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PESAWAT
         SEDERHANA                         F

                                 W
                                 T U A S
         F
W

KATROL

             RODA GIGI
                         BIDANG MIRING
Lb            Lk
            W


                     Titik tumpu
                                                F
W = Beban satuan Newton
 F = Gaya / Kuasa satuan Newton              WxLb=LkxF
Lb= Lengan beban satuan meter             Keuntungan mekanis tuas
Lk= Lengan kuasa satuan meter              Km =W/F atau Lk/Lb
 Lk = jarak titik tumpu sampai dengan kuasa/gaya
 Lb = Jarak titik tumpu sampai dengan Beban/W


                      Back         Next
Pada gambar ini menunjukan
beban W berada antara titik tumpu dan gaya/kuasa

                                                 F
                            W
         Titik tumpu
                       Lb
                                   Lk

   Keuntungan mekanis Tuas         W     atau
                                                Lk
                                   F            Lb

                               Lb x W = Lk x F


                        Back      Next
W

      F1                                        F2
A                                        Lb 2        B
           Lb 1
                             Lk

Beban W ditumpu oleh dua titik titik tumpu F1 dan F2
Sehingga beban W terbagi 2 yaitu pada titik tumpu A
  dan titik tumpu B




                      Back        Next
smpn2   W

                        F1                                     F2
                 Titik tumpu A                                Titik tumpu B




Saat mobil melalui jembatan beban mobil W terbagi menjadi 2 yaitu pada
Pondasi A dan pondasi B.
Bila kita perhatikan pondasi manakah yang lebih besar menerima beban
Mobil pondasi A atau pondasi B................................
Mengapa demikian......................................................


                           Back       Next
Contoh Soal 1
                               2m
                                 ete
                                       r
                                                    F
                    m
                5 0c
                                               Diketahui : Lb = 50 cm =0,5 meter


                W
                                                     Lk = 2 meter
                                                     w = 8000 Neton
                                               Ditanya F....
                                                       Km........
                                               Jawab : w . Lb = f . Lk
            8000 Newton
                                                                    W . Lb
                                                              F=     Lk
              Lk                           w
     Km =               atau   Km =
              Lb                           f
                                                                    8000 N . 0,5 meter
                                                              F=        2 meter
           2 meter                   8 000 N
  Km =                         Km =
           0.5 meter                 2 000 N
  Km = 4                       Km = 4                                4 000 N
                                                               F=      2

                                                               F= 2000 Newton


                                  Back           Next
Contoh Soal 2                         Benda beratnya 800 Newton didorong
                                         menggunakan kereta
                                      Berapa Newton besar gaya/ kuasa....
                                      Berapa Km
                                       Diketahui :w = 800 Newton
                     80 cm
                                                   Lb = 0,2 meter
                                                   Lk = 0,2 + 0,8= 1 meter
           20 cm
                                       Ditanya f..........
           Lk                       w      Km............
    Km =   Lb
                    atau     Km =   f  Jawab :      : w . Lb = f . Lk
                                                             W . Lb
        1meter                     8 00 N              F=
 Km =                        Km =                             Lk
        0.2 meter                  160 N
 Km = 5                      Km = 5                          800N . 0,2 meter
                                                       F=       1 meter

                                                              160
                                                        F=      1

                                    Back    Next       F= 160 Newton

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KEUNTUNGAN MEKANIS TUAS

  • 1. PESAWAT SEDERHANA F W T U A S F W KATROL RODA GIGI BIDANG MIRING
  • 2. Lb Lk W Titik tumpu F W = Beban satuan Newton F = Gaya / Kuasa satuan Newton WxLb=LkxF Lb= Lengan beban satuan meter Keuntungan mekanis tuas Lk= Lengan kuasa satuan meter Km =W/F atau Lk/Lb Lk = jarak titik tumpu sampai dengan kuasa/gaya Lb = Jarak titik tumpu sampai dengan Beban/W Back Next
  • 3. Pada gambar ini menunjukan beban W berada antara titik tumpu dan gaya/kuasa F W Titik tumpu Lb Lk Keuntungan mekanis Tuas W atau Lk F Lb Lb x W = Lk x F Back Next
  • 4. W F1 F2 A Lb 2 B Lb 1 Lk Beban W ditumpu oleh dua titik titik tumpu F1 dan F2 Sehingga beban W terbagi 2 yaitu pada titik tumpu A dan titik tumpu B Back Next
  • 5. smpn2 W F1 F2 Titik tumpu A Titik tumpu B Saat mobil melalui jembatan beban mobil W terbagi menjadi 2 yaitu pada Pondasi A dan pondasi B. Bila kita perhatikan pondasi manakah yang lebih besar menerima beban Mobil pondasi A atau pondasi B................................ Mengapa demikian...................................................... Back Next
  • 6. Contoh Soal 1 2m ete r F m 5 0c Diketahui : Lb = 50 cm =0,5 meter W Lk = 2 meter w = 8000 Neton Ditanya F.... Km........ Jawab : w . Lb = f . Lk 8000 Newton W . Lb F= Lk Lk w Km = atau Km = Lb f 8000 N . 0,5 meter F= 2 meter 2 meter 8 000 N Km = Km = 0.5 meter 2 000 N Km = 4 Km = 4 4 000 N F= 2 F= 2000 Newton Back Next
  • 7. Contoh Soal 2 Benda beratnya 800 Newton didorong menggunakan kereta Berapa Newton besar gaya/ kuasa.... Berapa Km Diketahui :w = 800 Newton 80 cm Lb = 0,2 meter Lk = 0,2 + 0,8= 1 meter 20 cm Ditanya f.......... Lk w Km............ Km = Lb atau Km = f Jawab : : w . Lb = f . Lk W . Lb 1meter 8 00 N F= Km = Km = Lk 0.2 meter 160 N Km = 5 Km = 5 800N . 0,2 meter F= 1 meter 160 F= 1 Back Next F= 160 Newton