SlideShare a Scribd company logo
1 of 57
chemical   equilibrium!
The double arrow tells us that this reaction can go in both directions : N 2  + 3H 2   2NH 3
1) Reactants react to become products, N 2  + 3H 2   2NH 3 (‘ forward ’ reaction) N 2  + 3H 2   2NH 3
1) Reactants react to become products, while simultaneously, N 2  + 3H 2   2NH 3 (‘ forward ’ reaction) 2) Products react to become reactants N 2  + 3H 2   2NH 3 (‘ reverse ’ reaction) N 2  + 3H 2   2NH 3
In a  closed  system,  where no reactants, products, or energy can be added to or removed from the reaction, a reversible reaction will reach  equilibrium . N 2  + 3H 2   2NH 3
At equilibrium, the rate   of the forward reaction becomes  equal  to the rate of the reverse reaction, and so, like our escalator metaphor, the two sides, reactants and products,  will have constant amounts,  even though the reactions continue to occur. N 2  + 3H 2   2NH 3
However (like the metaphor), the equilibrium  amounts  of  reactants and products are usually not equal, they just remain unchanged. N 2  + 3H 2   2NH 3
N 2  + 3H 2   2NH 3
N 2  + 3H 2   2NH 3
N 2  + 3H 2   2NH 3
N 2  + 3H 2   2NH 3
 
 
 
 
 
reverse forward
reverse forward
reverse forward
reverse forward
reverse forward
 
 
reverse forward
reverse forward
reverse forward
reverse forward
reverse forward
 
etc! the reactions go on continuously in both directions. reverse forward
Changes in the concentrations of the reactants and products can be graphed; the graph indicates when equilibrium has been reached.  concentration time
For  N 2  + 3H 2   2NH 3 ,  suppose you begin with the following:  N 2  = 1 M,  H 2  = 1 M,  and  NH 3  = 0 M  concentration time
For  N 2  + 3H 2   2NH 3 ,  suppose you begin with the following:  N 2  = 1 M,  H 2  = 1 M,  and  NH 3  = 0 M  concentration time
For  N 2  + 3H 2   2NH 3 ,  suppose you begin with the following:  N 2  = 1 M,  H 2  = 1 M,  and  NH 3  = 0 M  concentration time
For  N 2  + 3H 2   2NH 3 ,  suppose you begin with the following:  N 2  = 1 M,  H 2  = 1 M,  and  NH 3  = 0 M  concentration time
For  N 2  + 3H 2   2NH 3 ,  suppose you begin with the following:  N 2  = 1 M,  H 2  = 1 M,  and  NH 3  = 0 M  concentration time
For  N 2  + 3H 2   2NH 3 ,  suppose you begin with the following:  N 2  = 1 M,  H 2  = 1 M,  and  NH 3  = 0 M  concentration time
For  N 2  + 3H 2   2NH 3 ,  suppose you begin with the following:  N 2  = 1 M,  H 2  = 1 M,  and  NH 3  = 0 M  concentration time
For  N 2  + 3H 2   2NH 3 ,  suppose you begin with the following:  N 2  = 1 M,  H 2  = 1 M,  and  NH 3  = 0 M  concentration time
For  N 2  + 3H 2   2NH 3 ,  suppose you begin with the following:  N 2  = 1 M,  H 2  = 1 M,  and  NH 3  = 0 M  concentration time
For  N 2  + 3H 2   2NH 3 ,  suppose you begin with the following:  N 2  = 1 M,  H 2  = 1 M,  and  NH 3  = 0 M  concentration time
For  N 2  + 3H 2   2NH 3 ,  suppose you begin with the following:  N 2  = 1 M,  H 2  = 1 M,  and  NH 3  = 0 M  concentration time
For  N 2  + 3H 2   2NH 3 ,  suppose you begin with the following:  N 2  = 1 M,  H 2  = 1 M,  and  NH 3  = 0 M  concentration time
For  N 2  + 3H 2   2NH 3 ,  suppose you begin with the following:  N 2  = 1 M,  H 2  = 1 M,  and  NH 3  = 0 M  concentration time
For  N 2  + 3H 2   2NH 3 ,  suppose you begin with the following:  N 2  = 1 M,  H 2  = 1 M,  and  NH 3  = 0 M  concentration time
For  N 2  + 3H 2   2NH 3 ,  suppose you begin with the following:  N 2  = 1 M,  H 2  = 1 M,  and  NH 3  = 0 M  concentration time
For  N 2  + 3H 2   2NH 3 ,  suppose you begin with the following:  N 2  = 1 M,  H 2  = 1 M,  and  NH 3  = 0 M  concentration time
For  N 2  + 3H 2   2NH 3 ,  suppose you begin with the following:  N 2  = 1 M,  H 2  = 1 M,  and  NH 3  = 0 M  concentration time
For  N 2  + 3H 2   2NH 3 ,  suppose you begin with the following:  N 2  = 1 M,  H 2  = 1 M,  and  NH 3  = 0 M  concentration time [ N 2 ] [ H 2 ] [ NH 3 ]
For  N 2  + 3H 2   2NH 3 ,  suppose you begin with the following:  N 2  = 1 M,  H 2  = 1 M,  and  NH 3  = 0 M  concentration time Question 3: at what point has equilibrium been established? [ N 2 ] [ H 2 ] [ NH 3 ]
For  N 2  + 3H 2   2NH 3 ,  suppose you begin with the following:  N 2  = 1 M,  H 2  = 1 M,  and  NH 3  = 0 M  concentration time Question 4: what does the graph tell you about the concentration of each species once equilibrium is established? [ N 2 ] [ H 2 ] [ NH 3 ]
For  N 2  + 3H 2   2NH 3 ,  suppose you begin with the following:  N 2  = 1 M,  H 2  = 1 M,  and  NH 3  = 0 M  concentration time Question 5: what might a  rate  vs time graph look like for the above reaction? [ N 2 ] [ H 2 ] [ NH 3 ]
rate time Question 5: what might a  rate  vs time graph look like for the above reaction? For  and still beginning with N 2  = 1 M,  H 2  = 1 M,  and  NH 3  = 0 M  N 2  + 3H 2   2NH 3
For  and still beginning with rate time N 2  = 1 M,  H 2  = 1 M,  and  NH 3  = 0 M  N 2  + 3H 2   2NH 3
For  and still beginning with rate time N 2  + 3H 2  2NH 3 N 2  = 1 M,  H 2  = 1 M,  and  NH 3  = 0 M  Question 6: at what point has equilibrium been established? forward reverse
rate time Question 7: describe how the two graphs are related. concentration time N 2 H 2 NH 3 forward reverse
Question 8: do either of the two graphs indicate if K eq  >1 or K eq  <1? concentration time N 2 H 2 NH 3 forward reverse rate time

More Related Content

More from Navin Joshi

Treasure hunt sequences1296542856
Treasure hunt sequences1296542856Treasure hunt sequences1296542856
Treasure hunt sequences1296542856
Navin Joshi
 
Transition elements opt ok1294998077
Transition elements opt  ok1294998077Transition elements opt  ok1294998077
Transition elements opt ok1294998077
Navin Joshi
 
Thermochemistry ok1294993378
Thermochemistry   ok1294993378Thermochemistry   ok1294993378
Thermochemistry ok1294993378
Navin Joshi
 
Stoichiometry ok1294993172
Stoichiometry   ok1294993172Stoichiometry   ok1294993172
Stoichiometry ok1294993172
Navin Joshi
 
Squares and square roots ok1296542788
Squares and square roots  ok1296542788Squares and square roots  ok1296542788
Squares and square roots ok1296542788
Navin Joshi
 
Solving equations ok1296542729
Solving equations   ok1296542729Solving equations   ok1296542729
Solving equations ok1296542729
Navin Joshi
 
Solving equations
Solving equationsSolving equations
Solving equations
Navin Joshi
 
Slope ok12965426381296619795
Slope   ok12965426381296619795Slope   ok12965426381296619795
Slope ok12965426381296619795
Navin Joshi
 
Simplifying expressions ok1296542578
Simplifying expressions  ok1296542578Simplifying expressions  ok1296542578
Simplifying expressions ok1296542578
Navin Joshi
 
Polymer ok1294992673
Polymer   ok1294992673Polymer   ok1294992673
Polymer ok1294992673
Navin Joshi
 
Physical sepration ok1294992218
Physical sepration   ok1294992218Physical sepration   ok1294992218
Physical sepration ok1294992218
Navin Joshi
 
Periodic table1292657304
Periodic table1292657304Periodic table1292657304
Periodic table1292657304
Navin Joshi
 
Noble gases opt ok1294991905
Noble gases opt  ok1294991905Noble gases opt  ok1294991905
Noble gases opt ok1294991905
Navin Joshi
 
Naming of acid ok1294991670
Naming of acid  ok1294991670Naming of acid  ok1294991670
Naming of acid ok1294991670
Navin Joshi
 
Name of functional group ok1294991492
Name of functional group   ok1294991492Name of functional group   ok1294991492
Name of functional group ok1294991492
Navin Joshi
 
Mole concept ok1294991357
Mole concept  ok1294991357Mole concept  ok1294991357
Mole concept ok1294991357
Navin Joshi
 
Mineral identification ok1294991264
Mineral identification  ok1294991264Mineral identification  ok1294991264
Mineral identification ok1294991264
Navin Joshi
 
Metals and acids ok1294990932
Metals and acids   ok1294990932Metals and acids   ok1294990932
Metals and acids ok1294990932
Navin Joshi
 

More from Navin Joshi (20)

Treasure hunt sequences1296542856
Treasure hunt sequences1296542856Treasure hunt sequences1296542856
Treasure hunt sequences1296542856
 
Transition elements opt ok1294998077
Transition elements opt  ok1294998077Transition elements opt  ok1294998077
Transition elements opt ok1294998077
 
Thermochemistry ok1294993378
Thermochemistry   ok1294993378Thermochemistry   ok1294993378
Thermochemistry ok1294993378
 
Stoichiometry ok1294993172
Stoichiometry   ok1294993172Stoichiometry   ok1294993172
Stoichiometry ok1294993172
 
Squares and square roots ok1296542788
Squares and square roots  ok1296542788Squares and square roots  ok1296542788
Squares and square roots ok1296542788
 
Solving equations ok1296542729
Solving equations   ok1296542729Solving equations   ok1296542729
Solving equations ok1296542729
 
Solving equations
Solving equationsSolving equations
Solving equations
 
Slope ok12965426381296619795
Slope   ok12965426381296619795Slope   ok12965426381296619795
Slope ok12965426381296619795
 
Simplifying expressions ok1296542578
Simplifying expressions  ok1296542578Simplifying expressions  ok1296542578
Simplifying expressions ok1296542578
 
Prime numbers
Prime numbersPrime numbers
Prime numbers
 
Ppt0000000
Ppt0000000Ppt0000000
Ppt0000000
 
Polymer ok1294992673
Polymer   ok1294992673Polymer   ok1294992673
Polymer ok1294992673
 
Physical sepration ok1294992218
Physical sepration   ok1294992218Physical sepration   ok1294992218
Physical sepration ok1294992218
 
Periodic table1292657304
Periodic table1292657304Periodic table1292657304
Periodic table1292657304
 
Noble gases opt ok1294991905
Noble gases opt  ok1294991905Noble gases opt  ok1294991905
Noble gases opt ok1294991905
 
Naming of acid ok1294991670
Naming of acid  ok1294991670Naming of acid  ok1294991670
Naming of acid ok1294991670
 
Name of functional group ok1294991492
Name of functional group   ok1294991492Name of functional group   ok1294991492
Name of functional group ok1294991492
 
Mole concept ok1294991357
Mole concept  ok1294991357Mole concept  ok1294991357
Mole concept ok1294991357
 
Mineral identification ok1294991264
Mineral identification  ok1294991264Mineral identification  ok1294991264
Mineral identification ok1294991264
 
Metals and acids ok1294990932
Metals and acids   ok1294990932Metals and acids   ok1294990932
Metals and acids ok1294990932
 

Equilibrium ok1294987820

  • 1. chemical equilibrium!
  • 2. The double arrow tells us that this reaction can go in both directions : N 2 + 3H 2 2NH 3
  • 3. 1) Reactants react to become products, N 2 + 3H 2 2NH 3 (‘ forward ’ reaction) N 2 + 3H 2 2NH 3
  • 4. 1) Reactants react to become products, while simultaneously, N 2 + 3H 2 2NH 3 (‘ forward ’ reaction) 2) Products react to become reactants N 2 + 3H 2 2NH 3 (‘ reverse ’ reaction) N 2 + 3H 2 2NH 3
  • 5. In a closed system, where no reactants, products, or energy can be added to or removed from the reaction, a reversible reaction will reach equilibrium . N 2 + 3H 2 2NH 3
  • 6. At equilibrium, the rate of the forward reaction becomes equal to the rate of the reverse reaction, and so, like our escalator metaphor, the two sides, reactants and products, will have constant amounts, even though the reactions continue to occur. N 2 + 3H 2 2NH 3
  • 7. However (like the metaphor), the equilibrium amounts of reactants and products are usually not equal, they just remain unchanged. N 2 + 3H 2 2NH 3
  • 8. N 2 + 3H 2 2NH 3
  • 9. N 2 + 3H 2 2NH 3
  • 10. N 2 + 3H 2 2NH 3
  • 11. N 2 + 3H 2 2NH 3
  • 12.  
  • 13.  
  • 14.  
  • 15.  
  • 16.  
  • 22.  
  • 23.  
  • 29.  
  • 30. etc! the reactions go on continuously in both directions. reverse forward
  • 31. Changes in the concentrations of the reactants and products can be graphed; the graph indicates when equilibrium has been reached. concentration time
  • 32. For N 2 + 3H 2 2NH 3 , suppose you begin with the following: N 2 = 1 M, H 2 = 1 M, and NH 3 = 0 M concentration time
  • 33. For N 2 + 3H 2 2NH 3 , suppose you begin with the following: N 2 = 1 M, H 2 = 1 M, and NH 3 = 0 M concentration time
  • 34. For N 2 + 3H 2 2NH 3 , suppose you begin with the following: N 2 = 1 M, H 2 = 1 M, and NH 3 = 0 M concentration time
  • 35. For N 2 + 3H 2 2NH 3 , suppose you begin with the following: N 2 = 1 M, H 2 = 1 M, and NH 3 = 0 M concentration time
  • 36. For N 2 + 3H 2 2NH 3 , suppose you begin with the following: N 2 = 1 M, H 2 = 1 M, and NH 3 = 0 M concentration time
  • 37. For N 2 + 3H 2 2NH 3 , suppose you begin with the following: N 2 = 1 M, H 2 = 1 M, and NH 3 = 0 M concentration time
  • 38. For N 2 + 3H 2 2NH 3 , suppose you begin with the following: N 2 = 1 M, H 2 = 1 M, and NH 3 = 0 M concentration time
  • 39. For N 2 + 3H 2 2NH 3 , suppose you begin with the following: N 2 = 1 M, H 2 = 1 M, and NH 3 = 0 M concentration time
  • 40. For N 2 + 3H 2 2NH 3 , suppose you begin with the following: N 2 = 1 M, H 2 = 1 M, and NH 3 = 0 M concentration time
  • 41. For N 2 + 3H 2 2NH 3 , suppose you begin with the following: N 2 = 1 M, H 2 = 1 M, and NH 3 = 0 M concentration time
  • 42. For N 2 + 3H 2 2NH 3 , suppose you begin with the following: N 2 = 1 M, H 2 = 1 M, and NH 3 = 0 M concentration time
  • 43. For N 2 + 3H 2 2NH 3 , suppose you begin with the following: N 2 = 1 M, H 2 = 1 M, and NH 3 = 0 M concentration time
  • 44. For N 2 + 3H 2 2NH 3 , suppose you begin with the following: N 2 = 1 M, H 2 = 1 M, and NH 3 = 0 M concentration time
  • 45. For N 2 + 3H 2 2NH 3 , suppose you begin with the following: N 2 = 1 M, H 2 = 1 M, and NH 3 = 0 M concentration time
  • 46. For N 2 + 3H 2 2NH 3 , suppose you begin with the following: N 2 = 1 M, H 2 = 1 M, and NH 3 = 0 M concentration time
  • 47. For N 2 + 3H 2 2NH 3 , suppose you begin with the following: N 2 = 1 M, H 2 = 1 M, and NH 3 = 0 M concentration time
  • 48. For N 2 + 3H 2 2NH 3 , suppose you begin with the following: N 2 = 1 M, H 2 = 1 M, and NH 3 = 0 M concentration time
  • 49. For N 2 + 3H 2 2NH 3 , suppose you begin with the following: N 2 = 1 M, H 2 = 1 M, and NH 3 = 0 M concentration time [ N 2 ] [ H 2 ] [ NH 3 ]
  • 50. For N 2 + 3H 2 2NH 3 , suppose you begin with the following: N 2 = 1 M, H 2 = 1 M, and NH 3 = 0 M concentration time Question 3: at what point has equilibrium been established? [ N 2 ] [ H 2 ] [ NH 3 ]
  • 51. For N 2 + 3H 2 2NH 3 , suppose you begin with the following: N 2 = 1 M, H 2 = 1 M, and NH 3 = 0 M concentration time Question 4: what does the graph tell you about the concentration of each species once equilibrium is established? [ N 2 ] [ H 2 ] [ NH 3 ]
  • 52. For N 2 + 3H 2 2NH 3 , suppose you begin with the following: N 2 = 1 M, H 2 = 1 M, and NH 3 = 0 M concentration time Question 5: what might a rate vs time graph look like for the above reaction? [ N 2 ] [ H 2 ] [ NH 3 ]
  • 53. rate time Question 5: what might a rate vs time graph look like for the above reaction? For and still beginning with N 2 = 1 M, H 2 = 1 M, and NH 3 = 0 M N 2 + 3H 2 2NH 3
  • 54. For and still beginning with rate time N 2 = 1 M, H 2 = 1 M, and NH 3 = 0 M N 2 + 3H 2 2NH 3
  • 55. For and still beginning with rate time N 2 + 3H 2 2NH 3 N 2 = 1 M, H 2 = 1 M, and NH 3 = 0 M Question 6: at what point has equilibrium been established? forward reverse
  • 56. rate time Question 7: describe how the two graphs are related. concentration time N 2 H 2 NH 3 forward reverse
  • 57. Question 8: do either of the two graphs indicate if K eq >1 or K eq <1? concentration time N 2 H 2 NH 3 forward reverse rate time