class
· If the number of boys is 10, there
will be 21 girls and 31 students.
Probability =
10×9
31×30
· If the number of boys is 20, there
will be 31 girls and 51 students.
Statement 2 : There are 11more girls in the class.
What is the probability that two students selected are both boys?
There are 11 more girls in the class
· If the number of boys is 10, there
will be 21 girls and 31 students.
Probability =
10×9
31×30
· If the number of boys is 20, there
will be 31 girls and 51 students.
Probability =
20×19
51×50
Statement 2 : There are 11more girls in the class.
What is the probability that two students selected are both boys?
There are 11 more girls in the class
· If the number of boys is 10, there
will be 21 girls and 31 students.
Probability =
10×9
31×30
· If the number of boys is 20, there
will be 31 girls and 51 students.
Probability =
20×19
51×50
We are NOT able to
determine the probability
uniquely with this
statement.
Statement 2 : There are 11more girls in the class.
What is the probability that two students selected are both boys?
There are 11 more girls in the class
· If the number of boys is 10, there
will be 21 girls and 31 students.
Probability =
10×9
31×30
· If the number of boys is 20, there
will be 31 girls and 51 students.
Probability =
20×19
51×50
We are NOT able to
determine the probability
uniquely with this
statement.
Statement 2 alone is NOT sufficient
Statement 2 : There are 11more girls in the class.
Eliminate choice B
What is the probability that two students selected are both boys?
There are 11 more girls in the class
· If the number of boys is 10, there
will be 21 girls and 31 students.
Probability =
10×9
31×30
· If the number of boys is 20, there
will be 31 girls and 51 students.
Probability =
20×19
51×50
We are NOT able to
determine the probability
uniquely with this
statement.
Statement 2 alone is NOT sufficient
Statement 2 : There are 11more girls in the class.
Choices narrow down to C or E.
Eliminate choice B
What is the probability that two students selected are both boys?
There are 11 more girls in the class
· If the number of boys is 10, there
will be 21 girls and 31 students.
Probability =
10×9
31×30
· If the number of boys is 20, there
will be 31 girls and 51 students.
Probability =
20×19
51×50
We are NOT able to
determine the probability
uniquely with this
statement.
Statement 2 alone is NOT sufficient
Step 4
Let’s combine data from both the
statements.
Statements Together : The ratio of boys to girls in the class is 3 : 4 and there are 11 more girls in the class
What is the probability that two students selected are both boys?
We determined that for ‘b’ boys and ‘t’ total
students, the required probability is
b(b−1)
t(t−1)
·
Statements Together : The ratio of boys to girls in the class is 3 : 4 and there are 11 more girls in the class
What is the probability that two students selected are both boys?
We determined that for ‘b’ boys and ‘t’ total
students, the required probability is
b(b−1)
t(t−1)
·
From statement 1, we know there are 3k boys
and 4k girls.
·
Statements Together : The ratio of boys to girls in the class is 3 : 4 and there are 11 more girls in the class
What is the probability that two students selected are both boys?
We determined that for ‘b’ boys and ‘t’ total
students, the required probability is
b(b−1)
t(t−1)
·
From statement 1, we know there are 3k boys
and 4k girls.
·
From statement 2, we know 4k – 3k = k = 11.·
Statements Together : The ratio of boys to girls in the class is 3 : 4 and there are 11 more girls in the class
What is the probability that two students selected are both boys?
We determined that for ‘b’ boys and ‘t’ total
students, the required probability is
b(b−1)
t(t−1)
·
From statement 1, we know there are 3k boys
and 4k girls.
·
So, the class has 33 boys and 44 girls and 77
students.
·
From statement 2, we know 4k – 3k = k = 11.·
Statements Together : The ratio of boys to girls in the class is 3 : 4 and there are 11 more girls in the class
What is the probability that two students selected are both boys?
We determined that for ‘b’ boys and ‘t’ total
students, the required probability is
b(b−1)
t(t−1)
·
From statement 1, we know there are 3k boys
and 4k girls.
·
So, the class has 33 boys and 44 girls and 77
students.
·
From statement 2, we know 4k – 3k = k = 11.·
Probability =
33×32
77×76
Statements Together : The ratio of boys to girls in the class is 3 : 4 and there are 11 more girls in the class
What is the probability that two students selected are both boys?
We determined that for ‘b’ boys and ‘t’ total
students, the required probability is
b(b−1)
t(t−1)
·
From statement 1, we know there are 3k boys
and 4k girls.
·
So, the class has 33 boys and 44 girls and 77
students.
·
From statement 2, we know 4k – 3k = k = 11.·
Probability =
33×32
77×76
Using the two statements together,
we could determine the probability
uniquely.
Statements Together : The ratio of boys to girls in the class is 3 : 4 and there are 11 more girls in the class
What is the probability that two students selected are both boys?
We determined that for ‘b’ boys and ‘t’ total
students, the required probability is
b(b−1)
t(t−1)
·
From statement 1, we know there are 3k boys
and 4k girls.
·
So, the class has 33 boys and 44 girls and 77
students.
·
From statement 2, we know 4k – 3k = k = 11.·
Probability =
33×32
77×76
Using the two statements together,
we could determine the probability
uniquely.
Together the statements are SUFFICIENT.
Statements Together : The ratio of boys to girls in the class is 3 : 4 and there are 11 more girls in the class
Eliminate choice E
What is the probability that two students selected are both boys?
We determined that for ‘b’ boys and ‘t’ total
students, the required probability is
b(b−1)
t(t−1)
·
From statement 1, we know there are 3k boys
and 4k girls.
·
So, the class has 33 boys and 44 girls and 77
students.
·
From statement 2, we know 4k – 3k = k = 11.·
Probability =
33×32
77×76
Using the two statements together,
we could determine the probability
uniquely.
Together the statements are SUFFICIENT.
Statements Together : The ratio of boys to girls in the class is 3 : 4 and there are 11 more girls in the class
Answer is choice C
Eliminate choice E
What is the probability that two students selected are both boys?
We determined that for ‘b’ boys and ‘t’ total
students, the required probability is
b(b−1)
t(t−1)
·
From statement 1, we know there are 3k boys
and 4k girls.
·
So, the class has 33 boys and 44 girls and 77
students.
·
From statement 2, we know 4k – 3k = k = 11.·
Probability =
33×32
77×76
Using the two statements together,
we could determine the probability
uniquely.
Together the statements are SUFFICIENT.
Try this variant
What is the probability that a student selected to the
elocution competition is a boy?
Statement 1: The ratio of boys to girls in the class is 3 : 4
Statement 2: There are 11more girls in the class.
For GMAT Prep
Visit http://www.4gmat.com
GMAT Classes and GMAT Preparation
Send your comments / feedback to
info@4gmat.com
4GMAT
We offer classroom training in Chennai and Bangalore
Tutors include GMAT 98%ilers, US B School
graduates and IIM graduates
Call us: +91 95000 48484
Mail us: info@4gmat.com

