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# DMD of first course is equal to the depature of the course 2- DMD of a.docx

DMD of first course is equal to the depature of the course 2. DMD of any other course is equal to the DMD of the preceding course, plus the departure of the preceding course, pluse the departure of the course itself 3. DMD of the last course is numerically equal to the departure of that course, but with the opposite sign A = 1/2 DMD times latitude DPD (double parallel Distance) Method 1. DPD of first course is equal to the latitude of the course 2. DPD of any other course is equal to the DPD of the preceding course, plus the latitude of the preceding course, 2. DPD of any other course is equal to the DPD of the preceding course, plus the latitude of the preceding course, plus the latitude of the course itself 3. DPD of the last course is nu,erically equal to the latitude of that course, but with the opposite sign. a=1/2 DPD times Departure EX3: Given the following data shown, finti the area of the traverse using DMD method.
Solution
For AB = 32.43 x 9.2 / 2 = 151.178
For BC = (32.43+5.25+151.78)x -6.35 / 2 = -601.53
For CD = (-601.53+5.25-26.8) x -28.96/2 = 9014.54
For DE = (9014.54-4.47-26.8)x 5.36)/2 = 24075.16
For EA = (24075.16+6.41)x20.45/2 = 246234.4
Total area = AB + BC + CD + DE + EA = 278873.4381
.

DMD of first course is equal to the depature of the course 2. DMD of any other course is equal to the DMD of the preceding course, plus the departure of the preceding course, pluse the departure of the course itself 3. DMD of the last course is numerically equal to the departure of that course, but with the opposite sign A = 1/2 DMD times latitude DPD (double parallel Distance) Method 1. DPD of first course is equal to the latitude of the course 2. DPD of any other course is equal to the DPD of the preceding course, plus the latitude of the preceding course, 2. DPD of any other course is equal to the DPD of the preceding course, plus the latitude of the preceding course, plus the latitude of the course itself 3. DPD of the last course is nu,erically equal to the latitude of that course, but with the opposite sign. a=1/2 DPD times Departure EX3: Given the following data shown, finti the area of the traverse using DMD method.
Solution
For AB = 32.43 x 9.2 / 2 = 151.178
For BC = (32.43+5.25+151.78)x -6.35 / 2 = -601.53
For CD = (-601.53+5.25-26.8) x -28.96/2 = 9014.54
For DE = (9014.54-4.47-26.8)x 5.36)/2 = 24075.16
For EA = (24075.16+6.41)x20.45/2 = 246234.4
Total area = AB + BC + CD + DE + EA = 278873.4381
.

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### DMD of first course is equal to the depature of the course 2- DMD of a.docx

1. 1. DMD of first course is equal to the depature of the course 2. DMD of any other course is equal to the DMD of the preceding course, plus the departure of the preceding course, pluse the departure of the course itself 3. DMD of the last course is numerically equal to the departure of that course, but with the opposite sign A = 1/2 DMD times latitude DPD (double parallel Distance) Method 1. DPD of first course is equal to the latitude of the course 2. DPD of any other course is equal to the DPD of the preceding course, plus the latitude of the preceding course, 2. DPD of any other course is equal to the DPD of the preceding course, plus the latitude of the preceding course, plus the latitude of the course itself 3. DPD of the last course is nu,erically equal to the latitude of that course, but with the opposite sign. a=1/2 DPD times Departure EX3: Given the following data shown, finti the area of the traverse using DMD method. Solution For AB = 32.43 x 9.2 / 2 = 151.178 For BC = (32.43+5.25+151.78)x -6.35 / 2 = -601.53 For CD = (-601.53+5.25-26.8) x -28.96/2 = 9014.54 For DE = (9014.54-4.47-26.8)x 5.36)/2 = 24075.16 For EA = (24075.16+6.41)x20.45/2 = 246234.4 Total area = AB + BC + CD + DE + EA = 278873.4381