JCB JS460 Engine Isuzu AA-6SD1T Service Repair Manual Instant Download.pdf
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Formal Final Report
1. Solar Stirling Charger
Sparke Industries, Group 7
βAll it takes is an idea."
Contributors:
Ben Gajus, Juan Pablo Lopez, Allison Johnson,
Nicholas Natale, Kendall Wade, Samantha Webster
2. 2
1 TABLE OF CONTENTS
2 Introduction..................................................................................................................................................3
3 Performance Specifications..........................................................................................................................5
4 Individual Components.................................................................................................................................6
4.1 Sub-Assembly A....................................................................................................................................7
4.2 Sub-Assembly B..................................................................................................................................11
4.3 Sub-Assembly C..................................................................................................................................18
5 How it Works..............................................................................................................................................21
5.1 Nominal Use.......................................................................................................................................21
5.2 Analysis...............................................................................................................................................22
5.2.1 Kinematics and Dynamics ..........................................................................................................23
5.2.2 Thermodynamics and Heat Transfer .........................................................................................27
5.3 Failure.................................................................................................................................................47
5.3.1 Theoretical Analysis...................................................................................................................47
5.3.2 SolidWorks Finite Element Analysis...........................................................................................52
6 Design for Manual Assembly......................................................................................................................54
6.1 Steps to Assemble..............................................................................................................................54
6.2 Work Station Layout...........................................................................................................................70
7 Tolerancing and Closure.............................................................................................................................71
7.1 Shaft and Coupler...............................................................................................................................71
7.2 Starter and Slot ..................................................................................................................................72
7.3 Key and Gear......................................................................................................................................73
7.4 Hot Cylinder and Hot Support............................................................................................................74
7.5 Paraboloid and Engine .......................................................................................................................75
8 Cost Analysis...............................................................................................................................................77
9 Intellectual Property...................................................................................................................................80
10 Evaluation...............................................................................................................................................81
11 Appendix ................................................................................................................................................82
11.1 Tables for Shaft Failure Analysis ........................................................................................................82
11.2 Manual Assembly Time Table ............................................................................................................85
11.3 Machining Tolerances ........................................................................................................................96
12 References..............................................................................................................................................97
3. 3
2 INTRODUCTION
The purpose of this project is to analyze a design for and determine the feasibility of a portable 5
watt Stirling engine charger. The final design is driven by solar energy using an acrylic-based solar mirror
and water-based cooling. The heat is transferred to brass cylinders containing the hot pistons of the
Stirling engine. The Stirling cycle is achieved through the expansion of air in the hot cylinders, the
compression of air in the cold cylinders, and a cyclical volume change in each pair of cylinders. For
reference, an ideal Stirling cycle can be seen below in figure 1.
The cylinder volume change is induced through the rotation of a swash-plate, which separates the
hot and cold cylinders by a phase of 90o
. The main user interface is a dry bag on the side of the life ring,
where a phone can be left to charge during use. The main components of the design can be seen in figure
2 below.
Figure 2. Overview of the Solar Stirling Charger. The main components of the design are highlighted with arrows.
Figure 1. An ideal Stirling cycle, which consists of four phases: heating, expansion, cooling, and compression [3].
4. 4
The engine in the center of the design consists of four pairs of cylinders that are alpha type Stirling
engines. An alpha type Stirling engine has two cylinders that contain the working gas and the hot and cold
pistons, which are separately located in the respective cylinder. It is the simplest configuration of the
Stirling engine, however it has the disadvantage of requiring seals around both of the pistons [1]. An
example of this configuration can be seen in figure 3. The configuration of the designed engine and its
main components can be seen in figure 4. A description of each component can be found in Section 3
Individual Components.
A more complete description of the design and how it works can be found in Section 5 How it Works.
The following sections of this paper will discuss the feasibility of this design, including the analysis of the
system dynamics and thermodynamics, critical failure points, design for manual assembly, costing analysis,
safety, and intellectual property.
Figure 3. Example of an alpha type Stirling engine [1].
Figure 4. Overview of the engine. The main components are highlighted with arrows.
5. 5
3 PERFORMANCE SPECIFICATIONS
Table I contains the specifications determined for this project. These specifications will be compared
with the analytical model outputs of the design in order to support its feasibility.
TABLE I
PERFORMANCE SPECIFICATIONS
DESCRIPTION SPECIFICATION
Able to be carried with two hands Less than 2.5 ft.
Access to USB port
Must have convenient user
interface with USB port
Power output to USB port 5 W
Thermal Efficiency 20%
Must be portable Under 50 lb.
6. 6
4 INDIVIDUAL COMPONENTS
This section will introduce and discuss the details of each component, which can be found in the
bill of materials and exploded views in the following sections. The descriptions will include what the
component is made of, why the particular material was used, how the component was made, and how
much each component costs. All custom parts are manufactured via casting. The prices of all casted parts
are estimated using a cost estimator created by Dandong Funding Engineering Machinery Co. This cost
estimator can be used for various types of steel, complexities, and casting processes.
Figure 5. Full assembly exploded view.
7. 7
4.1 SUB-ASSEMBLY A
Sub-assembly A contains all components that encase sub-assembly B and C for transportation and
storage. This assembly also contains the reflective Paraboloid and the dry bag. The Paraboloid is attached
to the floatation tube using the clip straps. The dome is then attached to the Paraboloid using the dome
seal, clip-on nuts, and countersink screws.
Figure 6. Line drawing of sub-assembly A.
TABLE II
BILL OF MATERIALS FOR SUB-ASSEMBLY A
ITEM
NO.
DESCRIPTION NUMBER QTY.
1 Paraboloid PH-A-001 1
2 Dome Cover PH-A-002 1
3 Floatation Tube PH-A-003 1
4 Rope PH-A-004 1
5 Dry Bag PH-A-005 1
6 Clip Strap PH-A-006 3
7 Dome Seal PH-A-007 1
8 Clip-On Nut PH-A-008 4
9 1/4"-20 X 1/2" Countersunk Screw PH-A-009 4
8. 8
Paraboloid
Figure 7. Paraboloid.
The Paraboloid reflects sunlight on to the hot cylinders of the engine; this heats up the air in the
cylinders and begins the expansion phase of the Stirling cycle. It is an acrylic-based solar mirror that is
manufactured via injection molding. Acrylic was the material of choice because it is lighter and cheaper
than glass, as well as easier to manufacture. This part is parabolic in shape, where it is 22 in. in diameter
and 8.5 in. tall. It has four extrusions on the lip that will serve as fastening points for the dome cover and
three extruded slots on the lower portion for fastening the flotation device with clip straps.
Dome Cover
Figure 8. Dome cover.
The dome cover protects the engine from the environment and provides a barrier between the
engine and the user. This part is made of acrylic in order to minimize weight and provide a clear cover in
which radiation can still enter the dome at a high transmission rate. It is 22 in. in diameter in order to
match the shape of the Paraboloid and 1.5 in. tall to provide clearance for sub-assembly C. The dome
cover has four extrusions on its lip for attachment to the Paraboloid and a small cut-out for the USB cord
to exit the dome. This part is injection molded in order to support its complex geometry.
9. 9
Flotation Tube
Figure 9. Flotation device.
The flotation device, as the name implies, allows the Paraboloid assembly to float in a body of
water. This allows only the cold cylinders to be submerged in water and helps to keep water away from
the rest of the device. The floatation device also helps to stabilize the rest of the assembly in cases of
uneasy water surface conditions. The ropes on the flotation device allow easy retrieval of the assembly,
and also allows towing of the assembly. This part is made out of Elvaloy/Hypalon which is an extremely
buoyant material and is more than enough to keep the forty five pound device afloat. The flotation device
has a 24 in. outer diameter and is 4 in. in width. This 24 in. flotation device is bought from Wholesale
Marine for $64.99.
Rope
There is 10 ft. of extra rope that allows the assembly to be tied to various devices in order to tow
or maintain the assembly. The rope is made out of nylon which ensures that the rope is sturdy and can
sustain large pulling forces. The rope is bought from Wholesale Marine for $0.14 per foot. One assembly
requires ten feet which results in $1.40 per assembly.
Dry Bag
Figure 10. Dry bag.
The dry bag is a waterproof storage vessel that is used to house the charging electronic device.
The dry bag also houses the safety equipment needed to handle the device and is used to store other
loose articles or devices. The 2 L dry bag is made out of a proprietary composite material that is water
proof. The dry bag is purchased as a three pack from Walmart for $9.97. Due to only one dry bag being
used per assembly, the total cost for one assembly is $3.32.
10. 10
Clip Strap
Figure 11. Clip Strap.
The clip strap allows the floatation device to be attached to the Paraboloid via the Paraboloid
extrusions. The clip strap also helps to stabilize the assembly via tight attachment to the floatation device.
The clip strap is made out of nylon which ensures that the attachment is sturdy and can sustain large
pulling forces. A clip strap is 1 ft. long, 1 in. wide, and made out of Nylon webbing. An additional clip for
fastening is purchased from Strap Works. The nylon webbing cost $0.18 per foot and each clip is $0.29.
Three of these sets are necessary for each assembly, this results in a total of $1.41 per assembly.
Dome Seal
The dome seal is used to ensure that no water penetrates the inside of the dome when the dome
cover is placed on top of the Paraboloid. The seal is made out of fabric-reinforced high-temperature
silicone foam and has an adhesive backing so it is easy to place on top of the Paraboloid. The dome seal
foam is priced at $65.28 per 30 ft. For one assembly, 6 ft. of the 1/8 in. thick foam strip is needed and the
cost for the seal will be $12.46.
Clip-on Nut
The clip-on nut is a self-locking nut that slides on to the Paraboloid in a spring like fashion. This is
used to fasten the back of the screws given that the whole the screws go through are not threaded and
thus secure the dome cover. These 1/4'β-20 steel clip on nuts are bought in packages of 25 for $18.08 from
The Cliphouse. One assembly will require four nuts and these will cost $2.89 total.
1/4β-20 x Β½β Countersunk Screw
The countersink screws are standard Β½ in. long screws that are used to fasten the dome cover to the
Paraboloid. Countersunk screws were specifically chosen because a countersunk is normally used with
removable paneling and this made the most sense for the removable dome cover. These stainless steel
dome screws can be purchased in packages of 1000 for $100.00 from Bolt-Depot. One assembly requires
four screws which results in a cost of $0.40 per assembly.
11. 11
4.2 SUB-ASSEMBLY B
The following section will explore the components of sub-assembly B, along with their role in the
system. Sub-assembly B contains the most essential components of the Stirling engine. The assembly
contains the bottom half of the coupler, which attaches to the coupler connection for the generator in
order to transmit rotation between the two shafts. The drive shaft sits within the regenerator and depends
on a ball-and-socket joint for attachment with the cool cylinder support. The drive shaft contains the
swashplate, which aids in the transfer of thermal energy to mechanical energy. The rest of the
components directly interface with the fluid within the engine. The hot pistons sit within the hot cylinders
and are able to be manipulated by the fluid pressure. As the system cycles through, the fluid is shuttled
through the regenerator and is cooled down while heading towards the cool cylinders. The cool cylinders
contain the other half of the pistons. The motion of the pistons as the fluid travels between the cylinders
transfers the necessary forces to the swashplate to keep the cycle running.