More Related Content

Viewers also liked

Questions of basic probability for aptitude test
Questions of basic probability for aptitude test Questions of basic probability for aptitude test
Questions of basic probability for aptitude test
Dr. Trilok Kumar Jain
 
Module 7 triangle trigonometry super final
Module 7 triangle trigonometry super finalModule 7 triangle trigonometry super final
Module 7 triangle trigonometry super final
Dods Dodong
 

Viewers also liked (20)

4GMAT Diagnostic Test Q16 - Data Sufficiency - Statistics - Averages
4GMAT Diagnostic Test Q16 - Data Sufficiency - Statistics - Averages4GMAT Diagnostic Test Q16 - Data Sufficiency - Statistics - Averages
4GMAT Diagnostic Test Q16 - Data Sufficiency - Statistics - Averages
 
4GMAT Diagnostic Test Q12 - Problem Solving - Word Problem - Algebra - Ratios
4GMAT Diagnostic Test Q12 - Problem Solving - Word Problem - Algebra - Ratios4GMAT Diagnostic Test Q12 - Problem Solving - Word Problem - Algebra - Ratios
4GMAT Diagnostic Test Q12 - Problem Solving - Word Problem - Algebra - Ratios
 
4GMAT Diagnostic Test Q4 - Data Sufficiency : Number Properties
4GMAT Diagnostic Test Q4 - Data Sufficiency : Number Properties4GMAT Diagnostic Test Q4 - Data Sufficiency : Number Properties
4GMAT Diagnostic Test Q4 - Data Sufficiency : Number Properties
 
4GMAT Diagnostic Test 17 - Data Sufficiency - Algebra - Linear Equations
4GMAT Diagnostic Test 17 - Data Sufficiency - Algebra - Linear Equations4GMAT Diagnostic Test 17 - Data Sufficiency - Algebra - Linear Equations
4GMAT Diagnostic Test 17 - Data Sufficiency - Algebra - Linear Equations
 
4GMAT Diagnostic Test Q6 - Problem Solving - Geometry, Triangles
4GMAT Diagnostic Test Q6 - Problem Solving - Geometry, Triangles4GMAT Diagnostic Test Q6 - Problem Solving - Geometry, Triangles
4GMAT Diagnostic Test Q6 - Problem Solving - Geometry, Triangles
 
4GMAT Diagnostic Test Q1 - Problem Solving : Number Properties HCF
4GMAT Diagnostic Test Q1 - Problem Solving : Number Properties HCF4GMAT Diagnostic Test Q1 - Problem Solving : Number Properties HCF
4GMAT Diagnostic Test Q1 - Problem Solving : Number Properties HCF
 
4GMAT Diagnostic Test Q5 - Data Sufficiency : Algebra, equations
4GMAT Diagnostic Test Q5 - Data Sufficiency : Algebra, equations4GMAT Diagnostic Test Q5 - Data Sufficiency : Algebra, equations
4GMAT Diagnostic Test Q5 - Data Sufficiency : Algebra, equations
 
GMAT Geometry - Hard Math Problem
GMAT Geometry - Hard Math ProblemGMAT Geometry - Hard Math Problem
GMAT Geometry - Hard Math Problem
 
4GMAT Diagnostic Test Q14 - Problem Solving - Coordinate Geometry
4GMAT Diagnostic Test Q14 - Problem Solving - Coordinate Geometry4GMAT Diagnostic Test Q14 - Problem Solving - Coordinate Geometry
4GMAT Diagnostic Test Q14 - Problem Solving - Coordinate Geometry
 
4GMAT Diagnostic Test Q19 - Problem Solving - Ratio Word Problem
4GMAT Diagnostic Test Q19 - Problem Solving - Ratio Word Problem4GMAT Diagnostic Test Q19 - Problem Solving - Ratio Word Problem
4GMAT Diagnostic Test Q19 - Problem Solving - Ratio Word Problem
 
4GMAT Diagnostic Test Q8 - Problem Solving : Simple and Compound Interest
4GMAT Diagnostic Test Q8 - Problem Solving : Simple and Compound Interest4GMAT Diagnostic Test Q8 - Problem Solving : Simple and Compound Interest
4GMAT Diagnostic Test Q8 - Problem Solving : Simple and Compound Interest
 
GMAT word problem in rates. Q-51 series by 4GMAT
GMAT word problem in rates. Q-51 series by 4GMATGMAT word problem in rates. Q-51 series by 4GMAT
GMAT word problem in rates. Q-51 series by 4GMAT
 
4GMAT Diagnostic Test Q11 - Problem Solving - Geometry circles and triangles
4GMAT Diagnostic Test Q11 - Problem Solving - Geometry circles and triangles4GMAT Diagnostic Test Q11 - Problem Solving - Geometry circles and triangles
4GMAT Diagnostic Test Q11 - Problem Solving - Geometry circles and triangles
 
Hard GMAT Math Question - Absolute Value
Hard GMAT Math Question - Absolute ValueHard GMAT Math Question - Absolute Value
Hard GMAT Math Question - Absolute Value
 
Questions of basic probability for aptitude test
Questions of basic probability for aptitude test Questions of basic probability for aptitude test
Questions of basic probability for aptitude test
 
Discrete Probability Distribution Test questions slideshare
Discrete Probability Distribution Test questions slideshareDiscrete Probability Distribution Test questions slideshare
Discrete Probability Distribution Test questions slideshare
 
Right triangle trigonometry
Right triangle trigonometryRight triangle trigonometry
Right triangle trigonometry
 
Probability - The Basics Workshop 1
Probability - The Basics Workshop 1Probability - The Basics Workshop 1
Probability - The Basics Workshop 1
 
Module 7 triangle trigonometry super final
Module 7 triangle trigonometry super finalModule 7 triangle trigonometry super final
Module 7 triangle trigonometry super final
 
Probability concept and Probability distribution
Probability concept and Probability distributionProbability concept and Probability distribution
Probability concept and Probability distribution
 

Similar to 4GMAT Diagnostic Test Q10 - Data Sufficiency - Elementary Probability

G6 m1-a-lesson 1-t
G6 m1-a-lesson 1-tG6 m1-a-lesson 1-t
G6 m1-a-lesson 1-t
mlabuski
 
Do boys or girls have a larger growth spurt between the grades o.docx
Do boys or girls have a larger growth spurt between the grades o.docxDo boys or girls have a larger growth spurt between the grades o.docx
Do boys or girls have a larger growth spurt between the grades o.docx
jacksnathalie
 
G6 m1-a-lesson 1-t
G6 m1-a-lesson 1-tG6 m1-a-lesson 1-t
G6 m1-a-lesson 1-t
mlabuski
 
Tucson State University offers two MBA programs. In the first progra.pdf
Tucson State University offers two MBA programs. In the first progra.pdfTucson State University offers two MBA programs. In the first progra.pdf
Tucson State University offers two MBA programs. In the first progra.pdf
gowravy1
 
G6 m1-a-lesson 2-t
G6 m1-a-lesson 2-tG6 m1-a-lesson 2-t
G6 m1-a-lesson 2-t
mlabuski
 
1. A home pregnancy test was given to women, then pregnancy was v
1.  A home pregnancy test was given to women, then pregnancy was v1.  A home pregnancy test was given to women, then pregnancy was v
1. A home pregnancy test was given to women, then pregnancy was v
AbbyWhyte974
 
1. A home pregnancy test was given to women, then pregnancy was v
1.  A home pregnancy test was given to women, then pregnancy was v1.  A home pregnancy test was given to women, then pregnancy was v
1. A home pregnancy test was given to women, then pregnancy was v
MartineMccracken314
 
