This document calculates the mean, variance, and standard deviation of the weights of a sample of 20 pills from a batch. It finds the mean weight to be 60.25 grams. It then calculates the variance as 0.05 and the standard deviation as 0.0025 grams.

1. DETERMINAR LA MEDIA, VARIANZA Y DESVIACION ESTANDAR DE UN
LOTE DE MEDICAMENTOS QUE SE RE REQUIERE PARA UN CONTROL DE
CALIDAD.
Comprimido Pesos
1 60.5
2 60.5
3 60.1
4 60.7
5 60.2
6 60.3
7 60.5
8 60.5
9 60
10 60
11 60.1
12 60.5
13 60.2
14 60.2
15 60.3
16 60
17 60
18 60.5
19 60
20 60
= 60.5 + 60.5 + 60.1 + 60.7 + 60.2 + 60.3 + 60.5 + 60.5 + 60 + 60 + 60.1 + 60.5
+ 60.2 + 60.2 + 60.3 + 60 + 60 + 60.5 + 60 + 60.2 / 20 = 60.25
S2 = (60.5 - 60.25 )2 + (60.5 - 60.25 ) 2 + (60.1 - 60.25) 2 + ( 60.7 - 1.18 ) 2 + (60.2 -
60.25 ) 2 + (60.3 - 60.25) 2 + (60.5 - 60.25) 2 + (60.5 - 60.25) 2 + (60 - 60.25) 2 + (60 -
60.25) 2 + (60.1 -60.25 ) 2 + (60.5 - 60.25) 2 + (60.2 - 60.25) 2 + (60.2 - 60.25) 2 + (60.3 -
60.25) 2 + (60 - 60.25) 2 + (60 - 60.25) 2 + (60.5 - 60.25) 2 + (60 - 60.25) 2 + (60.2 -
60.25) 2 / 19 =
S2 = 0.0625+ 0.0625+ 0.0225+ 0.2025+ 2.5E10-3+ 2.5E10-3+ 0.0625+ 0.0625+0.0625+
0.0625+ 0.0225 + 0.0625+2.5E10-3+ 2.5E10-3+ 2.5E10-3+ 0.0625+0.0625+0.0625+
0.0625+ 2.5E10-3/19
S2 = 0.05
S = √0.05 = 2.5E10-3