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• Introduction
• Formulae
• Solving sums
• HOT Questions
• P e r i me t e r :
P   e   r i me t e    r  i s t h e
d   i   s t a n c e    a r o u n d a 2D
s   h   a p e . L i   k e i n t h e
f   o   l l o wi n    g s h a p e t h e
d   i   s t a n c e    o f t h e b o r d e r
o   r    t h e s h    a d e d p o r t i o n
i   s    t h e Pe     r i me t e r .
• Ar e a :
A   r   e a i s t h e i n n e r
s   u   r f a c e o f a s h a p e
o   r    t h i n g , i t i s
u   s   u a l l y a 2D s h a p e .
L   i   k e i n t h e
f   o   l l o wi n g s h a p e t h e
s   h   a d e d p o r t i o n i s
                             Area
t   h   e Ar e a o f t h e
s   h   a p e .
• I n t h i s p r e s e n t a t i o n we
  wi l l l e a r n a b o u t t h e
  f o l l o w i n g sPhea rp ie m : t e
                                s e
                        r     i s
1. R e c t a   n g l e
                        a    l wa y s
2.S q u a r    e        e    x p r e s s e
3.P a r a l    l e l o gdr   ai m U n i t
                                 n
4.T r i a n    g l e    a    n d a r e a
5.C i r c l    e        i    n U n i t 2.
We w i l l l e a r n a b o u t          t h e
a r e a a n d p e r i me t e r .
Re c t a                   Re     c   t   a
                                                      n g    l   e
 P e r i me t            en : l e
                            r g                       me     a   n   s
                             m e a n s , L +B +L +B   f o    u   r
                                     5 cm             s i    d   e
                                                      s h    a   p   e
                                                      wh     i   c   h
           2 cm                                       2 cm
                                                      h a    s
                                                      o p    p   o s
                                                      i t    e
Perimeter is 2 x (5+2) = 14 cm       5 cm             s i    d   e s
                                                      e q    u   a l .

Ar e a :
                                            5 cm


Area is 5 x 2              2 cm                                      2 cm
= 10 cm2

                                            5 cm
Sq u a r e                           Sq u a r e
                                                             i s a
• P e r i me t e r :                          , me         a snh s p e
                                                                 a
  S +S +S +S .                                               l i k e
                                                             r e c t a n g
                               2 cm
                                                             l e
                                                             wh i c h
Perimeter is 4 x 2                                           h a s a l l
                        2 cm                 2 cm
                                                             s i d e s
= 8 cm                                                       e q u a l .


                               2 cm
                                                    2 cm


• Ar e a :                            2 cm                         2 cm


Area is 2 x 2 = 4 cm2
                                                    2 cm
P a r a l l e l o g r aA m a l
                            p a r                          l e
• P e r i me t e r :                             l o g r a m
                                                 i s a
           , m e a n 5 s S +B +S +B .
                       cm                        s h a p e
                                                 wh i c h
                                                 h a s
                                                 o p p o s i t
                3 cm
                                         3 cm    e s i d e s
                                                 p a r a l l e
Perimeter is                                     l a n d
                       5 cm                      e q u a l .
2 x (5+3) = 16 cm

                                          5 cm
• Ar e a :
                              3 cm

Area is 5 x 3
= 15 cm2                      Altitude
                                          5 cm
Tr i a n g l e           I t
                                        s h
                                                i s a
                                              a p e
                                        wh    i c h h a s
• P e r i me t e r :                    3 s    i d e s
                                        c l   o s e d .(i t
                                        i s     h a l f o f
                                        a
                       3 cm          4 cm a
                                        p     r a l l e l o
Perimeter is                            g r   a m.
3+4+2 = 9 cm

                              2 cm




• Ar e a :
                                              3 cm
Area is
½ x 4 x 3 = 6 cm2                       4 cm
Ci r c l e i s a
               Ci r c l e     s h a p e
                              wh i c h h a s
• P e r i me t e r :          n o e d g e a n d
                              h a s a
                              Ce n t r e
                              p o i n t ,
                              d i a me t e r ,
Perimeter is                  r a d i u s (h a l
                       4 cm
                              f o f
3.14 x 4 = 12.56 cm           d i a m e t e r ),
                              e t c .