RANDOM VARIABLESsssssssssssssssssssssssssssssssssssssssssssssssssssssssssssss...
RANDOM VARIABLESsssssssssssssssssssssssssssssssssssssssssssssssssssssssssssss...RANDOM VARIABLESsssssssssssssssssssssssssssssssssssssssssssssssssssssssssssss...
RANDOM VARIABLESsssssssssssssssssssssssssssssssssssssssssssssssssssssssssssss...
AngeliqueVicente1
 

Similar to 4GMAT Diagnostic Test Q10 - Data Sufficiency - Elementary Probability (20)

G6 m1-a-lesson 1-t
G6 m1-a-lesson 1-tG6 m1-a-lesson 1-t
G6 m1-a-lesson 1-t
 
Data sufficiency
Data sufficiencyData sufficiency
Data sufficiency
 
Lesson-Exemplar.docx
Lesson-Exemplar.docxLesson-Exemplar.docx
Lesson-Exemplar.docx
 
Do boys or girls have a larger growth spurt between the grades o.docx
Do boys or girls have a larger growth spurt between the grades o.docxDo boys or girls have a larger growth spurt between the grades o.docx
Do boys or girls have a larger growth spurt between the grades o.docx
 
BPHS Seniors: The Relationship Between Extracurricular Activities and Academics
BPHS Seniors: The Relationship Between Extracurricular Activities and AcademicsBPHS Seniors: The Relationship Between Extracurricular Activities and Academics
BPHS Seniors: The Relationship Between Extracurricular Activities and Academics
 
Probability Overview with Hands-on from Object Automation
 Probability Overview with Hands-on from Object Automation Probability Overview with Hands-on from Object Automation
Probability Overview with Hands-on from Object Automation
 
Q3_WEEK7 DAILY LOG LESSON PLAN FOR MATHEMATICS 10.docx
Q3_WEEK7 DAILY LOG LESSON PLAN FOR MATHEMATICS 10.docxQ3_WEEK7 DAILY LOG LESSON PLAN FOR MATHEMATICS 10.docx
Q3_WEEK7 DAILY LOG LESSON PLAN FOR MATHEMATICS 10.docx
 
Comprehension students3k.com
Comprehension students3k.comComprehension students3k.com
Comprehension students3k.com
 
G6 m1-a-lesson 1-t
G6 m1-a-lesson 1-tG6 m1-a-lesson 1-t
G6 m1-a-lesson 1-t
 
Probability of Simple and Compound Events
Probability of Simple and Compound EventsProbability of Simple and Compound Events
Probability of Simple and Compound Events
 
Module week 2 Q1
Module week 2 Q1Module week 2 Q1
Module week 2 Q1
 
Tucson State University offers two MBA programs. In the first progra.pdf
Tucson State University offers two MBA programs. In the first progra.pdfTucson State University offers two MBA programs. In the first progra.pdf
Tucson State University offers two MBA programs. In the first progra.pdf
 
probabilityofsimpleandcompoundevents-190217133041.pptx
probabilityofsimpleandcompoundevents-190217133041.pptxprobabilityofsimpleandcompoundevents-190217133041.pptx
probabilityofsimpleandcompoundevents-190217133041.pptx
 
DEV2
DEV2DEV2
DEV2
 
G6 m1-a-lesson 2-t
G6 m1-a-lesson 2-tG6 m1-a-lesson 2-t
G6 m1-a-lesson 2-t
 
1. A home pregnancy test was given to women, then pregnancy was v
1.  A home pregnancy test was given to women, then pregnancy was v1.  A home pregnancy test was given to women, then pregnancy was v
1. A home pregnancy test was given to women, then pregnancy was v
 
1. A home pregnancy test was given to women, then pregnancy was v
1.  A home pregnancy test was given to women, then pregnancy was v1.  A home pregnancy test was given to women, then pregnancy was v
1. A home pregnancy test was given to women, then pregnancy was v
 
Tesol 2011 assessment workshop morita mullaney and adams march 14 2011 version
Tesol 2011 assessment workshop morita mullaney and adams march 14 2011 versionTesol 2011 assessment workshop morita mullaney and adams march 14 2011 version
Tesol 2011 assessment workshop morita mullaney and adams march 14 2011 version
 
RANDOM VARIABLESsssssssssssssssssssssssssssssssssssssssssssssssssssssssssssss...
RANDOM VARIABLESsssssssssssssssssssssssssssssssssssssssssssssssssssssssssssss...RANDOM VARIABLESsssssssssssssssssssssssssssssssssssssssssssssssssssssssssssss...
RANDOM VARIABLESsssssssssssssssssssssssssssssssssssssssssssssssssssssssssssss...
 
