1. IES BALÀFIA
Departament de Matemàtiques
Curs 2008-2009
NOMBRES ENTERS
Resol el següent enigma. Primer fes el càlculs i després substitueix cada
número per la lletra que li correspon:
21 2 10 14 -1 -2 21 -19 21 -2 9 10 12 21 16
21 10 -10 16 14 5 16 21 5 -2 -2 13 -19 -6 16
21 -2 21 -1 22 -4 14 5 -2 13 -37 22 5 -4
14 2 14 -4 -14 22 16 10 21 3 14 -2 10 21 2
-
10 21 -1 2 21 11 -37 14 14 22 -6 22 -2 10
. ,
21 2 10 12 16 21 10 -4 22 7 13 16 10 21 2 10
,
16 21 12 16 21 10 21 -2 -4 22 -37 21 -2 22 -19 -6
-4 14 -2 -4 22 -37 21 16 -19 21 2 2 22 7 22
‘
.
-17 5 14 -37 21 2 21 11 12 16 21 10 10 14 13
‘
21 10 -4 22 16 21 -2 -2 13 -19 -6 16 21 10 -37
“
21 16 -19 21 2 2 10 -17 5 22 -2 21 10 -4 21
“
-2 21 -2 7 21 5 -4 21 10
.
A. 10 − (− 3 ) + 14 + (− 5) =
5 + (− 8 ) − 3 =
B.
(− 30) ÷ [ (+ 9) ÷ (+ 3)]=
C.
(− 35) ⋅ (− 2) ÷ (+ 10) =
D.
16 − (− 5) =
E.

2. IES BALÀFIA
Departament de Matemàtiques
Curs 2008-2009
5 ⋅ (− 3 ) + 18 =
F.
(− 3 ) ⋅ (− 2 ) + (− 7) =
G.
5 − 3 ⋅ 4 + 10 ⋅ 3 =
H.
I. 12 ⋅ (− 3 ) + 5 ⋅ (− 4 ) + (− 7) ⋅ (− 10) =
J. 12 − [7 + 3 − 2] =
− (− 3 + 10 ) − [6 − (4 + 1 − 3 )] =
K.
(5 − 3) ⋅ (7 + 2 − 8) =
L.
− 10 − (5 + 3 ) + (− 2 + 1) =
M.
4 + 3 ⋅ (− 2 ) − (− 10) ÷ (+ 2 ) − 5 =
N.
8 − 6 + 12 ⋅ 3 − 25 =
O.
4 − [3 + (2 − 1) − (5 + 7)]=
P.
Q. 10 ⋅ (− 2 ) − (− 20 ) ÷ (− 5) + 7 =
9 − 3 ⋅ (− 2 ) + 1 =
R.
(10 − 3 ) − (6 + 3 − 12) =
S.
[7 − 5 ⋅ 3] ÷ (+ 2 ) =
T.
(8 + 7 − 5) ÷ (7 + 3 − 8) =
U.
9 ⋅ (− 3 ) + 5 ⋅ [4 − 7 + 1] =
V.
− 11+ 3 ⋅ [5 − 4 ⋅ 2] =
W.
12 − 5 ⋅ (− 3 ) + 8 ⋅ (− 2 ) =
X.
[5 − 3 ⋅ 2] ⋅ [7 + 8 ⋅ (− 2)] =
Y.
[9 + 3 ⋅ (− 2) − 5] − [7 + 3 ⋅ (− 1) − (− 8 )] =
Z.