Correlation of animal and plant respiratory surface area

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Correlation of animal and plant respiratory surface area

  1. 1. Correlation of Animal andPlant Respiratory SurfaceArea With Metabolic Rate Giovanni Biruetta, Vera Bunaidi, Steve Luong, and Carolina Guia
  2. 2. Mix and Match
  3. 3. Introduction
  4. 4. What is our hypothesis? Surface area is equal to ¾ metabolic optimum Surface area at least ¾ metabolic optimum Surface area is less than ¾ metabolic optimum
  5. 5. Methods
  6. 6.  The weights of plants in different phylum were measured in grams and the surface area in centimeters squared. Plant weight was obtained using an electronic scale. Additionally, surface area was calculated based on dimension on leafs and the amount of leafs per steam. Therefore, area in centimeters squared was taken from one leaf and was multiplied by the amount of leaves on one plant for angiosperms. The same was done for the patch of the Bryophyte and Pteridophyte. Area of a cylinder was used for the gymnosperm and was multiplied by how many pine needles were in one bush. Surface area was also measured for the following animals: rat, pigeon, frog, and turtle. Lungs were frozen and the sample was taken with an incision on the transverse plane of half of the lung. The sample was then placed on a slide with a cover slip and was observed under the light microscope at 10x magnification. The amount of circular cavities was counted in each sample and the areas were recorded using the formula of the area of a sphere. The field of view was calculated for the slide sample viewed and this was then factored in with the estimated number of incisions that would constitute half the lung. Finally, to get the surface area of the whole respiratory organ, we multiplied the surface area of a lung by two. To get the rate in which surface area and mass scale we plotted the surface area of the plant and animals and used a power trend line to get the general formula of y=cxb.
  7. 7. Results Animal Mass Versus Lung Surface Area 700 y = 0.6204x1.0233 R² = 0.7931 600 Turtle #2 Pigeon 500Surface Area (cm^2) 400 Turtle #1 Animals 300 Power (Animals) 200 Rat #1 Rat #2 100 Frog #1 Frog #2 0 0 100 200 300 400 500 600 700 Mass (g)
  8. 8. Plant Mass Versus Leaf Surface Area 10000 9000 y = 13.368x1.1788 R² = 0.97178 8000 7000Surface Area (cm^2) 6000 5000 Plants 4000 Power (Plants) 3000 2000 1000 0 0 50 100 150 200 250 300 Mass (g)
  9. 9. Correct!!!!
  10. 10. Wrong
  11. 11. Wrong
  12. 12. Bird
  13. 13.  Rat
  14. 14.  Turtle
  15. 15. Frog

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