Random variable
Random variableRandom variable
Random variable
 

Recently uploaded

Salient Features of India constitution especially power and functions
Salient Features of India constitution especially power and functionsSalient Features of India constitution especially power and functions
Salient Features of India constitution especially power and functions
KarakKing
 

Recently uploaded (20)

Python Notes for mca i year students osmania university.docx
Python Notes for mca i year students osmania university.docxPython Notes for mca i year students osmania university.docx
Python Notes for mca i year students osmania university.docx
 
Understanding Accommodations and Modifications
Understanding  Accommodations and ModificationsUnderstanding  Accommodations and Modifications
Understanding Accommodations and Modifications
 
Unit-V; Pricing (Pharma Marketing Management).pptx
Unit-V; Pricing (Pharma Marketing Management).pptxUnit-V; Pricing (Pharma Marketing Management).pptx
Unit-V; Pricing (Pharma Marketing Management).pptx
 
Kodo Millet PPT made by Ghanshyam bairwa college of Agriculture kumher bhara...
Kodo Millet  PPT made by Ghanshyam bairwa college of Agriculture kumher bhara...Kodo Millet  PPT made by Ghanshyam bairwa college of Agriculture kumher bhara...
Kodo Millet PPT made by Ghanshyam bairwa college of Agriculture kumher bhara...
 
Spatium Project Simulation student brief
Spatium Project Simulation student briefSpatium Project Simulation student brief
Spatium Project Simulation student brief
 
Salient Features of India constitution especially power and functions
Salient Features of India constitution especially power and functionsSalient Features of India constitution especially power and functions
Salient Features of India constitution especially power and functions
 
How to Create and Manage Wizard in Odoo 17
How to Create and Manage Wizard in Odoo 17How to Create and Manage Wizard in Odoo 17
How to Create and Manage Wizard in Odoo 17
 
Key note speaker Neum_Admir Softic_ENG.pdf
Key note speaker Neum_Admir Softic_ENG.pdfKey note speaker Neum_Admir Softic_ENG.pdf
Key note speaker Neum_Admir Softic_ENG.pdf
 
HMCS Vancouver Pre-Deployment Brief - May 2024 (Web Version).pptx
HMCS Vancouver Pre-Deployment Brief - May 2024 (Web Version).pptxHMCS Vancouver Pre-Deployment Brief - May 2024 (Web Version).pptx
HMCS Vancouver Pre-Deployment Brief - May 2024 (Web Version).pptx
 
Jamworks pilot and AI at Jisc (20/03/2024)
Jamworks pilot and AI at Jisc (20/03/2024)Jamworks pilot and AI at Jisc (20/03/2024)
Jamworks pilot and AI at Jisc (20/03/2024)
 
FSB Advising Checklist - Orientation 2024
FSB Advising Checklist - Orientation 2024FSB Advising Checklist - Orientation 2024
FSB Advising Checklist - Orientation 2024
 
On National Teacher Day, meet the 2024-25 Kenan Fellows
On National Teacher Day, meet the 2024-25 Kenan FellowsOn National Teacher Day, meet the 2024-25 Kenan Fellows
On National Teacher Day, meet the 2024-25 Kenan Fellows
 
HMCS Max Bernays Pre-Deployment Brief (May 2024).pptx
HMCS Max Bernays Pre-Deployment Brief (May 2024).pptxHMCS Max Bernays Pre-Deployment Brief (May 2024).pptx
HMCS Max Bernays Pre-Deployment Brief (May 2024).pptx
 
TỔNG ÔN TẬP THI VÀO LỚP 10 MÔN TIẾNG ANH NĂM HỌC 2023 - 2024 CÓ ĐÁP ÁN (NGỮ Â...
TỔNG ÔN TẬP THI VÀO LỚP 10 MÔN TIẾNG ANH NĂM HỌC 2023 - 2024 CÓ ĐÁP ÁN (NGỮ Â...TỔNG ÔN TẬP THI VÀO LỚP 10 MÔN TIẾNG ANH NĂM HỌC 2023 - 2024 CÓ ĐÁP ÁN (NGỮ Â...
TỔNG ÔN TẬP THI VÀO LỚP 10 MÔN TIẾNG ANH NĂM HỌC 2023 - 2024 CÓ ĐÁP ÁN (NGỮ Â...
 
SOC 101 Demonstration of Learning Presentation
SOC 101 Demonstration of Learning PresentationSOC 101 Demonstration of Learning Presentation
SOC 101 Demonstration of Learning Presentation
 
Holdier Curriculum Vitae (April 2024).pdf
Holdier Curriculum Vitae (April 2024).pdfHoldier Curriculum Vitae (April 2024).pdf
Holdier Curriculum Vitae (April 2024).pdf
 
Fostering Friendships - Enhancing Social Bonds in the Classroom
Fostering Friendships - Enhancing Social Bonds  in the ClassroomFostering Friendships - Enhancing Social Bonds  in the Classroom
Fostering Friendships - Enhancing Social Bonds in the Classroom
 