• Ar e a :
                                      3 cm


Area is 3.14 x 32
• A rectangular field is 45 m long 20 m wide, a person ran around it. How much
  did he run?
Length of the field = 45 m
Breadth of the field = 20 m
Therefore, Perimeter = 2 (45+20) m = 2 x 65 m = 130 m
Ans: He covered 130 m
• A rectangular field is 10 m long and 7 m wide. What is the area of the field?
Length of the field = 10 m
Breadth of the field = 7 m
Therefore, Area = 10 x 7 m 2 = 70 m2
Ans: The area is 70 m 2 .
• Find the perimeter of the square which has the sides of 2 cm.
Side of the square = 25 cm
Therefore the perimeter = 25 x 4 = 100 cm
Ans: The perimeter is 100 cm.


• Find the area of the square which has the side of 7 cm.
Side of the square = 7 cm
Area of the square = 7 x 7 cm 2 = 49 cm2
Ans: The area is 49 cm2
• Find the perimeter of a parallelogram which has the sides of 15 and
  10 cm.
Parallel sides of the parallelogram = 15 cm
Parallel sides of the parallelogram = 10 cm
Therefore, perimeter = 2 x (10+15) = 2 x 25 = 50 cm
Ans: The perimeter is 50 cm.


• Find the area of a parallelogram which has altitude of 14 cm and base
  of 20 cm.
Altitude of the parallelogram = 14 cm
Base of the parallelogram = 20 cm
Therefore area = 14 x 20 = 280 cm 2
Ans: Area of the parallelogram is 280 cm2
• An equilateral triangle has sides of 36 cm. A person rolled around a
  wire around it. What is the length of the wire?
Length of the side of the equilateral triangle = 36 cm
Therefore, perimeter = 36 x 3 = 108 cm
Ans: The length of the wire is 108 cm.


• A triangle has a base of 10 cm and has the altitude of 15 cm. Find the
  area of the triangle.
Base of the triangle = 10 cm
Altitude of the triangle = 15 cm
Therefore, Area = ½ x 10 x 15 = 75 cm 2
Ans: The area is 75 cm 2.
• Amit has a circular disc. He measured the radius which is 8 cm. What
  is the circumference of the circle.
Diameter of the circle = 8 x 2 = 16 cm
Therefore, perimeter is 3.14 x 16 = 50.24 cm
Ans: The circumference is 50.24 cm.


• Rajan has a wheel which has diameter of 10 cm. He wants cover it
  with a flat cover. For that he needs to find the area. What is the area?
Radius of the wheel = 10/2 = 5 cm
Therefore, area = 3.14 x 5 x 5 = 78.5 cm 2
Ans: The area is 78.5 cm 2
•   A man wants to fence around this shaped field. His brother wants put grass in that field.
    Cost of the fencing is Rs. 10 / m and cost of putting grass is Rs. 7 / m 2 . Which costs
    more?
Fencing: Perimeter is 2+7+7+4+10 cm
= 30 cm
                                                                               7m
Therefore, the cost is Rs. 30 x 10
= Rs 300 is cost of fencing.
Putting grass: Area of the square 7x 7                                 7m
                                                      4m
= 49 m2
Area of the rectangle 4 by 3 m                                                10 m
= 4 x 3 = 12 m 2
Area of the triangle = ½ x 3 x 3 = 4.5 m 2
Total area is 49+12+4.5 m 2 = 65.5 m2
Cost is Rs. 7 x 65.5 = Rs. 458.5
Ans: Putting grass is more costly.
• A square has a same area of a triangle. The side of the square is x, and base
  of the triangle is also x, what will be the altitude of the triangle?

