SlideShare a Scribd company logo
1 of 3
Download to read offline
2

1.                                                                                                                  (5 !     )
           #            $%
           1.            (Zero matrices) 0                                        1 2 3 2 3 4 5 4 0 467 2 467 4 5
                    78 4
           2.       $               !4     % 0                               87                      :         7#
           ; !<! 87 3% :%                                                                                =:%        24% %
                    :$               8 7#
                           0       0           0
                               a 21        a 22                a2n
                 :24% A =                                                   0 :%          4               :@          !

                        a n1 a n 2       a nn
           @ A : (cofactor) ! %
                    det(A) = a11C11(A) + a12C12(A) + a13C13(A) + G + a1nC1n(A)
                            = 0+0+0+G+0
                            = 0
            ! % det(A) = 0 7 0         A                          : :%                                                 Q.E.D.

                 p11         p12          p13
2.   J 4 24% P = p 21        p 22         p 23          6! P                                 3% PT                    @; $
                    p 31     p 32         p 33
          P                P = (PT)T                                                                                (5 !     )
                                                          p11                           p 21    p 31
           @       J4                 P      24% ! % PT = p12                           p 22    p 32
                                                                            p13         p 23    p 33
                                                 p11      p12        p13
              ; !<! 87      (PT)T =              p 21     p 22       p 23         = P                                  Q.E.D.
                                                 p 31     p 32       p 33
3.   21% M$                % !##                   :               8                                                               (10 !   )
              wOx+yOz =                    O4
              4w O x + 3y + z =            O8
              2w + x + y O z =             0
              3w + 2x + y O 3z =           1
              $ !##                        J 4 24% 2                                       7 8
                1      1 1                 1 w                                  4
               4         1 3           1           x                            8
                                                               =
                2    1         1           1       y                        0
                3    2         1           3       z                        1

                           1           1 1                 1                                    4           1 1           1
                           4           1 3             1                                        8           1 3       1
              det(A) =                                                 = O 4, det(A1) =                                           =8
                           2       1           1           1                                0           1     1           1
                           3       2           1           3                                1           2     1           3

                          1            4 1                 1                                1           1         4           1
                          4            8 3             1                                    4           1         8       1
              det(A2) =                                                = O 12, det(A3) =                                          = O4
                          2        0           1           1                                2       1         0               1
                          3        1           1           3                                3       2         1               3

                          1            1 1                 4
                          4            1 3                 8
              det(A4) =                                                =0
                          2        1           1       0
                          3        2           1       1
               ! %       w = 84 = O 2, x = 12 = 3, y = 4 = 1, z = 0
                                            4          4
a11 a12        a13
4.   J 4 24% A = a 21 a 22      a 23 3% A
                 a 31 a 32      a 33
          V4 AO 1                                                                    (10 !   )
               :         AO 1 = det(A ))
                                adj(
                                     A
                                                                                 T
                                          C11 ( A )    C12 ( A )    C13 ( A )
                                    1
                               = det( A ) C 21 ( A )   C 22 ( A )   C 23 ( A )
                                          C31 ( A )    C32 ( A )    C33 ( A )
                                          C11 ( A )    C 21 ( A )   C31 ( A )
                                    1
                               = det( A ) C12 ( A )    C 22 ( A )   C32 ( A )
                                          C13 ( A )    C 23 ( A )   C33 ( A )
                      + (a 22 a 33 a 32 a 23 ) ( a12 a 33 a 32 a13 ) + (a12 a 23 a 22a13 )
                1
           = det( A )   (a 21a 33 a 31a 23 ) + (a11a 33 a 31a13 )      ( a11a 23 a 21a13 )
                      + (a 21a 32 a 31a 22 )   (a11a 32 a 31a12 ) + (a11a 22 a 21a12 )