Figure 12. Upper half exploded view of sub-assembly B.
12. 12
Figure 13. Lower half exploded view of sub-assembly B.
TABLE III
BILL OF MATERIALS FOR SUB-ASSEMBLY B
ITEM
NUMBER
DESCRIPTION
PART
NUMBER
QTY.
1 Drive Shaft Flexible Shaft Coupler PH-B-001 1
2 Hot Cylinder Support PH-B-002 1
3 Swashplate Drive Shaft PH-B-003 1
4 Regenerator PH-B-004 1
5 Cool Cylinder Support PH-B-005 1
6 Hot Piston PH-B-006 4
7 Cool Piston PH-B-007 4
8
1/4"-20 X .75" Countersunk Machine
Screw
PH-B-008 4
9 O-Ring PH-B-009 16
10 Hot Piston Rod Seal PH-B-010 8
11 Cool Piston Seal PH-B-011 4
12 Hot Cylinders PH-B-012 4
13 External Retaining Ring PH-B-013 1
14 Shaft Key PH-B-014 1
15 Starter Gear PH-B-015 1
13. 13
Coupler
Figure 14. Coupler.
The purpose of the coupler is to provide a mechanical connection between the rotating swashplate
drive shaft and the generator shaft. The specific coupler selected is capable of attaching shafts of various
sizes, making it ideal for this system. The coupler is supplied by McMaster. The cost for two coupler hubs
and one spider is $10.03 per assembly.
Hot Cylinder Support
Figure 15. Hot cylinder support.
The hot cylinder support is required to supply stability to several components. It contains
indentations to mate with the generator support in sub-assembly C. The support also contains grooves
designed to accommodate the hot cylinder assembly and align it as needed with the hot pistons. The hot
cylinder support also requires alignment with the regenerator for proper fluid flow, which will be
accomplished using dowel pins. The geometry of the part facilitates the insertion of seals required to
contain the fluid. Upon considering all thermal and mechanical performance requirements for the part,
brass was selected as the optimum material. The part will be cast in order to reduce manufacturing costs.
The hot cylinder support is cast out of brass and weighs 1.27 kg. This component has average complexity
and is manufactured using water glass lost wax investment casting. Additional machining may be
necessary in order to ensure accuracy of the holes. This results in a cost of $13.12. All estimates for brass
casting take into account that brass is more expensive than steel and the price estimator is for steel. The
relative cost is found via the Ashby chart in Fig 6.20 and 6.28 [2].
14. 14
Drive Shaft
Figure 16. Drive shaft.
The swashplate drive shaft is the selected form of power transmission between the pistons and
the generator. This part contains a swashplate at an angle of 20β° relative to the horizontal. The tilt of the
swashplate generates enough instability for the part to rotate about the central axis when a force is
applied towards the radial extremes. The forces experienced by the swashplate are generated by both the
hot and cool pistons. The plate contains troughs on either side for alignment with the pistons. For proper
support, the base of the part contains the cup of a ball-and-socket joint, which is meant to attach with the
cool cylinder support. The swashplate acts as a flywheel for the system, using its inertia to keep the cycle
in motion and ease the flow of the pistons. The shaft diameter is reduced at the tip for attachment with
the coupler via a keyway. The tip of the shaft also attaches to the starter gear to provide the initial
momentum for motivating the system. Material analysis indicates that 304 stainless steel will provide the
necessary momentum properties, as well as strength, for the part to perform as needed. The most
effective method for manufacturing the part is casting due to the low tolerances and geometry of the part.
This component is cast using silica sol lost wax investment casting and possesses normal complexity.
Taking into account that simple machining may be needed to ensure smooth troughs, the final cost of the
drive shaft is $6.51.
Regenerator
Figure 17. Regenerator.
The regenerator serves multiple purposes in the assembly. The main function is to provide a shuttling
path for the fluid within the engine, while providing a method for storing and releasing thermal energy to
and from the fluid to improve engine efficiency. Another function of the regenerator for this design is to
15. 15
provide a protective enclosure for the rotating drive shaft. An effective regenerator is required to absorb
heat from the fluid as it flows from the hot cylinders to the cold cylinders, retain as much of the heat as
possible, and release the heat back to the fluid as it returns towards the hot cylinders. To accomplish all
of these tasks, the regenerator will be made from 304 stainless steel. The general shape of the regenerator
is a hollow cylinder. This shell will have the pathways for the fluid as well as threaded holes for attachment
with the hot and cold cylinder supports. In order to fit the rotating drive shaft inside, the inner diameter
is 3.50 in. with a thickness of 0.50 in. to accommodate the fluid pathways as well as the threads. To achieve
this complex geometry the regenerator will be cast. The regenerator is cast using silica sol lost wax
investment casting. This cast is considered complex due to the internal holes. There is also additional
machining needed to generate the threaded holes. This part weighs 2.22 kg and the total cost is $20.50.
Cool Cylinder Support
Figure 18. Cool cylinder support.
The cold cylinder support is the foundation of the engine assembly. The part is fastened to the
regenerator for proper alignments and allows the air to be shuttled into the chambers. The chambers
guide the cooling pistons and hold the shuttled air as it is cooled by the water. The center support holds
the drive shaft and allows it to rotate as it is driven by the piston. The piece is made of 304 stainless steel
to be corrosion resistant and strong. It measures about 5 in. in diameter and 3.5 in. tall and, due to the
complex geometry, the part will be cast which results in a cost of $14.78.
Hot Piston
Figure 19. Hot piston.
The hot pistons displace the air in the hot cylinders and drive the swashplate. The pistons are cast
out of 304 stainless steel for strength. Each piston is about 3.5 in. long, 1 in. in diameter, weighs 0.06 kg,
and costs $5.53.
16. 16
Cool Piston
Figure 20. Cool piston.
The cool pistons compress the air in the cool cylinders and drive the swashplate. The pistons are
cast out of 304 stainless steel for strength and corrosion resistance. Each piston is about 3.5 in. long, 1 in.
in diameter, weighs 0.06 kg, and costs $5.53.
Piston Seals
Figure 21. Piston seal.
The piston seals prevent the air moved by the pistons from escaping from the chamber except by
the desired channels. The part is used on both the hot and cool pistons. The high temperature piston rod
seals are purchased from McMaster-Carr for $17.88 per seal and approximately Β½ in. wide and 1/
8 in. thick.
Hot Cylinders
Figure 22. Hot cylinders.
The brass cylinders transfer the heat from the sunlight focused on its outer walls into the air
contained inside to fuel the Stirling cycle. They are welded to the hot cylinder support and hold the hot
pistons in line. The hot cylinders are cast out of brass and cost $9.73.
17. 17
Pull Start Gear
Figure 23. Shaft gear.
This 304 stainless steel gear is one component of the rack-pinion method of starting the device.
The gear is attached to the main shaft and helps begin the Stirling cycle in the engine. The starter gear is
purchased from Stock Drive Products Sterling Instrument for $9.83 each.
Piston O-rings
Figure 24. Piston O-ring.
The piston O-rings help provide a tight seal to the chamber walls and help decrease friction. The
piston O-rings are made out of stainless steel to withstand the high temperatures experienced in the
cylinders. The O-rings are purchased from Darcoid Nor-Cal Seal and the price is approximated at $10.00
per seal.
Screws
The regenerator screws are bought in packages of 1000 from Bolt-Depot for $236.00. Only eight
screws are needed per assembly, therefore, the cost for these screws is $1.89 per assembly.
External Retaining Ring
The external retaining ring is bought from McMaster as a pack of 10 for $8.46. Each assembly requires
one snap ring which totals $0.85 per assembly.
Shaft Key
The shaft key is manufactured by casting UNS G10180 CD Low carbon mild steel and weighs
approximately 0.002 kg. This geometry is very simple and costs $5.17.
18. 18
4.3 SUB-ASSEMBLY C
The following section will explore the components of sub-assembly C, along with their role in the
system. Sub-assembly C contains all of the electronic components necessary for the device. The coupler
present in this assembly is used to attach the generator to the mechanical drive shaft described in sub-
assembly B. The generator is fastened to the generator support which is epoxied to the starter cover. The
power output from the generator is delivered to the buck converter and finally output using a DC to USB
port.
Figure 25. Sub-assembly C.
TABLE IV
BILL OF MATERIALS FOR SUB-ASSEMBLY C
ITEM
NUMBER
DESCRIPTION PART NUMBER QTY.
1 Generator Support PH-C-001 1
2 Generator Flexible Shaft Coupling PH-C-002 1
3 Starter Cover PH-C-003 2
4 Generator PH-C-005 1
5 Buck Converter PH-C-006 1
6 DC to USB Port PH-C-007 1
7 Generator and Electronics Cover PH-C-008 1
8 3M x 10mm Hex Head Screw PH-C-009 2
19. 19
Generator Support
Figure 26. Generator support.
The generator support is used to stabilize the generator and provide a mounting location for the
generator as well as all of the electrical components. The geometry must be such that the generator and
the screws can be inserted properly. The cover must also be able to fit onto the top of the support in order
to protect the electronic components. The overall size of the support is 3.50 in. by 3.50 in. by 4.61 in. The
generator support is cast out of brass using water glass lost wax investment casting with no additional
machining. The material for this component is brass to allow for it to be welded to the hot cylinder support.
This support weight 0.26 kg and costs $3.08.
Generator Flexible Shaft Coupler
Figure 27. Generator flexible shaft coupler.
This half of the coupler mates with the coupler previously described in sub-assembly B.
Starter Cover
Figure 28. Starter cover.
20. 20
The purpose of the starter cover is to guide the pull key starter into the starter gear. This cover is cast
out of stainless steel using water glass lost wax investment casting. The overall dimensions of the cover
are 3.50 in. by 3.50 in. by 0.10 in. Each cover weights 0.06 kg and does not possess complex geometry nor
does it need additional machining. This results in each cover costing $1.07 each. Each assembly requires
two starter covers which totals $2.14.
Generator
The generator is used to convert the mechanical energy of the shaft into electrical energy that can
ultimately be used to charge a modern day cellphone. The generator is purchased from RobotShop for
$5.88.
Buck Converter
The Buck converts the AC current from the generator to a controlled DC current, which is supplied to
the DC to USB port. The buck converter is supplied by Amazon for $10.66.
DC to USB Port
The DC to USB converter is the direct interface between the engine and the device being charged.
This converter is DROK brand and purchased from Amazon for $5.80.
Generator and Electronics Cover
Figure 29. Generator and electronics cover.
The generator and electronics cover is used to insulate the sensitive electronic components from
the extreme temperatures experienced by the engine. It is made using a ceramic sheet from CeraMaterials
at a rate of $12.78 for 864 sq-in. Each assembly requires 37 sq-in and totals to $0.55 per assembly.
