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Запросы к поисковому серверу в ЕГЭ  о решении задания  B10
Задание  B10 ,[object Object],[object Object],[object Object],[object Object],[object Object],Путь рассуждений В   А   Б   Г
Метод диаграмм (круги Эйлера) ,[object Object],[object Object],[object Object],[object Object],Ч Б П
[object Object],[object Object],[object Object],[object Object],А) Б) В) Г) Ответ:   ВАБГ Ч Б П Ч Б П Ч Б П Ч Б П Ч Б П Е Ч Б П Ч Б П Ч Б П Ч Б П
С помощью таблиц истинности ,[object Object],[object Object],[object Object],[object Object]
Ч Б П Е X А X Б X В X Г 0 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 1 0 0 0 1 0 0 0 1 1 0 0 1 0 0 1 0 0 0 0 1 0 0 1 0 1 0 0 1 0 0 1 1 0 1 0 1 0 0 1 1 1 1 0 1 0 1 0 0 0 1 0 1 0 1 0 0 1 1 0 1 0 1 0 1 0 1 1 1 0 1 0 1 1 1 1 1 0 1 1 0 0 1 0 1 0 1 1 0 1 1 0 1 0 1 1 1 0 1 1 1 0 1 1 1 1 1 1 1 1
Ответ:   ВАБГ Ч Б П Е X А X Б X В X Г 0 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 1 0 0 0 1 0 0 0 1 1 0 0 1 0 0 1 0 0 0 0 1 0 0 1 0 1 0 0 1 0 0 1 1 0 1 0 1 0 0 1 1 1 1 0 1 0 1 0 0 0 1 0 1 0 1 0 0 1 1 0 1 0 1 0 1 0 1 1 1 0 1 0 1 1 1 1 1 0 1 1 0 0 1 0 1 0 1 1 0 1 1 0 1 0 1 1 1 0 1 1 1 0 1 1 1 1 1 1 1 1
Задание  B10  с числами ,[object Object],[object Object],[object Object],[object Object],Ключевое слово Количество сайтов, для которых данное слово является ключевым сканер 200 принтер 250 монитор 450
Решение задания  B10  с числами принтер | сканер   =  450   значит, круги П и С не пересекаются (450=200+250)! Известно, что  принтер & монитор  =  40 сканер & монитор  =  50 Искомая область:  (принтер | сканер) & монитор = = 50 + 40 = 90
Задание 2 (для самостоятельного решения) ,[object Object],[object Object],[object Object],[object Object],Ключевое слово Количество сайтов, для которых данное слово является ключевым сомики 250 меченосцы 200 гуппи 500
Задание 2 Т.к.  сомики  &  гуппи  =  0 , круги  C  и Г не пересекаются: Известно, что    сомики &   меченосцы  =  20   меченосцы &   гуппи  =  10 Искомая область:   сомики | меченосцы | гуппи =  = 200+(250-20)+(500-10) = 200+230+490 = 920
Задание 3 ,[object Object],[object Object],[object Object],[object Object],Ключевое слово Количество сайтов, для которых данное слово является ключевым сомики 250 меченосцы 200 гуппи 500
Задание 3 Т.к.  меченосцы  &  гуппи  =  0 , круги М и Г не пересекаются: Известно, что    сомики  |  гуппи  =  750   сомики &   меченосцы  =  100 Значит, искомая область:   (сомики & меченосцы) | гуппи = 500+100 = 600 Условие   сомики  |  гуппи  =  750  оказалось лишнее!
Задание 4 ,[object Object],[object Object],[object Object],Запрос Количество страниц фрегат | эсминец 3000 фрегат 2000 эсминец 2500
Задание 4 3000 = 2000 + (2500 –  x) 3000 = 4500 – x  x = 1500 Ответ: 1500 В аналогичном задании: x = 2000+2500-500 = 4000 Ответ:  40 00
Задание  B10  с нестандартным вопросом ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],Ответ:  1
Спасибо за внимание!

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Zadanie v10

  • 1. Запросы к поисковому серверу в ЕГЭ о решении задания B10
  • 2.
  • 3.
  • 4.
  • 5.
  • 6. Ч Б П Е X А X Б X В X Г 0 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 1 0 0 0 1 0 0 0 1 1 0 0 1 0 0 1 0 0 0 0 1 0 0 1 0 1 0 0 1 0 0 1 1 0 1 0 1 0 0 1 1 1 1 0 1 0 1 0 0 0 1 0 1 0 1 0 0 1 1 0 1 0 1 0 1 0 1 1 1 0 1 0 1 1 1 1 1 0 1 1 0 0 1 0 1 0 1 1 0 1 1 0 1 0 1 1 1 0 1 1 1 0 1 1 1 1 1 1 1 1
  • 7. Ответ: ВАБГ Ч Б П Е X А X Б X В X Г 0 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 1 0 0 0 1 0 0 0 1 1 0 0 1 0 0 1 0 0 0 0 1 0 0 1 0 1 0 0 1 0 0 1 1 0 1 0 1 0 0 1 1 1 1 0 1 0 1 0 0 0 1 0 1 0 1 0 0 1 1 0 1 0 1 0 1 0 1 1 1 0 1 0 1 1 1 1 1 0 1 1 0 0 1 0 1 0 1 1 0 1 1 0 1 0 1 1 1 0 1 1 1 0 1 1 1 1 1 1 1 1
  • 8.
  • 9. Решение задания B10 с числами принтер | сканер = 450 значит, круги П и С не пересекаются (450=200+250)! Известно, что принтер & монитор = 40 сканер & монитор = 50 Искомая область: (принтер | сканер) & монитор = = 50 + 40 = 90
  • 10.
  • 11. Задание 2 Т.к. сомики & гуппи = 0 , круги C и Г не пересекаются: Известно, что сомики & меченосцы = 20 меченосцы & гуппи = 10 Искомая область: сомики | меченосцы | гуппи = = 200+(250-20)+(500-10) = 200+230+490 = 920
  • 12.
  • 13. Задание 3 Т.к. меченосцы & гуппи = 0 , круги М и Г не пересекаются: Известно, что сомики | гуппи = 750 сомики & меченосцы = 100 Значит, искомая область: (сомики & меченосцы) | гуппи = 500+100 = 600 Условие сомики | гуппи = 750 оказалось лишнее!
  • 14.
  • 15. Задание 4 3000 = 2000 + (2500 – x) 3000 = 4500 – x x = 1500 Ответ: 1500 В аналогичном задании: x = 2000+2500-500 = 4000 Ответ: 40 00
  • 16.