More Related Content

Similar to เฉลยMetrix2

เฉลยข้อสอบเมทริกซ์ ตอนที่ 2
เฉลยข้อสอบเมทริกซ์  ตอนที่ 2เฉลยข้อสอบเมทริกซ์  ตอนที่ 2
เฉลยข้อสอบเมทริกซ์ ตอนที่ 2K'Keng Hale's
 
アルゴリズムイントロダクション 8章
アルゴリズムイントロダクション 8章アルゴリズムイントロダクション 8章
アルゴリズムイントロダクション 8章tniky1
 
Excel slide series - fractions introduction
Excel slide series -  fractions introductionExcel slide series -  fractions introduction
Excel slide series - fractions introductionPuworkUtara OnSlideshare
 
ข้อสอบMetrix
ข้อสอบMetrixข้อสอบMetrix
ข้อสอบMetrixNoir Black
 
11X1 T07 07 asinx + bcosx = c (2011)
11X1 T07 07 asinx + bcosx = c (2011)11X1 T07 07 asinx + bcosx = c (2011)
11X1 T07 07 asinx + bcosx = c (2011)Nigel Simmons
 
11X1 T08 07 asinx + bcosx = c (2010)
11X1 T08 07 asinx + bcosx = c (2010)11X1 T08 07 asinx + bcosx = c (2010)
11X1 T08 07 asinx + bcosx = c (2010)Nigel Simmons
 
11 x1 t08 07 asinx + bcosx = c (2012)
11 x1 t08 07 asinx + bcosx = c (2012)11 x1 t08 07 asinx + bcosx = c (2012)
11 x1 t08 07 asinx + bcosx = c (2012)Nigel Simmons
 
ข้อมูลและสารสนเทศ
ข้อมูลและสารสนเทศข้อมูลและสารสนเทศ
ข้อมูลและสารสนเทศchukiat008
 
Pc30 June 2001 Exam Ans Key
Pc30 June 2001 Exam Ans KeyPc30 June 2001 Exam Ans Key
Pc30 June 2001 Exam Ans Keyingroy
 
An order seven implicit symmetric sheme applied to second order initial value...
An order seven implicit symmetric sheme applied to second order initial value...An order seven implicit symmetric sheme applied to second order initial value...
An order seven implicit symmetric sheme applied to second order initial value...Alexander Decker
 
001 matrices and_determinants
001 matrices and_determinants001 matrices and_determinants
001 matrices and_determinantsphysics101
 

Similar to เฉลยMetrix2 (14)

เฉลยข้อสอบเมทริกซ์ ตอนที่ 2
เฉลยข้อสอบเมทริกซ์  ตอนที่ 2เฉลยข้อสอบเมทริกซ์  ตอนที่ 2
เฉลยข้อสอบเมทริกซ์ ตอนที่ 2
 
Math11
Math11Math11
Math11
 
アルゴリズムイントロダクション 8章
アルゴリズムイントロダクション 8章アルゴリズムイントロダクション 8章
アルゴリズムイントロダクション 8章
 
Excel slide series - fractions introduction
Excel slide series -  fractions introductionExcel slide series -  fractions introduction
Excel slide series - fractions introduction
 
ข้อสอบMetrix
ข้อสอบMetrixข้อสอบMetrix
ข้อสอบMetrix
 
Manual writer 3.0
Manual writer 3.0Manual writer 3.0
Manual writer 3.0
 
11X1 T07 07 asinx + bcosx = c (2011)
11X1 T07 07 asinx + bcosx = c (2011)11X1 T07 07 asinx + bcosx = c (2011)
11X1 T07 07 asinx + bcosx = c (2011)
 
11X1 T08 07 asinx + bcosx = c (2010)
11X1 T08 07 asinx + bcosx = c (2010)11X1 T08 07 asinx + bcosx = c (2010)
11X1 T08 07 asinx + bcosx = c (2010)
 
11 x1 t08 07 asinx + bcosx = c (2012)
11 x1 t08 07 asinx + bcosx = c (2012)11 x1 t08 07 asinx + bcosx = c (2012)
11 x1 t08 07 asinx + bcosx = c (2012)
 