3M x 10mm Hex Head Screw
Two 3M x 10mm Hex Head Screw are used in order to secure the generator to the generator support.
These screws are purchased in packages of 100 from Amazon for $6.57 per package. Two screws are
needed per assembly which totals to $0.13.
21. 21
5 HOW IT WORKS
5.1 NOMINAL USE
This device has several requirements that must be met in order to function as intended. These
requirements are as follows:
- Ensure reflective surface and clear dome is free of dirt and debris.
- Place assembly in an area with direct sunlight.
- Placed in a body of water at least 2 feet deep.
- Have dome securely attached to Paraboloid.
- Attach entire assembly to a fixed structure using the rope provided.
- Place electronic device in dry bag and close tightly.
In addition to these requirements, it is critical to visually inspect the device in order to ensure seals
are functioning as intended and that the flotation device and clip straps are in working condition. The
formal instruction manual for this product will contain safety warnings in the following format:
WARNING
ELECTRIC SHOCK, FIRE OR BURN INJURIES CAN OCCUR IF THIS EQUIPMENT IS NOT USED
PROPERLY. TO REDUCE RISK OF INJURY:
ο· Do not operate unattended.
ο· Assume all surfaces are hot while in use
ο· Only handle hot components while in a stable position and wearing safety gloves
ο· Keep face and eyes away from hot surfaces
ο· Do NOT attempt to start while swimming in the water
ο· Do NOT allow foreign materials into the dome and engine components
ο· Keep loose articles away from rotating components
Use
ο· Open dry bag and plug in electronic, retrieve safety gloves, and starter pull key
ο· Reseal bag and place device in the water, within reach, and in direct sunlight
ο· Use provided safety gloves to open dome cover
ο· Insert starter pull key and pull vigorously
ο· Repeat Step 4 until motor begins turning on its own
ο· Replace cover and seal tightly
ο· Ensure device is properly tethered to prevent drifting
ο· Check the charge on devices regularly
Follow maintenance procedures after each use
22. 22
Maintenance
1. Remove device from sunlight and place in safe area
2. Let it cool completely (checking with hand near but not touching the surfaces)
3. Empty dry bag and wipe out with a cloth
4. Rinse external surfaces with clean water; wipe dry
5. Dry and store in a cool, dry place away from sunlight
5.2 ANALYSIS
This section will detail the approach used to analyze the kinematics, dynamics, and
thermodynamics of the design. This is not an exhaustive analyzation, and there is a potential for future
calculations. The table below contains the definitions and variables used throughout the following
calculations.
TABLE V
VARIABLE SYMBOLS AND DEFINITIONS
SYMBOL DEFINITION
Ap Incident area of a single piston
g Gravity
r Instantaneous distance from the nth piston to the swashplate pivot
Mp Mass of a single piston
Ms Mass of swashplate
Pi Pressure realized by piston
Pi,Ξ΄ Pressure of 90o
offset cool cylinder
Ts Swashplate swivel torque
ο’ Tilt angle of swashplate
ο± Rotation angle of swashplate
d Diameter of hot and cool piston
h Height of hot piston
L Distance from hot cylinder support to the center of the swashplate
tswash Thickness of swash plate
s Distance between the origin and center of the track
VT Total volume of one pair of cylinders
ka Surface condition modification factor
kb Size modification factor
23. 23
kc Load modification factor
kd Temperature modification factor
ke Reliability factor
kf Miscellaneous-effects modification factor
Se
β
Rotary-beam test specimen endurance limit
Se
Endurance limit at the critical location of a machine part in the
geometry and condition of use
5.2.1 Kinematics and Dynamics
The overall geometry of the system is the driving factor for the design of many of the components.
The selected method of power transmission is a swashplate mechanism, which will rotate along the
central axis of the Paraboloid. This motion is due to the 20β° tilt of the plate portion of the drive shaft and
the pistons exerting forces on the swashplate.
Figure 30. Shaft and piston diagram to illustrate volume changes.
The nature of the Stirling cycle is one of dynamic volume. The volume for each of the four alpha
pairs depends on the angle of rotation of the shaft. The kinematics of the system will play a large role in
the behavior of the engine. Figure 30 depicts the relationship between one piston and the swashplate
drive shaft.
ππ = π β tan π½ β cos π π’Μ1 + π π’Μ2
Using the transport theorem, the velocity of the point as viewed by the plate is
π π§
π π₯
π’Μ1
π’Μ2
r
h
π½
24. 24
π£ π = βπ β sin π½ β tan π½ β πΜ β sin π π π₯ + π β sin π½ β πΜ β sin π π π§
And the acceleration becomes
π π = βπ β sin π½ β tan π½ β (πΜ sin π + πΜ2
cos π)π π₯ + π β sin π½ β (πΜ sin π + πΜ2
cos π)π π§ (1)
Figure 31. Shaft FBD.
Eulerβs 2nd
Law was used to analyze the angular momentum of the system
π
ππ‘
( H π
0
πΊ
) = β π
(2),
where the angular momentum, H π
0
πΊ
, is defined to be
H π
0
πΊ
= πΌ β π π
0
πΊ
I is the moment of inertia about the body-fixed coordinate system,
π½
π π§
π π₯
π’Μ1
π’Μ2
g
ππ
πΉ π, π
πΉπ,πΏ
r
πΉπ¦
25. 25
πΌ =
[
1
4
ππ π 2
0 0
0
1
4
ππ π 2
0
0 0
1
2
ππ π 2
]
and π π
0
πΊ
is the angular velocity about the vertical axis defined as
π π
0
πΊ
= [
0
0
πΜ
]
In addition to the dynamics of the swashplate, the dynamics of the pistons also needs to be
considered. The pistons move vertically with relation to a Newtonian reference frame and experience
forces due to the pressure inside the vessels. This motion can be described with the kinematics of the
swashplate previously analyzed, however, there is friction involved with this motion. The presence of air-
tight seals generates friction with the surface of the piston rods and reduces the force acting on the
swashplate, diminishing the final torque output.
Figure 32. Piston FBD.
The moments acting on the system directly depend on the pressures inside of the hot cylinders.
The force supplied by the hot cylinders is defined as
πΉπ,π = (ππ β π΄ π + πΉπ,π) π’Μ1
And the force due to the pressure from the cool system is
πΉπ,πΏ = (ππ,πΏ β π΄ π β πΉπ,πΏ) π’Μ1
Friction on the piston is to be modeled as viscous [11]
πΉπ = β(π β π β sin π½ β tan π½ β πΜ β sin π) π’Μ1
πΉπ πΉπ
ππ β π΄ π ππ β π΄ π
g
26. 26
where π is the coefficient of friction between the piston and the seals. This value was found to be 0.58
for 304 stainless steel [12].
The rotational friction due to the ball-and-socket joint at the base of the swashplate was modeled as
a linear torque opposing the rotation of the shaft, as shown below.
π π = π β πΜ π’Μ1
Combining all of the force relations and performing the cross product with their respective
displacements relative to the center of the swashplate, the moments in the three principle coordinates
become,
β π π₯
4
1
= π β sin π β cos π½ β (πΉπ,πΏ β πΉπ,π β 2 β π π β π β 2 β πΉπ) β π β sin π½ β πΜ,
β π π¦
4
1
= π β cos π β (πΉπ,πΏ β πΉπ,π β 2 β π π β π) β πΏ β πΉπ¦,
β ππ§
4
1
= π β sin π β sin π½ β (πΉπ,πΏ β πΉπ,π β 2 β π π β π β 2 β πΉπ) β π β cos π½ β πΜ.
Applying these relations to (2), the following is obtained
[
β
1
4
ππ π 2
sin π½ πΜ
1
4
ππ π 2
sin π½ πΜ2
1
2
ππ π 2
cos π½ πΜ
]
= [
π β cos π½ β (πΉπ,πΏ β πΉπ,π β 2 β π π β π β 2 β πΉπ) β sin π β π β sin π½ β πΜ
π β cos π β (πΉπ,πΏ β πΉπ,π β 2 β π π β π) β πΏ β πΉπ
π β sin π½ β (πΉπ,πΏ β πΉπ,π β 2 β π π β π β 2 β πΉπ) β sin π β π β cos π½ β πΜ
].
Based on these results, one can obtain a relationship for the angular acceleration of the system.
πΜ =
2 β tan π½ β (πΉπ,πΏ β πΉπ,π β 2 β π π β π β 2 β πΉπ) sin π β π β πΜ
ππ β π
(3)
Due to the complexity of the expression, it was evaluated through an iterative process to obtain
the steady-state value for the angular velocity as the process begins. Figure 33 illustrates the result of
these values.
27. 27
The steady-state torque produced by the system with a load of 0.06 N-m is calculated as
π = 0.06 ππ β πΜ,
which results in a mechanical power of 16.3 watts.
5.2.2 Thermodynamics and Heat Transfer
The following section goes into more detail on the thermal analysis of the Solar Stirling Charger
to show how the power output spec of 5 W is feasible thermodynamically. First is an overview of the
Stirling cycle and how it applies to the Solar Stirling Charger, showing how the air volume and pressure
varies with the rotational angle of the motor shaft. Second, the overall heat transfer is discussed,
explaining how sunlight is converted into a usable power output along with any heat losses incurred in
the process and calculated efficiencies. For these analyses, the following weather conditions were
considered:
TABLE VI
CLEAR SKY CONDITIONS
CONDITION VALUE
Solar Radiation, Gatm (W/m2) 893
Effective Sky Temperature, Tsky (K) 354 (177.53 Β°F)
Finally, the thermodynamic inputs, outputs, and efficiencies of the system were iterated at various
weather conditions to show how the Solar Stirling Chargerβs performance changes and whether it still
meets spec.
Figure 33. Steady state angular velocity of the drive shaft.
28. 28
5.2.2.1 The Stirling Cycle
The ideal Stirling cycle (figure 34b) consists of four phases, which follow the airβs movement throughout
a pair of cylinders:
a. Isothermal expansion (1 -> 2)
ο· The air in the hot cylinders receives heat input Qin from sunlight, causing the air to expand
and exert force on the hot pistons.
b. Isochoric cooling (2 -> 3)
ο· The air flows from the hot cylinder to the cool cylinder through the regenerator with some
of its heat, Qr, being transferred to the regenerator.
c. Isothermal compression (3 -> 4)
ο· The air in the in the cool cylinder rejects Qout into the water, causing the air to become
denser, enabling the piston to compress the air.
d. Isochoric heating (4 -> 1)
ο· The air flows from the cool cylinder to the hot cylinder through the regenerator with the
heat being stored in the regenerator, Qr, being returned to the air.
Figure 34. a) Heat movement throughout system. b) Ideal P-V diagram.
5.2.2.2 Volume
The total volume of the Solar Stirling Charger is dependent on three air volumes: the air in the hot and
cold cylinders, VH and VC, and the regenerator, VR. The following volume equations were derived from
kinematics and are dependent on π, the rotation angle of the drive shaft. In these equations, πΏ is the
phase difference between the hot and cold pistons (π/2 rad), d is the diameter of a piston, s is the distance
vector from the centroid of the swashplate to the connection point of the piston rod, π½ is the tilt of the
swashplate, πΎ is the local tilt of s, π is the global tilt of s, and tswash is the thickness of the swashplate.