The area of the triangle =   xxx
Therefore, let the altitude be a
ATQ

X x a x ½ = x2
   a x ½ = x2 / x
    a=xx2
    a = 2x
Ans: the altitude is 2x
• A parallelogram has a altitude of 10 cm . And a circle has a area
  of equal to the area of the parallelogram. The circle also has the
  diameter of 10 cm. find the base of the parallelogram.
Area of the parallelogram = Area of the Circle
Therefore, Area of the circle = 3.14 x r x r
Radius = 10/2 = 5 cm
Therefore area = 3.14 x 5 x 5 = 3.14 x 25 = 78.5 cm 2
Therefore base of the parallelogram = 78.5/10 = 7.85 cm
Ans: The base is 7.85 cm
Mathematics (Perimeter and Area)

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Mathematics (Perimeter and Area)

  • 1.
  • 2. • Introduction • Formulae • Solving sums • HOT Questions
  • 3. • P e r i me t e r : P e r i me t e r i s t h e d i s t a n c e a r o u n d a 2D s h a p e . L i k e i n t h e f o l l o wi n g s h a p e t h e d i s t a n c e o f t h e b o r d e r o r t h e s h a d e d p o r t i o n i s t h e Pe r i me t e r .
  • 4. • Ar e a : A r e a i s t h e i n n e r s u r f a c e o f a s h a p e o r t h i n g , i t i s u s u a l l y a 2D s h a p e . L i k e i n t h e f o l l o wi n g s h a p e t h e s h a d e d p o r t i o n i s Area t h e Ar e a o f t h e s h a p e .
  • 5. • I n t h i s p r e s e n t a t i o n we wi l l l e a r n a b o u t t h e f o l l o w i n g sPhea rp ie m : t e s e r i s 1. R e c t a n g l e a l wa y s 2.S q u a r e e x p r e s s e 3.P a r a l l e l o gdr ai m U n i t n 4.T r i a n g l e a n d a r e a 5.C i r c l e i n U n i t 2. We w i l l l e a r n a b o u t t h e a r e a a n d p e r i me t e r .
  • 6. Re c t a Re c t a n g l e  P e r i me t en : l e r g me a n s m e a n s , L +B +L +B f o u r 5 cm s i d e s h a p e wh i c h 2 cm 2 cm h a s o p p o s i t e Perimeter is 2 x (5+2) = 14 cm 5 cm s i d e s e q u a l . Ar e a : 5 cm Area is 5 x 2 2 cm 2 cm = 10 cm2 5 cm
  • 7. Sq u a r e Sq u a r e i s a • P e r i me t e r : , me a snh s p e a S +S +S +S . l i k e r e c t a n g 2 cm l e wh i c h Perimeter is 4 x 2 h a s a l l 2 cm 2 cm s i d e s = 8 cm e q u a l . 2 cm 2 cm • Ar e a : 2 cm 2 cm Area is 2 x 2 = 4 cm2 2 cm
  • 8. P a r a l l e l o g r aA m a l p a r l e • P e r i me t e r : l o g r a m i s a , m e a n 5 s S +B +S +B . cm s h a p e wh i c h h a s o p p o s i t 3 cm 3 cm e s i d e s p a r a l l e Perimeter is l a n d 5 cm e q u a l . 2 x (5+3) = 16 cm 5 cm • Ar e a : 3 cm Area is 5 x 3 = 15 cm2 Altitude 5 cm
  • 9. Tr i a n g l e I t s h i s a a p e wh i c h h a s • P e r i me t e r : 3 s i d e s c l o s e d .(i t i s h a l f o f a 3 cm 4 cm a p r a l l e l o Perimeter is g r a m. 3+4+2 = 9 cm 2 cm • Ar e a : 3 cm Area is ½ x 4 x 3 = 6 cm2 4 cm
  • 10. Ci r c l e i s a Ci r c l e s h a p e wh i c h h a s • P e r i me t e r : n o e d g e a n d h a s a Ce n t r e p o i n t , d i a me t e r , Perimeter is r a d i u s (h a l 4 cm f o f 3.14 x 4 = 12.56 cm d i a m e t e r ), e t c . • Ar e a : 3 cm Area is 3.14 x 32
  • 11. • A rectangular field is 45 m long 20 m wide, a person ran around it. How much did he run? Length of the field = 45 m Breadth of the field = 20 m Therefore, Perimeter = 2 (45+20) m = 2 x 65 m = 130 m Ans: He covered 130 m • A rectangular field is 10 m long and 7 m wide. What is the area of the field? Length of the field = 10 m Breadth of the field = 7 m Therefore, Area = 10 x 7 m 2 = 70 m2 Ans: The area is 70 m 2 .
  • 12. • Find the perimeter of the square which has the sides of 2 cm. Side of the square = 25 cm Therefore the perimeter = 25 x 4 = 100 cm Ans: The perimeter is 100 cm. • Find the area of the square which has the side of 7 cm. Side of the square = 7 cm Area of the square = 7 x 7 cm 2 = 49 cm2 Ans: The area is 49 cm2
  • 13. • Find the perimeter of a parallelogram which has the sides of 15 and 10 cm. Parallel sides of the parallelogram = 15 cm Parallel sides of the parallelogram = 10 cm Therefore, perimeter = 2 x (10+15) = 2 x 25 = 50 cm Ans: The perimeter is 50 cm. • Find the area of a parallelogram which has altitude of 14 cm and base of 20 cm. Altitude of the parallelogram = 14 cm Base of the parallelogram = 20 cm Therefore area = 14 x 20 = 280 cm 2 Ans: Area of the parallelogram is 280 cm2
  • 14. • An equilateral triangle has sides of 36 cm. A person rolled around a wire around it. What is the length of the wire? Length of the side of the equilateral triangle = 36 cm Therefore, perimeter = 36 x 3 = 108 cm Ans: The length of the wire is 108 cm. • A triangle has a base of 10 cm and has the altitude of 15 cm. Find the area of the triangle. Base of the triangle = 10 cm Altitude of the triangle = 15 cm Therefore, Area = ½ x 10 x 15 = 75 cm 2 Ans: The area is 75 cm 2.
  • 15. • Amit has a circular disc. He measured the radius which is 8 cm. What is the circumference of the circle. Diameter of the circle = 8 x 2 = 16 cm Therefore, perimeter is 3.14 x 16 = 50.24 cm Ans: The circumference is 50.24 cm. • Rajan has a wheel which has diameter of 10 cm. He wants cover it with a flat cover. For that he needs to find the area. What is the area? Radius of the wheel = 10/2 = 5 cm Therefore, area = 3.14 x 5 x 5 = 78.5 cm 2 Ans: The area is 78.5 cm 2
  • 16. A man wants to fence around this shaped field. His brother wants put grass in that field. Cost of the fencing is Rs. 10 / m and cost of putting grass is Rs. 7 / m 2 . Which costs more? Fencing: Perimeter is 2+7+7+4+10 cm = 30 cm 7m Therefore, the cost is Rs. 30 x 10 = Rs 300 is cost of fencing. Putting grass: Area of the square 7x 7 7m 4m = 49 m2 Area of the rectangle 4 by 3 m 10 m = 4 x 3 = 12 m 2 Area of the triangle = ½ x 3 x 3 = 4.5 m 2 Total area is 49+12+4.5 m 2 = 65.5 m2 Cost is Rs. 7 x 65.5 = Rs. 458.5 Ans: Putting grass is more costly.
  • 17. • A square has a same area of a triangle. The side of the square is x, and base of the triangle is also x, what will be the altitude of the triangle? The area of the triangle = xxx Therefore, let the altitude be a ATQ X x a x ½ = x2 a x ½ = x2 / x a=xx2 a = 2x Ans: the altitude is 2x
  • 18. • A parallelogram has a altitude of 10 cm . And a circle has a area of equal to the area of the parallelogram. The circle also has the diameter of 10 cm. find the base of the parallelogram. Area of the parallelogram = Area of the Circle Therefore, Area of the circle = 3.14 x r x r Radius = 10/2 = 5 cm Therefore area = 3.14 x 5 x 5 = 3.14 x 25 = 78.5 cm 2 Therefore base of the parallelogram = 78.5/10 = 7.85 cm Ans: The base is 7.85 cm