Group 7 4ChE A

Unit Operations Assignment on Conduction Jacinto, Stephanie Morenos, Jan Monil Sta. Rosa, Clariza Villanueva, Von Kirby 4ChE A Group 7

Problem no. 7 ,[object Object]

Problem no. 7 ,[object Object],T 1100 o C 38 o C T 1 = 1100 o C T 2 = 30 o C T= ? K brick = 1.3 W/mK K insulation = 0.034 + 0.00018T Basis: 1 m 2 Steady State: q 1 =q 2 20cm 5cm 1 2 Req’d: T Sol’n:

Problem no. 7 ,[object Object],Answer: Ti = 827.99ºC 827.99 0.4467 432.99 827.98 827.98 0.4467 433.01 828.03 828.03 0.4467 432.87 827.74 827.74 0.4461 433.74 829.49 829.49 0.45 428.39 818.79 818.79 0.4270 461.61 885.21 885.21 0.6066 269 500 Ti,q (ºC) R(K/W) Tave(ºC) Ti(ºC)

Problem no. 15 ,[object Object]

Problem no. 15 ,[object Object],50cm To=150ºC T ave =38ºC Ti=15ºC Cp=0.84KJ/kg·K K=0.70W/m·K ρ = 2480 kg/m3 Req’d: t=? Sol’n:

Problem no. 15 ,[object Object],[object Object],[object Object]

Geankoplis 4.1-2 ,[object Object]

Geankoplis 4.1-2 ,[object Object],[object Object],[object Object],T 1 =318.4K T 2 = 303.2K 25mm

Geankoplis 5.3-7 ,[object Object]

Geankoplis 5.3-7 ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],Req’d: T at the center Use Gurney and Lurie Chart for cylinders When X=1.6 4 and m = 1.99 , n=0 Y=0.29 T = 391 K Sol’n:

Group 7 4ChE A

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Group 7 4ChE A