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CAR BRIDGE  DESIGNED BY  MAJD KHALIL  ALAA DWIKAT
TRUSSES
EXTERNAL FORCES <ul><li>FIRST STEP : </li></ul><ul><li>WE SHOULD FIND THE EXTERNAL FORCES  BY THE EQUATION OF STATIC EQUIL...
<ul><li>∑ FX=0; AX=0; </li></ul><ul><li>∑ FY=0; YA+YD-9800=0; </li></ul><ul><li>∑ MA=0; 9800(6)-YA(9)=0 </li></ul><ul><li>...
<ul><li>2-ANALYSIS THE FORCES ON EACH MEMBER BY STATIC EQUATION </li></ul><ul><li>PIN A: </li></ul><ul><li>∑ FY=0; </li></...
<ul><li>PIN G: </li></ul><ul><li>∑ FY=0; AGSIN60-GBSIN60=0 </li></ul><ul><li>GB=7.5KN (TENSION) </li></ul><ul><li>∑ FX=0; ...
<ul><li>PIN B: </li></ul><ul><li>∑ FY=0; </li></ul><ul><li>GBSIN60+FBIN60-9800=0; </li></ul><ul><li>FB=3.7KN </li></ul><ul...
<ul><li>THE MAXIMAM TENSION FORCE ON MEMBER  AG=7544 N </li></ul><ul><li>THE MAXIMAM COMPRESSION FORCE ON MEMBER GB & GF =...
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Bridge (statics analysis)

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Bridge (statics analysis)

  1. 1. CAR BRIDGE DESIGNED BY MAJD KHALIL ALAA DWIKAT
  2. 2. TRUSSES
  3. 3. EXTERNAL FORCES <ul><li>FIRST STEP : </li></ul><ul><li>WE SHOULD FIND THE EXTERNAL FORCES BY THE EQUATION OF STATIC EQUILIBRIUM: </li></ul><ul><li>THESE FORCES ARE: </li></ul><ul><li>1- PIN A </li></ul><ul><li>2- ROLLER D </li></ul><ul><li>3- WEIGHT OF CAR </li></ul>
  4. 4. <ul><li>∑ FX=0; AX=0; </li></ul><ul><li>∑ FY=0; YA+YD-9800=0; </li></ul><ul><li>∑ MA=0; 9800(6)-YA(9)=0 </li></ul><ul><li>YA=6533.3 N </li></ul><ul><li>YD=3266.7 N </li></ul>
  5. 5. <ul><li>2-ANALYSIS THE FORCES ON EACH MEMBER BY STATIC EQUATION </li></ul><ul><li>PIN A: </li></ul><ul><li>∑ FY=0; </li></ul><ul><li>6.5KN-AGSIN60=0; AG=7.5KN (COMPRESSION) </li></ul><ul><li>∑ FX=0;AB-AGCOS60 </li></ul><ul><li>AB=3.7KN (TENSION) </li></ul>
  6. 6. <ul><li>PIN G: </li></ul><ul><li>∑ FY=0; AGSIN60-GBSIN60=0 </li></ul><ul><li>GB=7.5KN (TENSION) </li></ul><ul><li>∑ FX=0; </li></ul><ul><li>AGCOS60+GBCOS60 </li></ul><ul><li>-GF=0 </li></ul><ul><li>GF=7.5KN </li></ul><ul><li>(COMPRESSION) </li></ul>
  7. 7. <ul><li>PIN B: </li></ul><ul><li>∑ FY=0; </li></ul><ul><li>GBSIN60+FBIN60-9800=0; </li></ul><ul><li>FB=3.7KN </li></ul><ul><li>(TENSION) </li></ul><ul><li>∑ FX=0; </li></ul><ul><li>BC-AB-GBCOS60 </li></ul><ul><li>+FBCOS60=0; </li></ul><ul><li>BC=5.6KN </li></ul><ul><li>(TENSION) </li></ul>
  8. 8. <ul><li>THE MAXIMAM TENSION FORCE ON MEMBER AG=7544 N </li></ul><ul><li>THE MAXIMAM COMPRESSION FORCE ON MEMBER GB & GF =7544 N </li></ul><ul><li>MINIMAM TENSION FORCE ON MEMBER CD=1886 N </li></ul>

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