The document calculates the forces in the truss of a bridge. It uses summation of moments and forces equations to determine that the force at node A is 666.67 lbs of compression and the force at node C is 400 lbs of compression. The key steps are setting up the equations to equate summation of moments and forces to 0, and solving those equations to find the unknown reaction and internal forces.

1. CALCULO DE LAS FUERZAS EN LA ARMADURA DE UN
PUENTE

2. ΣMA = 0
− 800 4 + Cy 8 = 0
Cy = 400 𝑙𝑏
ΣF = 0 En “y”:
𝐴𝑦 − 800 + Cy = 0
𝐴𝑦 − 800 + 400 = 0
Ay = 400 𝑙𝑏
EN EL TOTAL:
En “x”:
𝐴𝑥 = 0
SOLUCION:

3. 3𝐾 = 400
𝐾 = 133,33
EN EL NUDO “A”:
FAE = 5𝐾 = 5(133,33)
FAE = 666,67 lb COMPRESION
DESARROLLANDO:

4. EN EL NUDO “C”:
-FCD + 400 = 0
FCD = 400 lb COMPRESION
ΣF = 0 En “y”: