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# Free Body Diagram

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Description of free body diagram drawing process

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• ### Free Body Diagram

1. 1. Free Body Diagram It’s Really Easy
2. 2. HI THERE! MY I’M BILLY THE NAME IS VINNIE BOX! THE VECTOR! AND I’M TERRY THE TABLE. TOGETHER WE WILL TRY TO EXPLAIN THE FREE BODY DIAGRAM
3. 3. I AM MADE OF MATTER, THEREFORE I HAVE MASS AND BECAUSE BILLY HAS MASS, THE EARTH PULLS HIM DOWN. WE CALL THIS PULL “WEIGHT”
4. 4. I HAVE A MASS OF 1O KILOGRAMS. EVERYONE SAYS I HAVE A REALLY NICE MASS. BECAUSE OF THE EARTH’S GRAVITY, BILLY HAS WEIGHT. THE WEIGHT IS A FORCE. EACH KILOGRAM OF MASS HAS A WEIGHT OF 9.8 NEWTONS. BILLY WEIGHS 98 NEWTONS.
5. 5. I WEIGH 98 NEWTONS! I BECAUSE WEIGHT IS A REPRESENT FORCE, WE USE VECTORS TO BILLY’S WEIGHT. I SHOW THE FORCE. VECTORS AM 98 NEWTONS HAVE 2 PARTS, SIZE AND DOWN. DIRECTION.
6. 6. I WEIGH 98 NEWTONS! NOW BILLY IS SITTING ON ME. I AM HOLDING UP HIS WEIGHT. I DO THIS WITH A FORCE OF MY OWN. I CALL IT A NORMAL FORCE. I REPRESENT BILLY’S WEIGHT. I AM 98 NEWTONS DOWN.
7. 7. NOTICE THAT THE NORMAL FORCE IS EXACTLY I THE SAME SIZE AS BILLY’S REPRESENT THE WEIGHT. NOTICE ALSO THAT NORMAL FORCE. I AM IT IS THE OPPOSITE IN 98 NEWTONS UP. DIRECTION. IMPORTANT THE TWO FORCES ARE THE SAME SIZE AND IN OPPOSITE DIRECTIONS. BECAUSE I OF THIS, THEY CANCEL REPRESENT BILLY’S WEIGHT. I EACH OTHER. WHEN AM 98 NEWTONS FORCES CANCEL EACH DOWN. OTHER, THE NET FORCE = 0 NEWTONS.
8. 8. NOW WE WILL WORK TOGETHER TO IT’S REALLY SHOW SOME EASY. TRUST ME, I’M EXAMPLES! A BOX LET’S START WITH AN EASY ONE....
9. 9. BILLY THE BOX IS PLACED ON A FLAT SURFACE. BILLY HAS A MASS OF 5 KILOGRAMS. A FORCE OF 12 NEWTONS IS APPLIED TO BILLY CAUSING HIM TO MOVE AT A CONSTANT SPEED TO THE RIGHT. DRAW THE FREE BODY DIAGRAM. I GET PUSHED AROUND. AND I HOLD 5 KG EVERYTHING UP... I WILL BE SHOWING THE FORCES.
10. 10. BILLY THE BOX IS PLACED ON A FLAT SURFACE. BILLY HAS A MASS OF 5 KILOGRAMS. A FORCE OF 12 NEWTONS IS APPLIED TO BILLY CAUSING HIM TO MOVE AT A CONSTANT SPEED TO THE RIGHT. DRAW THE FREE BODY DIAGRAM. BECAUSE I HAVE A MASS OF 5 KG, I HAVE A WEIGHT OF BECAUSE 5 KG 49 NEWTONS. BILLY IS MOVING AT A CONSTANT SPEED, THE NET FORCE ON HIM MUST BE ZERO. I AM A VECTOR THAT HAS A SIZE OF 49 NEWTONS AND MY DIRECTION IS DOWN
11. 11. BILLY THE BOX IS PLACED ON A FLAT SURFACE. BILLY HAS A MASS OF 5 KILOGRAMS. A FORCE OF 12 NEWTONS IS APPLIED TO BILLY CAUSING HIM TO MOVE AT A CONSTANT SPEED TO THE RIGHT. DRAW THE FREE BODY DIAGRAM. FIRST, WE PLACE BILLY ON ME. I AM NOW FEELING BILLY’S WEIGHT OF 49 NEWTONS. 5 KG 49 NEWTONS DOWN
12. 12. BILLY THE BOX IS PLACED ON A FLAT SURFACE. BILLY HAS A MASS OF 5 KILOGRAMS. A FORCE OF 12 NEWTONS IS APPLIED TO BILLY CAUSING HIM TO MOVE AT A CONSTANT SPEED TO THE RIGHT. DRAW THE FREE BODY DIAGRAM. 49 NEWTONS UP NEXT, IN ORDER TO HOLD BILLY UP, I APPLY A NORMAL FORCE. IT IS THE SAME SIZE AS BILLY’S WEIGHT. 5 KG 49 NEWTONS DOWN
