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PREGUNTA 1
Una barra de plástico con diámetro d=56 mm se torcerá por pares de torsión T
(consulte la figura) hasta que el ángulo de rotación entre los extremos sea 4.0º.
Si la deformación unitaria por cortante permisible en el plástico es 0.012 rad.
¿Cuál es la longitud mínima permisible de la barra?
Solución
∅ = 𝟒 (
𝝅
𝟏𝟖𝟎
) = 𝟎.𝟎𝟔𝟗𝟖 𝒓𝒂𝒅
𝜸𝒑𝒆𝒓𝒎 =
𝒓∅
𝑳
𝑳 =
𝒓∅
𝜸𝒑𝒆𝒓𝒎
=
(
𝒅
𝟐
)∅
𝜸𝒑𝒆𝒓𝒎
=
(𝟎.𝟎𝟐𝟖 𝒎)(𝟎.𝟎𝟔𝟗𝟖 𝒓𝒂𝒅)
𝟎. 𝟎𝟏𝟐 𝒓𝒂𝒅
= 𝟎.𝟏𝟐𝟔𝟐𝟖 𝒎
𝑳 = 𝟏𝟐𝟔.𝟖𝟔 𝒎𝒎

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Pregunta 1

  • 1. PREGUNTA 1 Una barra de plástico con diámetro d=56 mm se torcerá por pares de torsión T (consulte la figura) hasta que el ángulo de rotación entre los extremos sea 4.0º. Si la deformación unitaria por cortante permisible en el plástico es 0.012 rad. ¿Cuál es la longitud mínima permisible de la barra? Solución ∅ = 𝟒 ( 𝝅 𝟏𝟖𝟎 ) = 𝟎.𝟎𝟔𝟗𝟖 𝒓𝒂𝒅 𝜸𝒑𝒆𝒓𝒎 = 𝒓∅ 𝑳 𝑳 = 𝒓∅ 𝜸𝒑𝒆𝒓𝒎 = ( 𝒅 𝟐 )∅ 𝜸𝒑𝒆𝒓𝒎 = (𝟎.𝟎𝟐𝟖 𝒎)(𝟎.𝟎𝟔𝟗𝟖 𝒓𝒂𝒅) 𝟎. 𝟎𝟏𝟐 𝒓𝒂𝒅 = 𝟎.𝟏𝟐𝟔𝟐𝟖 𝒎 𝑳 = 𝟏𝟐𝟔.𝟖𝟔 𝒎𝒎