ICT Role in 21st Century Education & its Challenges.pptx
ICT Role in 21st Century Education & its Challenges.pptxICT Role in 21st Century Education & its Challenges.pptx
ICT Role in 21st Century Education & its Challenges.pptx
 
80 ĐỀ THI THỬ TUYỂN SINH TIẾNG ANH VÀO 10 SỞ GD – ĐT THÀNH PHỐ HỒ CHÍ MINH NĂ...
80 ĐỀ THI THỬ TUYỂN SINH TIẾNG ANH VÀO 10 SỞ GD – ĐT THÀNH PHỐ HỒ CHÍ MINH NĂ...80 ĐỀ THI THỬ TUYỂN SINH TIẾNG ANH VÀO 10 SỞ GD – ĐT THÀNH PHỐ HỒ CHÍ MINH NĂ...
80 ĐỀ THI THỬ TUYỂN SINH TIẾNG ANH VÀO 10 SỞ GD – ĐT THÀNH PHỐ HỒ CHÍ MINH NĂ...
 
Micro-Scholarship, What it is, How can it help me.pdf
Micro-Scholarship, What it is, How can it help me.pdfMicro-Scholarship, What it is, How can it help me.pdf
Micro-Scholarship, What it is, How can it help me.pdf
 

4GMAT Diagnostic Test Q10 - Data Sufficiency - Elementary Probability

  • 1. GMAT QUANTITATIVE REASONING ELEMENTARY PROBABILITY DATA SUFFICIENCY Diagnostic Test
  • 2. Question What is the probability that two students selected to the elocution competition are both boys? Statement 1: The ratio of boys to girls in the class is 3 : 4 Statement 2: There are 11more girls in the class.
  • 3. Step 1 Get clarity on when the data is sufficient
  • 4. What is the probability that two students selected are both boys? We will not even look at the statements while answering the following questions When is the data sufficient and when not?
  • 5. What is the probability that two students selected are both boys? We will not even look at the statements while answering the following questions When is the data sufficient and when not? The data is sufficient if we are able to get ONE value for the probability.
  • 6. What is the probability that two students selected are both boys? We will not even look at the statements while answering the following questions When is the data sufficient and when not? The data is sufficient if we are able to get ONE value for the probability. For instance, if we get more than one value or if an unknown is part of the expression, the data is NOT sufficient.
  • 7. What is the probability that two students selected are both boys? We will not even look at the statements while answering the following questions When is the data sufficient and when not? What expression will give the probability ? The data is sufficient if we are able to get ONE value for the probability. For instance, if we get more than one value or if an unknown is part of the expression, the data is NOT sufficient.
  • 8. What is the probability that two students selected are both boys? We will not even look at the statements while answering the following questions When is the data sufficient and when not? What expression will give the probability ? The data is sufficient if we are able to get ONE value for the probability. For instance, if we get more than one value or if an unknown is part of the expression, the data is NOT sufficient. Let the number of boys in the class be ‘b’ and let there be ‘t’ total students.
  • 9. What is the probability that two students selected are both boys? We will not even look at the statements while answering the following questions When is the data sufficient and when not? What expression will give the probability ? The data is sufficient if we are able to get ONE value for the probability. For instance, if we get more than one value or if an unknown is part of the expression, the data is NOT sufficient. Let the number of boys in the class be ‘b’ and let there be ‘t’ total students. Probability that two students selected are both boys = b(b-1) t(t-1)
  • 10. Step 2 Let’s evaluate statement 1 alone
  • 11. Statement 1: The ratio of boys to girls in the class is 3 : 4 What is the probability that two students selected are both boys? · Ratio of boys to girls 3 : 4
  • 12. Statement 1: The ratio of boys to girls in the class is 3 : 4 What is the probability that two students selected are both boys? · Ratio of boys to girls 3 : 4 If there are 3k boys, there will be 4k girls and a total of 7k students. ·
  • 13. Statement 1: The ratio of boys to girls in the class is 3 : 4 What is the probability that two students selected are both boys? · Ratio of boys to girls 3 : 4 If there are 3k boys, there will be 4k girls and a total of 7k students. · We determined in the last slide that for ‘b’ boys and ‘t’ total students, the required probability is b(b−1) t(t−1) ·
  • 14. Statement 1: The ratio of boys to girls in the class is 3 : 4 What is the probability that two students selected are both boys? · Ratio of boys to girls 3 : 4 If there are 3k boys, there will be 4k girls and a total of 7k students. · We determined in the last slide that for ‘b’ boys and ‘t’ total students, the required probability is b(b−1) t(t−1) ·  the probability = 3k(3k−1) 7k(7k−1) = 3(3k-1) 7(7k-1)
  • 15. Statement 1: The ratio of boys to girls in the class is 3 : 4 What is the probability that two students selected are both boys? · Ratio of boys to girls 3 : 4 If there are 3k boys, there will be 4k girls and a total of 7k students. · We determined in the last slide that for ‘b’ boys and ‘t’ total students, the required probability is b(b−1) t(t−1) ·  the probability = 3k(3k−1) 7k(7k−1) = 3(3k-1) 7(7k-1) Notice that the probability expression comprises a ‘k’ term. The probability value will depend on the value that k takes. So, we CANNOT determine the probability uniquely.