ππ»(π) = 0.25ππ2(π β sin π)(1 β cos π) (4)
ππΆ(π) = 0.25ππ2(π β sin π)(1 β cos(π β πΏ)) (5)
Qin
Qout
Qr
a) b)
29. 29
Wherein the geometry is defined as follows:
π½ =
π
9
πππ (6)
π β sin(πΎ) = π‘ π π€ππ β/2 (7)
π = π½ + πΎ (8)
Some of these geometric parameters are labeled in figures 35 and 36.
Whereas, the volume of the air in the regenerator is a constant:
ππ = 0.0348 ππ3
Figure 35. Geometry for volume model: a) Swashplate, b) Close-up.
Figure 36. Geometry for volume model: hot cylinders (aka bulbs).
π
a) b)
Swashplate
Drive Shaft
s
s
π½
πΎ
tswash
Stroke
Hot Cylinders
d
30. 30
Using the preceding relations, the total volume of a pair of cylinders ππ can be expressed as thus:
ππ = ππ»(π) + ππΆ(π β πΏ) + ππ (9)
The cyclical change of these volumes for a single pair of cylinders are plotted in figure 37.
Figure 37. Volume of one cylinder pair vs. crank angle of swashplate.
5.2.2.3 Pressure
Assuming ideal gas and constant pressure throughout the engine, the relationship between
pressure P and volume V can be expressed as follows:
ππ = ππ π (10)
Wherein m is mass of the air, R is the gas constant for air, and T is the air temperature.
Applying (10) to each section of the engine (hot (subscript H) and cold (subscript C) cylinders and
regenerator (subscript R)), the air mass can be calculated, individually.
π π» =
πππ»
π π π»
(11)
π πΆ =
πππΆ
π ππΆ
(12)
π π =
πππ
π ππ
(13)
The same relationship can be applied to the total mass (mT) of the engine at ambient conditions (P0 =
14.7 psi, T0 = 77Β°F), which is a constant:
π π =
π0 ππ
π π0
(14)
31. 31
The total mass can, of course, be written as the sum of the individual air masses.
π π = π π» + π πΆ + π π (15)
Therefore, (12) through (15) can be plugged into (16), giving
π π =
πππ»
π π π»
+
πππΆ
π ππΆ
+
πππ
π ππ
(16)
After rearranging, pressure is a function of volume which is a function of shaft rotation angle π.
π =
π π β π
ππ»
π π»
+
ππΆ
ππΆ
+
ππ
ππ
(17)
Using the geometry of the engine, pressure can be plotted as thus:
Figure 38. Pressure of cylinder pair vs. crank angle of swashplate.
32. 32
5.2.2.4 Non-Ideal Stirling Cycle
Now, the pressure and volume can be plotted parametrically, producing the actual P-V diagram
of the Solar Stirling Charger, as seen in figure 39.
Figure 39. P-V diagram for theoretical Stirling cycle.
In the actual Stirling cycle, the heating and cooling processes are no longer constant volume
processes. However, the effective temperatures of the air in the hot, cold cylinders, and the regenerator
are assumed to be constant. To define these temperatures, a heat transfer analysis was conducted as
explained in the following section.
5.2.2.5 Heat Transfer
This section explains the details of the heat transfer analysis of the Solar Stirling Charger in the
following order: First, the heat input is described from the Sun to the hot cylinders followed by a discussion
of the heat losses. Second, the effect of the regenerator on transmitting heat to and from the air is
investigated. Third, the heat dissipation from the cold cylinders is described, followed by the work output
resulting from an energy balance of the Stirling engine.
Solar Intake
On a clear day, the sun shines with the solar flux Gatm of 893 W/m2
, [13]. The effective sky
temperature πΜ π ππ¦ on a clear day is 354 K (177.53 β¦
F) as defined by (&), where π is the Stefan-Boltzmann
constant (5.67 Γ 10β8
π/(π2
β πΎ4
)), [14].
πΊ ππ‘π = ππΜ π ππ¦
4
(18)
33. 33
On such a day, the dome with an outer surface area π΄ ππππ of 0.2530 m2
(392.1 in2
) receives the
following in solar radiation:
π π ππππ = 225.9 W
As shown in figure 40, the Sunβs rays strike the dome of the Solar Stirling Charger, and are then
reflected by the Paraboloid which redirects the rays to the domeβs focus, where the hot cylinders stand.
Figure 40. Diagram of solar intake to the hot cylinders.
To calculate how much solar flux is transmitted into the engine is as follows:
For acrylic, the transmissivity π ππππ¦πππ is on average 90% between π1 = 0.4 Β΅m and π2 = 1.1 Β΅m,
as approximated by the similar material in figure 41. Using the Sun as a blackbody emitter, the product of
πππ π’π can be looked up in Table 12.2 of [14], wherein the effective temperature of the sun Tsun is 5800 K,
[14]. After linear interpolation, the fraction of radiation πΉ(0βπ) for each wavelength was figured to be:
πΉ(0βπ1) = 0.124509
πΉ(0βπ2) = 0.769234
Figure 41. Transmission spectrum of acrylic, [Arkema].
π π ππππ
ππ‘ππππ
π πππ
Paraboloid
Dome
Hot
Cylinders
34. 34
The fraction of radiation for the specified range of wavelengths πΉ(π1βπ2) is the difference of these
two fractions. The product of this and the acrylic transmissivity gives the total transmissivity [14],
π π‘ππ‘ππ = πΉ(π1βπ2) β π ππππ¦πππ (19)
π π‘ππ‘ππ = (0.769234 β 0.124509) β 0.90
π π‘ππ‘ππ = 0.5803
Thus, the solar flux transmitted through the dome is [14],
ππ‘ππππ
β³
= π π‘ππ‘ππ β πΊ ππ‘π (20)
ππ‘ππππ
β³
= 518.2 π/π2
The solar Paraboloid receives π ππππ
π ππππ = ππ‘ππππ
β³
β π΄ ππππ (21)
π ππππ = 177.2 π
where π΄ ππππ is the exposed surface area of the Paraboloid, 0.3419 m2
(530 in2
).
The solar Paraboloid reflects 68% of this sunlight, based on Table D from [16]. Though the
manufacturer gave a reflectivity of 90%, the 68% value is being used as a more conservative value.
π πππ = 0.68 β π ππππ (22)
π πππ = 120.5 π
This π πππ is the heat being directed to the hot cylinders.The temperature of the outside of the hot
cylinders is given by their grey body absorption.
πππ’π‘,β = π πππ/(ππ π π΄ πππ )1 4β
(23)
Where π is the Stefan-Boltzmann constant, π π is the emissivity of brass (oxidized) from [18] which
is 0.61, and π΄ πππ is the surface area of the hot cylinders (see figure 42) that is absorbing sunlight.
Figure 42. The geometry of the hot cylinder assembly, wherein cylinder/sun blocker height Lh = 2 in, inner diameter Dih = 0.925
in, cylinder wall thickness th = 0.1 in, cylinder outer diameter Doh = 1.125 in, and sun blocker width Wsb = 0.68 in. The absorbing
area as the combined, exterior surface area of the hot cylinders and the sun blockers connecting them.
Dih
Doh
Lh
Wsb
th
qref
qref
Hot CylinderSun Blocker
35. 35
Based on the geometry of the cylinders and the sun blockers, as seen in figure 42, the absorbing area is:
π΄ πππ = 4[(πΏβ ππ π) + 0.75(ππ· πβ πΏβ)] (24)
Thus, the temperature of the outside of the hot cylinders is:
πππ’π‘,β = 709.2 πΎ (816.89 Β°πΉ)
Solar Losses
Already, there are two losses accounted for during the radiation portion of the heat input: one
during the transmission of light through the dome, ππ‘ππππ ,πππ π and another during reflection of light off
the Paraboloid, π πππ,πππ π . These are as follows:
ππ‘ππππ ,πππ π = (πΊ ππ‘π β ππ‘ππππ
β³ ) β π΄ ππππ (25)
π πππππ,ππππ = ππ. π πΎ
Wherein π΄ ππππ is outer surface area of the dome 392.1.
π πππ,πππ π = π ππππ β π πππ (26)
π πππ,ππππ = ππ. π πΎ
Conduction and Convection Losses
Heat leaving the hot cylinders to the ambient conditions directly outside of the Paraboloid (assumed
to be 8 degrees above Tsky, based on [19]) is controlled by the following thermal resistances:
ο· Conduction resistance of air under the dome, π π‘,ππππ,ππππ,πππ.
ο· Conduction resistance of the Paraboloid π π‘,ππππ,ππππ,ππππ¦πππ and the dome, π π‘,ππππ,ππππ .
ο· Convection resistance of the wind, π π‘,ππππ£,π€πππ.
The overall resistance of the losses π π‘,πππ π is given as
π π‘,πππ π = π π‘,ππππ,ππππ,πππ + (π π‘,ππππ,ππππ,ππππ¦πππ
β1
+ π π‘,ππππ,ππππ
β1
)
β1
+ π π‘,ππππ£,π€πππ (27)
Losses through Parabolic Resistances
The air space underneath the dome was approximated to be one-dimensional conduction through
a Paraboloid of the equation
π§ ππππ =
πππππ
2
2π
(28)
Where z is the height of the Paraboloid, r is the radial distance from the central axis, and b is the
constant 7.1 in.
36. 36
Using the radial version of Fourierβs law of conduction from [14],
π π = βππ΄ (
ππ
ππ
) (29)
Where π π is the radial heat transfer, k is the conductivity, A is the surface area normal to the
heat transfer, and
ππ
ππ
is the radial temperature gradient.
With the surface area of a Paraboloid π΄ ππππ given by
π΄ ππππ = ((
π
π
)
2
+ 1)
3
2
(30)
Wherein
π =
2(7.12
π)
3
ππ2
After rearranging substituting (30) into (29) and solving for the heat transfer, the following
relationship is derived:
π π,ππππ =
ππ(π1 β π2)
πΌ
(31)
Where I is the integral
πΌ ππππ = β«
ππ
((
π
π
)
2
+ 1)
3
2
π2
π1
(32)
Which solves to
πΌ ππππ =
π
β(
π
π
)
2
+ 1
]
π2
π1 (33)
Based on (31), conduction thermal resistance of the Paraboloid is given as
π π‘ππππ,ππππ =
πΌ
ππ
(34)
This formula can be applied to both the conduction resistance of the air and the acrylic Paraboloid
as such:
TABLE VII
THERMAL RESISTANCES OF PARABOLOIDS
MEDIUM
THERMAL
CONDUCTIVITY,
K, (W/(MβK))
RPARA, 1 , (IN) RPARA,2 , (IN)
THERMAL
RESISTANCE, RT,
(K/W)
Air at 600K 46.9 x 10-3
10.916 11.084 33.29
Acrylic Paraboloid 0.2 1.8225 10.916 0.05
37. 37
Figure 43. Geometry of the Paraboloid.
Losses through the Dome
Similarly the conductive resistance of the dome (spherical cap) can be calculated using radial
Fourierβs law (31), where surface area π΄ ππππ is given by
π΄ ππππ = π(π ππππ
2
+ β ππππ
2
) (35)
Wherein the geometry is given by figure 44.
Figure 44. Geometry of the dome, π ππππ = 11 ππ, β ππππ,1 = 1.75 ππ, π‘ ππππ, = 0.2 ππ, and. β ππππ,2 = β ππππ,1 + π‘ ππππ,
For Fourierβs law, π ππππ is kept constant and β ππππ is assumed to change (from β1,ππππ
to β2,ππππ), wherein the radial heat transfer is given as
π π,ππππ =
ππ ππππ πΞπ
arctan(
β2,ππππ
π ππππ
) β arctan (
β1,ππππ
π ππππ
)
(36)
Thus, the conduction thermal resistance of the dome is given by:
π π‘,ππππ,ππππ =
arctan(
β2,ππππ
π ππππ
) β arctan (
β1,ππππ
π ππππ
)
ππ ππππ π
(37)
π π‘,ππππ,ππππ = 0.1007 πΎ/π
Wherein the geometric variables are in figure 44 and the conductivity k is of acrylic (0.2 W/mK).
π§ ππππ
πππππ
_
Air Space
Acrylic
β ππππ,1
π ππππ
π‘ ππππ
38. 38
Losses due to Wind
Based on grey body emission, the temperature of the outside of the dome πππ’π‘,ππππ is
πππ’π‘,ππππ = (
πΊ ππ‘π
ππ ππππ
+ ππ ππ¦
4
)
1
4
(38)
πππ’π‘,ππππ = 427 πΎ
Where π ππππ is the emissivity of the acrylic dome which is 0.9 as given by [14].
From [14], the convection heat transfer coefficient due to wind β π€πππ is
β π€πππ = 0.22(πππ’π‘,ππππ β ππππ)
1 3β
(39)
β π€πππ = 0.8835
π
π2 β πΎ
And the convection resistance of the wind is, thus, given by
π π‘,ππππ£,π€πππ = 1/(β π€πππ π΄ ππππ) (40)
π π‘,ππππ£,π€πππ = 4.4747 πΎ/π
Altogether, the resistance of the heat losses is
π π‘,πππ π = 37.8 π/πΎ
The heat loss ππππ π from the hot cylinders to the ambient can be given by
ππππ π = (πππ’π‘,β β ππππ)/π π‘,πππ π (41)
πππππ = π. ππππ
Now, all the heat losses can be summarized in the table below.
TABLE VIII
SUMMARY OF HEAT LOSSES
LOSS TYPE TRANSMISSION LOSS REFLECTION LOSS CONDUCTION AND CONVECTION
Thermal Loss, W 94.8 56.7 9.2
Thus, taking the conduction and convection losses into account, the net heat input π πππ‘,ππ to the
hot cylinder assemblyβs surface is
π πππ‘,ππ = π πππ β ππππ π (42)
π πππ‘,ππ = 111.3 π
Dividing this values equally among the four hot cylinders gives, πππ,β, which is ultimately the heat
input into each separate pair of cylinders.
πππ,π = ππ. π πΎ
39. 39
Figure 45. The geometry of the hot cylinder assembly, wherein Lh = 2 in, Dih = 0.925 in, th = 0.1 in and Doh = 1.125 in, Wsb = 0.68
in.
Heat Transfer through the Hot Cylinder
Assuming one-dimensional conduction through a cylinder, the thermal resistance of each hot cylinder is
π π‘,ππππ,β =
ln (
π· πβ
π·πβ
)
2ππ‘β π π
(43)
π π‘,ππππ,β = 0.1115 πΎ/π
Where π π is conductivity of the brass hot cylinders (110 W/mK) from [14] and the hot cylinder
geometry is from figure 45.
Once the heat transverses the wall thickness of the hot cylinder, it encounters the forced
convection thermal resistance of the moving air inside. This thermal resistance is dependent on velocity
of the air, which has been approximated to the velocity of the hot sideβs piston, π’ πππ π‘ππ(π).
π’ πππ π‘ππ(π) = π(tanπ½)(π πππ)π (44)
Wherein π is the distance vector between the center of the drive shaft and the piston rod, π½ is the
tilt of the swashplate, and π and π are the rotational angle and velocity of the drive shaft, respectively.
These variables are shown in figure 46.
Dih
Doh
Lh
Wsb
th
qnet,in
qnet,in
Hot CylinderSun Blocker
40. 40
Figure 46. Swashplate and piston geometry.
Since the velocity of the piston is sinusoidal, the root-mean-square of the velocity is used to
represent the fluid velocity in the hot cylinder, π’β. At rotational speed achieved on a βclear day,β (2590
RPM), the air velocity is:
π’β = 21.4 π/π
Furthermore, the Reynoldβs number of the hot side air π π π·,β is thus, using the thermal
properties of air at 600K, which are listed in Table IX [14]:
π π π·,β = π’β π·πβ/πβ (45)
π π π·,β = 9525.7
Where Dih is the inner diameter of the hot cylinder and πβ is the kinematic viscosity of the hot air.
TABLE IX
THERMAL PROPERTIES OF AIR AT 600K
DENSITY,
π π‘ (
π€π
π¦ π)
DYNAMIC
VISCOSITY,
π π‘ (π β π¬/π¦ π
)
KINEMATIC
VISCOSITY,
π π‘ (π¦ π
/π¬)
PRANDTL
NUMBER,
Prh
THERMAL
CONDUCTIVITY,
π€ π‘ (W/M K)
SPECIFIC
HEAT, π π,π
(J/(KG K))
0.5804 305.8 x 10-7
52.69 x 10-6
0.685 46.9 x 10-3
1051
The Dittus-Boelter equation is used to determine the non-dimensional heat transfer coefficient,
the Nusselt number, of the hot cylinder flow [14]. The flow was assumed to be fully developed and
turbulent despite the Reynoldβs number being slightly below the turbulence realm (π π π· β₯ 10,000).
ππ’ π·,β = 0.023π π π·
4 5β
Pr0.4
π
π½
π, π
Swashplate
Drive Shaft
Hot Piston
41. 41
ππ’ π·,β = 30.1
Which is then used to find the heat transfer coefficient for the hot side, ββ:
ββ = ππ’ π·,β πβ/π·πβ (46)
ββ = 60.2 π/π2
πΎ
Where πβ is the thermal conductivity of the air (see Table IX). From which the convection thermal
resistance of the air in the hot cylinder is:
π π‘,ππππ£,β = 1/(ββ ππ·πβ πΏβ) (47)
π π‘,ππππ£,β = 4.43 πΎ/π
Where the term ππ·πβ πΏβ is the inner surface area of the hot cylinder.
Putting the thermal resistances of the hot cylinder together with the heat input πππ,β gives the
temperature difference from outside the cylinder πππ’π‘,β to the effective temperature of the air in the hot
cylinder, πβ.
πβ = πππ’π‘,β β πππ,β β (π π‘,ππππ,β + π π‘,ππππ£,β) (48)
π» π = πππ. ππ π² (πππ. ππ Β°π)
Regenerator
The regenerator plays an important role in improving the efficiency of the system as a whole. It
functions as a heat bank. As the hot fluid flows to the cool cylinders, the regenerator absorbs some of the
thermal energy in attempt to cool the fluid as much as possible before it reaches the compressive
chambers. When the fluid returns towards the hot cylinders, the regenerator releases the thermal energy
back to the fluid to raise its temperature to reduce the amount of energy required to expand the fluid and
keep the cycle in motion. The following section will explore the various modes of heat transfer involved
with the regenerator as the fluid travels between the hot and cool cylinders.
Figure 47. Transparent view of the regenerator.
Fluid flow
πβ
ππ
qref
qref
42. 42
The surface temperature of the regenerator will play a large role in its performance, therefore
one must first consider its surface temperature due to the thermal radiation contained within the
Paraboloid-dome system.
ππ π =
π πππ
π β π π π β ππ΄ πππππ
(49)
The nature of the system dictates that convection is expected to be the dominant mode of heat
transfer in the system. To determine the convective thermal resistance, one must obtain the coefficient
of convective heat transfer, shown below.
β π =
ππ’ π·π β πβ
π·π‘π’ππ
(50)
The geometry of the regenerator is already known, as is the conductance of the fluid, therefore
one only needs to determine the Nusselt number, the Dittus-Boelter relation for cooling was selected
based on the flow conditions [14].
ππ’ π·π = 0.023 β π π π·π
4
5
β ππβ
0.3
(51)
The Reynolds for this flow can me calculated using the
π π π·π =
4 β πΜ
π β π·π‘π’ππ β πβ
(52)
For calculating the Reynolds number the mass flow rate can be obtained based on fluid properties
and the fluid velocity based on the angular velocity of the system,
πΜ = πβ β π’β β π΄ π‘π’ππ.
Using these relations, the coefficient of convective heat transfer can be obtained using 50 and the
convective thermal resistivity calculated as follows
π π‘,ππππ£,π =
1
2 β β π β π β π·π‘π’ππ β πΏ π‘π’ππ
(53)
The system specifics yield a value of 5.79 K/W.
The conductive thermal resistivity of the regenerator is calculated via the following relation,
approximating the pathway of the fluid to be cylindrical
π π‘,ππππ,π =
ln
π‘ πππππ + π·π‘π’ππ
π·π‘π’ππ
2 β π π β π β πΏ π‘π’ππ
(54)
This resistivity results in a value of 0.10 K/W.
43. 43
The total heat flux across the regenerator shell can be expresses as
π π =
(πβ β ππ π )
(π π‘,ππππ + π π‘,ππππ£)
(55)
yielding a total flux of 3.54 W/m2
across the regenerator.
Based on this analysis, the fluid temperature at the cool end of the regenerator can be calculated
with the following relation
ππ =
βπ π
πΜ β πΆ π,β
+ πβ
(56)
Therefore, the cool temperature across the regenerator is expected to be 528K.
Heat Rejection
The following section discusses the heat flow when the air enters the cool cylinder and is cooled
by the water that the Stirling Solar Charger is suspended in.
Once the effective temperature of the air in the cool cylinder is known, the heat rejected from the
system can be calculated following the reverse method that was applied to the hot cylinder. First, internal
convective heat transfer can be applied to get a convective thermal resistance. Using the geometry in
figure 48, the thermal properties shown in Table X [14] assuming the velocity of the air in the cool cylinder
π’ π is the same as that of the air in the hot cylinder, π’β, the Reynoldβs π π π·,π number can calculated as
such:
π π π·,π = π’ π π·ππ/ππ (57)
π π π·,π = 12,599
Where π·ππ is the inner diameter of the cool cylinder (0.9 in) and ππ is the kinematic viscosity.
Once again, using the Dittus-Boelter equation (for cooling), the Nusselt number of the cool
cylinder air can be calculated [14]
ππ’ π·,π = 0.023π π π·,π
4 5β
Prc
0.3 (58)
ππ’ π·,β = 39.1
Then, the convection heat transfer coefficient β π can be found:
β π = ππ’ π·,π π π/π·ππ (59)
β π = 45.0 π/π2
πΎ
and then the convection resistance π π‘,ππππ£,π can be found:
π π‘,ππππ£,π = 1/(β π ππ·ππ πΏ π) (60)
π π‘,ππππ£,π = 8.12 πΎ/π
Where ππ·ππ πΏ π is the inner surface area of the cool cylinders.
44. 44
Figure 48. Geometry of the cool cylinder assembly: Lc = 1.5 in, Dic = 0.9 in, Doc = 1.125 in, and tc = (Doc-Dic)/2.
TABLE X
THERMAL PROPERTIES OF AIR AT 500K
DENSITY,
π π (π€π /π¦ π
)
DYNAMIC
VISCOSITY,
π π (π β π¬/π¦ π
)
KINEMATIC
VISCOSITY,
π π (π¦ π
/π¬)
PRANDTL
NUMBER,
PrC
THERMAL
CONDUCTIVITY,
π€ π (W/M K)
SPECIFIC
HEAT, π π,π
(J/(KG K))
0.6964 270.1 x 10-7
38.7 x 10-6
0.684 26.3 x 10-3
1040
The conduction resistance of the cold cylinders, which are made of stainless steel (thermal
conductivity, kss = 15.1 W/m K, [14].
π π‘,ππππ,π =
ln (
π· ππ
π·ππ
)
2ππ‘ π π π π
(61)
π π‘,ππππ,π = 0.8231 πΎ/π
Where π· ππ, π·ππ, and π‘ π are the geometric properties of the cold cylinder.
On the outside of the cold cylinder heat is being dissipated via natural convection. The following
relation can be used to obtain the Nusselt number for natural convection of a short, vertical cylinder, [20].
ππ’ π·,π€ =
4
3
[
7πΊπ π·,π€ πππ€
2
5(20 + 21Prw)
]
1 4β
+
4(272 + 315Prw)
35(64 + 63Pr π€)π· ππ
(62)
Where πΊπ π·,π€ is the Grashof number of the cooling water about the cool cylinder. Technically, the
Grashof number should be calculated with the temperature of the outer surface of the cylinder but since
this value is unknown, the effective temperature of the cool cylinders ππ is used instead. The thermal
properties of water listed in Table XI are based on sea water at 17Β°C (290K). For simplicity, these properties
were used despite the calculated water temperature, which is calculated as such with respect to the solar
flux.
π·ππ
π· ππ
πΏ π
π‘ π
Cool
Cylinder
Support
Cool
Cylinder
qout
qout
45. 45
π π€ππ‘ππ = (πΊ ππ‘π/ππ π€)1/4
(63)
For clear day conditions and with water having an emissivity of π π€ = 0.97, [14].
π π€ππ‘ππ = 356.97 πΎ
TABLE XI
THERMAL PROPERTIES OF WATER AT 290K
SPECIFIC VOLUME,
π― π° (π¦ π
/π€π )
DYNAMIC
VISCOSITY,
π π° (π β π¬/π¦ π
)
KINEMATIC
VISCOSITY,
π π° (π¦ π
/π¬)
COEFFICIENT
OF
THERMAL
EXPANSION,
π· π
PRANDTL
NUMBER,
PRW
THERMAL
CONDUCTIVITY,
π€ π° (W/M K)
1.001 x 10-3
1.080 x 10-3
1.0811 x 10-6
1.740 x 10-4
7.56 0.598
Now, with this temperature, thermal properties of water, and acceleration due to gravity g as
9.81 m2
/s, the Grashof number πΊπ π·,π€ can be calculated as follows:
πΊπ π·,π€ = ππ½ π€(ππ β π π€)/π π€ (64)
πΊπ π·,π€ = 5.868 Γ 106
Now, the Nusselt number of the water can be calculated using (62):
ππ’ π·,π€ = 53.8
Then, the heat transfer coefficient of the natural convection can be formulated:
β π·,π€ = ππ’ π€ π π€/π· ππ (65)
β π·,π€ = 1.1265 Γ 103
π/π2
πΎ
From here, the convection thermal resistance of naturally cooling water π π‘,ππππ£,π€ can be
calculated with:
π π‘,ππππ£,π€ = 1/(β π€ ππ· ππ πΏ π) (66)
π π‘,ππππ£,π€ = 0.2595 πΎ/π
Now, that all three thermal resistances of the cool side have been found (convection inside the
cool cylinder π π‘,ππππ£,π, conduction through the cool cylinder π π‘,ππππ,π, and natural convection around the
cool cylinder π π‘,ππππ£,π€), the heat rejection of a single cool cylinder π ππ’π‘,π can be calculated:
π ππ’π‘,π = (ππ β π π€ππ‘ππ)/(π π‘,ππππ£,π + π π‘,ππππ,π + π π‘,ππππ£,π€) (67)
π ππ’π‘,π = 18.72 π
The total heat rejection π ππ’π‘ is four times this amount to account for all the cool cylinders:
π πππ = ππ. ππ πΎ
46. 46
5.2.2.6 Work Out
By the first law of thermodynamics with no internal heat generation, the thermodynamic work
output is the difference between net heat intake of the hot side π πππ‘ππ and the heat rejection of the cool
side, π πππ:
πππ’π‘ = π πππ‘ππ β π ππ’π‘ (68)
πππ’π‘ = 111.3 π β 74.87
πΎ πππ = ππ. ππ πΎ
47. 47
5.3 FAILURE
5.3.1 Theoretical Analysis
The drive shaft is considered a critical component of this design due to inherent loading conditions
of the system. For this reason, the following failure analysis is performed on the drive shaft. It is
determined through visual observation that the drive shaft will have critical points in the trough and in
connection to the swashplate. In order to ensure high factors of safety and a long operating life, the drive
shaft is analyzed using DE Goodman methodology. It is important to note that the swashplate-shaft
system is modeled as a gear and shaft structure in order to easily evaluate the system. The shaft is
analyzed in SolidWorks FEA and compared with the predicted theoretical model. All tables referenced in
this section can be found in Section 11 Appendix.
5.3.1.1 Shaft Design
Figure 49. Modeled drive shaft.
From Table 7-1 Initial and initial guesses
πΎπ‘ = 1.7, πΎπ‘π = 1.5, πΎπ = πΎπ‘, πΎππ = πΎπ‘π
Using 1020 cold drawn steel as initial material
π π’π‘ = 68 πππ π
Using Table 6-2
πΎπ = ππ π’π‘
π
= 2.70(68)β0.265
= 0.883
Guess
πΎπ = 0.9, π π = π π = π π
π π
β²
= 0.5π π’π‘
50. 50
π ππ = 1 + 0.5(3.0 β 1) = 2
Finding the alternating Von Mises stress π π
β²
:
π π
β²
=
32π π π π
ππ3
=
32(1.513)(0.4425)
π(0.4375)3
= 81.43 πππ/ππ3
Finding the midrange Von Mises stress π π
β²
:
π π
β²
= β3
16π ππ π π
ππ3
= β3
16(2)(0.4425)
π(0.4375)3
= 5779.5 πππ/ππ3
1
π π
=
π π
β²
π π
+
π π
β²
π π’π‘
=
81.43
27000
+
93.27
68000
π π = 227.91
5.3.1.3 Key
For 0.4375 in shaft
πΉ =
π
π
=
0.4425
0.4375/2
= 2.02286πππ
Distortion energy
ππ π¦ = 0.577(54) = 31.2 πππ π
Using UNS G10180 cold-drawn low-carbon mild steel as initial material
ππ π¦
π
=
πΉ
π‘π
=
31200
1.5
=
2.022
0.125π
π = .00184 (this is the minimum length of the key)
5.3.1.4 Snap Ring
For 0.4375 in snap ring,
Groove width = 0.029 in
Depth = 0.025 in
Diameter = 0.412
π
π‘
= 0.20
51. 51
π
π‘
=
0.029
0.025
= 1.16, π = (0.2)(0.025) = 0.005ππ
From Figure A-15-16
π π‘ = 4.4
From Figure 6-20
π = 0.45
π π = 1 + π(π π‘ β 1)
ππ = 1 + 0.45(4.4 β 1) = 2.53
The fatigue factor of safety is then:
π π =
π π
π π
β² =
27000
32π π π π
ππ3
=
27000
32(2.53)(0.4425)
π(0.4375)3
= 198.27
From the analysis above, it can be seen that the modeled shaft diameters are sufficient. The shaft
diameters of the design are much larger, and are therfore acceptable with respect to failure. Moreover,
the keyway, key, and snap ring have large factors of safety, which shows that the chosen hardware is more
than sufficient. Commercially availble couplers limit the shaft design parameters, which provides
additonal opportunities for optimization
52. 52
5.3.2 SolidWorks Finite Element Analysis
Figure 50. Drive shaft modeled in SolidWorks with an applied torque.
The FEA model assumes that the bottom of the shaft is fixed in all three planes and that the torque
acts along the plane of the swashplate as shown above. These conditions lead to the stress results shown
below. Unfortunately this critical analysis is not exact.
Figure 51. The drive shaft is fixed on the bottom, which does not completely reflect the physical model of the shaft; however, it is
able to reflect two critical points on the drive shaft.
53. 53
While there will be critical points on the bottom of the shaft due to forces and friction with the
ball and socket joint, the forces on the small area of the lower shaft shown above are due to the
assumptions of the model and will not be as critical during normal operation. Another critical stress point
is in the groove for the pistons to move through as the shaft rotates.
Figure 52. Critical point in the trough of the swashplate.
The stress point in the grove makes sense as that is the thinnest section of the part and has an
inherent stress concentration due to the shape of the groves. In addition to this concentration, the real
world shaft would also have stress points at the connection between the main shaft and the swashplate
as this also would create a stress concentration at the sharp corner. The stress levels seen in this analysis
are significantly lower than yield stress (by orders of magnitude) therefore the shaft will be considered to
have an infinite fatigue life.
54. 54
6 DESIGN FOR MANUAL ASSEMBLY
6.1 STEPS TO ASSEMBLE
The steps required to assemble this product are outlined below in Table XX. The Boothroyd and
Dewhurst method of assembly was used to accomplish this analyzation, and the overall assembly time is
924 seconds.
TABLE XII
MANUAL ASSEMBLY PROCESS
Step
Number
Step Name Repetitions
Total
Time (s)
Picture
1
Handle hot
cylinder
support
1 1.8
2
Handle and
insert hot
cylinders
1 2.63
3
Weld hot
cylinder
support
1 132
69. 69
53
Application of
epoxy
1 14.9
54
Handle and
insert sub
assembly B/C
1 4
55
Handle and
insert water
seal
1 16.59
Total: 924
Further details on the manual assembly can be found in Section 11 Appendix.
70. 70
6.2 WORK STATION LAYOUT
The workstation for manual assembly of each Solar Stirling Charger is based on figure 52 below.
Each part will have its own 15 in. by 20 in. bin laid out in a straight line on an 84 in. by 134 in. table. The
bins will have three rows stacked on top of each other for a total of 33 bins for each unique part. This
comes to a total of 200 sq. ft. /work station. This workstation layout will be used as an estimate in the cost
analysis for floor space, as well as floor space for the welding station.
Figure 53. Workstation layout.
Component Bins
Table Fixture
Epoxy and Lubrication Bin
71. 71
7 TOLERANCING AND CLOSURE
Five locations on the design were selected for closure analysis. This will ensure all of the components
have the correct clearance when being assembled together. A table of machining tolerances can be found
in Section 11 Appendix.
7.1 SHAFT AND COUPLER
An analysis is conducted to determine the radius of the shaft knowing that a loose fit is necessary.
An analysis is also conducted to determine the max gap tolerance between the coupler and the shaft.
Figure 54. Coupler and shaft clearance.
πΆππ’ππππ β πβπππ‘ β πΊππ = 0
Shaft:
π₯π = πβ²
(1 Β± ππ )
ππ = 0.06 (Silica Investment Casting)
π πππ = 0.94πβ²
π πππ₯ = 1.06πβ²
Coupler:
(Fine Machining) 0.001 =
π₯πΆ
0.4375/2
π₯πΆ = 0.00021875
72. 72
π πππ = (πΆ) πΏππΆ β (π) πππΆ
π πππ = (0.21875 β 0.00021875) β (1.06πβ²) = 0
πβ²
= 0.20616
π πππ₯ = (πΆ) πππΆ β (π) πΏππΆ
π πππ₯ = (0.21875 + 0.00021875) β (0.94(0.20616))
π πππ₯ = 0.025178
7.2 STARTER AND SLOT
An analysis is conducted to determine the width of the starter knowing that a loose fit is necessary.
An analysis is also conducted to determine the max gap tolerance between the slot and the starter.
Figure 55. Starter and support clearance.
ππππ‘ β ππ‘πππ‘ππ β πππ = 0
Starter :
π₯ππ‘ = ππ‘β²
(1 Β± ππ π‘)
ππ π = 0.002 (Machining)
ππ‘ πππ = 0.998ππ‘β²
ππ‘ πππ₯ = 1.002ππ‘β²
Slot:
(Water Glass Investment Casting) 0.09 =
π₯ππ
0.33
π₯ππ = 0.0297
2π πππ = (ππ) πΏππΆ β (ππ‘) πππΆ
73. 73
2π πππ = (0.33 β 0.0297) β (1.002ππ‘β²) = 0
ππ‘β²
= 0.2997
2π πππ₯ = (ππ) πππΆ β (ππ‘) πΏππΆ
2π πππ₯ = (0.33 + 0.0297) β (0.998(0.2997))
2π πππ₯ = 0.0302997
7.3 KEY AND GEAR
An analysis is conducted to find the min and max gap tolerance between the gear and the key on
the shaft. This analysis concludes that both loose and press fits are functional fits for the gear and key.
Figure 56. Key and gear clearance.
πΊπππ β πΎππ¦ β πππ = 0
Key:
(Silica Investment Casting) 0.06 =
π₯πΎ
0.125
π₯πΎ = 0.0075
πΎβ²
+ π₯πΎ = 0.125 Β± 0.0075
Gear:
(Machining) 0.005 =
π₯πΊ
0.13
π₯πΊ = 0.00075
πΊβ²
+ π₯πΊ = 0.13 Β± 0.00065
2π πππ₯ = (πΊ) πππΆ β (πΎ) πΏππΆ
74. 74
2π πππ₯ = (0.13 + 0.00065) β (0.125 β 0.0075)
π πππ₯ = 0.006575
2π πππ = (πΊ) πΏππΆ β (ππΎ) πππΆ
2π πππ = (0.13 β 0.00065) β (0.125 + 0.0075)
π πππ = β0.00315 (Press Fit)
7.4 HOT CYLINDER AND HOT SUPPORT
An analysis is conducted to determine the radius of a hot cylinder knowing that a loose fit is
necessary. An analysis is also conducted to determine the max gap tolerance between the hot support
and the hot cylinder.
Figure 57. Cylinder and support clearance.
ππ’πππππ‘ β πΆπ¦ππππππ β πΊππ = 0
Cylinder:
π₯πΆ = πΆβ²
(1 Β± π πΆ)
π πΆ = 0.06 (Silica Investment Casting)
πΆ πππ = 0.94πΆβ²
πΆ πππ₯ = 1.06πΆβ²
Support:
(Water Glass Investment Casting) 0.09 =
π₯πΆ
0.56
π₯πΆ = 0.0504
π πππ = (π) πΏππΆ β (πΆ) πππΆ
π πππ = (0.56 β 0.0504) β (1.06πΆβ²) = 0
75. 75
πΆβ²
= 0.48075
π πππ₯ = (π) πππΆ β (πΆ) πΏππΆ
π πππ₯ = (0.56 + 0.0504) β (0.94(0.48075))
π πππ₯ = 0.1585
7.5 PARABOLOID AND ENGINE
An analysis is conducted to determine the radius of the lower Paraboloid opening knowing that a
particular amount of space must be between the Paraboloid and the engine in order to apply sealant. An
analysis is also conducted to determine the max gap tolerance between the Paraboloid and the engine.
Figure 58. Clearance between Paraboloid and engine.
ππππππππππ β πΈπππππ β πΊππ = 0
Paraboloid:
π₯π = πβ²
(1 Β± π π)
π π = 0.008 (Injection Molding)
π πππ = 0.992πβ²
ππππ₯ = 1.008πβ²
Engine:
(Silica Investment Casting) 0.06 =
π₯πΈ
2.5
π₯πΈ = 0.15
π πππ = (π) πΏππΆ β (πΈ) πππΆ
77. 77
8 COST ANALYSIS
The landed cost is totaled to be $832.22 and can be used along with the direct labor, indirect labor,
burden labor, and facility expenses to approximate the total cost per engine if 8,000 engines are
manufactured per month. In order to ensure an even number of workstation production, the actual
number of engines produced per month is 8,104. For this analysis, one shift that consists of 160 hours per
month per workstation will be used.
Based on the production layout discussed previously, the facility expenses are approximated. The
calculated assembly time of fifteen minutes per engine is used to approximate the number of work
stations necessary. The electricity cost is estimated based on the average commercial rate in Florida [7].
The cost per square foot is found to be $7.50 per sq. ft. per year [8] and the millage rate is found to be
approximately $24.55/1k$/year [9]. The price for umbrella insurance is estimated to be $3,000. The
product liability rate is determined based on the average for a new business [10]. All other values are
decided based on experience.
TABLE XIII
FACILITY EXPENSES
ITEM VALUE UNITS
Sq. ft. per workstation 200 (ft2
/WS)
Number of workstations 13 (WS)
Sq. ft. for workstation 2600 (ft2
)
Indirect sq. ft. factor 100 (%)
Total sq. ft. (raw) 5200 (ft2
)
Total sq. ft. 5700 (ft2
)
Sq. ft. cost 7.50 ($/ft2
/year)
Electricity cost 0.08 ($/kwh)
Power per workstation 300 (W/WS)
Brazing power 10 (kW)
AC power 35 (kW)
Cost for lights 100.21 ($/month)
Cost for AC/heat 449.68 ($/month)
Brazing power 256.96 ($/month)
Value of property 200000.00 ($)
Millage rate 24.55 ($/1k$/year)
Umbrella insurance rate 3000.00 ($/year)
Product liability rate 17 (%/year)
Estimated annual sales 0.19 ($M/year)
Rent 3562.50 ($/month)
Electricity 806.85 ($/month)
Phone/internet 500.00 ($/month)
Water 300.00 ($/month)
Waste 500.00 ($/month)
License 100.00 ($/month)
Property text 409.17 ($/month)
Security 200.00 ($/month)
Insurance 2970.00 ($/month)
Supplies 1000.00 ($/month)
Total 10348.52 ($/month)
78. 78
Next, the direct labor cost can be evaluated. This is the total cost associated with the employees at
the workstations. The gross hourly rate is determined based on typical assembler pay. This is then
multiplied by the total hours each direct laborer completes in one month. The taxes are found by
multiplying the tax rate by the gross wages. The sum of the gross wages and taxes is equal to the total
direct labor cost. This is equal to $0.40/min per workstation.
TABLE XIV
DIRECT LABOR
Item Value Units
Gross hourly rate 18.00 ($/hr)
Gross wages 37440.00 ($/month)
Taxes 7488.00 ($/month)
Fringe 5000.00 ($/month)
FICA/MC/UI/WC rate 20.00 (%)
Total 49928.00 ($/month)
Indirect labor costs will be analyzed next. This cost accounts for the employees that do not have
direct contact with the product. The number of workers is found by assuming there are three runners,
one maintenance person, and one shift manager.
TABLE XV
INDIRECT LABOR
Item Value Units
Number of workers 5 People
Wage scale 1.25
Total 24003.85 ($/month)
The burden labor is found by determining the salary for one engineer, one marketer, and one
manager.
TABLE XVI
BURDEN LABOR
Item Value Units
Engineer 75000 ($/year)
Marketing 80000 ($/year)
Manager 90000 ($/year)
Total 20416.67 ($/month)
The use rate is then found to be $0.44/min/WS using the equation below where UR is the use rate,
IDL is the indirect labor, BL is the burden labor, and FE is the facility expenses.
ππ
$/πππ
ππ
= (
πΌπ·πΏ($ ππβ ) + π΅πΏ($ ππβ ) + πΉπΈ($ ππβ )
#ππ
) (
1 ππ
168 βπ
) (
1 βπ
60 πππ
)
(70)
79. 79
The cost to assemble one engine is found using the equation below and yields $12.92.
πΆππ π‘ π‘π ππ π πππππ
$
πππππ
= ππππ π‘π ππ π πππππ
πππ
πππππ
β (ππ
$
πππ
+ π·πΏ
$
πππ
)
(71)
The total cost per engine is found by adding the cost to assemble to the landed cost per engine. This
totals to $845.14 per engine.
The overhead is found to be 110% by dividing the use rate by the direct labor and multiplying by
100%. The fully burdened labor rate is then found to be $50.34/hour by summing the direct labor and
the use rate. The total monthly budget is summarized below.
TABLE XVII
MONTHLY BUDGET
Item Value Units
Direct Labor 49928.00 ($/month)
Indirect Labor 24003.85 ($/month)
Burdened Labor 20416.67 ($/month)
Facilities Expenses 10348.52 ($/month)
Landed Cost 6744250.50 ($/month)
Total 6848947.54 ($/month)
The minimum sales per year in order to break even is approximately $82.19 million. This means
that each engine would need to be sold for $845.14.
80. 80
9 INTELLECTUAL PROPERTY
The invention claimed is a multiple-cylinder single-acting engine which utilizes a Stirling cycle wherein
the hot and cold cylinders act on opposing sides of a swashplate in order to rotate the swashplate as
shown in figure 59. This design allows the hot and cold cylinders to be separated in an effort to increase
the temperature difference between the cylinders while still generating a large force on the swashplate.
In addition, this engine is solar-powered wherein the devices employs a self-reflecting Paraboloid surface
as shown in figure 60. This feature allows the system to be one assembly in order to decrease the size and
increase the portability.
Figure 59. Double-sided swashplate.
Figure 60. Self-reflective Paraboloid Stirling engine.
81. 81
10 EVALUATION
Based on the analysis, the product meets the specifications determined in the preliminary phase of
the design process, i.e., a portable 5 W Stirling engine powered USB charger. These specifications can be
seen in Section 3 Performance Specifications.
From the solar input (about 225 W based on the calculation above in Section 5), the solar to thermal
efficiency is 16.2%. The thermal to mechanical efficiency is 44.6%, which results in 16.27 W of power from
the engine. The mechanical to electrical efficiency is 50%, creating a final electrical output of 8.11 W.
Based on these efficiencies, the design has a 3.6% overall efficiency. This exceeds the 5 W specification
for the device. It is thought that the excess power can be used to charge additional devices, remain as a
safety buffer (for charging in low light/cloudy conditions), or allow the design to be reduced/optimized in
further prototypes.
The final weight of the assembly is approximately 45 lbs., and it measures 25 in. in diameter. This
puts the device within the parameters of man portable according to MIL-STD 1472D [4] and can be carried
with two hands. This weight is considered to be fatiguing for a single person to carry, but the user would
only have to physically carry it a short while, as the device is buoyant. Nevertheless, weight reduction is a
point for future optimization.
The stress analysis of the system shows that the factor of safety is higher than 4 on the critical
components, which will provide a long fatigue life and leaves room for optimization. Fatigue life due to
heating, solar radiation damage, salt water corrosion, and impact strength have not been considered and
should be added in further evaluations.
When producing 8 000 units, final cost of the device comes to $845.14 with an overhead of 110%.
The sale of this product is primarily for high volume orders (e.g. FEMA or cruise lines) so this is not an
unreasonable price range. The ideas used in this design are open to the possibility of patents which secure
sales of this device from copycat devices on the market.
Overall the device is a viable product and is ready for optimization and testing in further prototyping
stages.
85. 85
11.2 MANUAL ASSEMBLY TIME TABLE
Notes
Step
Number
Step Name
Step
Description
Repetitions
Tool
Access
Alpha Beta Sum
Handling
Code
Handling
Time
Insertion
Code
Insertion
Time
Total
Time
1
Handle hot
cylinder
support
Initial
handling of
hot cylinder
support
1 0 360 180 540 20 1.8 0 1.8
2
Handle and
insert hot
cylinders
Insert hot
cylinders
into hot
cylinder
support
1 0 180 90 270 00 1.13 00 1.5 2.63
3
Weld hot
cylinder
support
Weld hot
cylinders to
hot cylinder
support
1 120 NA NA NA 0 96 12 132
4
Handle and
insert hot
cylinder
seal
Place hot
cylinder seal
into hot
cylinder
support
4 0 180 0 180 01 1.43 31 5 25.72
5
Handle hot
cylinder
assembly
Place hot
cylinder
assembly
aside
1 0 360 180 540 20 1.8 0 1.8
86. 86
6
Handle
generator
support
Initial
handling of
generator
support
1 0 360 90 450 10 1.5 0 1.5
7
Application
of epoxy
Apply epoxy
below dowel
pin of
generator
supports
4 2.9 NA NA NA 0 97 12 50.9
8
Handle and
insert
starter
cover
Insert
starter cover
until
stopped by
generator
support pins
1 0 180 90 270 00 1.13 00 1.5 2.63
9
Handle
generator
support
Place
generator
support
assembly
aside to
cure
1 0 360 180 540 20 1.8 0 1.8
10
Handle dry
bag
Initial
handling of
dry bag
1 0 360 180 540 20 1.8 0 1.8
11
Application
of epoxy
Apply epoxy
on bottom
of dry bag
1 2.9 NA NA NA 0 97 12 14.9
87. 87
12
Handle
floatation
device and
attach dry
bag
Initial
handling of
floatation
device and
insertion of
dry bag
1 0 360 0 360 10 1.5 06 5.5 7
Pre-
Assmbly
Above
13
Handle
floatation
device
assembly
Place
floatation
device
assembly
aside
1 0 360 360 720 30 1.95 0 1.95
14
Handle cold
piston
Initial
handling of
cold pistons
4 0 360 0 360 10 1.5 0 6
15
Handle and
insert of O
Rings
Initial
handling of O
ring and
place O rings
in groove of
cold pistons
8 0 180 0 180 03 1.69 31 5 53.52
16
Handle cold
piston
assembly
Place cold
pistons aside
4 0 360 0 360 10 1.5 0 6
17
Handle cold
cylinder
support
Initial
handling of
cold cylinder
support
1 0 360 180 540 20 1.8 0 1.8
88. 88
18
Handle and
insert cold
seals
Place cold
selas into
cold cylinder
support
4 0 180 0 180 01 1.43 31 5 25.72
19
Insert cold
piston
assembly
Handle and
insert cold
piston
assembly into
cold cylinder
4 0 360 0 360 10 1.5 31 5 26
Using
tooling
support
to raise
and hold
assembly
20
Handle cold
cylinder
assembly
Place cold
cylinder
assebly on
tooling
fixture
1 0 360 180 540 20 1.8 0 1.8
Piston
joints are
press fit
21
Handle and
insert
swashplate
Place
swashplate
on ball joint
of cylinder
support
1 0 360 0 360 10 1.5 31 5 6.5
Dowl
pins help
to align
the
regenera
tor
22
Handle and
insert
regenerator
Place
regenerator
on cold
cylinder
support and
align
1 0 360 180 540 20 1.8 00 1.5 3.3
89. 89
Screw
gun does
not
interfere
due to
fixture
23
Handle and
insert
screws
Secure
regenerator
to cold
cylinder
4 2.9 360 0 360 10 1.5 38 6 32.9
Dowl
pins help
to align
the
regenera
tor
24
Handle and
insert hot
cylinder
support
Place hot
cylinder
support on
top of
regerator and
align
1 0 360 180 540 20 1.8 00 1.5 3.3
25
Handle and
insert
screws
Secure
regenerator
to hot
cylinder
4 2.9 360 0 360 10 1.5 38 6 32.9
26
Handle hot
piston
Initial
handling of
hot pistons
4 0 360 0 360 10 1.5 0 6
27
Handle and
insert of O
rings
Initial
handling of O
ring and
place O rings
in groove of
hot pistons
8 0 180 0 180 03 1.69 31 5 53.52
28
Handle hot
piston
assembly
Place hot
pistons aside
4 0 360 0 360 10 1.5 0 6
90. 90
29
Insert hot
piston
assembly
Insert hot
piston
assembly into
hot cylinder
4 0 360 0 360 10 1.5 31 5 26
30
Handle and
insert insert
snap ring
Insert snap
ring onto
shaft
1 0 180 0 180 03 1.69 31 5 6.69
31
Handle and
insert key
Insert key
into keyway
of shaft
1 0 180 90 270 00 1.13 00 1.5 2.63
32
Handle and
insert gear
Insert gear
onto keyway
of shaft on
top of snap
ring
1 0 180 360 540 20 1.8 02 2.5 4.3
Tightenin
g of set
screw
33
Handle and
insert
bottom
coupler
Insert and
secure
bottom
coupler
1 2.9 360 0 360 10 1.5 38 6 10.4
34
Handle sub
assembly B
Set aside sub
assembly A
1 0 360 90 450 10 1.5 0 1.5
35
Handle DC
motor
Initial
handling of
DC motor
1 0 360 180 540 20 1.8 0 1.8
91. 91
36
Handle and
solder buck
converter
Handling of
buck
converter
and sodering
wires of DC
motor to
buck
converter
1 32.9 360 360 720 30 1.95 95 8 42.85
37
Handle and
solder USB
converter
Handling of
USB
converter
and sodering
wires of USB
to buck
converter
1 2.9 360 360 720 30 1.95 95 8 12.85
38
Handle
generator
support
assembly
Initial
handling of
generator
support
assembly
1 0 360 90 450 10 1.5 0 1.5
92. 92
39
Handle and
insert
electronics
assembly on
generator
support
assembly
Insert motor
into hole of
generator
support and
place
electronics
next to motor
1 0 360 360 720 30 1.95 00 1.5 3.45
M3x10m
m screws
40
Handle and
insert
screws
Insert and
secure
bottom of
motor with
screws
4 2.9 360 0 360 11 1.8 38 6 34.1
Using
Press Fit
41
Handle and
insert USB
cover
Insert and
secure USB
cover onto
generator
assembly
1 0 360 360 720 30 1.95 02 2.5 4.45
42
Handle and
insert top
coupler
Insert coupler
onto top
shaft and
tighten set
screw
1 2.9 360 0 360 10 1.5 38 6 10.4
43
Handle sub
assembly C
Set aside sub
assembly B
1 0 360 360 720 30 1.95 0 1.95
93. 93
44
Handle
paraboloid
Initial
handling of
paraboloid
1 0 360 120 480 10 1.5 0 1.5
45
Handle and
insert clip
strap
Handling of
strap and
insertion into
clip of
paraboloid
3 0 180 180 360 10 1.5 02 2.5 12
Make
sure
floating
device is
dry bag
up
46
Handle and
insert
floatation
device
assembly
Handling of
floatation
device and
insertion of
paraboloid
into
floatation
device
1 0 360 360 720 30 1.95 00 1.5 3.45
47
Place and
tighten
straps
around
floatation
device
Handling of
straps around
floatation
device and
tightening
3 0 360 120 480 10 1.5 32 4 16.5
48
Handle sub
assembly A
Set aside sub
assembly C
1 0 360 360 720 91 3 0 3
49
Handle sub
assembly B
Initial
handling of
sub assembly
A
1 0 360 90 450 10 1.5 0 1.5
94. 94
50
Handle and
insert sub
assembly C
Place sub
assembly C
into the
grooves of
sub assembly
B
1 0 360 90 450 10 1.5 00 1.5 3
51
Weld legs of
sub
assembly C
Weld legs of
sub assembly
C onto the
hot cylinder
support of
sub assembly
B
4 120 NA NA NA 0 96 12 168
52
Handle sub
assembly A
Initial
handling of
sub assembly
A
1 0 360 360 720 91 3 0 3
53
Application
of epoxy
Epoxy inside
of paraboloid
of assembly A
1 2.9 NA NA NA 0 97 12 14.9
95. 95
54
Handle and
Insert sub
assembly
B/C
Handling of
sub assembly
B/C and
insertion into
sub assembly
A
1 0 360 360 720 95 4 0 4
55
Handle and
insert water
seal
place water
seal on top of
paraboloid
1 2.9 180 0 180 03 1.69 97 12 16.59
Total Time (s) 924
97. 97
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