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We know that absorbance , A = log ( Io It ) Where Io = intensity.pdf

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We know that absorbance , A = log ( Io / It ) Where Io = intensity of incident light It = intensity of transmitted light = 3 % ofIo = 0.03 Io Plug the values we get A = log ( Io /0.03Io ) = log (1/0.03) = 1.52 Solution We know that absorbance , A = log ( Io / It ) Where Io = intensity of incident light It = intensity of transmitted light = 3 % ofIo = 0.03 Io Plug the values we get A = log ( Io /0.03Io ) = log (1/0.03) = 1.52.

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We know that absorbance , A = log ( Io / It ) Where Io = intensity of incident light It = intensity of transmitted light = 3 % ofIo = 0.03 Io Plug the values we get A = log ( Io /0.03Io ) = log (1/0.03) = 1.52 Solution We know that absorbance , A = log ( Io / It ) Where Io = intensity of incident light It = intensity of transmitted light = 3 % ofIo = 0.03 Io Plug the values we get A = log ( Io /0.03Io ) = log (1/0.03) = 1.52

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We know that absorbance , A = log ( Io It ) Where Io = intensity.pdf

  • 1. We know that absorbance , A = log ( Io / It ) Where Io = intensity of incident light It = intensity of transmitted light = 3 % ofIo = 0.03 Io Plug the values we get A = log ( Io /0.03Io ) = log (1/0.03) = 1.52 Solution We know that absorbance , A = log ( Io / It ) Where Io = intensity of incident light It = intensity of transmitted light = 3 % ofIo = 0.03 Io Plug the values we get A = log ( Io /0.03Io ) = log (1/0.03) = 1.52