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Jan. 31, 2023•0 likes•5 views

Jan. 31, 2023•0 likes•5 views

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Difference Equations: Solve the following difference equation using recursion by hand (for n=0 to n=4) y[n] + 0.5y[n-1] = 2x[n-1]; x[n] = ?[n], y[-1] = 0 Solution Del n =0 for n = 0 and -1 for n < 0 and 1 for n > 0. So, using this we get .

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- 1. Difference Equations: Solve the following difference equation using recursion by hand (for n=0 to n=4) y[n] + 0.5y[n-1] = 2x[n-1]; x[n] = ?[n], y[-1] = 0 Solution Del n =0 for n = 0 and -1 for n < 0 and 1 for n > 0. So, using this we get n x(n) y(n) y(n-1) x(n-1) 0 0 -2 0 -1 1 1 1 -2 0 2 1 1.5 1 1 3 1 1.25 1.5 1 4 1 1.375 1.25 1