  • 16. Statement 1: The ratio of boys to girls in the class is 3 : 4 Statement 1 alone is NOT sufficient What is the probability that two students selected are both boys? · Ratio of boys to girls 3 : 4 If there are 3k boys, there will be 4k girls and a total of 7k students. · We determined in the last slide that for ‘b’ boys and ‘t’ total students, the required probability is b(b−1) t(t−1) ·  the probability = 3k(3k−1) 7k(7k−1) = 3(3k-1) 7(7k-1) Notice that the probability expression comprises a ‘k’ term. The probability value will depend on the value that k takes. So, we CANNOT determine the probability uniquely.
  • 17. Statement 1: The ratio of boys to girls in the class is 3 : 4 Eliminate choices A and D Statement 1 alone is NOT sufficient What is the probability that two students selected are both boys? · Ratio of boys to girls 3 : 4 If there are 3k boys, there will be 4k girls and a total of 7k students. · We determined in the last slide that for ‘b’ boys and ‘t’ total students, the required probability is b(b−1) t(t−1) ·  the probability = 3k(3k−1) 7k(7k−1) = 3(3k-1) 7(7k-1) Notice that the probability expression comprises a ‘k’ term. The probability value will depend on the value that k takes. So, we CANNOT determine the probability uniquely.
  • 18. Statement 1: The ratio of boys to girls in the class is 3 : 4 Choices narrow down to B, C or E. Eliminate choices A and D Statement 1 alone is NOT sufficient What is the probability that two students selected are both boys? · Ratio of boys to girls 3 : 4 If there are 3k boys, there will be 4k girls and a total of 7k students. · We determined in the last slide that for ‘b’ boys and ‘t’ total students, the required probability is b(b−1) t(t−1) ·  the probability = 3k(3k−1) 7k(7k−1) = 3(3k-1) 7(7k-1) Notice that the probability expression comprises a ‘k’ term. The probability value will depend on the value that k takes. So, we CANNOT determine the probability uniquely.
  • 19. Step 3 Let’s evaluate statement 2 alone.
  • 20. Statement 2 : There are 11more girls in the class. What is the probability that two students selected are both boys? There are 11 more girls in the class
  • 21. Statement 2 : There are 11more girls in the class. What is the probability that two students selected are both boys? There are 11 more girls in the class · If the number of boys is 10, there will be 21 girls and 31 students.
  • 22. Statement 2 : There are 11more girls in the class. What is the probability that two students selected are both boys? There are 11 more girls in the class · If the number of boys is 10, there will be 21 girls and 31 students. Probability = 10×9 31×30
  • 23. Statement 2 : There are 11more girls in the class. What is the probability that two students selected are both boys? There are 11 more girls in the class · If the number of boys is 10, there will be 21 girls and 31 students. Probability = 10×9 31×30 · If the number of boys is 20, there will be 31 girls and 51 students.
  • 24. Statement 2 : There are 11more girls in the class. What is the probability that two students selected are both boys? There are 11 more girls in the class · If the number of boys is 10, there will be 21 girls and 31 students. Probability = 10×9 31×30 · If the number of boys is 20, there will be 31 girls and 51 students. Probability = 20×19 51×50
  • 25. Statement 2 : There are 11more girls in the class. What is the probability that two students selected are both boys? There are 11 more girls in the class · If the number of boys is 10, there will be 21 girls and 31 students. Probability = 10×9 31×30 · If the number of boys is 20, there will be 31 girls and 51 students. Probability = 20×19 51×50 We are NOT able to determine the probability uniquely with this statement.
  • 26. Statement 2 : There are 11more girls in the class. What is the probability that two students selected are both boys? There are 11 more girls in the class · If the number of boys is 10, there will be 21 girls and 31 students. Probability = 10×9 31×30 · If the number of boys is 20, there will be 31 girls and 51 students. Probability = 20×19 51×50 We are NOT able to determine the probability uniquely with this statement. Statement 2 alone is NOT sufficient
  • 27. Statement 2 : There are 11more girls in the class. Eliminate choice B What is the probability that two students selected are both boys? There are 11 more girls in the class · If the number of boys is 10, there will be 21 girls and 31 students. Probability = 10×9 31×30 · If the number of boys is 20, there will be 31 girls and 51 students. Probability = 20×19 51×50 We are NOT able to determine the probability uniquely with this statement. Statement 2 alone is NOT sufficient
  • 28. Statement 2 : There are 11more girls in the class. Choices narrow down to C or E. Eliminate choice B What is the probability that two students selected are both boys? There are 11 more girls in the class · If the number of boys is 10, there will be 21 girls and 31 students. Probability = 10×9 31×30 · If the number of boys is 20, there will be 31 girls and 51 students. Probability = 20×19 51×50 We are NOT able to determine the probability uniquely with this statement. Statement 2 alone is NOT sufficient
