1. D¯cw Is ¯mtam ?
1. F«v XhW 8 FgpXn 1000 B¡mtam ?
2. Hcp ¹mÌnIv Ip¸nbn sh® nd¨v Xq¡n tm¡nbt¸mÄ 950
{Kmw Dmbncp¶p. F¶m Ip¸nbn n¶pw ]IpXn sh®
amänbtijw hopw Xq¡nbt¸mÄ 500 {Kmw `mcapmbncp¶p.
Ip¸nbpsS `mcsa{Xbmbncn¡pw ?
3. HcmÄ amthentÌmdn n¶pw Hcp Intem{Kmw ]©kmc
hm§nbXv 35 cq]bv¡mWv. F¶m asämcmÄ {XnthWn
Un¸mÀ¨vsaâv tÌmdn n¶pw 1000 {Kmw ]©kmc
hm§nbt¸mgpw 35 cq]tb sImSpt¡n h¶pÅq.
ImcWsa´v?
D¯c§Ä
1. 888 + 2. 500 -þ475 = 25 {Kmw `mcw 3. 1000
{Kmw = 1 In.{Kmw
88 F® 950 {Kmw Bbncp¶mepw,
8 ]IpXn Bbmepw Ip¸nbpsS `mcw
8 H¶pXs¶bmbncn¡pw.
8 ]IpXn F® (475 {Kmw) amänb tij
1000 apÅ ]IpXn F®bptSbpw Ip¸n
bptSbpw `mcw 500 {Kmw . F¦nÂ
Ip¸nbpsS `mcw = 500-- -þ 475= 25 {Kmw