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Balanceo de ecuación redox (1)
- 2.
1) Asignar número de oxidación
2+ 6+ 8- = 0
1+
21+ 1- = 0
2+ 2- = 0 2+ 2- = 0
1+
1+
0
H2SO4 + HI
I 2 + H2S + H 2O
- 3. 2+ 6+ 8- = 0
1+
21+ 1- = 0
0
H2SO4 + HI
I 2 + H 2S + H 2O
S6+
S0
I 1-
I0
2+ 2- = 0 2+ 2- = 0
1+
1+
- 5. 2 (S6 + 8e8 (2I1- -2e2S6 + 16I1-
S2-)
I20)
2S2- + 8I2
- 6. 2 (S6 + 8e-
S2-) Se reduce (H2SO4
8 (2I1- -2e-
I20) Se oxida (HI Ag. Red.)
Ox.)
Ag.