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Đây chỉ là bản mình upload để làm demo trên web, để tải đầy đủ tài liệu này, bạn vui lòng truy cập vào website tuituhoc.com để tải nhé. Chúc bạn học tốt
The document provides solutions to mathematical equations and inequalities involving radicals, fractions, and variables. It contains 50 problems involving solving equations and inequalities for variables on the set of real numbers. The problems cover a range of techniques including isolating variables, combining like terms, factoring, and applying properties of radicals, fractions and inequality signs.
This document provides 30 equations and inequalities and asks the reader to solve them on the set of real numbers. It uses variables like x, square roots, exponents, and basic arithmetic operations. The problems range from simple one-variable equations to more complex expressions with multiple variables. The goal is to calculate the value(s) of the variable(s) that satisfy each equation or inequality.
This document contains solutions to various equations and inequalities involving radicals on the set of real numbers. It is divided into 6 sections, with multiple problems provided in each section ranging from simple single-term radical equations to more complex multi-term radical equations and inequalities. The document provides the step-by-step workings for solving each problem.
The document provides solutions to mathematical equations and inequalities involving radicals, fractions, and variables. It contains 50 problems involving solving equations and inequalities for variables on the set of real numbers. The problems cover a range of techniques including isolating variables, combining like terms, factoring, and applying properties of radicals, fractions and inequality signs.
This document provides 30 equations and inequalities and asks the reader to solve them on the set of real numbers. It uses variables like x, square roots, exponents, and basic arithmetic operations. The problems range from simple one-variable equations to more complex expressions with multiple variables. The goal is to calculate the value(s) of the variable(s) that satisfy each equation or inequality.
This document contains solutions to various equations and inequalities involving radicals on the set of real numbers. It is divided into 6 sections, with multiple problems provided in each section ranging from simple single-term radical equations to more complex multi-term radical equations and inequalities. The document provides the step-by-step workings for solving each problem.
Nghệ thuật trần thuật trong tiểu thuyết hồ anh tháitruonghocso.com
Thi thử toán đào duy từ hn 2011 lần 4
1. www.VNMATH.com
-fRU'oNG rr-rpr EAo ouv rrj un Tnr rgtl D4.I HQC LAN lv (2710212011)
mON roAr'{ Hqc
xHOr a
Tttdi gian lam biti lB{) phitt; khong k€ thdi gian phdt di
PHAN cHUNG cHo rAr ca cAc rni SmH
Ciu I:
mx-4m-r3
Cho hirm'6 Y: x-m
1) Lrhao s5t vir vE d0 thi hdm s0 khi m= 2'
2),chf11;;; ;il;;; ili;
;1 "-ao t i .h'r.'? 1u6n di q"i lT di6m c0 dinh
g6c bang 1,5' Tinir
A va B.
diQn
Tri hai di6m A vi B hdy lap phucmg fiinh cua hai duong thangc6 hQ s6
tich hinh thang gi6i han bdi AB, hai dumrg thdng niry vd trlic Ox'
CAu il;
i; GiAi b6t phuong trinh:
2a{4*1ra <L
x
2) Giai phucrng trinh:
sinox+cosox i ^ 1
5 sin 2x 2 Ssin 2x
Ciu III:
Tinh tich phAn:
ft
? ,. '---rl+cosr
l= lln(l+srnx) &.
'0 'l + cosx 1
CAU IV:
Cho hinh chop S.ABCD, co da,v ABCD lA hinh vu6ng, dulng cao
SA' Gqi M lir trung
rli6m SC; N, P lan luqt nam tr€n SB va SD sao cho
-'^" = = ta, phang GvO-lP) chia hinh
* + 1
3 sB sD
chop thdnh hai ph6n. Tinh ti sO AC tich cuahal pUan dO'
Cfiu V:
Chimg t6 rang vsi mqi 916 ui cua tham s0 m, hQ phuong trinh sau lufin co nghiQm:
l*+*Y+Y=2m+1
i
1xY(x+ !)=m2 +m'
X6c dinh m ae ne cO ngtriem duY nhdt.
pHAN mtNC ( rgi SINH CHi LAIVI MQT TRONG HAI PHAN A HOAC B )
2. www.VNMATH.com
A. Theo chuong trinh chuAn:
CAuVIa: _ j
' l) Tinh diQn tich tanr gi6c dAu nQi tii5p elip (E), ;+'r- = i. nhan dii5m A (u;2) la dinh
i,ir trpc turig lirm truc ddi xirng.
. ?)Trong kh6ng gian voi h0 uuc tga dQ oxyz, tim ba di6m M, N, P lan lugt thu0c c6c
rJucrng thing: (d,) +1 ='=' =+,
2 -)' "j/
(dr) + =*=+t
2 7 -1'
tor) i2=+=+
sao cho M'
1 i
N. P thang hAng, dOng thoi N lir trung di6m ciia doan flrang MP'
Ciu VII a:
.lnx1
Cho x > 0, x *1. Chimg minh rang:
,_l.G'
B" Theo chucrng trinh ning cao
Ciu VI b:
1) Tinh di€n rich tam gi6c dAu nQi ti0p paraboi (P): 1p
:2x, nhan dinh ctra parabol ldm
mQt dinh vir tryc hoanh Ox ldm trgc ddi ximg.'
2) Trong khOng gian voi h0 truc tga dQOxyz:
a) Tinh khoang crlch gita hai duong thdng:
I x =2-I
(o,l? =+:-i,^ o',
1r-::t*,
r
l.! -
b) Tinh goc gitadudrng therrg (dr)
r' +4 =+=+ -2
|
voi m{tphang (a):x+y-z+Z:0'
Cfru VII b:
Gi6su u1v. Chrmgminhring:u'-3u < v3-3v+4'
---------Gi6m thi coi thi khdng gi6i thich gi th6m-:
3. www.VNMATH.com
TRCSTqG TEtrT SAG FUV T'EI
T'E{ANG Bstreg s'sgs sg{€t PAH E{Qa E"AN Hv G7
tfiztzw1l}
*Ap AN -
e{0lN , T'o6nu, umoi a
N$i dung cho
^ 2x-5 /--. 1- ,.,- I
m:2:) y=-- -,.) x-2-' Y - (x-2)'= , 0.
Khi
- x-Z "
TiQrn c$n dimg x = 2, tiQm cin ngang y :2'Ei0m dac Uiat ( J;O) ; O;|)
Phucrng hinh: xY - my = rnx - 4m + 3 ching Vre
e (x+ y-4)m+ 3 - xY = 0 dirng v6i Ym +1'
I lr=1
.ltoy-4=0 lx+y-4=o ltr=,
'[3-xY=g otr' -4x+3=o€lJ"=''
O<
LL'''=t
cO dinh lA A (1; 3); B (3; 1
- Phuong trinh dudng thing qua A c6 hg s0 g6c
t
i
-3 = 1G -l) e y - :x *;. (d t)
r =1r+1. rcrt
2-"' 2 2
- Fhuong trinh clubng thdng qua B c6 h0 sA gOc 1b
ld c
Orl- Giao diAm ciia (d1) vdi ox
(-1 ; 0), cria
y + =){r- 3) <+ , =1* -f,.
(d2) vdi ox ld D (1;o).
J
cao cta hinh thang
Khoang c6ch gita (d1), (d2) cfing ohinh ld chiAu
4. www.VNMATH.com
Vpy, diQn tich hinh thang Phf,i tim li:
4n;5 20
5 =(AC +BDt=(Ji3.*'#= -.{lJ.=-=-'
3 J13 3
..:-
2
BiiII/I
1
1 Xdt hai trudrng hgP:
2a"[j; aaa <2x e
{zx-z> o
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0.5
f-:"t * x+4<(7x-2)'z=4x2 -Bx+4
(4
i"t
t4 lt'''=, is 4 .-..s 4
o1-1{x{; *1 s' o1.,=; (v t<1e27<28:duns-)
IJC>-
fzr'-0" r o lz
ong duong v6i:
2a'[4; a xa > 2x a't4r' + x + 4 > 2x -2'
0.5
Nh$n xdt rAng khi x < 0 thi 2x-2 < 0 n6n b6t phuortg toinh trOn sE tiring khi
-3x' + x+ 4>-0 <+ -1 = t 11.Vi
a
x < 0 :> -1 < x < 0'
J
r 0. (*). Vcyi tfi6u kiQn ndy, phucrng trinh ffiong ouong vo.t
bieu kign sin2x
l-2sin2xcos'x I coszx-l1€' ---2x - 5 coslx + I = o'
- o
< - '- cos'
=
z-""''" I 4
a
-sl"orzr=21lopi1 i
,-'l
o z
,nuu mdn (*) vi sin2x : xf * o 'l
f'orr' 1,
=
CAU
HI
5. www.VNMATH.com
r = [t [(1 + cos x; in(l + s inx) - lrr(l + cos;r][dx
: .lo ",..
{i nrt+ s inx)d;r * [i ror r ln(l + sinx)d;c -
' Jo --"'- ""- / -:i- [i
Jo
fn(f + cos x)dx. Chri y ring nrSu
lr
AaTt:--x
'2
^Toro'no m{l + s inx)dx'
trri
fi lnlr + cos x)d:r = Ii t, + sin l)(-)dr = f
m{t + sin t)dt =
f
Y 4y, I= j'u lntr * lin*Vt' D?t t : l+5inx, ta c6:
"out
ln(l + s inx)dx = J tn{t + s inx).
Jcosx
d(l+sinx) :
llntdt = tlnt -t +c= (1 + sinx)ln(l+ s inx) - (1 + sinx) +c.
JJt =lnt.t - l r.L.a,
l+
:> I : (l+sinx)ln(l+sinx)-lsinxl =21n2-1.
t'
BAi XV
Gqi ffiacdi6md6i ximg cria C qua B vd qua D.
S
C
0r5
F
LEFC +A le trung ctiam cria EF*(MNP) di qua A. Theo da bdi' ta ph6i tinh ti 005
T/
-A
JU ' SAPMN
Vrou.,
6. www.VNMATH.com
.fac6: v"".," s,4.si/.sP 22 4 l/,u*u 2
/sANp
!auv' =Dtar)iv'Di ::-a-'3'sANl' -1.
/rnr,r- sl.sB.st 3'3 9 vrro,,,, 9
11) ')
=-,-.-
323
=
I
---Vrrr,, =l-Vrnrr,
- '- Vr^rr,, 9 Vrnur o -
Vdy, ti sO hai phdn trOn vd duOi bane j
(x=l'
-
DE th6y: ]- Id nghipnn cfia hQ v6iYm. Ngodi ra n6u (xo; Yo) 1d nghigm
ly =m
duy nhSt thi m =
cria hQ thi (ys; x6) ctng ld nghiQrn cria h6. vfly, da hQ c6 nghiQm
CAU
Vla
gi6c
Ggi B, C ld hai dinh cdn lai crla tam gi6c dAu thi B ( -m; n)' C (m; n)' Tam
ABC dAu nQi ti6p elip (E) khi vd chi khi:
l*' *!'
i16 4 =l ^ €j lntz
+4n' =16
l'- :
l4nt' nt'+n'-4n +4 l3m'=n'-4n+4
Tri he tr€n tim du-o.c : ,=-3 (n:2lopi vi A= B =C), tt d6 nz=J€ no*
16.,8 o -,"-^rr#-76BJt
(dl) c6 tqa d0 M (a+l ; 2"+2'-2"), N (2b+2 ; 2b ; -b+1), P (2c ; c ; c+l )'
Gii sir M thudc
Ba di6m M, N, P thing hdng khi m cing phucrng vot MP. Sir dgng gin thi5t N ld
11
trung diiim MP, tatim dugc M ( -14 ; -28 ; 30 ) ; N (-17 ; -1s ; ?) ;
'?," P ( -20 ; -10 ; -9 )'
X6t trudng hqp:
") x> 1: Bdtphuongtrinh ban dAu <+ fnt'f e f @)=lnx-Jx*f 'O'
(")
Ta c5: -f
I
'(x)=t--^---v
1 I -i=---------7-'
z zJi-x-r
x'/Jx 2 ZxJx
Theob6tdingthr?ccdsi: x+ i.>zJ;=.f '(x)<0 khix> 1'
: ) :) Bat d$ng thirc (*)
f(x) nghfch biiin trom [r;+o) + f(x) < f(1) 0 khi x 1
7. www.VNMATH.com
*) 0 . x < 1: Bdt ddng thftc ban ddu
<> rnx ,#.e f (x):lnx-G*;;'0. (**)
Gi6ng tr6n ta c6 f '(x) =
2",[i -x-1 < 0 + Hdm s6 nghleh biiln tr6n ( o; 1):'
f(x) > f(l): 0:) eat dang th{rc (8+) tl6ng"
Cdu 2,0S
vIb
@ (n r 0 ) ld hai dinh con l4i cria tarngtilc otsc. Khi d6
tam gibcoBC d6u nQi ti6p (p) e tiuo'c ffi : 5, n : 2J1. I,00
I
It:. r::;:;rrim
T* d6 Soec: nJ.
Kho6ng c6ch gifra dr vd dz O** Gqi q ld goc gita d3 vi m$t phang @) ta
# 1,S0
2
t;
v/
co Slnq= .
3
C6u I,0s
vHb
Xdt hem s6 f(x): x'- 3x. :> f(x) =3x'- 3:0 € +1.
,.t
I a co bang Dlen mlen:
@,25
,f'{" +
----"+
Xetba trulng hgp:
*)u<-l
*v <-1.
-Vihdmf(x)ldd6ngbi6nh6n [-oo;-1) n6nf(u) <"f (v)'f(v) 14:] ut-3u'
'l^
v--Jv+4. U,75
*v>-1.
- Vi hdm f(x) c6 mQt cpe hi duy ntr6t tai x : I ndn: (v) > f (l) = -2, (u) < f (-1)
-L.
:>(u)-(v)<2-(-21:4.
*)-1.u(1:>v>-1.
5
8. www.VNMATH.com
Vi hdm f(x) nghich bi*5n h6n [_t;t] nen f(u) . f (-1) :2' Ngodi ra tr6n khoang
(-1;+*) hdm sO c6 mQt cuc tri duy nh6t tai x : I ndn f(v) > f(1) : -2' VAy f(u) -
f(v)<2-{-21=4.
*) u >l=v>1.
-.Vi hdm f(x) d6ng bitfn fr€n [1;**; ndnrf(u) < f(v) + 4. =] u3 - 3u . o3 - 3v + 4.
,Ju,-JSr;: VrX f/"e;