13. 13. BILLY THE BOX IS PLACED ON A FLAT SURFACE. BILLY HAS A MASS OF 5 KILOGRAMS. A FORCE OF 12 NEWTONS IS APPLIED TO BILLY CAUSING HIM TO MOVE AT A CONSTANT SPEED TO THE RIGHT. DRAW THE FREE BODY DIAGRAM. 49 NEWTONS UP NOW WE APPLY THE 12 NEWTON FORCE PUSHING BILLY TO THE RIGHT. THE DIRECTION OF THE ARROW 12 NEWTONS IS THE THE DIRECTION OF THE FORCE. RIGHT 5 KG 49 NEWTONS DOWN
14. 14. BILLY THE BOX IS PLACED ON A FLAT SURFACE. BILLY HAS A MASS OF 5 KILOGRAMS. A FORCE OF 12 NEWTONS IS APPLIED TO BILLY CAUSING HIM TO MOVE AT A CONSTANT SPEED TO THE RIGHT. DRAW THE FREE BODY DIAGRAM. 49 NEWTONS UP THIS IS IMPORTANT! BECAUSE BILLY MOVING AT A CONSTANT SPEED, THE NET FORCE ON HIM MUST BE ZERO. THEREFORE, 12 NEWTONS SOMETHING MUST BALANCE THE APPLIED RIGHT FORCE. 5 KG 49 NEWTONS DOWN
15. 15. BILLY THE BOX IS PLACED ON A FLAT SURFACE. BILLY HAS A MASS OF 5 KILOGRAMS. A FORCE OF 12 NEWTONS IS APPLIED TO BILLY CAUSING HIM TO MOVE AT A CONSTANT SPEED TO THE RIGHT. DRAW THE FREE BODY DIAGRAM. 49 NEWTONS UP THAT FORCE IS FRICTION. IT WORKS IN THE OPPOSITE DIRECTION THAT BILLY IS MOVING. BECAUSE HE IS MOVING AT A 12 NEWTONS CONSTANT SPEED, THE 12 NEWTONS FRICTION IS THE SAME SIZE RIGHT LEFT AS THE APPLIED FORCE. 5 KG 49 NEWTONS DOWN
16. 16. BILLY THE BOX IS PLACED ON A FLAT SURFACE. BILLY HAS A MASS OF 5 KILOGRAMS. A FORCE OF 12 NEWTONS IS APPLIED TO BILLY CAUSING HIM TO MOVE AT A CONSTANT SPEED TO THE RIGHT. DRAW THE FREE BODY DIAGRAM. 49 NEWTONS UP BECAUSE ALL OF THE FORCES ON BILLY ARE BALANCED, THE NET FORCE IS ZERO AND HE IS AT 12 NEWTONS 12 NEWTONS EQUILIBRIUM. LET’S TRY RIGHT ANOTHER... LEFT 5 KG 49 NEWTONS DOWN
17. 17. BILLY THE BOX IS PLACED ON A FLAT SURFACE. BILLY HAS A MASS OF 5 KILOGRAMS. A FORCE OF 12 NEWTONS IS APPLIED TO BILLY CAUSING HIM TO ACCELERATE TO THE RIGHT. IF THE NET FORCE ON BILLY IS 10 NEWTONS RIGHT, DRAW THE FREE BODY DIAGRAM. 49 NEWTONS UP BILLY STILL WEIGHS THE SAME, SO THE WEIGHT AND NORMAL FORCES ARE THE 12 NEWTONS ? NEWTONS SAME. WHAT’S DIFFERENT? RIGHT LEFT 5 KG 49 NEWTONS DOWN
18. 18. BILLY THE BOX IS PLACED ON A FLAT SURFACE. BILLY HAS A MASS OF 5 KILOGRAMS. A FORCE OF 12 NEWTONS IS APPLIED TO BILLY CAUSING HIM TO ACCELERATE TO THE RIGHT. IF THE NET FORCE ON BILLY IS 10 NEWTONS RIGHT, DRAW THE FREE BODY DIAGRAM. 49 NEWTONS UP BECAUSE BILLY IS ACCELERATING, THE NET FORCE ON HIM CANNOT BE ZERO. THE FORCE OF FRICTION MUST BE SMALLER 12 NEWTONS ? NEWTONS THAN THE APPLIED FORCE. RIGHT LEFT HOW MUCH SMALLER? 5 KG 49 NEWTONS DOWN
19. 19. BILLY THE BOX IS PLACED ON A FLAT SURFACE. BILLY HAS A MASS OF 5 KILOGRAMS. A FORCE OF 12 NEWTONS IS APPLIED TO BILLY CAUSING HIM TO ACCELERATE TO THE RIGHT. IF THE NET FORCE ON BILLY IS 10 NEWTONS RIGHT, DRAW THE FREE BODY DIAGRAM. 49 NEWTONS UP IF WE ARE APPLYING A 12 NEWTON FORCE TO BILLY AND YET THE NET FORCE IS ONLY 10 NEWTONS, THERE IS A DIFFERENCE OF 2 12 NEWTONS ? NEWTONS NEWTONS. THIS RIGHT LEFT DIFFERENCE COMES FROM 5 KG FRICTION. 49 NEWTONS DOWN
20. 20. BILLY THE BOX IS PLACED ON A FLAT SURFACE. BILLY HAS A MASS OF 5 KILOGRAMS. A FORCE OF 12 NEWTONS IS APPLIED TO BILLY CAUSING HIM TO ACCELERATE TO THE RIGHT. IF THE NET FORCE ON BILLY IS 10 NEWTONS RIGHT, DRAW THE FREE BODY DIAGRAM. 49 NEWTONS UP IN ORDER FOR ALL THIS TO WORK, THE FORCE OF FRICTION MUST BE 2 NEWTONS TO THE LEFT. 12 NEWTONS 2 NEWTONS HOPE THIS HELPS. RIGHT LEFT 5 KG 49 NEWTONS DOWN