ข้อมูลและสารสนเทศ
ข้อมูลและสารสนเทศข้อมูลและสารสนเทศ
ข้อมูลและสารสนเทศ
 
Pc30 June 2001 Exam Ans Key
Pc30 June 2001 Exam Ans KeyPc30 June 2001 Exam Ans Key
Pc30 June 2001 Exam Ans Key
 
An order seven implicit symmetric sheme applied to second order initial value...
An order seven implicit symmetric sheme applied to second order initial value...An order seven implicit symmetric sheme applied to second order initial value...
An order seven implicit symmetric sheme applied to second order initial value...
 
Ch15s
Ch15sCh15s
Ch15s
 
001 matrices and_determinants
001 matrices and_determinants001 matrices and_determinants
001 matrices and_determinants
 

เฉลยMetrix2

  • 1. 2 1. (5 ! ) # $% 1. (Zero matrices) 0 1 2 3 2 3 4 5 4 0 467 2 467 4 5 78 4 2. $ !4 % 0 87 : 7# ; !<! 87 3% :% =:% 24% % :$ 8 7# 0 0 0 a 21 a 22 a2n :24% A = 0 :% 4 :@ ! a n1 a n 2 a nn @ A : (cofactor) ! % det(A) = a11C11(A) + a12C12(A) + a13C13(A) + G + a1nC1n(A) = 0+0+0+G+0 = 0 ! % det(A) = 0 7 0 A : :% Q.E.D. p11 p12 p13 2. J 4 24% P = p 21 p 22 p 23 6! P 3% PT @; $ p 31 p 32 p 33 P P = (PT)T (5 ! ) p11 p 21 p 31 @ J4 P 24% ! % PT = p12 p 22 p 32 p13 p 23 p 33 p11 p12 p13 ; !<! 87 (PT)T = p 21 p 22 p 23 = P Q.E.D. p 31 p 32 p 33
  • 2. 3. 21% M$ % !## : 8 (10 ! ) wOx+yOz = O4 4w O x + 3y + z = O8 2w + x + y O z = 0 3w + 2x + y O 3z = 1 $ !## J 4 24% 2 7 8 1 1 1 1 w 4 4 1 3 1 x 8 = 2 1 1 1 y 0 3 2 1 3 z 1 1 1 1 1 4 1 1 1 4 1 3 1 8 1 3 1 det(A) = = O 4, det(A1) = =8 2 1 1 1 0 1 1 1 3 2 1 3 1 2 1 3 1 4 1 1 1 1 4 1 4 8 3 1 4 1 8 1 det(A2) = = O 12, det(A3) = = O4 2 0 1 1 2 1 0 1 3 1 1 3 3 2 1 3 1 1 1 4 4 1 3 8 det(A4) = =0 2 1 1 0 3 2 1 1 ! % w = 84 = O 2, x = 12 = 3, y = 4 = 1, z = 0 4 4
  • 3. a11 a12 a13 4. J 4 24% A = a 21 a 22 a 23 3% A a 31 a 32 a 33 V4 AO 1 (10 ! ) : AO 1 = det(A )) adj( A T C11 ( A ) C12 ( A ) C13 ( A ) 1 = det( A ) C 21 ( A ) C 22 ( A ) C 23 ( A ) C31 ( A ) C32 ( A ) C33 ( A ) C11 ( A ) C 21 ( A ) C31 ( A ) 1 = det( A ) C12 ( A ) C 22 ( A ) C32 ( A ) C13 ( A ) C 23 ( A ) C33 ( A ) + (a 22 a 33 a 32 a 23 ) ( a12 a 33 a 32 a13 ) + (a12 a 23 a 22a13 ) 1 = det( A ) (a 21a 33 a 31a 23 ) + (a11a 33 a 31a13 ) ( a11a 23 a 21a13 ) + (a 21a 32 a 31a 22 ) (a11a 32 a 31a12 ) + (a11a 22 a 21a12 )