  • 29. Step 4 Let’s combine data from both the statements.
  • 30. Statements Together : The ratio of boys to girls in the class is 3 : 4 and there are 11 more girls in the class What is the probability that two students selected are both boys? We determined that for ‘b’ boys and ‘t’ total students, the required probability is b(b−1) t(t−1) ·
  • 31. Statements Together : The ratio of boys to girls in the class is 3 : 4 and there are 11 more girls in the class What is the probability that two students selected are both boys? We determined that for ‘b’ boys and ‘t’ total students, the required probability is b(b−1) t(t−1) · From statement 1, we know there are 3k boys and 4k girls. ·
  • 32. Statements Together : The ratio of boys to girls in the class is 3 : 4 and there are 11 more girls in the class What is the probability that two students selected are both boys? We determined that for ‘b’ boys and ‘t’ total students, the required probability is b(b−1) t(t−1) · From statement 1, we know there are 3k boys and 4k girls. · From statement 2, we know 4k – 3k = k = 11.·
  • 33. Statements Together : The ratio of boys to girls in the class is 3 : 4 and there are 11 more girls in the class What is the probability that two students selected are both boys? We determined that for ‘b’ boys and ‘t’ total students, the required probability is b(b−1) t(t−1) · From statement 1, we know there are 3k boys and 4k girls. · So, the class has 33 boys and 44 girls and 77 students. · From statement 2, we know 4k – 3k = k = 11.·
  • 34. Statements Together : The ratio of boys to girls in the class is 3 : 4 and there are 11 more girls in the class What is the probability that two students selected are both boys? We determined that for ‘b’ boys and ‘t’ total students, the required probability is b(b−1) t(t−1) · From statement 1, we know there are 3k boys and 4k girls. · So, the class has 33 boys and 44 girls and 77 students. · From statement 2, we know 4k – 3k = k = 11.· Probability = 33×32 77×76
  • 35. Statements Together : The ratio of boys to girls in the class is 3 : 4 and there are 11 more girls in the class What is the probability that two students selected are both boys? We determined that for ‘b’ boys and ‘t’ total students, the required probability is b(b−1) t(t−1) · From statement 1, we know there are 3k boys and 4k girls. · So, the class has 33 boys and 44 girls and 77 students. · From statement 2, we know 4k – 3k = k = 11.· Probability = 33×32 77×76 Using the two statements together, we could determine the probability uniquely.
  • 36. Statements Together : The ratio of boys to girls in the class is 3 : 4 and there are 11 more girls in the class What is the probability that two students selected are both boys? We determined that for ‘b’ boys and ‘t’ total students, the required probability is b(b−1) t(t−1) · From statement 1, we know there are 3k boys and 4k girls. · So, the class has 33 boys and 44 girls and 77 students. · From statement 2, we know 4k – 3k = k = 11.· Probability = 33×32 77×76 Using the two statements together, we could determine the probability uniquely. Together the statements are SUFFICIENT.
  • 37. Statements Together : The ratio of boys to girls in the class is 3 : 4 and there are 11 more girls in the class Eliminate choice E What is the probability that two students selected are both boys? We determined that for ‘b’ boys and ‘t’ total students, the required probability is b(b−1) t(t−1) · From statement 1, we know there are 3k boys and 4k girls. · So, the class has 33 boys and 44 girls and 77 students. · From statement 2, we know 4k – 3k = k = 11.· Probability = 33×32 77×76 Using the two statements together, we could determine the probability uniquely. Together the statements are SUFFICIENT.
  • 38. Statements Together : The ratio of boys to girls in the class is 3 : 4 and there are 11 more girls in the class Answer is choice C Eliminate choice E What is the probability that two students selected are both boys? We determined that for ‘b’ boys and ‘t’ total students, the required probability is b(b−1) t(t−1) · From statement 1, we know there are 3k boys and 4k girls. · So, the class has 33 boys and 44 girls and 77 students. · From statement 2, we know 4k – 3k = k = 11.· Probability = 33×32 77×76 Using the two statements together, we could determine the probability uniquely. Together the statements are SUFFICIENT.
  • 39. Try this variant What is the probability that a student selected to the elocution competition is a boy? Statement 1: The ratio of boys to girls in the class is 3 : 4 Statement 2: There are 11more girls in the class.
  • 40. For GMAT Prep Visit http://www.4gmat.com GMAT Classes and GMAT Preparation Send your comments / feedback to info@4gmat.com
  • 41. 4GMAT We offer classroom training in Chennai and Bangalore Tutors include GMAT 98%ilers, US B School graduates and IIM graduates Call us: +91 95000 48484 Mail us: info@4gmat.com